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00:00
Let me read it
lol
i was snarking at you because you said an impossible number
still Faust you were rude af
the number is at most 10
ic
unless the question means that 10 have those 2 and not the third, specifically
@GFauxPas maa.org/sites/default/files/pdf/upload_library/22/Ford/… he's doing what they're doing in 2.
00:01
i am sorry @KasmirKhaan i didnt mean to be rude the question was just pissing me off
But that notation is too weird I wouldn't learn it from that page.
@Faust no problem, and i think you are right, question should not be stated thay way ><
I just dont see where the numbers are coming from
the number 17 must be at least 19 for the question to make sense
i think
it's true for 17 sufficiently large then
00:04
lmao @ "thus, inspired..."
it works for 17 goes to 19
Group theory is the mathematical language of symmetry. For discrete symmetries we use Galois representations and for continuous symmetries we use lie group representations
00:28
@Symposium I know the guy who put up the proof, he's a character, let me show you a bit more of his personality
I wrote the differentials part
but its lul
> Is there an Emma Lehmer Lemma?
yeah that's his too
Emma Markovna Lehmer (née Trotskaia) (November 6, 1906 – May 7, 2007) was a mathematician known for her work on reciprocity laws in algebraic number theory. She preferred to deal with complex number fields and integers, rather than the more abstract aspects of the theory. == Biography == She was born in Samara, Russian Empire, but her father's job as a representative with a Russian sugar company moved the family to Harbin, China in 1910. Emma was tutored at home until the age of 14, when a school was opened locally. She managed to make her way to the USA for her higher education. At UC Berkeley...
Consider $R = k[X]$.
$m : R \to R \otimes_k R : X \mapsto X \otimes 1 + 1 \otimes X$
$i : R \to R : X \mapsto -X$
$e : R \to k : X \mapsto 1$
@loch is back!
$m(X) = X \otimes 1 + 1 \otimes X$
what is associativity supposed to look like
4 hours ago, by Leaky Nun
Now $L := \operatorname{Hom}(T_K, \operatorname{Spec}(K[X,X^{-1}]))$
$\begin{array}{rcl} \operatorname{Hom}_{K-GS}(T_K, \operatorname{Spec}(K[X,X^{-1}])) &\subseteq& \operatorname{Hom}_{K-S}(T_K, \operatorname{Spec}(K[X,X^{-1}])) \\ &=& \operatorname{Hom}_{K-A}(K[X,X^{-1}], \mathcal O(T_K)) \\ &=& \mathcal O(T_K)^\times \end{array}$
I suppose some of my words mean something
what the actual
$k \setminus \{0\}$ embeds into $\Bbb A^2$ by the rule $x \mapsto (x,x^{-1})$
the image is closed as it is the zero locus of $xy-1$
but in the same time, $k \setminus \{0\}$ is an open subset of $\Bbb A^1$
the complement of the zero locus of $x$
@EricSilva ola
01:14
@GFauxPas Haha. What the hell @ his reply in the discussion section!
which discussion section
he is grumpy in general I try not to take it personally
he's the biggest contributor to the wiki by far, he's very talented
Click discussion on that page on the abuse of notation.
I don't think it's bad, it's just funny!
Very pompous!
Can somebody help explain to me quotienting on the unit square?
01:19
context?
what's the quotient? moebius strip etc
did you want an example?
@GFauxPas what is your background?
Ashkenaz
I mean mathematical background
I know i was joking
grad student at NYU
second year
I thought for a minute I always wrongly assumed Lehmer (Lehmer's theorem of the degree of cosine or converse of FLT or primality test etc) was male, but it turns out there are multiples of them!
01:21
@GFauxPas specialization?
Are locally Lipschitz continuous functions dense in C(R) with respect to $L^\infty$ norm?
my major is just "mathematics" at the moment
but you can't learn everything
there are subjects that I like more than others
like?
01:23
functional analysis, analysis, calculus
are my favorite subjects
oh we belong to different fields :c
what's yours?
geocalc what's your question, why it's a tube like that?
algebra
01:24
ah
well let's start without the hole geocalc
Didn't like functional analysis. I tried to learn it from Bollobas a while ago, but just got bored.
we glue the left side and the right side of the square to each other, what do you get
to each their own
I personally have cut out paper squares and played with them in situations like this, you can do the same
if you think it will help
we get a cylinder
01:25
no
@LeakyNun What type of algebra?
not without the hole
@Symposium abstract algebra
we get a tube
we get a cylinder with the caps not there
I'm thinking of it like an ice cream cone
im not considering the hole
01:26
okay
do you see why it's an ice cream cone?
go ahead and actually play with a paper square if you need to
so basically you can equate the top bar of the square
so taht shrinks to one point
when you equate two sides theyre glued together
topologists literally call it gluing
so if you glue two adjacent sides of a square together, do you see why we get an ice cream cone?
