« first day (2771 days earlier)      last day (2546 days later) » 

10:00
Well... Quantifiers elimination in model theory
But I also want to see a couple of algebraic/geometric applications, in particular the Nullstellensatz and Tarski-Seidenberg
So yes :D
Aha
What qualifies as a quantifier in model theory?
Like what unites $\forall$, $\exists$, $\Box$ and $\diamond$
I think quantifier is just an informal term? Anyway I'm interested in FOL so I only worry about the first two
How very amoral :p
(MODAL LOGIC JOKE)
there are amoral models?
10:12
Modal logic has been used for axiomatization of morality
Jesus god everything I have been thinking for the last couple minutes is totally flawed
frikfraking hell
that's math for you
There's some breakthrough today in office. After plotting a colorful scatter plot, I figure out what the trends should be and how to slice that high dimensional data
:applause:
I can make two plots of the same set of dots, but i can change the color gredient to run through the 3rd axis or 4th axis. The 2D graph plus the colors then give me the trends I am looking for and switching the color schemes effectively slice the dots along the 3rd and 4th direction respectively. Now to experiment further cause I have procratinated enough already
actually. post a better one:
so the color pattern determines whether the data is being sliced in the L2 direction or the L3 direction
10:38
Why do physics people and math people use different symbols for the second fundamental form
10:49
I thought it is always $\mathrm{I\!I}$?
No, it's
Mar 2 at 16:43, by Balarka Sen
$\underline{I}\!\!\overline{I}\!\!\underline{I}\!\!\overline{I}$ is the second fundamental form
Physicists usually use $K$
And call it the extrinsic curvature
I thought K is the gaussian curvature (or is that kappa?)
Well $K_{ab}$
Hence not a very scalar quantity
10:52
make sense
@AkivaWeinberger You want to write a topology apologist answer on this old thread? Should be a good summary of all of what we discussed
It popped on my active feeds a few minutes ago
The two answers are basically elaborate calculations which does not really do the fact a justice
11:11
hi I have a question, is the relational inverse just as simple as swapping all the ordered pairs?
@WhatsThePoint Yes
An exponential factorial is a positive integer n raised to the power of n − 1, which in turn is raised to the power of n − 2, and so on and so forth, that is, n ( n − 1 ) ( n − 2 ) ⋯ . {\displaystyle n^{(n-1)^{(n-2)\cdots }}.} The exponential factorial can also be defined with the recurren...
tetration is weird
11:33
@TobiasKildetoft thought so
11:51
[Random]
42224242422224244444222422242424444444224422224222242424222
In computability theory, a Specker sequence is a computable, monotonically increasing, bounded sequence of rational numbers whose supremum is not a computable real number. The first example of such a sequence was constructed by Ernst Specker (1949). The existence of Specker sequences has consequences for computable analysis. The fact that such sequences exist means that the collection of all computable real numbers does not satisfy the least upper bound principle of real analysis, even when considering only computable sequences. A common way to resolve this difficulty is to consider only sequences...
@AlessandroCodenotti Listening to Russian Circles rn
They're great, which album?
Station
11:57
@Secret Very interesting
@BalarkaSen the best one in my.opinion
Hah yeah it showed up in my youtube feed and I remembered you recommended it to me once
@Secret Death due to YouTube compression
Youngblood and station are my favourite songs from the album
I'm on Harper Lewis. Amazing instrumentation
Great drums, good shreds
This borders on metal
12:02
@AkivaWeinberger there is no relation between $Y$ and $B$
I think they're classified as post metal but they're pretty heavy compared to other bands in this genre
Mmm I see that
It's so sad that everytime the chat become active, I had to go to sleep
Someone please F888 timezones!
@Vrouvrou Then $\partial B$ and $\partial(Y\setminus{\rm int}(B))$ need not be related
Take two disjoint closed disks
Oh wait sorry
It was $\partial Y$ and $\partial(B\setminus{\rm int}(Y))$
Same thing though
no relation ?
12:08
If $B$ and $Y$ are disjoint closed disks then $\partial Y$ and $\partial(B\setminus{\rm int}(Y))$ are disjoint circles
ok thank you @AkivaWeinberger
@AkivaWeinberger we must prove that $\partial Y\subset \partial (B\setminus{\rm in}(Y)$
@Secret "F888"?
not $\partial B\subset..$
Then there must be some additional conditions on $B$ and $Y$
Maybe $Y\subset B$, with $Y$ closed and $B$ open
Something like that
i have that $Y$ and $B$ are the two closed
but i don't see any inclusion
12:28
@Alessandro Youngblood is flipping awesome
@BalarkaSen You mean the Brass Band?
