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12:00
hm :) again, I'm confused about your topic. When you've mentioned the Poisson boundary, I thought it implied dealing with random walks
@Ilya I used the Poisson boundary and understood it from an ergodic/measure-theoretic perspective which was sufficient for my needs. I don't have a lot of probabilistic intuition about it, if any at all.
@tb: but what do you call an ergodic perspective? Doesn't it imply thinking of measurable maps (which is equivalent to a discrete-time Markov process)?
@Jeff Hi.
@Ilya In fact I think about it as the action of $\mathbb{N}$ or $\mathbb{Z}$ which of course is equivalent to a Markov process but that don't impress me much nor help me much with my understanding.
@skullpatrol hi skull
12:07
@tb does that LeoGirl signs about Markov processes?
@Ilya No, I think male specimens of the human race are much more predictable...
@tb I proved an already known result in an answer to a question on sci.math. It counts the number of walks of length 2n that stay on one side of the origin and return to the origin
there are obviously $\binom{2n}{n}$ walks of length $2n$ ($n$ "$+1$"s and $n$ "$-1$"s)
and there are exactly $\frac{1}{n+1}\binom{2n}{n}$ walks that return to $0$ and never have a negative partial sum.
And how do you get that? The immediate recursion "count number of paths that return at time $2k$ but no earlier and add up the result for $2n-2k$" looks a bit ugly.
Oh, I just looked, and after that proof is one which counts the number of walks that end at different values without going negative.
@tb here
@robjohn Are you going to run for moderator Rob?
12:16
@robjohn heh, less ugly than what I thought it would be... Nice! By the way: why don't you TeX that? :P
@skullpatrol I may. I have been looking at the rights and responsibilities, etc.
@tb I should write that up a bit more readable for non-ASCII readers :-p
@Ilya Apart from teddys: no, not anymore as they have all been executed.
@tb generating functions make it simpler than it might otherwise be.
@robjohn yeah, I still have GFology buried under many many other things on my "should read that when I have time"-stack
Is there any of us here who doesn't have a tall "should read that when I have time"-stack? :)
(Also, hi.)
12:20
@tb it helped to prove a binomial coefficient question recently :-)
Claim: I have the tallest pile.
@JM Hi there :-) I like the teapot... very SIGGRAPH-like
@JM Mine looks more like this :)
@robjohn Well, it really is the Utah teapot I used in Mathematica... :)
12:22
@tb My dorm room back when I was still an undergraduate was like that. :D
@JM Yes, that is the teapot I was meaning. It was drawn all over the place when I worked at Apple.
all over the place?
@robjohn Heh. I would have loved to see that scene...
@KannappanSampath in many graphics examples
can someone advise how to do $\int_0^\infty \frac {1}{x^5+a^5}dx$?
12:24
@tb BTW, I guess it is not you on top. :P
@Jeff What is $a$?
real, greater than 0
@Jeff $\displaystyle\frac{1}{x^5+1} =\frac15\left(\frac{1}{x+1}+\frac{\zeta}{x+\zeta}+\frac{\zeta^2}{x+\zeta^2} +\frac{\zeta^3}{x+\zeta^3}+\frac{\zeta^4}{x+\zeta^4}\right)$
Every single thing happening makes me believe KV Raman has several user handle here.
render
@Jeff where $\displaystyle\zeta=e^{i2\pi/5}$
12:28
@KannappanSampath Unless you've something concrete, it's a bit easy to dismiss conspiracy theories...
Owow, J.M. is here ... Are you back or not yet again?
After factoring the bottom, did you split up the fraction using partial fractions? Is the final step to integrate each fraction - giving Ln of each denominator?
@tb You like Shania? :D
@JM I'll collect more evidences. But, mods can do it more effectively. He has once already been suspended for this kinda behaviour.
@Jeff then combining the log expressions in a nice way
12:30
@Gigili More or less, I'll be staying for quite a while...
