« first day (2758 days earlier)      last day (2558 days later) » 

00:00
someone said my name?
@MatheinBoulomenos What's the question? What are we convolving?
is it a positive summability kernel?
@XanderHenderson we're convolving to approximate by continuous functions. @quallenjäger wants to extend some integral bound from continuous functions to a larger class of functions. I pinged you because you seemed to be there
I see; I was not there
what is the inequality? there are a couple of ways that one can try to make it work, depending on what kind of functions you are working with
@quallenjäger are you there?
as you seem to have indicated, the typical trick is to mollify
@quallenjäger Where you at?
I WANT TO MOLLIFY!
00:18
Yes I am here.
I have a Lipschitz continuous path $\gamma$ and I want to find a lower bound on the increment $\Delta \gamma =\gamma(t_1)-\gamma(t_2)$.
For a $C^1$ path $\gamma*$, I have the lower bound $\Delta \gamma* > C$
So what I have so far is $\Delta \gamma = \int_{t_2}^{t_1} \dot{\gamma}(t) dt$, where $\dot{\gamma}(t)$ is almost everywhere bounded.
Do you see what I want to do?
Or shall I continue?
no, please continue
$\dot{\gamma}$ is the derivative with respect to $t$, yes?
(I am not a physician---the physics notation is unfamiliar to me)
you can bound the integral explicitly in terms of the Lipschitz constant, no?
00:25
But not from below
I need something from below
oh, yeah...
I need it to be greater than 0.
oi...
hrm...
So my thought is, if I can mollify my $\dot{\gamma}(t)$
00:28
then I know that the bound hold for the mollifier, namely $\Delta \gamma*>C$ for $\gamma*$ being mollifier and thus continuous.
I hoped that the lower bound would still hold true if I take the limit.
@BalarkaSen
it seems like you should be able to use standard arguments to push the bound into $L^1$
but lower bounds are weird in this case...
that said, it is probably a standard $\frac{\varepsilon}{3}$-style argument
which 3 parts do I need?
plus some reverse triangle inequality?
hrm...
no... I don't see it...
What I have thought is
$|\int_{t_2}^{t_1}\dot{\gamma}(t)-\int_{t_2}^{t_1}\dot{\gamma}^*(t)|<|\dot{\gamm‌​a}(t)-\dot{\gamma}^*(t)|_{L_1}$
lol what is this....
Anyway, we know that the latter term converges
because the mollifer converges against $\dot{gamma}(t)$ under $L^1$ norm.
00:34
So...$$ \left| \int_{t_1}^{t_2} \dot{\gamma}(t) - \gamma^{\ast}(t) \right| $$ converges to zero, no?
by general abstract nonsense...
And I can somehow control the term $\int_{t_2}^{t_1}\dot{\gamma}(t)$ from not being to far away from the lower bound of $\int_{t_2}^{t_1}\dot{\gamma}^*(t)$
Yes, sorry for my notation.
Something is not working right.
Would this work?
so $\|\dot{\gamma} - \dot{\gamma}^{\ast}\|_{1} \to 0$.
so fix $\varepsilon < \frac{C}{2}$
and pick a mollifier $\gamma^{\ast}$ such that $\|\dot{\gamma}(t) - \dot{\gamma}^{\ast}\|_1 < \varepsilon$.
By (reverse?) triangle inequality, you should get the bound you want on $[t_1, t_2]$
I see, so this would work?
00:38
right?
maybe?
Exactly what I have on my mind
it seems like a reasonable approach
Alright, I will work this out, thanks
By the way
How do you make this double absolute value sign?#
I always use | on my keyboard :D
00:39
not ell, pipe
it is a slash, then the usual absolute value symbol
\|
hit the same key twice, just with the shift key down the first time
$\|$
$\ ||$
shift key? I am using mac
same combination?
yes, so am I
slash pipe
\|
it is two characters
(right click on the symbol and view the math as TeX; maybe that will help
\| x - y \| is rendered as $\| x-y \|$
okay, I need to go make food; my people will be home soon
Thanks, I will try this later:D
Thank you for your help.
01:13
(If the next era is mollification, what will that even mean?)
(Cause I have been seeing that word popping up quite frequently in recent weeks)
(Not that I don't know what mollification means, but rather, how broad it can be)
Sometimes, strange things happen when a meta analysis of the chat is performed
 