01:29
@LeakyNun Who teaches the ANT course in third/fourth year at Imperial now?
@Symposium Ambrus Pal
like that??
oh I was assuming they were gluing the sides together with the dashes
I wasnt reading the heading I was looking at the picture sorry
then its wrong, it's not a cylinder if it has a hole in it...
so by equating certain points to eachother you can make some pretty cool shapes
torus, mobius strip, klein bottle, etc.
01:36
its how you define things like the torus
it has geometric intuition but you can express it purely algebraically
resists urge to talk about torus in algebraic geometry
So what if i had that thing
and it's in the unit square
are the only things you could equate
the corners?
lol leaky
well its one way to define them, im sure there are many
you mean, what happens if you draw that on a square and pinch all the corners together?
I'm just trying to play around with different curves in the unit square and equate them in different ways to see what shape i get
01:40
is that what you're asking?
It seems like you can only equate points on the outer edges
why do you say that?
surely you can equate more than that
let's say you equate every single point on the border. what do you get?
they're all the same now
Let $S \subseteq k[X_1,\cdots,X_n] = A$. Then, for $R$ a $k$-algebra: $$S(R) := \{ v \in R^n \mid \forall f \in S : f(v) = 0 \} = \operatorname{Hom}_{k-Alg}(A/S, R) = \operatorname{Hom}_{k-Sch}(\operatorname{Spec}(R), \operatorname{Spec}(A/S))$$
01:46
a point?
what happened to the middle part
Assuming that $S$ is an ideal, we have the exact sequence $0 \to S \to A \to A/S \to 0$, which gives rise to an exact sequence $0 \to \operatorname{Spec}(A/S) \to \operatorname{Spec}(A) \to \operatorname{Spec}(S) \to 0$
I'm not sure im trying visualise this
so $\operatorname{Spec}(A/S)$ is a subset of $\operatorname{Spec}(A) =: \Bbb A^n$
think of glue
01:48
but anyway, $S$ is now a functor from k-Alg to Set
@GFauxPas do you learn algebra?
a sphere?
yup, very good
you ever make a mobius strip out of paper?
try to describe how you did it in words to me, and we'll try to translate that into algebra
if you want
we take the unit square, and fold it along the diagonal crease of y=x. Then cut it straight across to the bottom right corner. then glue the pieces together but we have to twist it
something like that
02:00
you're thinking too hard lol
let me try
you twist opposite sides and glue them together
sound about right? ;)
yeah :)
okay
so we have to think about what it means to twist one side and not the other
have any ideas?
think linear algebra
how do we flip the orientation of a line segment
we have a matrix that performs a rotation
you dont need it if you're just flipping the orientation, it's overkill
we want to flip which way an arrow goes
I mean, you can
will give you the right answer
a negative sign
02:04
right
so
a mobius strip is described by
$I \times I / x \sim -x$
actually thats not a good way to write it
$I^2 / (x,0) \sim (-x,1)$
that's better
on the "zero" side, we're the same as the negative of the "one" side
$I^2 = [0..1]^2$
make sense?
okay
now lets do one that's common in topology but you can't actually create in the 3rd dimension
it's a 3d object but you have to make it in 4d
first let's make a torus, which we can do without complication
any ideas of how to make a torus? It's harder than the examples we've done so far
yeah glue the left side and right side and then stretch the cylinder thing so that the circles are glued together
nice!
though I personally glue the top and bottom one and do it the other way, but that doesn't matter
okay so opposite sides are glued together
and you want to glue the two circles at the end together
but instead of gluing them together in a straightforward way
we'll negate it the same way we did for a mobius strip
so one circle will be oriented clockwise and the other will be oriented counterclockwise
and then we glue them together
this twist-and-glue needs 4 dimensions to work
02:13
this is called the Klein bottle
like a mobius strip, it has the property that if you walk all the way around, you'll come back to the original position upside-down
:)
that's what "non-orientable" means in this comic
so how would you quotient this shape? like what would you equate to what?
posting image momentarily
pretend it's rotated so that it's like a square
idk what that is
it's some lines on a square
I dunno what you can do with it
just like equating successive diagonal lines going up the square yields a helical curve that winds around the cylinder thing
I'm wondering what sets of points to equate for this shape
02:25
I mean in topology you generally are interested in loops and the question to ask is "I did this, is the loop still a loop"
I guess you could do lots of things like make it into a torus
and see how the curves are stretched around the torus
just keep in mind that anything you're analyzing is going to be "up to stretching without tearing" so don't get hung up on angles or lengths
yeah :)
so what could you analyze after stretching the curves onto the torus
02:42
I'm not good at topology i just happen to be here :P
i can talk about loops, but not sure how to deal with lattices like the thing you posted
loops are very important because you can give them a group structure
like a loop meaning the initial point is glued to the final point?
