Mathematics - 2012-03-19 (page 2 of 4)

N3buchadnezzar

13:02

heya

hey ho

@KannappanSampath See here for something nice

Kannappan Sampath

@N3buchadnezzar I just saw that integral question. As it happens, it has been long pending at AMM!

N3buchadnezzar

AMM ?

Kannappan Sampath

American Math Monthly...

N3buchadnezzar

Oh

It have been long pending at two three other sites as well

Matt N.

Now someone ask a question I'd like to answer, please.

N3buchadnezzar

13:07

Would you like a beer?

Matt N.

No thanks. That would make me go to sleep, I'm already tired because I had to get up at 8 this morning.

I meant on SE, actually.

Kannappan Sampath

@Matt Have you come across the exercise about ideals maximal with respect to empty intersection with a multiplicatively closed subset? : )

Matt N.

@JM Ah, that's cool. Didn't see that before. Looking forward : )

@KannappanSampath No. I can't look at it today, I had an overdose yesterday.

Kannappan Sampath

@MattN Well, I'll tell you later. I just solved it. It is quite interesting!

N3buchadnezzar

@KannappanSampath Are these things you learn in school, or are you a self learner? I have wondered about this you see =)

Kannappan Sampath

13:13

@N3buchadnezzar Which one do you mean? About commutative Algebra?

N3buchadnezzar

Yes¨,and in generall

You seem to learn some quite advanced things for your age!

Kannappan Sampath

I learn about Commutative Algebra on my own--of course, this means everyone here at SE helps me a lot. And other wise, I just do course work!

N3buchadnezzar

@KannappanSampath !

Kannappan Sampath

@N3buchadnezzar I am not sure I do advanced things. I think I am doing pretty elementary stuff!

N3buchadnezzar

Same =)

Kannappan Sampath

13:16

@5T0M You preparing for JEE? Or you are in some IIT now?

BTW, welcome here.

5T0M

I am preparing , Sir.

Thanks :-)

N3buchadnezzar

@KannappanSampath ntnu.edu/studies/courses/TMA4145

Kannappan Sampath

I think Matt is angry with me today. </3

N3buchadnezzar

One of the courses I am taking next year, it sort of makes me afraid.

5T0M

Are you in some IIT @KannappanSampath

Kannappan Sampath

13:18

@5T0M Nah! My profile pretty much has it! : )

@N3buchadnezzar I am frightened too. I have no idea what some of them mean?!

N3buchadnezzar

Same!

Jonas Teuwen

@JM :)))).

5T0M

Oh you are even younger than me, I thought you were a professor or something.

@KannappanSampath

ypercube

@KannappanSampath: You mean my answer at SO ?

Kannappan Sampath

@5T0M I am running out of smilies to respond to this remark! How would I be a professor and ask a question on silly induction! : (

@ypercube Yes! :-)

Did you also read what followed that without an explicit ping?

Matt N.

13:23

@JM So you don't read every single bit of the transcript anymore, is that right?

J. M.

@JonasTeuwen Heh. Sorry I can't give your Bessel stuff time today; maybe when I'm regular again.

5T0M

@KannappanSampath , I came to that conclusion by seeing the quality of answers,, and frequent mention of your name at many places on this site, nice

J. M.

@MattN I don't think I can now; you guys are too damn mouthy. :P :D

Matt N.

: )

Kannappan Sampath

@5T0M I don't quite understand about the frequent mention of my name whatever But oh well .... You were mistaken!

@Matt Are you angry with me?

Matt N.

13:26

@KannappanSampath What? Why would I be angry with you?

What makes you think that?

Kannappan Sampath

@MattN You did not respond well to my mentioning that exercise, while you usually respond quite well to these things. So,...

t.b.

@JM will you still be here in about an hour?

Matt N.

@KannappanSampath Oh, I'm just tired. I'm sorry.

t.b.

Nice take on the Weierstrass $\wp$, by the way!

J. M.

@tb I think so, yes. Why?

user1123950

13:28

hi guys

5T0M

hi user112395

Kannappan Sampath

hi

t.b.