1 hour later…
02:23
@Secret I gotta ask, man, 'cause I'm worried about you: how many hallucinogenic mushrooms do you ingest in a typical day?
@BalarkaSen heeeelp
02:48
@XanderHenderson on a related note, mushrooms, especially shiitake mushrooms improve gut health and have several testosterone boosting micronutrients
I no longer really believe what biological scientists tell me about the body and food, because it seems they keep changing their mind.
the one thing that almost always remains consistent though is whatever they say about testosterone
whenever in doubt, always follow the diet/habits/lifestyle that increase testosterone
uh... sure...
I'm, like, super worried about my testosterone :eyeroll:
I've found so much overlap between natural testosterone boosting foods and habits and foods and habits that boost cognitive performance and cardiovascular health
good for you
02:55
Cold showers, intermittent fasting, magnesium supplementing are among the several things in that overlap.
@AlessandroCodenotti yes
what about magnesium showers
@XanderHenderson well. zero. I am on an immunesupressant, which interact with many other food chemicals and drugs meaning I won't take anything else not prescribed
Balarka, Blue and many others have been wondering why on Earth I have so many weird dreams and even more weird behaviour, and has asked me whether I have take any hallucination agents, and I have took none
So I have no idea...
@MeowMix why are you showering yourself with magnesium?
for my testosterone duh
Actuallly googles magnesium shower
search results are pleasantly surprising
03:05
Ah I see, magnesium products, not magnesium flakes
there are magnesium gels but sadly most of them would likely have BPA's that would introduce xeno-estrogens into the body that would reduce testosterone
1
Q: Finite dimensional vectors spaces external direct products and linear maps.

FaustSuppose that V is a finite dimensional vector space over a field $\Bbb F$, and that $T \in L(V )$. Suppose also that $V = U_1 \oplus U_2 $, where $U_1 $ and $U_2$ are T-invariant. Let $\beta_1 $ and $\beta_2$ be bases for $U_1 $ and $U_2$, respectively, and let $\beta = \beta_1 \cup \beta_2$. ...

can someone help me with the hint given for part 1? i cant seem to tell what $[T]_{\beta}^{\beta}$ is
i hate the fact that its been 7 years since i learned linear algerbra
have to look so much stuff
it's been nearly 20 for me ;P
yeah but i was in the tech industry for those 7 years
linear algebra doesnt come up...
the hardest question of the day, what to eat for lunch?
that is moderately surprising
food
03:10
good start
though, typically, I don't bother with lunch
where
what kind
coffee for breakfast
thats a hard question
more coffee for bunch
then a light meal of coffee for lunch
followed by a late afternoon snack consisting of coffee
and a sensible dinner!
03:11
@Faust My guess is the coordinate vector of the map $T$ under the basis $\beta,\beta$
now, a hint to get you started: using the $T$-invariance of the subspaces, which entries of $A$ can you guarantee will be zero?
i have nfi what hes talking about
@Secret i think so as well but have no idea how the hint follows from that
@XanderHenderson i normally when i worked would only eat one meal and it was lunch
If my 2nd memory serves: T invariance is that when you have some subspace W, then T(W)=W, meaning that any vector w in W will stay stuck inside W when mapped by T
i think the answer is that its upper triangular but i have no idea what that has to do with anything
@Secret also correct ^^
Suppose the subspace is a plane, then if there is a T such that the subspace is T invariant, then you expect the image T(w) will also be vectors on the plane, meaning that there will be a set of vectors in the whole space missing from its image, thus this suggest some of the coefficients of T has to go away otherwise the image can fall outside of the subspace
One example is a T that does sheering in the xy plane, you will not expect any vectors at the xy plane to leave it after mapping by T
well i think they are saying that A is upper triangular
question makes me feel like an idiot been working on it on and off for a week
03:24
U1, U2 are T invariant meaning that T(U1)=U1 and T(U2)=U2. The only way that can happen is if T is a direct sum (a block diagonal matrix under some basis, so that off block diagonal elements has to vanish otherwise the vectors in U1 can map to U2 and vise versa, contradicting T invariance of the subspaces)
I don't remember if block diagonal matrices depend on basis though, need to revise
hmm this actually sort of makes some sense
do we know that dim$T|_{U_1} = dim U_1 $
or more simply do we know that $dim [T]_{\beta}^{\beta}$ = dim V ?
ANyway thank for your time @Secret you defiantly helped
@Daminark If I have $f$ holomorphic in the unit disk and $\exists r\in(0,1)$ such that $|f(1/n)|\le r^n$ for each $n\in\Bbb N$, then $f\equiv 0$ by a power series argument, right?
Also hi
$f(1/n)=a_1/n+a_2/n^2+\cdots$ causes issues if the $a_i$'s are not all zero
In the part 2 of his anawer, he proved $\beta_1\cup \beta_2=\beta$ is a basis for $V$, thus T has to be of the same dimension as V otherwise it cannot map any vectors in V to V
03:42
ok thanks =)
hi whats the correct way to write this:
ln(cos(x) - c) where c is an arbritrary constant.