ya
given a parameterization $T$ on unit time, it means $T(0) = T(1)$
I remember hearing that closed curves were more interesting than open ones from a prof
well as I said, you can give loops a group structure
Hello, Could someone tell me why the terms $c_1c_2 \Delta w_1 \cdot \Delta w_2 + c_2 c_1 \Delta w_2 \cdot \Delta w_1 + ... $ were added here
$(\sum c_k \Delta w_k, \sum c_j \Delta w_j) = (c_1 \Delta w_1 + ...+ c_n \Delta w_n, c_1 \Delta w_1 + ...+ c_n \Delta w_n) \\ = \iiint c_1^2 \Delta w_1 \cdot \Delta w_1 + ... + c_n^2 \Delta w_n \cdot \Delta w_n + c_1c_2 \Delta w_1 \cdot \Delta w_2 + c_2 c_1 \Delta w_2 \cdot \Delta w_1 + ... d \mathbf{x} = \\ \sum (\Delta w_j, \Delta w_j) c_j^2 + 2 \sum \sum_{j\neq k} (\Delta w_k, \Delta w_j) c_kc_j$?
Isn't just a dot product?
02:48
And you can't give non-loops a group structure?
well I've never tried, let's google
no you cant
you need to fix a point and parameterize the loops to end and start at the point, then you can multiply them
but otherwise they wont obey group laws
how would you multiply them if they werent loops, theyd have to start where the other ended and that's very restrictive
the requirement that you fix a point for the loops to have in common isnt that big a deal because in general the choice of the point doesn't affect anything
you could glue the square with the lattice onto a torus and then all four points would be at the same spot on the torus and then you could assign a group structure
I don't understand the lattice so no comment
i mean like the four corner points would end up all in the same spot
four corner points of the square
I dunno, I guess check the group axioms on what you're trying to do
 
1 hour later…
04:05
Assuming obvious compatibility relations, here you have a morphism of functors $Hom(-,G) \rightarrow Hom(-,\mathbb{G}_m)$ (on the category of affine schemes over $k$). Now let $R = G$, and consider the image of the identity. This recovers your map $G\rightarrow \mathbb{G}_m$.

(This is basically Yoneda)
@LeakyNun This is how you show how given an affine variety, the locus $\{f\ne 0\}$ is also an affine variety (These opens are sometimes called principal opens/distinguished opens and they are a basis for your Zariski top - they are important!)
@LeakyNun you have to careful by what you mean by exact. Your first exact sequence is exact as a sequence of $A$-modules. I don't think your second exact sequence makes sense (even if, say, you identify this with the opposite category of fin gen. $k-$algebras - this is not an abelian category!)
04:24
@BalarkaSen sup
Hey there nerds
yo wazzup?
04:41
Not much, how about you?
Hey
did anyone listen to any cool albums this week?
link
Here's a link
04:59
@Daminark think*
@Daminark What number theory are you learning atm?
And from where?
we apparently have a mod from Warwick now...
perhaps, that's what keeping Alec away
};-)
Zee
Zee
Yo skull
Sup my man
yo
Zee
Zee
How are you ?
05:09
isn't skull a girl?
Zee
Zee
Raiders fans are all guys
(assuming that statement is correct) I was lied to then. (but it's not apparently) so nvm.
unsure how true that is^
Zee
Zee
Lol it’s not
reverse the order of those messages btw.
lol
actually
raiderettes exist
05:11
@Alex I'm working with a prof of mine at the moment, he wants me to learn p-adics next since he wants to prove Kronecker-Weber locally
Zee
Zee
Are you one ? :):):):)
fixed
Zee
Zee
I just kicked out of school :)
Though I feel I should review some things from last session a bit better, in particular one of his proofs of quadratic reciprocity didn't quite stick. I think it'll help also if I go over the proof that cyclotomic polynomials are irreducible, since the two were similar in spirit
for what?
Zee
Zee
05:13
Bad grades
@anon, is it true: Let $\{a_n\}$ be real sequence. If $|a_{n+1}-a_n|<\frac1{3^n}$ for all $n$, then $a_n$ convergent.
@Daminark Reading Neukirch then?
Zee
Zee
It’s a bit freeing , now I could do research
wait what
Zee
Zee
^
05:16
grad school?
