However, the integral that I'm trying to solve comes from this original one:
$$\int{\frac{x^5-3x^4+x^3-2x^2+x+1}{x^3+x}}\,dx = \int{x^2-3x}\,dx + \int{\frac{x^2+x+1}{x^3+x}}\,dx =$$
$$= \int{x^2}\,dx + \int{x}\,dx + \int{\frac{x^2+x+1}{x^3+x}}\,dx = \frac{x^3}{3}+\frac{3x^2}{2}+ \int{\frac{x^2+x+1}{x^3+x}}\,dx$$