@JM not really (not my type at all and the "music" ....), but it seemed to fit well...
(At the very least, I would love to keep tabs on this election; it's looking to be a bit more colorful than the last two ones...)
@KannappanSampath it's as easy to get multiple personalities here as it is to get multiple email addresses, I guess.
@JM Ah okay. Good.
@robjohn Yes, right. But, he was not clever atleast once.
12:32
@JM how is moderator-dom? I may run here.
@robjohn I think you'll do quite well. All that's really needed for a mod is that s/he has a good amount of not-so-common sense.
2
...and you have that in spades, it looks to me.
weill, I guess one might say I am not-so-common, but whether it is as a compliment...
Should a mod be Tech-Savvy?
@KannappanSampath It certainly helps, but the willingness to learn is more important I think.
@robjohn (Common sense is after all, the most uncommon thing in the world.)
12:35
@KannappanSampath I don't know if they need to be extremely tech savvy, but they need to know how to maintain things.
The learning curve for the mod tools doesn't look that steep anyway.
Right. Thanks both of you.
@JM good, I may not know a lot of the in's and out's here yet, but I like to learn.
@KannappanSampath Precisely. It's one of the things in this world that is so wrongly named...
@KannappanSampath may I ask about the problem I told you about yesterday? You became unresponsive after I posted it. Was it because it didn't interest you or for some other reason?
12:38
@ymar I was terribly sleepy--night before the exam, I did not sleep well.
@KannappanSampath OK, thank you.
At the risk of being called an elitist, I for one would like to see some more candidates with a decent knowledge of mathematics. The current moderators are way above the threshold I would set for that but some of the current candidates so fare are struggling with the most basic things.
Sorry @ymar. But, I could not think of a solution. Let me see it again.
@JM now I know what JM stands for :-)
@KannappanSampath It's nothing important, don't worry.
12:40
@robjohn Shh... :)
@tb Well, we'll have to define "decent" I suppose. :D
I'm sure you can prove existence... I'm not convinced about uniqueness, though...
@tb Why is that? I don't agree. A moderator doesn't need to understand every question on the site or doesn't need to be a professional mathematician.
May be I'd say, reasonable knowledge to distinguish between the cranks and the Math.
And, fairly good knowledge to tag a post appropriately.
(^and by that, I mean, not by appearance, but with knowledge of what ingredients one would need for answering it.)
What Kannappan said. I don't believe mods have to be cutting-edge researchers, but they should have some amount of experience "herding cats", if you catch my drift...
@ymar This thank you is a kind of making me feel odd. :(
12:45
@tb well that would depend on the shape of the universe, right? arxiv.org/abs/1203.6902 ;-)
@Gigili Well, Qiaochu, Zev, (and Akhil back when he was still a moderator) are students and not pro mathematicians. :)
And, I really admire all of them. They are amazing people!
@Gigili I didn't say anything of the kind. I don't think there's one single person that understands every question, after all. We only have two "professional mathematicians" currently (whatever that means) but there are quite a few tasks that a layman simply cannot perform: how to decide if an answer actually contributes something to the thread, for example?
@KannappanSampath I'm sorry if it appears curt. I was just thanking you for the explanation. I simply hadn't understood your unresponsiveness before. Now I do. :)
12:47
"how to decide if an answer actually contributes something to the thread" - on the nose.
Kind of hard to be able to read and judge crankery if the basics remain sticky for you.
@kahen glad about the publication date of that one :)
@tb Umm, then I think it's enough if each of them understand a topic so that they can moderate the site altogether.
@Gigili yes, that's sort of what I was trying to imply with "decent grasp" without going further with actually defining the notion.
@tb "I can't quite define what 'decent grasp' is, but I know it when I see it." ;)
The current number of moderators is probably "enough," but we're not totally minimalists when it comes to having a moderator team.
12:50
@anon With moderators, redundancy is always a good idea.
(Just like file backups.)
@anon especially when we have a policy of moderation in moderation.
