Metropolis Algebra Complex: There exists an $M$ such that for all possible algebraic structures $A$, $A \subsetneq M$
The Metropolis unifies abstract algebra by collecting and linking them all into one single structure, such that different algebraic structures becomes portions of it
Hey guys, I'm studiyng functional analysis and want to ask if an element of linear span of some infinite set, is always a finite linear combination elements in the set.
Like @TobiasKildetoft said a while back, if not, perhaps you should take it to a private room where you can record your findings or thoughts. Right now, people's questions are getting crowded out.
Let $x=uv, u\in S$, $v\in \overline S$ and $y=wz, w\in S$, $z\in \overline S$. Removal of $x,y$ make the graph disconnected. Suppose there exists a cycle $\mathscr C$ consists of $x$ without $y$. So, there exists a $u-v$ path other than edge $x$. Let it be $u e'_1u_1 u_2e'_2 ...u_k e'_k v$. Ther...
I dislike the way Marystar asks her questions, everytime following a ping when it is obvious that Leaky is following her
She does that all the time, and it is remind of help vampire behaviour which is very annoying
Combined with weeks of frustration that the research is going nowhere because of stupid things like programming input wars, I cannot think of anything but drowning everything out of existence
> whenever a bunch of regular help vampires are on chat, drown them out so that nobody can see and feed them. The "ignore" button does absolutely nothing in helping to mitigate this regard
Let $L$ be the space of Lie formal series, i.e. $E\oplus [E,E] \oplus [E,[E,E]]\oplus ....$. Is this Lie algebra necessary finite dimensional, if $E$ is finite dimensional linear space?
@N.Maneesh I have not got that far into graph theory yet thus it will be best for me to not judge. Besides, this research frustration is occupying my brain right now that I cannot think other than want to drown everything out of existence
One can give the cross product as a Lie bracket on $\mathbb{R}^3$ and the matrix commutator to $\mathbb{R}^{n^2}$ ($n \ge 2$). They both give a perfect Lie algebra structure.
However, every Lie algebra of dimension $1$ is abelian, and for $2$-dim we can write any nontrivial Lie bracket as $[x, y...
Lie algebra $\mathfrak{g}$ is perfect if and only if $\mathfrak{g}=[\mathfrak{g},\mathfrak{g}]$.
And we know semisimple Lie algebra must satisfy the $\mathfrak{g}=[\mathfrak{g},\mathfrak{g}]$ then it's perfect.
What is the example of perfect Lie algebra but not semisimple? And what's the suffi...
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Why isn't reflexivity redundant in the definition of equivalence relation?
We had a heated discussion in class today and i still cant be sure if the professor was any good with the solution. The question is:
If a relation is symmetric and transitive, then it wil...
Before you pass $N'$, you have some terms $x_1 + \cdots + x_{N'}$. These might be big; who knows. So what if we take $N$ so big that $(x_1 + \cdots + x_{N'})/N$ is less than, let's say $\epsilon/2$?
We then have to account for the remaining terms, $(x_{N'+1} + \cdots + x_N)/N$.
Express $\Delta = $$\left|\begin{matrix}{2bc-a^2}&{c^2}&{b^2}\\c^2&{2ac-b^2}&{a^2}\\{b^2}&{a^2}&{2ab-c^2}\end{matrix}\right|$ as a square of two determinants.
@LeakyNun For above question I tried, using the property that determinant of cofactors is equal to actual determinant^2 but couldn't get the answer that way. :( .
If I have a p-torsion module M where p in A is irreducible then I can define a valuation on M sending x to the smallest natural number n such that p^n x = 0
this has many similarities with the p-adic valuation
If I have a p-torsion module M where p in A is irreducible then I can define a valuation on M sending x to the smallest natural number n such that p^n x = 0
the stuff with duals can be generalized at least to PIDs: Let $A$ be a PID and $p \in A$ be irreducible and $\widehat{A}$ be the completion of $A$ at $(p)$. Let $Q=\mathrm{Frac}(A)/A$. Then I think if $M$ is a $p^\infty$-torsion module (so every element is annihilated by some power of $p$), then $\mathrm{Hom}_A(M,Q)$ is a $\widehat{A}$-module
In two boxes we have similar balls numbered from 1 to 5. We pick two balls from the first box and two from the second one. Is the probability that all the 4 balls are different the following? $$\frac{5}{5}\cdot \frac{4}{4}\cdot \frac{4}{5}\cdot \frac{3}{4}=\frac{3}{5}$$ ?
In two boxes we have similar balls numbered from 1 to 5. We pick two balls from the first box and two from the second one. Is the probability that all the 4 balls are different the following? $$\frac{5}{5}\cdot \frac{4}{4}\cdot \frac{3}{5}\cdot \frac{2}{4}=\frac{3}{10}$$
I thought so because: At the beginning we can choose 5 from 5 balls at the first box Then we have 4 balls left in the first box and we can choose one of these 4 From the second box we can choose 3 of the 5 because we have already picked 2 numbers
And so this gives a linear map $(\oplus_i M_i) \otimes (\oplus_j N_j) \to \oplus_{i,j} M_i \otimes N_j$, which does the obvious thing. Surjectivity is clear because to map to any generator you just manufacture the element
Hello Everyone. I really need help from someone. I have been trying to properly answer the following question that I posted: https://math.stackexchange.com/questions/2902199/show-that-the-number-of-elements-of-a-finite-set-is-well-defined But even after the help I got, I still was unable to solve it. I am getting really depressed. Help would be very much appreciated.
could I get some help on some stats homework? I took a course before this one a few years ago and Im a bit rusty.
I dont mind doing the work, this book just isnt very clear on which thing to do where, or rather, its too clear, too succinct.
its very simple, it is a 'based on the mean and variance of a set of samples' and given a population std dev, is a stated mean for the population acceptable within a=0.05
so i did the first part and got the sample statistics, but I dont remember which formula to use to compare them. and I know they are giving me part of the variables and expecting me to do it backward a bit to find the missing part
so, I have x-bar = 18472.9, and an s^2 of 41.724 then I have, mu = 18470, and sigma^2 = 40. with an alpha of 0.05
Im not sure if this is a z-test or test one mean
also, I think the z-score formula looks a lot like the formula for a derivative in limit form with z being in respect to the derivative, and h = to the std dev
The random variables $X_1, X_2, \ldots , X_{10}$ are independent and have the same distribution function and each of them gets exactly the values $\pm 2$ and with equal probability. We define the random variable $S=X_1+X_2+\ldots +X_{10}$. How can we calculate $\mathbb{E}(S^2)$ ?
@MaryStar: You have S, the sum of 10 independently distributed random variables, uniform on {+2, -2}. In distribution, X_i = 4Y_i - 2 , where Y_i is uniform on {0, 1}, so in distribution S = 4 * T - 20, where T is Bin(10, 0.5). Thus E[S^2] = E[16T^2 - 80T + 400] = 400 - 80 E[T] + 16 E[T^2]. Note that E[T] = 5, and E[T^2] = 2.5. Plugging this in, we get E[S^2] = 40. (Here's another, easier way to do it: E[S^2] = 10 E[X^2] + 90 E[X_1X_2] = 40.)