Ah, no, a song of Russian Circles I'm listening to
12:41
So a kid in my HS class came up to me after the exam:
"Mr. Nitsua, I hope it's alright, but one of the proofs I found easier to explain if I used Kronecker deltas."
"Of course that's fine--Kronecker deltas are maybe my favorite- no, one of my favorite bits of simplification. Einstein summation-notation, though, is probably my favorite."
"Oh. I used that, too."
Some days it's really nice being a teacher =)
@BalarkaSen I watched Serre again last night
I didn't see the part you mentioned
was it the $f=O(g)$ thing?
0
Q: Space of Sequences with Finitely Many Nonzero Terms is Paracompact

user193319I just proved the following theorem: If $X$ is a regular space that can be written as a countable union of compact subspaces of $X$, then $X$ is paracompact. I am now working on the following: Show that $\Bbb{R}^\infty$ is paracompact as a subspace of $\Bbb{R}^\omega$ with the box top...

I'd have to find it. But yes, something like that; you have things like, let $\epsilon > 0$ blah blah blah $K_1 |f| < |g_\epsilon| < K_2 |h|$ say, but a major pitfall is not to mention that $K_1$ and $K_2$ depend on $\epsilon$ or if it's a uniform bound or whatever the hell
He explicitly mentioned it
Found it
@BalarkaSen I'm working on something where there's three parameters and I feel like it's cheating because I get a bunch of shitty error terms that they don't get in the paper, but I can send something to zero and works out in the end
lmao
Well Serre gives you a good notation to say it
12:50
I've never seen that double less than for what he says
in pde you can write $f\lesssim g$
that's the same as little o or some shit?
no, it means $f\le Cg$
oh just big O
no!
he explains that people abuse big O all the time
modulo abuse i meant
i'm from the clan of gromov, don't show abuse to me
12:54
if you want to be correct, you do something like
i'll $\mathcal{Op}(E)$ you up
@0celo7 yeah but that just looks horrible
But probably helpful
Serre might object to the dependence on $\Omega$, like what properties of $\Omega$ does it actually depend on
@BalarkaSen I've found that to be a good notation for personal notes
I've tried to use it when explaining stuff to people but they think you're insane if you do
it's the origin of the abuse of statement of h-principle
really, a function on Op(A) is a germ at A
right
@BalarkaSen look at this horrible shit i.gyazo.com/52dec34f36a6f5d5b35515b5af10369a.png
is the trickery in "assume delta is small such that ..." statement?
everything else seems carefully chosen
there's a little o hanging around but that's fine
13:02
@BalarkaSen yeah you need to choose $\delta\ll \rho$ and then $\varepsilon$ will be $\ll \delta$ or something
the idea is that you make $\rho$ small s.t. the term in [] is positive
$A$ is positive
and then for $A$ fixed, you can choose $\delta$ as small as you want
so the first term goes to zero, but the second one goes faster
so eventually the overall contribution is negative
That sounds fair
'cuz you have \delta^2 hanging around at []
it's not so bad now, but it took me a long time to figure this out
the paper and book have typos, so...
but the thing you need to make absolurely sure about is that $C$ doesn't depend on anything
@BalarkaSen I'm debating writing out what the $o(\delta^2)$ term should be
I'll be back in 15 minutes after I do this diffraction computation
I am become physicist
6
13:08
it's really like $\delta^{2+2/(n-2)}$ with some more crap
Destroyer of rigor
good luck
@BalarkaSen Destroyer of notation
I love physics notation so much
@Slereah ???
…?
arrow goes up
arrow goes down
is it not clear
13:40
also great : birdtrack notation
Oh please stop
The agony
please continue hurting Balarka
15
speaking of agony
@Slereah Right OK whose book is this
Ancient egyptian math
13:52
Does anyone know what a temperate solution is?
In the context of diff eqs
Sounds cool
@Balarka My officemate was showing me a paper in which they write $k^{-\epsilon}$ where $k$ is a constant that depends implicitly on $\epsilon$
@Lozansky like a tempered distribution?
@0celo7 Is that when $\varphi_n \to 0 \Rightarrow U[\varphi_n] \to 0$ as $n \to \infty$?
@MikeMiller Oof
13:54
The dependence on epsilon was stated on a different page
Sooo... a solution bounded/tend to $0$ at $\pm \infty$?
Also Geneva is pretty good if you want to listen to another Russian Circles album @Balarka
The context is: "We look for tempered solutions to $-\Delta u=f$ when $\Omega = \mathbb{R}^n$. Linear system theory tells us solving $-\Delta u = \delta$ is enough and we call these tempered solutions fundamental solutions"
@MikeMiller That's like seriously mean
@Lozansky what?
