In mathematics, the Dehn–Sommerville equations are a complete set of linear relations between the numbers of faces of different dimension of a simplicial polytope. For polytopes of dimension 4 and 5, they were found by Max Dehn in 1905. Their general form was established by Duncan Sommerville in 1927. The Dehn–Sommerville equations can be restated as a symmetry condition for the h-vector of the simplicial polytope and this has become the standard formulation in recent combinatorics literature. By duality, analogous equations hold for simple polytopes.
== Statement ==
Let P be a d-dimensi...
Didn't know about this - this is the generalization of V-E+F=2
Question: If a ring $R$ has an ideal $I$ such that $R/I\cong\mathbb{Z}$ can we say that $R$ is isomorphic to a direct product of rings such that one coordinate of that product is $\mathbb{Z}$?
Alright, more general question: given any ring homomorphism $\phi: R\to Q$, is it true that $\text{ker}(\phi)\times\text{Im}(\phi)\cong R$? I know there is an analogous statement that's true for vector spaces, but I can't find details about if this is true in a general ring
I initially thought that the (2n-1) was a drop in replacement for the top of the Σ. So whenever you would see (2n-1) you just put that at the top. But, that's not always the case.
You might also see something like $\sum\limits_{i\in I}f(i)$, which means "I have this bunch of things that I call $I$, and I want to apply this function $f$ to each thing in $I$ and then add together the resultant values" (and clearly, $\sum\limits_{i\in I}f(i)$ is easier to write)
@MikeMiller Does any functor representable by a spectrum satisfy Mayer-Vietoris? Surely not, right? I suppose you can always get a long exact sequence by dualizing the Puppe sequence
(as far as I recall Mayer-Vietoris is part of the hypothesis when stating Brown representability)
Given an odd number n, you can add 2*k to n and the result will be odd. Is there a way to extend this concept to skip multiples of 2 and 3? For example if you know n does not have factors 2 nor 3, what can you add to it to ensure the result also doesn't have multiples of two or 3?
Well, you just need to look at the number modulo 2 and modulo 3. (a + b) modulo p $\equiv$ (a modulo p) + (b modulo p)
So, if a $\equiv$ 1 mod 2, then you need to add something that is not equivalent to 1 mod 2. So it must be equivalent to 0 mod 2. In other words, it's of the form $2k$ for some $k\in\mathbb{Z}$. If a $\equiv$ 1 mod 3, then you need something that isn't equivalent to 2 mod 3, and so must be of the form $3k$ or $3k+1$ for some $k\in\mathbb{Z}$. If a $\equiv$ 2 mod 3, you need something that isn't equivalent to 1 mod 3, and so must be of the form $3k$ or $3k+2$ for some $k\in\mathbb{Z}$
So, $6k$ always works if you want to ensure that adding it does not introduce any factors of 2 or 3.
If a $\equiv$ 1 mod 3, then $6k+4$ also works. If a $\equiv$ to 2 mod 3, then $6k+2$ also works
My mentor tommy1729 told me :
Let $b_1 = 1.$
Let $ b_2 = x.$
Also $ \frac{1}{2} < x < 2 $
Define for $ n>2 $:
$$ b_n = \frac{\exp(\ln(b_{n-1})^3)}{b_{n-2}} $$
Then
$$ \sup_{n>2} b_n = x , \inf_{n>2} b_n = \frac{1}{x} $$
Is this true ?
How to show that ?
We can rewrite the sequence $b_n$ ...
If i have some equation which equates to null and then another equation with different variables and different topic which also equates to null ( think of physics for example where you can use different subjects with different variables ) can then those two equations be equated to eachother_
A stupid example would be i dont know lets say that the velocity minus elephant equals zero and then say that the resistance plus voltage equals zero can then we say veloctiy minus elephant equals resistance plus voltage
in your example, g' is the tangent if what you are trying to do is a derivitave.
Or actually that is nevertheless a tangent. Derivitave or not, but as far as I know is that the definition of a tangent is defined newly in Analysis. Considering what you mean I guess you do not know that.
But I wouldn't belive what I say I am just a noob afterall :D
Let $f: X\rightarrow Y$ be a continuous open map. Show that if $X$ satisfies the second countability axiom, then so does $f(X)$.
My attempt:Let $B_1,B_2,B_3....$ be an enumeration of the basis $\mathbb{B}$ the topology on $X$ admits. Then clearly, $A=$ $\{$ $f(B_i)$ $:$ $B_i \in \mathbb{B}$ $\}$...
Hi, I have a question about the wave equation for pde. u_tt-4u_xx=0 t>0 u(x,0)=1-x^2 when |x|<=1 and u(x,0)=0 when |x|>1 u_t(x,0)=4 when 1<=x<=2 and u_t(x,0)=0 else. I'm looking for all points when u is not C^2 (twice differentiable)
Monoid problems seem harder than group problem from shear lack of textbooks about monoids. That is why if they were groups we'd already know the answer.
It's a trap. The question is really about twin primes, lol
If $f(x) = x^2 = 1 \pmod {pq}$ but no other primes (using CRT here) can only be done finitely often, then $\ker f \subset \bigcup_{r \neq p,q} \ker \pi_{r}(x)$ for any $p, q \gt N$ for some $N \in \Bbb{N}$.
Since for $p,q$ past all the twin primes, we have $x^2 = 1 \pmod {pq} \implies x^2 = 1 \pmod r$ for some $r \neq p,q$.
In mathematics, a hyperbolic angle is a geometric figure that defines a hyperbolic sector. The relationship of a hyperbolic angle to a hyperbola parallels the relationship of an "ordinary" angle to a circle.
The magnitude of the hyperbolic angle is the area of the corresponding sector of the hyperbola xy = 1. This hyperbola is rectangular with a semi-major axis of
2
{\displaystyle {\sqrt {2}}}
, analogous to the magnitude of a circular angle corresponding to the area of a circular sector in a circle with radius...
In relativity, rapidity is commonly used as a measure for relativistic velocity. Mathematically, rapidity can be defined as the hyperbolic angle that differentiates two frames of reference in relative motion, each frame being associated with distance and time coordinates.
For one-dimensional motion, rapidities are additive whereas velocities must be combined by Einstein's velocity-addition formula. For low speeds, rapidity and velocity are proportional, but for higher velocities, rapidity takes a larger value, the rapidity of light being infinite.
Using the inverse hyperbolic function artanh, the...
To show that it is a point in the graph, we need the left component $e^{e^s}$ plugged into $f(x) = e^{1/\ln x}$ as an argument and the result has to be the right component $e^{e^{-s}} e^{1/\ln x}$
LOL ... So let's take $E=TS^2$. Can you give me an argument that $\text{Hom}(E,E)$ is nontrivial? I don't think we can use characteristic classes. Doing $E$ the universal bundle on $G(2,4)$ (oriented) might give an easier example, but I can't do it either, yet.
We are OK because the base is a small-dimensional sphere. The small-dimensionality reduces the problem to stable bundles, and the sphere lets us classify bundles as homotopy classes in the understood space BSO