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RPO
RPO
17:05
Hi
is it possible to write a tuple with conditions ?
e.g. $G = (f(x) | x = D, |G| = 4)$
17:22
What are you trying to do
Hi, here ([1]: https://i.sstatic.net/g40dH.png
[2]: https://i.sstatic.net/SJRsl.png) in a generalization of the implicit function theorem I don't understand the fact that the domain is an open subset of $R^{n+m}$
Can anyone help?
It's in Italian, but if necessary I'll translate it
Che cosa ti confonde esattamente?
Non mi è ben chiaro perchè il dominio è in $R$ elevato a m+n
la potenza
Se questa è una generalizzazione la versione "base" è con funzioni $\Bbb R^2\to\Bbb R$?
o a partire da funzioni di tre variabili
17:37
Ok allora nella versione base hai funzioni $\Bbb R^{1+1}\to\Bbb R$ e ti serve un minore $1\times 1$ dello Jacobiano non nullo (quindi di fatto basta chiedere $\partial _yF(x_0,y_0)\neq 0$)
Mh, ma non abbiamo due come dimensioni n?
no in questo caso hai $n=m=1$
Ah, cioè ogni vettore ha una sola componente?
No nel dominio ne hanno due, nel codominio una
perciò per n bisogna guardare al codominio?
17:44
$m$ è la dimensione del codominio, $n$ la differenza fra quella del dominio e quella del codominio (la prima deve essere più grande)
Ah, capito, grazie mille
Dove studi per curiosità?
Grazie anche per l'Italiano :P
Politecnico di Milano
é un corso misto tra ingegneria biomedica e Medicina e chirurgia
purtroppo in matematica saltiamo molti argomenti
17:54
Perché tutti parlano italiano? 🙃
Warum nicht?
Pourquoi non?
Perché no?
Mi piace l'italiano ma il mio è male
@AlessandroCodenotti Warte, du warst ja in Bonn 👍 Ok dann schlage ich vor, dass wir auf Deutsch umstellen 😉
17:58
Da die Vorlesungen in Bonn auf Englisch sind, ist mein Deutsch ziemlich schlecht :S
@AlessandroCodenotti umso besser, wenn wir uns nur noch auf Deutsch unterhalten hehe
Vielleicht...
There's many people here in the chat that speak German
18:15
Oui
18:39
Ita est.
19:07
Niemand darf auf deutsch reden.
@Shoot: First of all, that text committed the sin of writing $I\in\Bbb R^n$ instead of $\subset$. That upsets me for an actual text, and not a student. What is the problem with having the domain be an open subset of $\Bbb R^{m+n}$? This generalizes $2+1$ that you had before.
This reminds me of my analysis prof who used to write $(a_n)_n\subset\mathbb{R}$ for sequences. Not as upsetting as $I\in\mathbb{R}^n$, but it still makes me shudder.
Well, if you think of a sequence as an indexed subset, it's fine.
19:24
The problem is that the indexing doesn't happen in $\mathbb{R}$
@TedShifrin True, that generalizes. Forgive me but I'm quite struggling with these concepts. For example I don't get how these n dimensions relate to the vector X we choose, while Y has m components
You're just writing the variables in $\Bbb R^n$ as one vector variable and the variables in $\Bbb R^m$ as the other vector variable. It's the best notation to use. You can see this stuff explicitly in my YouTube lectures.
But I am very upset by the error in the text.
ahahah yes that was really awful, even to me
@TedShifrin ok, this evening @TedS' lectures marathon for me :p
It's generalizing write $z=\phi(x,y)$ as $\vec Y = \phi(\vec X)$, where in this case $\vec Y = z$ and $\vec X = (x,y)$.
No, for the implicit and inverse function theorem you only need the one lecture with the statement(s) and example(s). You don't need the proofs.
@TedShifrin ahh, I see, thanks
19:29
The introductory, less fancy, version is 3500 days 39-40; the general version is 3510 day 20.
Great! Thanks very much!
A way to think about it is as sort of similar to a system of linear equations (after all, differentiable just means locally well-approximable by linear functions). You have n+m variables and m equations, so once after fixing n of the variables, you have m variables and m equations left, which - with a regularity assumption, the invertibility of the Jacobian - yields you a unique solution. The remaining n variables can be thought of as giving you n degrees of freedom.
Indeed, in the first lectures I listed, I talk about how one should understand this as the generalization of solving linear equations (pivot variables, free variables).
In concept, a lot of multivariable analysis is trying to do linear algebra with things that aren't really linear :p
Absolutely. That's why I created my course/text putting the two subjects together.
19:59
@Thorgott that's "calculus" in a nutshell.
@Thorgott Thanks!