@JM I'm sleepy. Siesta time. Nothing too important, just wouldn't want to wake up and see you're already gone.

user1123950

anyone know combinatorics?

J. M.

@tb Well then, enjoy your break. :)

t.b.

13:30

I will. See you later!

J. M.

@user1123950 Just ask, and we can judge if it's simple enough for chat, or should be moved to main.

5T0M

who doesnt, :)

Matt N.

@tb Sleep well!

t.b.

@JM Oh, I forgot: Here's a piece of "meta" you might find interesting.

5T0M

@KannappanSampath I had a question, where do students get placed from ISI, what all companies come to recruit there?

t.b.

13:32

@MattN thank you. I came back to give J. M. the link above, so no worries about the ping :)

user1123950

i am trying to create sets of nontransitive dice

Matt N.

I realised : )

t.b.

teddy bear out.

Matt N.

: )

user1123950

counting possible sets more specifically

Kannappan Sampath

13:33

@5T0M None at all. Because, most students come here with interests in research, especially, in pure Math. So, you see, no recruitments usually are organized!

user1123950

for instance A=[1,4,4,4,4,4], B=[2,2,2,5,5,5], C=[3,3,3,3,3,6]; B beats A on average, C beats B on average, A beats C on average

J. M.

@tb *facepalm*

5T0M

@KannappanSampath, So you study pure maths,hmmmmmm, How is it, am sure it must be very hard, Who should join this branch? Someone genius in maths, or anyone with interest in maths and willing to work hard? I asked this because I am looking forward to join mathematics and computing at some IIT, if i dont get CS there,

N3buchadnezzar

@5T0M Study what you want, just b sure you know what jobs you can get afterwards.

Kannappan Sampath

@5T0M You could read the brochure of the program instead of my telling you. I always try to persuade people to do Math...:)

N3buchadnezzar

13:41

@KannappanSampath How many courses do you have each semesteR?

Kannappan Sampath

5. That's all...

5T0M

hmmmmm,

N3buchadnezzar

We normally have 4

I am taking 5...

5T0M

@N3buchadnezzar where do you study?

N3buchadnezzar

AT SCHOOL

5T0M

13:46

at ISI or elsewhere

N3buchadnezzar

University, NTNU

Kannappan Sampath

Hi @Dan

Dan M. Katz

Hey =) How goes it?

Kannappan Sampath

In a long time, you have not been here? Have you?

Dan M. Katz

I come by every now and then.

Two Cents

13:55

hi

Kannappan Sampath

@DanMKatz I see! :)

user1123950

anyone know?

Dan M. Katz

Currently reading the Wiki page about generalizations of the derivative. =P

Two Cents

i have more than 50 points, but I can't add bounties to questions. why?

J. M.

@TwoCents Which question(s)?

@DanMKatz Well, differintegrals should keep you busy at the very least... :)

Two Cents

14:00

@JM For example this old question math.stackexchange.com/q/35664/18516

(but eventually i'd like to bounty my own question)

(but i can't since my question is rather new)

Kannappan Sampath

What the...? Is the site down?

Daniil

Hi

@KannappanSampath not working here

Kannappan Sampath

@Daniil Hi!

@Daniil Thanks for confirming that.

.......

The site's back!

user1123950

14:20

@Kannappan do you know anything about intransitive dice

Kannappan Sampath

@user1123950 I am sorry! I have no idea what they are.

user1123950

dice where B>A, C>B, A>C

i know how to tell if one die is better than another but it involves conditional probability

i dont know how to count large numbers of possible sets

since it's a constraint across all three dice

making a cycle

J. M.

@TwoCents I can't see why you can't; it's a rather old question. Ask meta perhaps?

ypercube

@user1123950: What exactly is your question?

user1123950

counting possible sets

for instance A=[1,4,4,4,4,4], B=[2,2,2,5,5,5], C=[3,3,3,3,3,6] is just one of many valid sets for N=6 (maximum value of 6 for a given side)

