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02:00 - 22:0022:00 - 00:00

02:46
0
Q: How do Tensors are the generalisation of ordinary vectors?

Failed to be a Mathematician Doubt:- What is the physical meaning of tensor? Tensors are $k-$ linear functions. Right?. I can see that $L_0(V)$ is a set of scalars. So I can understand tensors are the generalization of scalars. How do Tensors are the generalisation of ordinary vectors? Do tensors have direction? How do I...

@FailedtobeaMathematician Is there any particular reason you link that here?
@nitsua60 I didn't get the answer. If anyone in this group knows the answer. Please help me.
Okay. It's been 23 minutes. I suggest a little patience. Also, if you have a request for the people in the room go ahead and make it. Just dropping the link in here it's unclear if you want help answering it, you want help writing a coherent question, if you think someone in here you know might be interested in it, you think it should be closed....
@nitsua60 Can you help me to correct the errors in the question? Someone had downvoted my question :(
Probably not very much--I don't know if you've noticed my rep, but I've got virtually no experience around math.se. But I know chat, so felt free to chime in on a bald link dropped into an empty room.
 
2 hours later…
05:01
Hey there guys this might be off topic but I have question on how to manage and handle notes?
Context: I am preparing for indian civil services examination and for it i have to study maths as a subject. Now there are about 14 topics ranging from all areas of mathematics and I will have study mutiple books and keep in my head large numbers of concepts ranging from linear algebra to modern algebra, real analysis, odes etc.
I want to make notes, but usually what happens is that notes tend to get more and more unorganzied as I do make more of them. I wanted to know if there is some system of organization that you are familiar with that i can use to manage the content.
 
1 hour later…
06:27
For a topology with compact basis, an open set is compact iff it is a finite union of the basis.
07:12
What happens if the basis is noncompact?
i don't see how a finite union of them will fail to cause the resulting open set to be noncompact
just take the non-compact basis, and express it as the finite union of basis as such: it is the union of itself, and 1 is finite
$$I = 2 \int_0^1 e^{-x^4}(1-4x^4) dx$$
I have tried integration by parts but that doesn't help here.
what does wolfram alpha say
@LeakyNun integral calculator gives an answer: integral-calculator.com
"gives an answer" is not enough
it gives an answer in terms of gamma
07:21
@LeakyNun See the "manually computed antiderivative" part
I see
then it answers your question
just click "show steps"
@LeakyNun K
Hmm, so you mean for the noncompact open sets in the noncompact open basis, those will be the union of itself hence noncompact open with finite unions?
@Secret I mean if B is not compact then B is not compact
B is the union of {B}
the closure of S is:
1. the intersection of every closed set that contains S
2. points x such that every open set containing x intersects non-trivially with S
how on earth can it be described with closed sets and with open sets
@Secret exercise: prove that they are equivalent
 
1 hour later…
08:58
Consider a point x in an open set U such that $S \cap U$ is empty. Then by definition of closed set $U^{\complement}=X-U$ is closed and contains $S$. Repeat for all those disjoint $U$s and take their arbitrary intersection. Then you end up with the smallest closed set containing $S$ and this is $cl(S)$
Now as for those x whose $U$ such that $S\cap U$ is nonempty ... (processing)
09:13
Ok for 2, the points x are limit points of S by definition. A set is closed if it contains all its limit points. 2 ensures the resulting set K contains S and all its limit points hence it is a closed set containing S, in fact the smallest such thus K=cl(S)
So they are equivalent
...
hmm...
can we generalise this further...?
Consider some structure X that is more general than a topolpgy such that you have some set A and a collection in X such that for each point m in each member M in X, $M \cap A$ is nonempty but there exists some points a in U in A such that $U \cap M$ is empty
Intuitively, this capture some asymmetric notion of closeness such that there are two points a and m such that a is in all neighbourhoods of m (hence m is a limit point of a), but m is not in all neighbourhoods of a (thus a is not a limit point of m)?
Will figure this out later. I need a lot of pen and paper
(the aforementioned asymmetric closeness is very commonly encountered in Escher-esq themed games, where walking pass some one way doorway and you will be sent far away from the starting point)
Hmmm... maybe a quasiuniform space can model that
60
Q: What concept does an open set axiomatise?