20:26
np
btw @Balarka, my aforementioned friend just returned from his vacation, but he told me he hasn't seen the Janson-Suen inequality before. However, in the meanwhile, I have checked Random Graphs from Luczak, Rucinski and Janson himself; didn't have the time to ponder all the details, but it has a proof of the inequality, which is self-contained and accessible, so you might consider checking that out.
20:37
Let $F_X$ be the CDF of a random variable $X$. Then $F_{\max \{A, B\}} = F_A F_B$. Is there a similar expression for the quantile function (inverse CDF) $F^{-1}_{\max \{A, B\}}$ in terms of $F_A$, $F_B$, $F^{-1}_A$, $F^{-1}_B$, and similar terms?
20:53
Most areas of mathematics are developed to solve some already known problems - this is essentially necessary for enough mathematicians to gain interest to develop them. Can someone tell me what types of problems intersection theory in algebraic geometry is developed for?
Oh @loch is here, you were the person I was going to @ lol
Or does it go the other way? Intersection theory was already interesting in classical AG, where it seemed actually intuitive, and now we're just putting it in a more general framework to deal with more general schemes?
Hi @MatheinBoulomenos
21:09
You have some good answers on main
What do you study?
number theory, mostly
algebraic or analytic? (or both) and from an AG perspective or no?
more algebraic than analytic and with lots of AG
21:10
Oh nice
Are you interested in intersection theory in AG by any chance?
regarding your question on intersection theory: the theory of general schemes allows to capture more even for intersections of classical varieties
How so?
I get that intersecting lines with curves for example just 'gives' the correct intersection numbers, which is quite beautiful (when dealing with them as schemes)
there's a simple example: consider in the plane the line y=0 and the parabola y=x^2. These intersect non-transversally which is captured by the fact that the scheme-theoretic intersection is non-reduced
Ah yeah, that's one of the ones I had in mind
I also liked intersecting $x=0$ with $y^3=x^2+ax$ (I think it was, as $a$ varies)
but the modern approach seems to intersection theory seems to use derived algebraic geometry to capture even more information
there's a nice talk by Lurie on that on youtube
21:13
Actually, that's why I'm reading intersection theory
Since it seems to be the entry point to motivating DAG
maybe you already know this talk, then: youtube.com/watch?v=htTL0VvfsvM
I didn't, I'll watch it
as far as motivations for DAG go, this is the best I've seen so far
this derived approach to intersection theory is really hot in NT right now as well
Does transverse intersection only make sense for smooth subvarieties of a smooth variety?
from the abstract of a recent paper by Galatius/Venkatesh that seems to be very much discussed among some number theorists right now "speaking informally, the locus of crystalline Galois representations of $\mathrm{Gal}(\overline{\Bbb Q}/\Bbb Q)$ is obtained by intersecting the space of Galois representations of $\mathrm{Gal}(\overline{\Bbb Q}/\Bbb Q)$ with the space of local geometric representations of $\mathrm{Gal}(\overline{\Bbb Q}/\Bbb Q)$ and the intersection is
not, in general, transverse."
21:19
I see
@TedE hmm, good question. Maybe, one might say that a non-smooth variety doesn't intersect itself transversally
What is meant by locus in that context?
Does it mean something like taking the direct sum of all irreps, and taking the kernel?
Nah that wouldn't make sense I guess, since it wouldn't give a space
no, you have some "space" (probably a stack in general, in any case a geometric object) such that every point corresponds to a galois representation
Is $\text{Gal}(\overline{\Bbb Q}/\Bbb Q)$ an algebraic group here?
Oh, I see
We can deal with intersections of stacks (that aren't represented by schemes) then?
I'm no expert, but I think so, yes
21:23
Hmm, I wonder how
What do you study? Are you a student?
I'd be interested in seeing how intersections of stacks classifying G-torsors and H-torsors behaves
I'm not a student atm, taking a gap year, but I did do my undergrad in math
ah I see
I'm in the process of finishing my undergrad myself
Oh nice, and then phd?
masters first, I'm European
21:37
@TedShifrin are you around? long time no see
21:53
@MatheinBoulomenos I find the part at 12:30 slightly confusing
It seems he's moved onto $C,C'$ subvarieties of $\Bbb CP^n$, and he's taking $C$ to be given by some homogeneous polynomial, and then he says $C'$ has ring of functions $R$. Is $C'$ by assumption affine for some reason?
Hi there @MaximilianJanisch
@TedShifrin Damn not bad
Hi there @MaximilianJanisch
Oh wait, I just realised he said "Lets consider a special case, which is not really applicable to our situation"
21:56
Ok so I found out that at least two people in this chat play chess
Well, I only just started playing really a few days ago haha
Do you play on lichess?