(A,B,C) isomorphic to (B, C, A) or (C, A, B) etc -- all the same set

likewise with the ordering of faces

ypercube

14:25

So you want to count all possible combinations of transitive sets?

user1123950

yes

the problem is that i don't know how to count them without resorting to some sort of brute force

because i can calculate if B>A but only by looking at conditional probabilities

for instance B beats A because 1/2*1/6 + 1/2 (1/2 chance of rolling a 2 which only wins 1/6th of the time, 1/2 chance of rolling a 5 which beats everything in A)

trying to figure out some sort of mathematical pattern or constraint

or method for counting possible sets

ypercube

Start with less sides first (and smaller numbers (up to 2, not up to 6)

then 3, etc

user1123950

i'm trying 3 now

ypercube

and see if you can come up with a formula

user1123950

running a program for it but taking forever

N=2 didn't show anything useful

since there are only two numbers to a face

no valid sets returned with N=2 anyway

not even sure that N=3 is possible

obviously N=6 is

t.b.

14:48

@TwoCents I voted a question of yours up, so you should now be able to set a bounty. You need 75 points to set bounties, you only had 72.

@JM indeed.

user1123950

anyone know?

J. M.

15:04

I'm not sure that measure-theory is the best tag for this...

t.b.

@JM seen this?

:)

J. M.

As you can see I haven't been back-reading chat... :D

t.b.

Obviously...

I assume it's gonna be quite a while until we meet again here. I'm making a coffee and then I should head out... I'll only be back after you (usually) go to sleep.

J. M.

In which case: I'll see you at a hopefully better time... :)

t.b.

I was just about to write that...

Matt N.

15:14

I'll miss you.

J. M.

@t.b.: it's like we're siblings... :D

Nimza

Good <time of day>!)

user1123950

hi

Matt N.

But I guess that's "obvious" so no need to say it...

t.b.

@MattN it's not like I'll be gone for good. I'll just not spend hours and hours here anymore because this room is simply distracting me too much from what I really should do now.

Matt N.

15:19

It is. And same here.

Nimza

Do you know how to estimate in 2d a function's support given a set of it's line integrals?

I mean, is there some exact formula...

Matt N.

@tb Are you going to say good night before you go to bed later or is it good bye for today?

t.b.

@JM Yeah, lil' bro :) Okay, I wish you all the best and have a good comeback in a few weeks! I was happy to see you.

@MattN I'll be back at around ten.

Matt N.

Nice : )

@JM Are you still here?

Ah, never mind. : )

J. M.

@MattN Yes, why?

Matt N.

15:30

@JM Actually, I was going to ask you something then change my mind. But by now I have a new question:

J. M.

BTW: did you manage to finish Pushing Daisies?

Matt N.

Yep : )

It was good.

@JM Could you have a look at this: math.stackexchange.com/questions/116151/… (the comments below the answer)

J. M.

@MattN Good to hear. Still think it was gone too soon, though.

Matt N.

@JM Yes. Although the girl annoyed me.

J. M.

She's a bit cloying, yes...

Matt N.

15:35

So how do I see that a slice is measurable?

J. M.

@MattN Oh dear; I'm not with my books, and I'm hazy with measures now. I'll get back to you on that when I'm regular again...

Matt N.

No problem. Thanks! : )

It's probably a "stupid" question, for some reason he decided to ignore me. Maybe I can work it out on my own if I have another go at it.

Gigili

@MattN I don't think you're the only one he ignores. I once asked a question and he didn't reply. He probably thinks he's done by clicking "post your answer" or you must be the OP to ask questions for further clarification or whatnot.

Rajesh D

Hi folks

Matt N.

@Gigili Well he did reply to my first question. So maybe he got fed up with me. But I remember that I actually thought about it carefully before asking.

Rajesh D

15:41

Hey @Matt Wazzup dude ?

Matt N.

Nothing much bro', yourself?

Gigili

@MattN Or everyone is allowed to ask one question only and you must pay for more questions. I recall that happened to me once anyway.

Rajesh D

same....logged in just before going to bed

Matt N.

@Gigili Oh, I see.

Jonas Teuwen

@JM No problem!