I was thinking i should add | | to state it cannot be negative (x is defined between -pi/2 and pi/2) but since c is arbitrary and not important should i still add them since c can technically be a positive number anyway?
Do you have an initial condition?
only that -pi/2 < x < pi/2
well, that at least means cos(x)>0
yup
but can we just assume c < 0
or should i apply absolute
03:51
if you're not told to, I doubt you can assume it.
okay, ill play it safe then
@Semiclassical reading BBS string theory for my hyperbolic PDE class
I'm in the upside down
help
@WDUK what is the context in which that expression pops up?
god help you
(BBS?)
Becker, Becker, Schwarz
03:52
that should dictate (to some extent) what $c$ can be
it has a decent section on conformal groups
@XanderHenderson it was from differential equation giving me e^(-y) =cos(x) - c
needed to get it to be y = . . .

so i applied log to get -y
Is that like Virasoro algebra stuff?
no, because I want it for 3+ dimensions
2D conformal stuff is crazy
03:54
@0celo7 sounds right
It's $\mathrm{SO}(D+1,1)$
I'm just not sure what the prof really wants me to do
so $D>1$, hmm
yeah
conformal mappings are fun, but conformal groups...yikes
and CFT is scary
I think I'll talk about how the conformal group acts on light cones.
Or I could just talk about GR...
idk
03:56
lol
talk about twistors :P
Duuuuuuuude
I wish I knew that
same tbh
it seems like crazy stuff
@Semiclassical do you want to read something this summer on it
I might be up for that if I've got the time
03:58
[Some random rambles] Actually understanding the significance of the off block diagonal entries of a linear map is quite useful:
sounds right
I think it's fairly elementary
my main exposure to twistors is in Penrose's big book
which has nice pictures
While nobody have found a way to visualise the linear map itself because it is too high dimensional, what the linear map does to the space in terms of blocks can be easily understood by its block diagonal and off block diagonal elements
but probably not great for getting a grounding in it
04:00
and I really learn of this view from chemistry, when computing overlap integrals
@WDUK In that case, it is probably safe to assume that the argument of the logarithm is positive
unless you have an initial condition that tells you otherwise
@Semiclassical I'm also looking at some CFT books for this
but in that context, the constant of integration relates to an initial value
good luck tbh
@Semiclassical her english is terrible so I'm really just guessing what she wants me to do
04:02
Given a linear map $\bigoplus_{i=1}^n U_i$ the off block diagonal components mixes the subspaces i=\=j
there's a big yellow book which is standard for CFT but it's tough going from what I've heard
she's like "you're a geometry expert, so you can tell us about these conformal transformations"
@Semiclassical Francescoooo
ah, you've heard of it
04:03
I've read part of it
I was into string theory back in the day
I think we can go even further, that the 1st upper and lower diagonal quantify nearest neighbour mapping and then in general the nth upper/lower diagonal quantify the nth nearest neighbour mapping
my knowledge of CFT is pretty much limited to "according to these papers, the leading term of the corrections to a certain computation one can do is dictated by the central charge"
@Semiclassical CFT/ST/QFT is full of mystery calculations
it's black magic
@Semiclassical the mathematical equivalent is probably algebraic topology
there's just these strange formulas for things
04:08
the math/physics I'd like to know better is known as resurgence theory
we had a guy here just today/yesterday for that (who actually recognized my name from some previous stuff, which was neat)
he was here as a candidate for a faculty position. no idea if he'll get it
what on earth is resurgence theory
bloody weird
not going to try to explain it in detail, but a lot of QM/QFT physics stuff is basically all to do with asymptotic series
ah, asymptotic series
usually, you just do perturbation theory calculations and accept that you're not going to do better than that
and that's not a bad attitude to have, since if it's an asymptotic series you don't expect to be able to resum the series in order to get an infinitely precise answer; asymptotic series don't converge
asymptotic series are definitely strange
04:13
(For those who are interested, head to Rambles to hear about my ramblings about linear maps. The current conversation is too interesting to risk flooding it)
ugh there are too many things I want to learn
@Semiclassical so I've got 1 hour to go from 0 to linear stability of perfect stars in full GR
presentation in fluids 2
it's gonna be a disaster
resurgence theory is basically a whole bunch of stuff geared at overcoming that barrier in asymptotic series and getting stuff which works despite that
@Semiclassical I definitely want to learn some more physics this summer
which basically amounts to analytic continuation out the wazoo
twistors or asymptotic series both seem worthy
04:16
taught me twistors and resurgence theory when you guys are ready, my wavefunction is already too delocalised to squeeze time from my chemistry to learn more stuff :P
lol
the person who was speaking was (as I'd understand it) trying to point towards the possibility of using resurgence theory to understand the mass gap in QCD
@0celo7 a lot of this is linked with semiclassical approximation stuff, so you can see why I'd be interested
are transversals useful in rudimentary group theory
@Semiclassical Do you have any pubs? I don't actually know what you do
a few, actually
but they're a bit hodgepodge
i like to joke that my thesis is going to be more like an anthology of short stories than a novel for that reason
what's the physics version of mathscinet
inspire?
god, searching you there just gives me ATLAS papers
04:22
i guess? i mostly rely on arxiv
@Semiclassical you have a CFT paper :P
central charges
yeah