Zhen LinIn the context of metric (and in general first-countable) topologies, it's reasonably clear what a closed set is: a set $F$ is closed if and only if every convergent sequence of points in $F$ converges to a point also in $F$. This naturally generalises to the definition of a closed set in an arbi...

A computational perspective of topology
0
Q: Is the intersection of two non-open/non-measurable sets non-open/non-measurable?

PaulVery simple question. If I have two sets A and B that are both non-open in some topological space, is their intersection necessarily non-open? And similarly, is the intersection of two non-measurable sets non-measurable? I think the answer is that it could go either way. But I can't find any go...

More exotic topologies
10:33
2
Q: Need help with this question.

Jasmine I was trying to solve this question but got stuck. If we further solve it we get $I'(e)=0 $ which does no help to find the value of the integral. I know an alternate way to take $7$ as variable but I want to know if the process I used can help in anyway to evaluate this integral. How will we fin...

I need help with this.
11:24
0
Q: How to solve $ f(\sqrt[3](1 - z^3))^2 = 1 - f(z)^2 $?

mickHow to Find analytic $f(z)$ such that $$ f(\sqrt[3](1 - z^3))^2 = 1 - f(z)^2 $$ Koenigs function can not be used here So I am stuck. How does the riemann surface look like ?

 
3 hours later…
14:04
***Question:-*** Let $V$ denotes the vector space of all sequences $ \boldsymbol{a}=(a_{1},a_{2},...)$ of real numbers such that $\sum{2^{n}\left|{a_{n}}\right|}$ converges.

Define $\|.\| : V \rightarrow \mathbb{R}$ by $\|\boldsymbol{a}\|=\sum{2^{n}\left|{a_{n}}\right|}$. Which of the following ***are*** true?

1. $V$ contains only the sequence $(0,0,...)$.
2. $V$ is finite dimensional.
3. $V$ has a countable linear basis.
4. $V$ is a complete normed space.

***My attempt:-*** As we know $$\|\boldsymbol{a}\|=0 \Leftrightarrow \boldsymbol{a} = 0$$
@LeakyNun, here, do we measure angle t from TC to CP or from CP to TC? In particular, I am finding very hard to digest that coordinates of vector CP are (-a sin t,-acos t), which is iscussed a couple minutes later
14:25
in CSIR-TIFR-ISI-NBHM, 5 mins ago, by Failed to be a Mathematician
for a cauchy sequence in the space $a_n$, for $\epsilon>0$,$\exists N;n,m \ge N||a_m-a_n||<\epsilon$
$a_{n}=(a_{n1},a_{n2},...,)$
$a_{m}=(a_{m1},a_{m2},...,)$
$||a_n-a_m||=\sum 2^k|a_{nk}-a_{mk}|$
$\implies$ $\{a_{nk}\}$ is cauchy sequence of real numbers. Hence, convergent.
$|a_{nk}-a_{mk}|\leq 2^k|a_{nk}-a_{mk}|\leq ||a_m-a_n||<\epsilon$
let it converges to $a_{0k}$.
$a_{n1}\to a_{01}$
$a_{n2}\to a_{02}$
...
Let $a_0=(a_{01},a_{02},...)$
Now we need to prove $a_0 \in V$
We need $\sum 2^k |a_{0k}|$ convergent.
I hope this solution is correct.
Yes. It is right. Thanks @FailedtobeaMathematician
 