Yes, Balarka invited me there
Or was it Leaky
One of those two lol
I'm actually pretty active there
What's your username
Has anyone a software which can factor with the quadratic sieve the 89 digit composite number :
(5^164+3^164+1)/268850372931522596788077287 ?
21:58
TedE112412413 (I tried TedE and a bunch of combinations, and it kept failing, so I mashed some numbers)
Oh hi @Peter. Somehow I could've guessed who asked this question without even seeing the username ;)
Ok I'll follow you on lichess @TedE
Would you like to play a 3+2 game?
sure lets go
22:25
heya @Mathein!
@MaximilianJanisch I wonder if he just had a script
@TedE There were some videos of him playing 1/4+0 against Stockfish level 1
which is super crazy because that thing has almost 0 delay between moves
Also there is one guy who beat Stockfish level 1
You mean he beat stockfish level 1 in actual chess (in 1/4+0), or he won in the 'fastest player challenge' by flagging it?
He (not the fast guy, somebody else) won against it in 1/4+0 chess
Oh gotcha
22:30
there is a live playback feature
Doesn't stockfish play the same way in response to your moves, so you could choose a move sequence?
@TedE I think there is some randomness
on the lichess version
especially level 1
okay actually the game I linked you is really lame
because Stockfish just resigns on move 151
Here is a real win: lichess.org/FH6GH3Xq/black
I think I'll give this a shot
hehe good luck
I thought stockfish 1 was meant to be terrible lol
It just rekt me
22:36
Yeah it plays really bad but super fast
So I never managed to beat it for example in 1/4+0
Already in 1+0 it is easy to beat I think
My latest failed attempt: lichess.org/8AO2RVKh
also 1/2+0 is still hard: lichess.org/FS1q96TM
hi @Zacky
Hello there!
@Shootforthemoon Do you have new insights on the implicit function Theorem? 😄
Hey
yesm somehow XD
I've almost done with my research on it
Do u play chess @Max?
@Shootforthemoon Yes I do
:D
@TedE 1+0 is already (somewhat) easy: lichess.org/MYCSkWn5
Nice, I play sometimes too
22:46
Also sometimes on lichess ?
@MaximilianJanisch I'll have to try it out later on :). For now I'm just watching that video lecture posted above
have fun @TedE
@Shootforthemoon What's your username?
luca51 but don't look at my score lol
Lets do an atomic game
22:48
at least I've beaten @Leaky
@Shootforthemoon So did I 😄
@MaximilianJanisch ok
what time control?
7+2?
around that
or 5+5
okay lets go 7+2
22:50
fine!
23:05
can someone explain me, how did Adriano replace 10 by k in this proof? math.stackexchange.com/questions/447923/…
Cause $10\le k$
so if have N and T such that N < T, I can replace N by T?
Can someone answer my question here? stats.stackexchange.com/questions/442555/…
i don't know what you mean by replacing
it's simply estimating
Is there anyone else here who wants to play chess ?
23:22
@Thorgott here's what I don't get it. He's trying to proove that $(k+1)^3 < 2^{k+1}$ he expands the polynomial to $k^3 + 3k^2 + 3k + 1$ and on the next line he changed it to $k^3 + 3k^2 + 9k + 10$. So to me, he doesn't seem to be proving the original problem. He's now prooving that $k^3 + 3k^2 + 9k + 10 < 2^{k+1}$ rather than $(k+1)^3 < 2^{k+1}$
One implies the other, because $k^3+3k^2+3k+1<k^3+9k^2+9k+10$
don't you have to prove that before?
well, Adriano probably considered this to be obvious
23:39
@Trey By the way a different "continuous" approach to this problem: We have for $k\geq e$ by taking the logarithm to basis $e$: $$k^3\le 2^k\iff 3 \ln(k)\le k\cdot\ln(2)\iff\frac{3}{\ln(2)}\le\frac{k}{\ln(k)}$$
But $\frac{k}{\ln(k)}$ is increasing for $k\geq e$ as can be proven by taking the derivative
So we need to solve $\frac{3}{\ln(2)}=\frac{k}{\ln(k)}$
It turns out that no symbolic solutions (without the Lambert W function) exist
but numerically we have $k\approx 9.94$
So in fact the above inequality holds for all $k\geq 9.95$
Admittedly this is overkill, one can also just check that $\frac{10}{\ln(10)}\geq\frac{3}{\ln(2)}$ to get the same result for all $k\geq 10$ (but in this result, non-natural numbers $k$ are also allowed)
Ok does anybody of you know something about Bernoulli walks
?
Because I am wondering
If I have a 1D-walk where each added Bernoulli r.v. has parameter $p\in[0,1]$, then what is the probability of ever crossing the zero line?
I think it should be $1-|p-(1-p)|=1-|1-2p|$

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