though from my pov that one came down to finding the spectrum of an n-by-n matrix for large n
@Semiclassicalq this Riemann surfaces paper has an insane title.
@Semiclassical I think that's what K theory is?
04:27
it's definitely related
better hope Mathein doesn't show up
algebraic K theory is def just linear algebra 1
@Semiclassical what the heck is nonhermitian QM
non-self adjoint operators
I figured that, but what does that mean physically
@MatheinBoulomenos
it means you're not actually doing quantum mechanics :P
in the context of our problem, it showed up because $e^{i n x}$ had an interpretation of a creation operator for a +n ion. so if you had a gas with +1 and -1 charges then it'd be just e^ix+e^-ix
04:30
Hmm, I think I am gonna delete my account soon, this time just after a few days, lol.
again?
@Gasparo do you have some condition that forces you to do that
@0celo7 It's not related to my OCD. I'm just weird.
but when you want to have +2 and -1 charges then you're forced to have something genuinely complex
@Secret I hope you will find peace in your heart soon, since you seem very troubled.
04:31
so it's reflecting a certain charge balance condition in the system
@Semiclassical What does many-body theory in the context of advanced quantum mechanics study? I heard about it only recently...
ultimately it ends up not being a big deal, since the potential is symmetric enough that all eigenvalues end up being either real or coming in complex conjugate pairs
but you can also play around for fun with examples that don't even have that
@Gasparo lmao
and what's weird is that the semiclassical approximation still works pretty well
@Gasparo at a certain level, it's just what it sounds like: a system composed of many particles and their interactions
@Semiclassical Do you know about WKB approximation methods?
04:33
yeah. that's what the semiclassical approximation more or less is
though I was always much more happy to work with the formulas derived from WKB vs. deriving stuff myself from it
WKB is a pain to work with
Currently, I am deciding between buying Feynman's Lectures On Physics 1,2,3 and Nolting's Theoretical Physics 1,2,3,4,5,6,7,8,9.
uh, feymann's lectures are online, so you don't need to buy them
@Secret I use only physical books for serious reading.
That's true, but isn't the online version of the feymann lecture webpage always the most up to date?
i don't know Nolting, but Feynman is a good one
04:37
I really want to mention the Nolting books. Like I said, the last two volumes are still being translated from German into English. They are really excellent and come with exercises and full solutions for every volume. It is a masterpiece. Nolting is a good man for writing them.
@Secret The latest print version is as up to date as it can get. Hundreds of errata have been fixed. Currently the latest is the so called New Millennium Edition published by Basic Books.
Hmm I see
However, note that the nine volumes of Nolting obviously cost a bomb.
tradeoffs, yeah
I don't think I just justify reading Feynman when I could learn about nonconvolution singular integral operators instead
i.e. I think basic physics might kill me
lol
@0celo7 Figure out Riemann-Hilbert problems and then explain it to me
04:41
@Semiclassical you sound like Balarka
(they're related to singular integral equations iirc)
There are many good calculus texts, that is, not those two hundred dollar colourful ones, on the market. But for basic physics, hmm, hard to find the equivalent.
I don't need a calculus book either
Of course, my favourite calculus books are Calculus And Linear Algebra 1,2 by Kaplan and Lewis. The best for me.
04:42
@Semiclassical Do you mean nonlocal PDE?
Again, that pair of books is unheard of these days. Michigan students might know about it though.
actually, that link isn't great. i shouldn't have jumped to it
why did you send that to @ÍgjøgnumMeg
...i have no idea
@ÍgjøgnumMeg get busy!
04:45
if i do @ on its own, without typing anything further, then his is the only one that shows up momentarily
so probably what's happening is that i'm trying to do "@0" and tab to finish it, but I do it too fast
it's weird that I do that, though. i don't quite get it
I send the messages to the wrong people all the time
@0celo7 well, what I have in mind is stuff like this (which is from a random abstract)
@0celo7 It's more important not to send the wrong message to the right person.
"The Cauchy singular integral operator, S, is one of the main actors in the theory of Fourier convolutions, Toeplitz operators, Riemann-Hilbert problems, Wiener-Hopf and singular integral equations."
the PV operator?
04:49
it's related, I think. not sure it's identical
@0celo7 it's the article which starts here (Google books link) books.google.com/…
Hello. I've a suggestion to put out there, to the users of Math SE. I think it's a great idea to create a WhatsApp group for Math SE discussion, working together on problems, sharing ideas and contributing to the growth of the community. It'll be a much more convenient and efficient way for the best minds to stay connected. What say?
That's why we create other rooms :-)
I think you should start by getting a list of people who would be interested and see if there's a critical mass there. I'm not especially interested myself, but others may be.
@Semiclassical that's actually in the book I would read if I had so much time I could :P
lol
that's not an article I plan on reading myself, tbh
way too much stuff that's over my head
04:55
the ending sound in Sylow is like fan or van
@Semiclassical The amount of Fourier analysis in hyperbolic PDE is shocking.
singular integral operators are fourier analysis
Sy-low
@skullpatrol The fact that chat rooms can't be accessed via the app is a bit inconvenient. Any suggestions on how I may spread the idea?
soo-lof? syuh-lov?
Ask on meta?
04:58
Also, I request you all to have a look at this question-
0
Q: Binomial coefficient: Search for multiples of 13