1 hour later…
15:48
How does (3.7) coming?
How $\sigma (\sum_{\tau \in S_k} (sgn \tau)(\tau f) \tens g)$ transformed?
How $\sigma (\sum_{\tau \in S_k} (sgn \tau)(\tau f) \otimes g)$ transformed?
@Secret
$\sigma (\sum_{\tau \in S_k} (sgn \tau)(\tau f) \otimes g)=\sigma (\sum_{\tau \in S_k} (sgn \tau)\tau (f \otimes g)$
Is $\sigma$ linear?
16:46
Hello! For a,b be real positive numbers what is wrong with $a^2+b^2>or=0$ then a+b is > or = (2ab)^(1/2)(why isnt it in accordance with Am Gm inequality i know that minimum value of a+b is (4ab)^(1/2)
@Jasmine $\ge$ (\ge)
@Jasmine a can be negative, same for b. AM-GM is for positive numbers.
@Jasmine Sum of squares is always positive.
@Jasmine There's nothing to laugh about it.
How to calculate the probability of getting each outcome at least once from n attempts? Like if I have coins it’s just 1 − 2/2ⁿ
@Abcd yes actually that wasn't my question it's little different I interpreted it differently
17:11
nevermind, I got it
hi friends
math.nyu.edu/student_resources/wwiki/index.php/… in the first solution, how do we know that the lower limit of integration should be $0$?
17:30
nm I see it
17:43
I get to know from here that angle $\theta$ here is measured clockwise. Then why is $\theta$ positive?
(The picture gives derivation of parametric equations)
@GFauxPas, do you have any idea?
because as the circle moves to the right, it'll rotate clockwise as well
@Semiclassical I can see why angle is measured is clockwise. But I was taught that if you measure angles counter-clockwise, then they are positive but if you measure them clockwise, they are considered negative. But here , even though clockwise, $\theta$ is cosidered positive.
positive angles being CCW is a convention, not a necessity
So, we can violate that as and when we want?
if you're clear about it, sure. same as any coordinate system
17:54
So, if i stick to that convention, will i get same result?
you should, yes. in fact, i'd say it's easier to do it this way than the other
ok, thank you
if you do it the other way, you'll need to $s=-a\theta$. that still works, but it's a good deal more tedious
alternatively, you could have the disk roll to the left and get a CCW rotation
then it'd match the convention
math.nyu.edu/student_resources/wwiki/index.php/… now I dont understand the very last line. How can we throw away $\delta$ like that?
Semi, that would depend if there's any room behind the circle for you and your phone camera
:P
17:59
if it's rotating clockwise, to get it to rotate ccw you have to step behind it
maybe there's no room
wuz joke
lol
or, y'know, you could just stop it and push it the other direction :P
can you take a look at the last line of the solution I linked to Semi, please
the question's phrased very sloppily
"find an equivalent"
but the question is, how to absorb $\delta$ into a constant multiple
@FailedtobeaMathematician I am too sleepy and afking to look at the question (as well I am not that familar with k vectors). you might need to ask someone else
I probably can't say anything. My recollection of real analysis is very old, and I"m not sure I remember dominated convergence
no not that part
just the very last line, it's one of those "after some algebra" cheats
18:02
ah
which I dislike
glancing it at it quickly, I imagine it's something like: In this manipulated form, we see that it'd have been more convenient had we defined $a=b+1$ not $a=b$. So we'll redefine it like that
the mathjax isn't loading correctly for me tho
try in firefox
or maybe it's just loading v e r y s l o w l y
it doesnt work in Chrome well for me for osme reason
18:05
that'd do it
Let $F_n$ denote the free group on $n$ generators, and let $g_1,...,g_\ell \in F_n$ be distinct elements. Then $\langle g_1,...,g_\ell \rangle$ is a free subgroup of $F_n$. Suppose that $\pi : \langle g_1,...,g_\ell \rangle \to \mathcal{U}(M_k(\Bbb{C}))$ be some unitary representation. Is it possible to extend $\pi$ to all of $F_n$?
well here we're making $x < \delta$ so that the error of a limit term is less than epsilon
so we can always make $\delta$ smaller
still dont see how that helps
it does seem a bit handwavey
indeed it does, and now I have to unwave the hand
good luck with that :P
18:08
ugh
One thing I do find weird about that description of it: As $\epsilon\to 0$, one has $\log(1+\delta^2/\epsilon^2)\approx \log(\delta^2/\epsilon^2)=2\log (1/\epsilon)+2\log \delta$