I'm looking through Neukirch to supplement our sessions, along with the book my prof recommended, Ireland & Rosen
you can't get kicked from undergrad because you're just a number to them that supplies monet$$$.
Zee
Zee
Ya grad
But am not even a PhD student
what are you
Zee
Zee
It don’t really bother me , I never was a good student , I’ll show these bastards that I don’t need them to do research
05:18
that's an unhealthy state of mind.
Zee
Zee
Why ?
because it's right at the edge of a downward spiral for your academic career.
if you don't like courses and feel you're misrepresented you can ask to be accommodated.
Zee
Zee
That career is over , I never cared for it much anyway , I just wanna Get some theorems
that's not how it works.
@Daminark Are local fields even defined in that text?
Zee
Zee
05:21
Why not ?
how will you sustain yourself financially if you're not paid to do mathematics?
Zee
Zee
That the issue , but I’ll find the time , I’ll kill my social life
can't you appeal their decision?
Looking through contents, yeah it's in chapter 2
Zee
Zee
Maybe sell drugs make money or foot prison in which case I can still do math !
05:22
@Zee where's the $$$$$ coming from, my dude?
yeah you're already spiralling.
good luck.
@Daminark I mean Ireland
@everyone someone talk some sense into this guy
Zee
Zee
I can appeal, I might but am sick of them
you're either being super edgy or have fully lost it.
Zee
Zee
Come on now , I don’t think what am saying is irrational
05:24
@Eulb Zee is a known troll
let your wounds heal, my brother
Zee
Zee
It may be weird but it makes sense
@Alex oh
Zee
Zee
@Alex now am sick of you too
1 min ago, by skull
let your wounds heal, my brother
05:25
@Zee proof?
Zee
Zee
What’s the point ?
@Daminark Oh I see, I think I misread. You are supplementing your sessions with the pair of books, not supplementing Ireland and your meetings with Neukirch :P
Zee
Zee
It don’t matter , I appreciate you sympathy @Eulb but it really don’t matter
prove that $\mathrm{what you're saying} \in \mathbb Q$.
Zee
Zee
Math is much more important than a bunch of buerocrats
05:26
true
Yeah tru
truest
Zee
Zee
You only need time to do mathematics nothing else , time is not easy to get but you can get it
I’ll get married and have a social life when I publish my first paper
be true to thyself
@Zee that's not how it works.
Zee
Zee
05:28
^
Why not ?
Why do things have to be complicated ?
you don't simply "get married."
Zee
Zee
Well it’s not an equality but an inequality
I can only get married on or after I publish
Maybe I’ll find me a rich girl wholl support me :)
mathematics is a collaborative effort.
sugar mamas are tough to find
Zee
Zee
That don’t mean you have to physically be around people , reading research papers is a collaborative effort
05:31
too many girls are looking for sugar daddy's
Zee
Zee
True skull , am banking on my sense of humor
(Don’t bank too much pal )
:-D
@Zee I'm not going to discuss this with you anymore because you don't seem to want to come to your senses. (or because you're trolling)
Zee
Zee
What do you want me to say ?? Am faced with reality and that is how I deal with it , do you have a better way ?
@Daminark, is it true that : There exists a pair of disjoint subsets of $\Bbb Q$ such that both of them are dense in $\Bbb R$?
Zee
Zee
05:36
Just take the even index in any sequence it still has the same limit silent
Yes, actually, there are better ways than venting on the internet
:-)
Zee
Zee
Ok
Am not venting am just talking ...
I know, no offence intended
Zee
Zee
Non taken , o just wanted to share this thing , am not sure why though
@Zee You mean Dyadic? Let Dyadic rationals form set $\Bbb D$, how do we know $\Bbb Q-\Bbb D$ dense in $\Bbb R$?
Zee
Zee
05:39
Start listing the fractions and skip every other number
Then any limit , you can still get
As a sequence of those fractions
@Zee Is it true that $\{\frac{a}{m^n}: a\in \Bbb Z, n\in \Bbb N\}$ is dense in $\Bbb R$, where $m$ is fixed natural number?
Zee
Zee
Sorry , can you write it without Latex
well, it will be very hard to read!
trying
Zee
Zee
I think you can get countable many such disjoint sets that are dense in the reals actually
Is it true that the set of a/m^n, where a is any integer and n is natural number, is dense in reals, where m is fixed natural number?
@Zee so, {a/p^n} for any prime p will be dense subset of R right?
Thanks for your help!
Zee
Zee
05:46
Wait am not sure
Zee
Zee
Am sure about what I said but idk about what you just said
@Zee ok so there are countably many disjoint subsets of Q which are all dense in R, is that what you are sure about?
Zee
Zee
ya
thank u
Zee
Zee
05:49
You are most welcome silent

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