Kannappan Sampath

16:08

Close Votes needed

N3buchadnezzar

How is it going?

Kannappan Sampath

Going well!

N3buchadnezzar

Kannappan Sampath

What is that?

N3buchadnezzar

Its a well.

Kannappan Sampath

16:18

I see... I guessed but still..

N3buchadnezzar

You said Going well!

Kannappan Sampath

Hmph... : (

N3buchadnezzar

Sorry...

mathematica.gr/forum/viewtopic.php?f=9&t=7842&start=180

Does that page work for you?

anon

nope

Kannappan Sampath

The heck!

N3buchadnezzar

16:22

=/

k

Kannappan Sampath

I killed that ever growing page!

anon

unless the page is supposed to write the same error line over and over again

Kannappan Sampath

@anon Did you vote to close that question I put out here?

J. M.

@anon: snazzy new avatar...

anon

@Kanna: I'll check it out. @J.M. Thanks.

Kannappan Sampath

16:39

Martin is active. How I wish, he drops into chat for sometime! I wish everything is fine with him.

N3buchadnezzar

I think I might have asked this before

but can the following equality be explained geometrically?

$$ \int_0^a f(x) \, \mathrm{d}x = \int_0^a f(x) \, \mathrm{d}x $$

Kannappan Sampath

Huh?

That is a tautology!

anon

copy/paste problems?

N3buchadnezzar

Blushes

I actually type all latex by hand...

J. M.

@KannappanSampath Yes, not very difficult to prove. No need for geometry even...

anon

16:46

Use the substitution y=x. Then use the substitution x=y.

Kannappan Sampath

:-) to both the preceding messages!

N3buchadnezzar

@anon I know how to prove it using algebra, I wanted to show it by geometry. And I think I have =)

f(a-x) is just a reflection so it morrors f around a/2

Kannappan Sampath

@ymar Have you come across this exercise about multiplicatively closed sets, and prime ideals?

anon

@N3bu: So is the actual equation what you posted but with the second integrand f(a-x)?

N3buchadnezzar

@anon Did I not write that?

anon

16:52

Can you not see what you wrote?

N3buchadnezzar

I see, I obtained some error. I edited it, and it gave me a timeout warning.

$$ \int_0^a f(x) \, \mathrm{d}x = \int_0^a f(a-x) \, \mathrm{d}x $$

"ofcourse"

anon

Yes your explanation works.

Kannappan Sampath

@ymar Here. No. Are. you. here. ?

J. M.

Yes, if you need further convincing, you can try shifting things so that the middle of the integration interval is zero.

Kannappan Sampath

@SidharthIyer Hi!

N3buchadnezzar

16:56

It is time for another silly question. If I have some integral $I$ and i use some substitutions on I such that I obtain $-I$. What can i then say about I?

I know that then $I=0$, but can you say anything else about I ?

anon

Aren't substitutions supposed to preserve the value of integrals?

Oh, okay.

J. M.

@N3buchadnezzar That's really the only thing you could say...

There isn't really any other number that's equal to its negative...

N3buchadnezzar

@JM Yeah, I am a bit bad with words.

I am just trying to visualize what substitutions actually do with functions, how they change.

J. M.

@anon I think that's supposed to be the thought right before saying "Eureka!"... ;)

Kannappan Sampath

I have a reference request to make: Can someone help me get this paper (I know it is in German, but would like to give a try.) Idealtheorie in Ringen ohne Endlichkeitsbedingung?

anon

17:01

@Kanna: Try here.

Hmm. Can we define integration in fields of positive characteristic?

Kannappan Sampath

@anon Ah... Thank You, so much. : )

anon

@Kanna: BTW, I've downloaded just over 1/6th of that FTP now. :)

(Unfortunately, concurrent downloads seem to be throttled...)

Kannappan Sampath

@anon Oh, I see. :-) I have not yet started! I need to buy myself a hard disk.

N3buchadnezzar

Oh I see

Substitutions presserve the value of integrals.

anon

mathoverflow.net/questions/71664/…

N3buchadnezzar

17:06

So if I have -I = I, and add these. They cancel each other out, sort of.