which means that the $2\log \delta$ term is not going to be part of the $C$ term in front
it'll be an additive constant, not a multiplicative one.
that's exactly my problem
not to mention I don't get the squiggly equality either
well, if $\epsilon$ is small (compared with $\delta)$, then $\delta^2/\epsilon\gg 1$
sure
ah, I see
$\delta \in (0..1)$ so we can't just set it to $1$
in this case
$\epsilon$ is arbitarily small and $\delta$ is strictly between 0 and `1
I think the thing to bear in mind is what 'arbitrarily small' actually means
18:14
maybe it's a mistake
hm?
0.01 is small compared to 1, but not compared to 0.001
right
@Semiclassical Thank you so much for this. So, if $\theta$ negative, $x$ co-ordinate will be $-a\theta+\sin\theta$, right?
just flip the horizontal axis
18:16
positive on the left and negative on the right
you may need to have it be $\sin(-\theta)=-\sin \theta$ as well
but I think it's less confusing to just have the wheel roll the other way
to the left
yeah
I always get a bit mixed up geometrically with this business if I'm honest
there's a reason I stick with stuff like "better make sure s and \theta have the same sign"
so Semi do you think it's a mistake or is the answer salvagable and I just have to unwave the hand
i think it's just a matter of being clear
18:19
but I think it should be $+2 \log \delta$, where $\delta \in (0..1)$
sure, which (following their tack) you could equally well write as $-2\log(1/\delta)$
with the advantage that the log is then positive
good point
I'd also point out that $\delta$ doesn't actually appear in the problem statement
so its definition is inherently arbitrary
well, it is between zero and one
so it's an error term
as such, you could redefine $\delta \to \delta \epsilon$
18:23
because $\delta \epsilon < \delta$ and $\delta$ was arbitrary
okay, then what
then $\delta/\epsilon\to 1/\epsilon$
more formally, I'm doing $\delta'=\delta/\epsilon$
oooh
last question posted 10 hours before :(
that goes back to your first guess
18:24
ya
though, actually, something's off
yeah, that doesn't make sense. $\delta/\epsilon \to (\delta \epsilon)/\epsilon = \delta$ under that prescription
i dunno
well $\epsilon < \delta \epsilon$ as well
err other way
$\delta \epsilon < \epsilon$
i'm not convinced that helps
if one wanted $\delta/\epsilon\to 1/\epsilon$, one would do $\epsilon\to \delta \epsilon$
i.e. redefine $\epsilon$
this feels goofy
the whole question is silly
"find an equivalent"
it reminds me of physics tbh---figure out the asymptotic behavior of a given integral
well the first part does that
first half of the question
actually that's not helpful
18:30
I think it might be possible using the universal property of a free group, though I am not certain.
that would tell you $h(\epsilon) \sim 0$ for $\epsilon$ small
not helpful when integrating over a shrinking interval
Well, let's be specific for a moment and take $f(x)=x$
as the simplest example
sure
then $\displaystyle \int_0^1 \frac{x}{x^2+\epsilon^2}\,dx = \frac12 \log(1+1/\epsilon^2)$
right
18:32
I think I know why this question is bothering me. In the physics context, this integral doesn't make sense unless $x,\epsilon$ are already pure numbers
since the range is $x=0$ to $1$
pure? meaning, constants?
right. i.e. dimensionless
in physics, you'd instead have something like $\displaystyle \int_0^\Lambda \frac{x}{x^2+\epsilon^2}\,dx$
$\Lambda$ is?
and $\epsilon$ being small/large would be $\epsilon\ll \Lambda$ and $\epsilon\gg \Lambda$ respectively
some quantity with the same dimensions as $x$ and $\epsilon$
You'd need that for the dimensions to work out
oh, okay
well let's not worry about that
18:35
I'm not sure that's a crucial difference tho.
Agreed.
so here instead of $x$ we have $f(x)$ where $f(0) = 0$, $f'(0) \ne 0$, and $f$ is continuous on a compact set
Right
I dunno. That last line does just feel sloppy
I don't even know if it's correct
"absorb it into the constant"
which constant?
this isn't an official page, it's a wiki made by students
18:38
yeah
so it might be wrong
I don't think it's 'wrong,' just not well stated
I mean, the $-2\log(1/\delta)$ is an additive constant after all
it won't be relevant as $\epsilon\to 0$
yeah
okay better
18:40
though it seems like the key point there is that $\delta$ is independent of $\epsilon$
