@Semiclassical First we find the acceleration of the bullet by using the relevant equation: $v_f=v_i+a(t)$\\
$0=350+a(7.43\times10^{-4})$\\
$a=\frac{-350}{7.43\times10^{-4}}$\\
$a=-471153.85$\\

The negation is due to our convention that up and right are positive, it is accelerating $471153.85 m/s^2$ to the left.\\

Using N3L, we know that any force has an equal and opposite force. This means that the bullet will exert a negative force on the tree (due to our conventions) and the tree will exert a positive force on the bullet (again, due to our conventions.)\\

Let $|G| = p_1^{k_1} p_2^{k_2} \cdots p_n^{k_n}$ with $n>1$.

Let $P$ be a Sylow $p_1$-subgroup of $G$. It is a proper subgroup of $G$. Then, we can enlarge the group to form a maximal subgroup containing $P$. Its order divides the order of $G$ by Lagrange. However, its order is not equal to $|G|$, since it is a proper subgroup of $G$. Hence, there is a prime power $p_i^{k_i}$ with $i \ne 1$ that does not divide $|P|$. By Sylow theory, we can construct a proper Sylow $p_i$-subgroup of $G$ and expand it to another maximal subgroup, creating another maximal subgroup.