@JM Yes, J. Potter M. Stewart :)
@JM redundancy is good in moderation ;-)
Well, speaking of which, I would stand as a moderator myself. But I intend to ponder all aspects before acting.
"I intend to ponder all aspects before acting." - as we all always should. :)
12:54
tru dat
I would like moderators to be regular contributors and with a good sense of what it means to talk illicit about others' nationality.
@KannappanSampath Oh, that's the other requirement for being a mod, at least in my book: somebody with a good understanding of "don't be a dick", and can apply it properly.
and on anon anon anon...
Okay, time for me to go. See you guys later!
12:57
later
See you t.b.!
Ack, I saw that an edit was by "anon" and the original post was by "anon" so I accepted the edit which I thought would be better as a comment because I thought they were the same anon. I guess I will just roll it back.
Have fun Tee-Bee.
@JohnSmith Hallöchen.
@tb later!
12:58
lol
@robjohn don't! the gravatars indicate that they are the same person
@tb hm, that's what I thought, but they have different id numbers.
@robjohn: That means the individual forgot their original login credentials, was unregistered etc and created a new account.
@robjohn The Gravatars match, and I don't believe a hash clash is quite likely...
So, they are using same email ids and probably would need merging.
13:00
is there a general pattern/algorithm to finding subsets of a set in terms of meeting some condition
@anon okay, I will leave it. Although I still think the addition would better be a comment :-)
He's unregistered.
If the username is "anon" I don't think we can assume the individual is a he!
@JohnSmith That all depends on what the condition is. Some open problems in Combinatorics are precisely on this theme AFAIunderstand.
We can't trust usernames and avatars here, as I've learned.
13:02
Also helpful for being a moderator: good forensic abilities!
2
@anon which comes for free with every good mathematics student.
@KannappanSampath I have a set [1, 2, 3, 4, 6, 9, 13, 19, 28, 41] and I am trying to figure out how many subsets fit condition X where X = largest element of subset is smaller than the sum of the rest of the subset
@KannappanSampath If only.
(this phrase is more or less synonymous with "I wish")
13:04
[2,3,4] valid, [3,6,13,41] is not
trying to find some combinatoric approach
or understand how to even approach it
i do it by hand and nothing stands out
@JohnSmith Sounds like one of those tough combinatorical tasks.
That sounds so tough in fact it should more properly be classed as an algorithmic problem.
not even sure how to understand the combinatorics behind it though
it seems like a sum of combinatorics
"I was a personal detective for 13 years. I can stalk people everywhere to find out their fake identities"
13:07
@Gigili who said that?
There is less combinatorics here, IMO. You'd need to find an algorithm to construct every such subset I think. What do you say @JM?
well it's from a PE problem and they're asking about a list 10^18 elements long... so I don't think it's an algorithm question because there's no way to iterate that high
@robjohn A moderator candidate, apparently.
@Gigili ah, I hadn't seen the most recent candidates.
13:08
@JohnSmith Then, you gave us any old subset?
yes
the recurrence relationship for constructing the main set is a fibonnaci sequence
What is exactly theirs? They may have some amount of rationality behind them.
@KannappanSampath Knapsack and subset sum problems are notoriously tough; not sure this isn't quite different.
a(n) = a(n-3) + a(n-1) with 1,2,3 hardlined
the set i gave is the n=10 case
there are 501 valid subsets for it
i wrote a program for this already to verify but it is slow/not using combinatorics
@JohnSmith That is supposed to be exploitable structure...
13:10
i understand that
but i don't see where to even begin exploiting it
clearly, it's not like most subset problems (the np complete tough kind) becauise we know something about the sequence
@JohnSmith Quite right.
I tried listing everything out by subset sizes to see if there was a pattern in how they grow from one n to the next but nothing seems to hold consistently
@robjohn No one's said it by far.
@Gigili I found that out :-)
@robjohn I guessed so!