right, all we assumed about it was that $0 < \delta < 1$
we didn't assume anything else
Right. and the quantity being bounded doesn't depend on $\epsilon$
so the required value of $\delta$ is also not $\epsilon$-dependent
so it will be negligible compared to the $\epsilon$ term, as the $\epsilon$ terms grow without bound. slowly, but they do
I guess the reason they want that factor of 1/2 in said bound is to have $\frac12 \log(1/\epsilon^2)=\log(1/\epsilon)$
eh, just do $\epsilon$ in reciprocal powers of 10 :P
the 1/2 factor was convenient earlier
18:43
in physics, btw, the terminology is that the integral has a 'logarithmic divergence'
I like that
so yeah, the 1/2 was from earlier, it was $1/c$ where $c >1$
more precisely, you'll have integrals of the form $\int_0^1 \frac{f(x)}{x^2}\,dx$
and you argue that this shows up because the setup of the calculation wasn't sufficiently careful
I didnt understand that last line
yeah, I'm handwaving a bit
it's more or less a point about how you have to regularize certain badly-defined integrals in QFT
ah, the discussion here is pretty much identical to the $f(x)=x$ case given earlier: hitoshi.berkeley.edu/230A/regularization.pdf
(with $d^2 p = 2\pi p \,dp$ upon going to polar coordinates with radial coordinate $p$ and integrating over angle)
(also, $dp^2=d(p^2)=2p\,dp$ on the second page. i have no idea why they did that)
thanks for your help Semi
19:09
np
19:21
What is the maximum value of:
$$f(x)= \int_0^1 t\sin(x+\pi t)dt$$
I don't understand why Leibniz Rule isn't helping in this problem .
I differentiated and set the resultant integral to zero which is when $x= \dfrac{\pi}{2}- \pi t$
So we get maximum value $= \dfrac{1}{2}$
Which is not even remotely close to the right answer.
Is anyone going to reply?
nevermind, Ill ask on main then
19:40
@Abcd What integral did you get upon differentiation? The $t$ in front doesn't go away, so I don't think it's any easier than the integral you started with
more to the point, one simple approach is by doing f(x) by parts and only then differentiate
Is there a definition for continuous functions between a set and a topology? Usually I see continuity only defined between two topological spaces.
no, there isn't.
@Semiclassical Wont we partial differentiate wrt x?
$f'(x)= \displaystyle\int _0^1 t\cos (x+\pi t) dt$.
Sure, but how do you do the resulting integral?
All you've done so far is trade sin for cos
@Semiclassical For maxima f'(x)=0
so x= $\pi/2 - \pi t $
19:47
...yes, and? You need $\int_0^1 t\cos(x+\pi t)\,dt=0$
Why, exactly?
@Semiclassical cos pi/2 is zero
Thats why x = pi/2 - pi*t
So? You've got $t$ ranging from 0 to 1
and you need to pick one value of x
at most, you can make the integrand vanish at one point
but vanishing at one point doesn't mean it vanishes everywhere
oh
so what do I do?
I think I already said what one could do.
20:49
Hey, I'm not officially introduced to matrices but I've got a rough understanding for it. mathworld.wolfram.com/RotationMatrix.html Here there is the line $v' = \mathbb{R}_\theta\,v_0$. Is it the "matrix multiplication" going on that line or I'm wrong?
My concern is that $v_0$ is not a matrix but a vector.
What;s the simplest way to say (prove/ciaim ) this^ ?
@AbdullahUYU if you have matrices A,B which are j-by-k and k-by-l respectively, then the matrix multiplication AB is well-formed and gives a j-by-l matrix
Do you have any idea about my question?
In particular, if l = 1, then B is k-by-1 ie a column vector
So multiplying a column vector on the left by a matrix of appropriate size gives another column vector
In particular, one has v’=Av with matrix sizes n-by-1, n-by-n, and n-by-1 respectively
Hmm, so a vector is not really much different from a matrix other than the dimension it has.
Considering them solely as data types.
21:07
Yep
well, yes, but it's often helpful to view rhem
view them as objects matrices act upon
It should be noted that, in most linear algebra contexts, that ‘vectors’ are taken to be column vectors
I don't have a motivation yet but yes, intuitively, the matrices are inclusive.
though it's trivial to show that a space of row vectors is isomorphic to a space of column vectors of the same length
Huzzah for the transpose
21:10
trivial, but you should prove it to yourself for practice
we generally think of (rectangular) matrices as maps that act on objects called vectors