14:00
Thanks @Alessandro, I shall check it out
@Lozansky They mean a solution in the sense of a tempered distribution, I think.
So in the dual of Schwarz space
@0celo7 I don't know what "dual of Schwarz space" is
Um
What does $-\Delta u=\delta$ mean to you
They claim the Laplace operator has the fundamental solution $K(\textbf{x}) = -\dfrac{1}{2\pi} ln|\textbf{x}|$ in $\mathbb{R}^2$
@0celo7 Some kind of point-source problem
use \log
14:04
Oh.. too late
\operatorname{logarithm}
$$\operatorname{NeperFunction}(x)$$
For comparison: In electrostatics, the potential of an infinite line charge $\lambda$ along the z-axis is $V(\mathbf{x})=\frac{\lambda}{2\pi \epsilon_0}\ln s$ where $s$ is the distance from the z-axis.
I call the log the Napierian operator and write $\mathrm{Nap}(x)$
And the potential of a line charge is a harmonic function away from $s=0$.
@Slereah great minds...
14:06
@Semiclassical But what does tempered mean? I thought it meant bounded of some sorts
It's a definition.
It means that it's a solution in the sense of tempered distributions.
Oh that looks difficult
I'm trying to write a paper for this environmentalism class I'm taking
The literature in this field is so bad
14:07
Tempered distributions are nice because you can do calculus on them (i.e. derivatives) without running into problems.
But it is not a condition that is easily checked?
well, check out the paragraph that starts as "The tempered distributions can also be characterized as slowly growing..."
I'm actually not 100% certain that the Green's function is a tempered distribution. It probably is, but...
You'd have to do the estimates
@0celo7 This is a chapter under "Green's function" so I guess it is :P
Well your book doesn't seem to be terribly precise
14:10
No it is meant for engineers
then you should ignore that line and move on lol
The main thing is whether or not it makes sense to do differentiation (and therefore integration by parts) on your functions. If you're doing tempered distributions, then that's always safe.
@Semiclassical Oh I remember that locally integrable functions such that $|f(t)| \leq c |t|^k$ for large $|t$ are an example of tempered distributions
wtf
yeah, that fits with the 'slowly growing' line I quoted earlier
14:14
10 seconds ago you'd never heard of tempered distributions
I'm more concerned with the pole than the long-range growth, anyhow
No I had heard of tempered distributions but not functions :P
Fantano says "ION" by Portal is the best metal album this year so far
I hope the melonboy's right
'cuz I'm going to listen to it
hmmm
how do I pick a random pair of orthogonal 3-vectors
hmmmm
14:18
So if $K$ is a tempered solution (in distributional sense) to $-\Delta u = \delta$ then the function $u = K * f$ is a solution to $-\Delta u = f$?
@Semiclassical Matlab?
@Lozansky yes
Is this due to Schwartz kernel theorem?
well, i could do either matlab or mathematica
it's the method I'm not sure about
Guys , I'm stuck on this for a while now , any hints how to proceed ?
Also, meant to say that they should be unit vectors
14:21
Why don't you just iterate random 3-tuples until the inner product between them is $0$?
Well, there's some probability distribution on their inner product presumably
in which case the probability of getting exactly zero is nil
I have no idea how to proceed , it is $\frac{0}{0}$ form , but I can't even use L' Hospital
But one can instead demand it be close to zero and do a lot of random samples
What is "greatest integer"
14:22
@Slereah the floor function
Shouldn't that be $\lfloor \cdot \rfloor$
So I think that method works.
@Semiclassical So random integers in some closed interval?
@Slereah It's called that and written like that here in Iindia (at least in high school mathematics)
@Lozansky What?
14:23
I mean if it's the floor function
Wouldn't $\lfloor x/2 \rfloor$ be a constant function around $\pi/2$?
@Slereah how ?
it'd be constant for $4>x>2$, yeah
@Lozansky why does an engineer know about the schwarz kernel theorem
Engineers are allowed to know things :P
Like, how have you seen SKT but not Green's function
14:25
Hence it's just $0$ in that region
That's worse than Balarka learning calculus after homotopy theory
Or at least it has zero left and right limits
@Slereah yes , it is 0 in that region, completely agreed
then what is the issue
@Lozansky this Green's function calculation is done in every book. Gilbarg-Trudinger, Evans, Shankar, Straumann, pretty much every book in every field has this
14:26
@0celo7 Probably not.
I think we both secretly agree on that
@Slereah how do I solve it or simplify it from $\frac{0}{0}$ form ?
@Semiclassical Say you choose a closed interval and fix a random 3-tuple of integers and then iterate a new 3-tuple of integers until their inner product is $0$?