13:16
anyhow you guys are much smarter than me... do you guys have any insight that might put me on the right track
13:28
Man, after those power tower and Newton-Girard questions, I'm dry again...
@JM more Newton-Girard questions? I haven't seen one in a while. I think I answered one back in December.
@robjohn Yeah, this one. Once I saw it I was scrambling to answer it...
@JohnSmith Nothing really obvious comes to mind. Maybe you'll figure something out after you sleep it over.
There must be a disconnect between math and cs types i guess
13:32
@anon Ooh, interesting. I knew I miss nice questions just by sleeping and being away from the keyboard... :P
@JM nicely done, too.
@rob: Well, it's that "I don't know what I want to see, but I'll know it when I see it." thing... :)
(...and that's partly why I try to be very helpful otherwise, at least with interesting questions.)
I have to go off to the park with Lilly. bbl.
what would be something to look for that is typical of this sort of problem that i may have overlooked
@JohnSmith I would dig a bit on solutions of linear recurrences and their sums, like the one you have.
There should be an exploitable result somewhere...
13:41
thing is how would this even be exploitable for 10^18?
matrix exponentiation or something?
Sorry, I'm far from my refs. You'll really have to do some library digging for this, methinks.
14:09
should be some recursive relationship or two somewhere
ok well we know each set of solutions for n must necessarily contain all previous n
so that's one part there
f(n) = f(n-1) + X where X is the new solutions
It may not be nicely linear. $f(n)$ may depend on $f(n-1)$ wildly.
?
well what I mean is that all solutions for n are contained in the solution set for n+1
@KannappanSampath Nah, he has a constant-coefficient linear recurrence. He mentioned this a few lines ago.
if I take the differences between answers starting with N=4: 5, 12, 28, 61, 128, 265, 544, 1104, 2229
14:28
This is going to be an exceedingly colorful election, methinks.
@JM $\color{red}{\text{e}}\color{green}{\text{l}}\color{orange}{\text{e}}\color{blue‌​}{\text{c}}\color{purple}{\text{t}} \color{red}{\text{i}}\color{green}{\text{o}}\color{blue}{\text{n}}$
aghhhh I thought I had it just there
Good day! Congratulations!
@Nimza to whom congratulations?
to everybody) today it is labor day
Can you please advise me some good book on parametrix of elliptic PDE?
14:46
tried OEIS already JM
wouldn't have asked otherwise
@JohnSmith That little bit, you should have mentioned in the question. :) If not from me, it's the first suggestion you'll receive on questions like that.
leo
leo
15:03
hi there
leo
leo
What exactly does it mean $\limsup_{x\to\infty}f(x)$?
Can someone help me parse Chessmath's comment to me in here?
leo
leo
@anon There is no mention to $\limsup_{x\to\infty}f(x)$
15:16
@Kanna: Well, he seems to be professing opinions irrelevant to actual moderator issues IMO. He's basically against the community downvoting things without explanation, or with too little charity, because it discourages newbies from using the site.
@leo: Surely you can figure out what $\limsup\limits_{x\to\infty}f(x)$ is from the information in that article?
I think what he's saying is that he wants to guard against downvoting that discourages people who may be asking silly/misinformed questions
@KannappanSampath I must be going dumb; it reads like a ramble to me...
@JM Same thing happened to me.
At the very least guess that it means $$\lim_{x\to\infty} \sup\{f(y):y>x\}$$
Anon has succeeded apparently.
leo
leo
15:18
@anon I'm having trouble with $\limsup_{x\to\infty}f(x)=\infty$
@anon I have guessed that as well
In any event, he seems to want to do something that isn't really in the list of a mod's responsibilities...
leo
leo
If that is the case then, $\limsup_{x\to\infty}f(x)=\infty$ iff all the sets $\{f(y):y>x\}$ are unbounded
Means it's not bounded, even if you ignore a finite number of singularities.
Yes.
leo
leo
I'll try to work with that
@JM Yes, right!