rather than thinking of column vectors as matrices in their own right. depends on context
but (column) vectors are nx1 matrices
alright, thanks all
@AbdullahUYU , are you comfortable with proofs by induction?
Yes, i think so.
alright then
@Abcd: That's immediate if you use the addition formula for $\tan(\alpha-x)$ and do the little bit of algebra.
21:23
@TedShifrin Not really.
I just did it.
Is an integral with variable limits always differentiable?
That's a vague question. What do you mean?
@TedShifrin let me show the question
The answer is no.
Do you know a statement of the fundamental theorem of calculus (there are two parts)?
21:25
@TedShifrin cant recall. But I know them
if you can't recall them, review them
it's pretty ... fundamental
@GFauxPas Both those theorems were quite obvious I felt.
so obvious you don't remember them
?
@Abcd, "quite obvious" — again, do you understand what's going on? Is there a hypothesis in there you're forgetting that you need to answer your question?
21:31
@TedShifrin hi
I wish
@TedShifrin you've been gone quite a while; I wanted to ask you a question
I assumed that the integral is differentiable so applied L Hospital and got the right answer
@TedShifrin What exactly did you convert it to?
21:33
so, is it differentiable?
@Abcd it's intuitive maybe (that's controversial), but it's anything but obvious
Notice that the theorem assumes continuity of $f$ to get differentiability of $F$.
@Ted my question is, what is your opinion on this paper? (The Non-Existent Complex 6-Sphere, Michael Atiyah, Differential Geometry)
And your question has continuity as a hypothesis. But if $f$ fails to be continuous, $F$ may fail to be differentiable.
@Leaky: I have consulted with experts on this and it's not believed to have any validity.
I myself am not qualified to judge it
isn't you yourself an expert
21:35
Not on the stuff he's using, no, and it's totally vague and inexplicit.
isn't -> aren't
@GFauxPas yes because $\sin (t^2)$ is differentiable
@Abcd: There's nothing tricky going on. The denominator in $\tan(\alpha-x)$ cancels out and you're left with 4 terms to add up, 2 of which cancel. And then you use $1+\tan^2\alpha = \sec^2\alpha$.
lol at the references, everything is citing himself
Who's been watching the world cup?
21:37
@LeakyNun I think I saw on English.SE that "how is you" is also acceptable in place of "how are you"...just telling
@Ted what is Spec(2^N) where 2 is the field of two elements? According to theorems, it should be in bijection to N, compact, hausdorff, but I have no idea what it is
I don't know, @Leaky. I have a question on main I have to write up.
@TedShifrin I want to die now. I was using hellish things and it wassss so simple!
don't die
21:40
I told you how to do it directly and, of course, you contradicted me without trying it. You get annoying!
I'm going to try to write up a multivariable calculus answer now.
@TedShifrin Oh sorry about that.
Hey guys
Can someone tell me what type of graph this is? I posted a question about it but didn't get an answer
$$\int_0^{\pi/2}\cos^{10}x (\sin 12x )dx$$
Hi @TedShifrin @LeakyNun
21:48
Does anyone know by what theorem or property I can estimate an upper bound for a sum with its integral? i.e. I want to claim $\sum_{x=0}^\infty e^{-\frac{1}{2} \pi x^2/r^2} \le \int_{-\infty}^{+\infty}e^{-\frac{1}{2} \pi x^2/r^2}dx$
the summation is only summing for positive values of x and the integral is summing over negative values and positive values of x
I mean bounding a summation by its integral. I remember there were some small details such as monotonicity from what I recall
I don't know, @LeakyNun @Rudi_Birnbaum do you guys know the answer to Maximus's question?
Hi guys!
Hi :)
21:56
7
Q: When is infinite sum bounded by an integral?

user59560What conditions does $f(i)$ have to have for the inequality $\sum_{i=1}^{\infty} f(i) \leq \int_{i=0}^{\infty} f(i)$ to hold? My guess is that $f(i)$ has to be monotone and that the sum and integral should both exist. Is it right that you don't need to worry about whether $f$ is increasing or ...

@LeakyNun Thank you so much
by the integral bound theorem?
@LeakyNun Are you interested in that integral?
I mean some integrals really are upper bounds to series
@Abcd not really
21:58
I see.
Integration is just tricks, tricks and tricks. Lot many tricks!
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