schrodinger_16Question: The coefficients of how many terms in the expansion of (1+x)2018 are multiples of 13? So, we've to investigate the powers of 13 in ${2018 \choose r}$, where 0 ≤ r ≤ 2018 I tried using the following: $$s_p(N!) = \left \lfloor \frac{N}{p} \right \rfloor + \left \lfloor \frac{N}{p^2} \ri...

cannot norsk
Any ideas?
You're right @schrodinger_16 I don't use the mobile app for that reason, instead I use the full site option.
Basically, $(1+x)^{2018}$ with coefficients mod 13
@Semiclassical my advisor wants me to give a talk in the junior colloquium (undergrad seminar)
why am I giving so many talks
this is absurd
05:04
because he thinks you like to talk?
like an old woman :P
@schrodinger_16 fwiw, mathematica agrees with 1395
Yes, 1395 is right. I tried a Python code that gave the same result. @Semiclassical How do I calculate it with hand? Without using advanced computational tools like Wolfram, Mathematica and stuff?
Count[CoefficientList[(1+x)^2018,x],u_/;Divisible[u,13]]
LOL
Did you understand my question?
I wish to calculate it without advanced computational tools.
I was including it for reference.
05:09
Ooh, thanks for that
05:36
anyone here use maxima
06:07
@0celo7 hi
want to discuss something related to frames ?
@Secret finally got it.
@TedShifrin cowardice lies you know tons of interesting things.

« first day (2758 days earlier)      last day (2558 days later) »