15:24
I think you need like - what was it, 10 rep? - to talk in chat...
I was speaking in reference to Holowitz entering the room.
leo
leo
I see
Apparently bans don't extend to the chatroom.
Sure, but bans take all but 1 rep away, so you become a spectator.
15:27
@leo ^
Now that is one high quality scan if I do say so myself.
Definition 3 appears related
@anon I asked my DjVu reader to convert that page into an image and it said, "Yes!"
leo
leo
@KannappanSampath Thanks :)
Help, trying to find a list of the tex code that is allowed to used to post a question. The reason for this is because I tried \begin{array} but that didn't render. I have tried searching on se.tex and on there, but can't find it.
arrays should work in questions. anything that previews correctly is allowed, and then maybe a tiny bit more (because of potential bugs in the previewer)
It's possible you didn't correctly write the markup for your array, or your browser decided to take a nap. In the latter case refreshing should work, though be sure to copy everything you've written in case it wasn't all saved..
15:38
@anon thanks, but do you know if there is a check list I could review before trying to figure out how to write my question in (la)tex. I would be nice for a newbie of LaTeX to know what I can use, or what tags I should learn, so I can post a better question.
leo
leo
@MaoYiyi $$\begin{array}{cl} center & 2x \\ e^4 & 123\end{array}$$
there probably is, but the previewer itself is much better than any sort of list
unless you're trying to memorize a whole bunch of stuff at once for future use, I guess
@anon Not to complain, but I have tried that and my code works on mike tex editor I have that runs under virtual box, it could be because I use chrome and the school I am at blocks or hampers the usages of non-Chinese websites.
Just because something works in miktex or a document creator does not mean it works on the mainsite (math.stackexchange). I'm talking about the preview that exists under the box where you type in your question; it's live.
15:40
@leo why the $$ and not $? and yes Kannappan I always think its Mike Tex, not MikTex.
leo
leo
@MaoYiyi Have you put the array between $ signs?
@leo, thanks.
double dollar signs are displaystyle equations that are centered, whereas single dollar signs are inline equations
@anon half the time, I just see the latex code even for
@Mao: see this
15:41
that's a browser issue then, but robjohn has an antidote for that, lemme get the link
@anon stuff Iknow that has worked before, it could be because I use program to switch between Chinese and English to type online.
@J.M. thanks.
leo
leo
@MaoYiyi for small matrix is better $\begin{matrix} 34 &fc &5\\ 34 & f(4) &t\end{matrix}$$
you can use this too to re-render things in the preview
@leo @anon thanks.
leo
leo
see you all
have a nice day
15:43
@leo bye bye. 88
Bah. Who indexes a summation from $i=k^*$ to $K$? That's just annoying.
Is getting a masters in mathematics in China worth it?
@MaoYiyi You think it is Mike TeX, but is it?
@KannappanSampath its easier for me to think of it as Mike than Mik, I know that its wrong, but it helps me to know it.
Oh, holy, you're so defensive!
15:47
I doubt anyone here would know that much about education in China.
@anon Jasper Loy!
Eh?
@anon thanks, just planning my future and I guess then I have to go overseas.
@anon Jasper Loy would know a bit about it!
I misunderstood an answer and downvoted it. Is it OK to edit it only to remove my downvote? Or ask the answerer to edit the answer?
15:56
I would say it's OK.
OK, thanks. :)
this is driving me insane
every single relationship i find diverges
I've edited a question before for the sole purpose of removing an accidental downvote
it's like some sort of math ghost is hiding in these numbers
ah, math has many ghosts hiding in its lands..
15:58
@ymar I would doubt that anyone would care if you edited their post (a little) so that you could change a downvote to an upvote. However, I think you can change a downvote at any time; at least, I think I've had people rescind their downvote without my post being edited.
@robjohn I can't. The vote becomes locked after some time. At it was a couple of days ago.
Indeed, just like I had to edit the linked question to remove my downvote to it.