Kannappan Sampath

@anon I cannot make it a .pdf! Have any idea there?

anon

Painstakingly save each page as an image? How long is the article?

The hard way would be easier than learning how to e.g. wget something like that.

Kannappan Sampath

Let me try! 6 pages!

Jonas Teuwen

What do you want to do, @KannappanSampath?

Kannappan Sampath

@JonasTeuwen Thank you for asking me. I would like to save the image files here as .pdf.

Jonas Teuwen

17:12

Doesn't load.

ymar

Hi, Kannappan, I wasn't here. :)

anon

@Jonas: See my link: digizeitschriften.de/…

It can't be more than 14 pages, I think. Download the pages as pics and put them together as a pdf/djvu using some 3rd party program.

Jonas Teuwen

Huh, I can just click the pdf-button and get a pdf.

ymar

@KannappanSampath Do you mean $P$ is prime iff $R\setminus P$ is multiplicatively closed?

Kannappan Sampath

@JonasTeuwen Try saving that... Does it save as .pdf?

@ymar No, that's almost trivial! :-P

ymar

17:14

Yes, it is. So what exercise?

J. M.

Wait... they're supposed to have PDF versions...

anon

lol, derp

Kannappan Sampath

The ideal maximal with respect to empty intersection with a multiplicatively closed set is prime...

@ymar The above exercise. ^

J. M.

Otherwise... Digizeitschriften is supposed to be a (limited) mirror of the Gottingen library; did you guys check if they have that article as well?

Jonas Teuwen

No. But I will fix that!

ymar

17:17

@KannappanSampath I did see that, about a year ago in a seminar. What about it?

Kannappan Sampath

@ymar I just wanted to mention it to you because it is interesting. No?

@JonasTeuwen What do you mean?

Jonas Teuwen

To obtain the pdf.

Kannappan Sampath

@JonasTeuwen Oh, you mean, talk to the file and ask it to heal well, so that we could open it as a .pdf?

ymar

@KannappanSampath Yes. I remember it had some nice corollaries. If you want, I'll try to prepare myself and we can talk about it later.

Kannappan Sampath

@ymar I'd be happy to know more results of this kind and its corollaries of course... :-)

ymar

17:23

@KannappanSampath OK, so I'll be back later. :)

anon

@Kanna: open the pdf in chrome browser, Ctrl+P, set destination to "Print to PDF"

Kannappan Sampath

@anon Hey Works buddy! I am not geeky. : (

@ymar See you...

J. M.

And if that still doesn't work try gdz.sub.uni-goettingen.de/dms/load/img/…

Kannappan Sampath

@anon Thank You so much... Panic...Over.

anon

It works, I got it on my desktop.

J. M.

17:26

Okay. Sometime GDZ is flaky when Digizeit isn't and vice-versa...

robjohn

@JM hey there!!

J. M.

Hey rob!

Kannappan Sampath

@JM Thank you. That's quickie too. Thank you so much. : )

robjohn

@JM: I was working on this problem and saw your comment

Kannappan Sampath

@anon thank you too...

J. M.

17:27

Unfortunately I'm leaving in a few minutes. I might be regular again in two or so weeks, though.

anon

no prob

J. M.

@robjohn I must confess I hadn't realized that Chu-Vandermonde would be a much simpler route... :D

robjohn

@JM I hope to see you. Did you see my Mma animation?

J. M.

@robjohn Ah, I have. Nice work with envelopes!

(It's also valuable in showing that the hyperboloid of one sheet is indeed a doubly-ruled surface)

robjohn

@JM Thanks! I hadn't seen you around since I did that. I had help from some people on the Mathematica site for that :-)

Skullpatrol

17:30

@rob could i see please

robjohn

@Skullpatrol math.stackexchange.com/a/115797

Skullpatrol

@robjohn Thanks.

robjohn

@Skullpatrol thanks for the vote :-)

J. M.

Unfortunately, my time's up for today. See you guys in a few weeks...