@Tanuj You don't have to
@0celo7 They mention it in my book
I'm not really seeing why you're suggesting random integer 3-tuples
14:27
For any $x < \pi/2$ it is equal to zero
Hence the limit by inferior values is zero
and same for the limit by superior values
So the limit is just zero
But, I mentioned something in passing that I should've emphasized
I want these to be unit vectors as well
@Slereah but isn't the denominator also getting 0 for those intervals ?
@Tanuj Doesn't matter here
The easiest way I know how to do that is to create triplets of standard normal random variates and then project them onto the unit sphere
14:29
@Slereah why is that so ?
You can use the proper definition of limits to convince yourself that it is true
Guess you need to impose some error limit :O
Yeah
Which is fine
Check that for all values of $x$ arbitrarily close to the limit, $f = 0$
hence it is the limit
God this album is full of abrasive sounds
100% noise metal
14:31
@Slereah I'm just not getting it how .Isn't $\frac{0}{0}$ by an indet form ?
I give up
RIP me
user280247
Hello..just want to make you a question..
@Slereah I'm sorry mate , it must be something simple , but I just don't get what you're trying to say
user280247
Is there any book in history of maths with nice explanations on the discoveries?
@BalarkaSen Die Melone loves that crap
14:34
i prefer some r a t t l i n g h i g h h a t s
There's a lot of pop math books (like, math for a popular audience), you mean like that? @santimirandarp
@0celo7 is that German for "the melon"
Like The Pythagorean Theorem: A 4,000-Year History by Eli Maor, and various others
I hear that Pythagoras got into his bathtub
I have a headache from listening to "Prey for sickness" being whispered into my ears with abrasive guitar riffs and white noise on the background
jesus christ
14:36
And then realized that the water formed a perfect right triangle
So he leapt out, screaming Εύρηκα!
accurate
And then they made the movie "The Shape of Water" based on that event
most mathematican discoveries were done in the bath
I don't even dare tell you how they found the hairy ball theorem
@Slereah yes
@Slereah wasn't that Archimedes who shouted Eureka when he calculated the mass of gold stone by displacing water in his bath tub ?
14:38
that is true
@Tanuj He's just being silly
Okay @AkivaWeinberger , I'm too silly to realise someone is being silly
@Slereah old jok
the old joke I've seen is that Archimedes Εύρηκα a nail in his bath
Hence why he got out
@Lozansky think I got it working in the way I outlined. (I was using a similar approach for a different aspect of the problem, so it was easy to to adapt it.)
14:45
@AkivaWeinberger could you help me with this
@Semiclassical Cool, not too long running time?
nah
though I"m using a pretty generous error tolerance
I think you could do it pretty easily in Python
There's a lin alg package in numpy
14:48
I did it in mathematica
The main problem is that, if I do a more restrictive error tolerance, then I have to do a lot more samples
But that's sorta inevitable with this kind of approach.
In any case, I can use it to verify (within the error tolerance) a claim I thought should be true
So that's good
Neat :)
@Tanuj Should be 0
@AkivaWeinberger I don't get why
$[x/2]$ is zero when $x$ is between $0$ and $2$, right?
@AkivaWeinberger the numerator should always be zero , for left as well as right handed limits
@AkivaWeinberger yes
14:55
Which means that, on that interval, $\frac{x/2}{\ln(\sin x))}$ just equals $\frac0{\ln(\sin x)}=0$
@AkivaWeinberger I don't get why denominator isn't always 0 in the vicinity of $\pi/2$
and $\pi/2$ is in that interval
@AkivaWeinberger doesn't $\sin(x)$ approach 1 as we move on its graph from left hand and right hand sides towards $x=\pi/2$ ?
@Tanuj $\sin(\pi/2)$ is $1$, which means that $\ln(\sin(\pi/2))=0$. But when $x$ is slightly different from $\pi/2$, $~\sin(x)$ is gonna be slightly different from $1$ and $\ln(\sin(x))$ is gonna be slightly different from $0$
Suppose you were to do $x=\pi/2-0.1$. What would you get on the top and bottom?
14:57
Uhh.. my book says $\dfrac{\partial}{\partial \textbf{n}} = -\dfrac{\partial}{\partial r}$ for a disk
On the edge of a disk or on the surface of it
Okay guys , thanks for help , I got it that 'slight' error in the logic ! @Semiclassical @Slereah @AkivaWeinberger :)
Edge
@Lozansky Yes.
Then that's not so strange. A disk is a cross section of a cylinder, and the surface normal in that case is just $\hat{r}$
14:59
Um, wait
The minus sign
Which orientation for $\mathbf n$
yeah, I was about to say
But it could make sense in context.
That's the thing, they say like 100 pages before that the outwards direction is standard

« first day (2771 days earlier)      last day (2546 days later) »