I think there's something like a 5 or 10 min window.
I rarely downvote, unless the question is really worth it, most of the time, I put a comment saying how they need to fix their question, or post an answer with sarcasm.
@ymar I guess that maybe I added a second answer to my Law of Cosines post before André rescinded.
@MaoYiyi I thought that answer was completely trivial and I didn't even bother to comment on my downvote. It must have been unpleasant to the answerer. It's even more embarrassing because it's the only answer "competing" with mine in that question.
16:03
@MaoYiyi I have never downvoted. I would rather give a helpful comment. I haven't run into a case where the OP doesn't repair the error. If they didn't, I might downvote.
I've changed it to an upvote now out of shame.
It's kind of interesting to go through the users page and check out the up-to-downvote ratios of people.
Didier and Dubuque are pretty hard to please!
@ymar I see no reason not to upvote another's answer to a question you've answered (as long as the answer is good). It doesn't hurt the number of votes you get.
I don't like to downvote, mostly because I got so harshly downvoted asking about a book and all I could remember was that it had KY birds in it, then finally someone gave me the answer, but it really hurt. I understand now that my question was not worded as carefully as I could have worded it, but still, it wasn't a terrible question.
Personally, I think the Sportsmanship badge should be something you can get an indefinite number of.
16:07
@anon It would be nice :-)
@robjohn Of course not! I don't mind upvoting another's answer. But this one I wouldn't upvote otherwise simply because I think it's not that good.
@ymar then I wouldn't upvote it, just because you made a mistake before.
For sure, upvote when their answer is better than yours, or more complete. I like when people write nice answers, it helps me to write better English here.
Holy!
Long answer I typed Aw snapped!
@robjohn That would be what reason says, sure. But I'm too ashamed not to upvote that answer. :)
16:10
Do you think I would be downvoted if I posted a questions in poor English, and then wrote what I wanted to say in another language? Mostly because I don't have the English skills to explain the question very well.
@ymar whatever :-) it's your decision.
No way can I recover that!
:(
@MaoYiyi I've never been heavily downvoted on main. Just occasional downvotes so it wasn't very painful.
@ymar it was my first question and I got so downvoted, that I couldn't do anything, I finally send a message to some of the users that left comments and explained that I was searching for a book not being a pervert, and told them the title of the book.. Then one of the mods, fixed it and have me some points back and now I am very careful about what questions I ask.
@MaoYiyi I definitely wouldn't downvote that. I've seen a question here posted entirely in Italian I think.
16:16
well, bye bye.
88
@MaoYiyi you might want to take a look here.
afk for a bit.
Aw snap again!
What the hell!
:(
16:33
hello
can anyone help me with a mega super quick fast question
this is utterly ridiculous. i've gone through like 30 OEIS sequences which all match like 12 terms of all these different ways of splitting up the problem and they ALL DIVERGE after a certain point
@PaulSlevin depends on what the question is; if your quick question is "Describe BSD Conjectures."--very short but I am not sure the answer is :P
So, ask your question anyway @Paul
16:58
@KannappanSampath What's wrong?
Oh, the SE page crashed like five times!
@KannappanSampath main site?
In the middle of composing an answer.
@robjohn All SE pages, including the Chat site and a transcript page I was reading.
@KannappanSampath try disabling the mathjax preview while composing, and only turning it on periodically.
All? that is bad
Yes, indeed! ^
I finally finished composing the answer.
@robjohn Nice tip. Have not tried it as yet. I'll do it and see what happens.
17:02
@KannappanSampath MathJax can't crash if it's not processing.
I see. But, they should quicly fix this or I should get a Mac. The latter is expensive and not affordable for me at the moment. :P
does anyone else experience this? if not, it is probably something with your computer.
I don't know. FWIW, there is a upvote for a report I wrote in BD's question.
But, nowhere else does it crash. Only SE pages crash.
For a few weeks, it was only main site, but now every SE window is dead.
@K
@KannappanSampath sorry I was away
I was just wondering if the tensor product map $\otimes: V\times W \to V \otimes W$ was injective, surjective, neither or both in general
for vector spaces or modules really
@Paul We don't have with us one person who I know would be very interested in discussing this question: Benjamin Lim.
Of course, Zhen, t.b., ymar, anon, kahen(?), Didier(?) can help you too if they are not occupied at the moment.
I am not sure if people with ? can actually help you. I have never interacted with them.
17:12
cool, i was talking to benjamin earlier on one of my questions
anywya, its my bedtime so i wil come back later
see you guys
Later @PaulSlevin
@robjohn Do you have a slight error in this comment? I get that $x^5+1=0$ factors to $x=e^{i(\frac{\pi}{5}+\frac{2k\pi}{5})} \quad (k \in \mathbb{Z})$. That means $x=e^{\frac{\pi}{5}},\ e^{\frac{3\pi}{5}},\ e^{\frac{5\pi}{5}},\ e^{\frac{7\pi}{5}},\ e^{\frac{9\pi}{5}}$
...but your equation seems to show $x=e^{0\frac{\pi}{5}},\ e^{\frac{2\pi}{5}},\ e^{\frac{4\pi}{5}},\ e^{\frac{6\pi}{5}},\ e^{\frac{8\pi}{5}}$
@Jeff I believe that by using $x+\zeta$ rather than $x-\zeta$, we get the same thing. $e^{i6\pi/5}=-e^{i\pi/5}$
17:29
ok. ty
Hmm, I see, there was only one upvote there. I'll wait for more!
@KannappanSampath where is that?
@robjohn Here is that answer, that took several rounds of edit due to Aw!Snap. And, this is what I was talking about in terms of upvote too.
@robjohn and did you actually do that partial fractions (and so quickly), or do you recognize the result from previous work? that's a doozy!
What's Aw!Snap?
17:33
@Jeff I saw your question on chat yesterday, and did the partial fractions. :-) You were gone when I saw the question and finished.
@ymar That's what Chrome tells you if it wants to kill your time!
@Jeff However, thinking about it this morning, I can see why it is what it is pretty quickly now.
how long did it take you? :D I need to get it done in time to teach a student at 2:30 (it's now 1:30 my time)
@KannappanSampath Oh, I use Firefox. Thanks.
oh, and I can't figure out how to get Maple to spit out the answer.
17:35
@Jeff Do you know the Heaviside Method for partial fractions? If so, it doesn't take too long.
(and i hate taking shortcuts and just copying others' (aka your) answers).
@Jeff I couldn't get it from Mathematica either.
no, I've heard of Heavside
well, if you can't get it from Mathematica, then I have no chance of getting it from Maple. :D
@ymar Have you received a valid answer to award that bounty on left and right zero divisors?
@KannappanSampath Nope.
17:38
@ymar Hmph. So, the bounty goes to the thin air?
Probably so...
I'd say award to the answer you have got and leave a note saying although this answer does not answer the question, you wanted the bounty to be awarded in a useful way!
I've already spent 800 rep this way, it's not a big deal if a bit of it goes to hell. I've learned a lot from answers I got after offering bounties.
@KannappanSampath Sure I can do it.
can you lend me some rep so i can set lots of bounties, too? :D
I don't know, can I?
Interestingly, a lot of my reputation comes from the questions with bounties.
I mean, my bounties.
(I don't really get reputation from answers)
17:44
@robjohn well, i think I got Maple to correctly distribute and refactor the numerator, anyway
@ymar You should write a lot more answers than you do now. :)
I write an answer every time I know one. :-)
I guess you have your implications wrong.
hmm?
I know the answer every time I write one, (but the converse is not necessarily true).
17:48
Unfortunately, it almost is. :) (I did exaggerate a bit)
@robjohn I retract that. I can't even figure out how to do this partial frac using Maple or on paper.
I should have said: every time I know one and it's not already there.

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