Gigili

@JM Have fun.

Skullpatrol

17:39

@robjohn When I told t.b. that the asker of this question doesn't understand Relativity; he scoffed "What does it have to do with Relativity?" What do you think Sir?

Matt N.

@JM See you soon! And nice to see you!

robjohn

@JM be strange, but don't be a stranger!

4

Kannappan Sampath

@JM See You... Have a good time...:-)

J. M.

Not really fun, but I'll make the most out of things. Thanks for keeping me in your thoughts.

robjohn

@JM There is always a torus in my thoughts for you ;-)

Kannappan Sampath

17:43

Can someone tell me if Satz 1 means Remark 1?

robjohn

@KannappanSampath close enough

Kannappan Sampath

I translated a Lemma using Google Translate. See what it says: "For each element or a non-prime ideal is divisible by at least a lowest prime ideal of a"

Matt N.

@JM You got 12 stars...

Kannappan Sampath

Here's the original: "Jedes Zu a nichtprime element oder ideal ist durch mindestens ein niederstes Primideal von a teilbar"

@Matt Can you help me with the above translation, please? (I know nichtprime means non-prime, Jedes Zu-For each...)

Matt N.

It says "Every element or ideal that is not prime to $a$ is divisible by at least one lowest prime ideal of $a$."

@KannappanSampath It means Theorem 1.

Kannappan Sampath

17:49

Thank You!

Matt N.

Np : )

Skullpatrol

18:02

@MattN What do you think the asker of this question means?

ymar

@KannappanSampath I think I have two statements (one very simple) you might like.

Kannappan Sampath

@ymar Ah, let's shift over to CA then. : )

ymar

OK.

Skullpatrol

@ymar Is that the very simple one ;-)

That's suppose to be a joke ;-) = joke.

Matt N.

18:30

@Skullpatrol It sounds as if he's asking whether attempts have been made to define a unit with which you can measure length absolutely.

Skullpatrol

18:52

@MattN Thanks

Asaf Karagila

@JM Oh boy! Look at you... all grown up.

N3buchadnezzar

sup?

Gigili

19:11

Remove another message and I'll remove you ;)

I missed your message BTW.

Skullpatrol

@Gigili How's life?

anon

It was "btw how are you" or something like that.

Daniil

@anon got a new userpic, nice :]

Skullpatrol

I just found out people are talking to their iphone "person" called Siri ...

Gigili

@Skullpatrol Yes, it's really cool

Skullpatrol

19:16

Siri (software)

Siri (Speech Interpretation and Recognition Interface) () is an intelligent personal assistant and knowledge navigator which works as an application for Apple's iOS. The application uses a natural language user interface to answer questions, make recommendations, and perform actions by delegating requests to a set of web services. Apple claims that the software adapts to the user's individual preferences over time and personalizes results, and performing tasks such as finding recommendations for nearby restaurants, or getting directions. Siri was originally introduced as an iOS appli...

@Gigili It reminds me of "Hal 9000" the computer in "2001 a space odyssey"

HAL 9000

HAL 9000 is a character in Arthur C. Clarke's science fiction Space Odyssey saga. The primary antagonist in ', HAL (Heuristically programmed ALgorithmic computer) is an artificial intelligence that interacts with the astronaut crew of the Discovery One spacecraft. Being a computer, HAL has no distinct physical form, though is visually represented as a red television-camera eye located on equipment panels throughout the ship. HAL is voiced by Douglas Rain in the two film adaptations of the Space Odyssey saga, and speaks in a soft, calm voice and a conversational manner, in contrast to the ...

Jonas Teuwen

Could you stop spamming trivialities? Thanks.

6

Matt N.

Hello Jonas. : )

Skullpatrol

@JonasTeuwen I assume you would you call "green hair" a non-triviality?

Jonas Teuwen

Yes.

@MattN Hi.

Skullpatrol

@JonasTeuwen I guess it depends on the context.

robjohn

19:30

I've capped for the day, but I wonder why someone downvoted this answer

Skullpatrol

@robjohn Where is the down vote?

anon

After a certain rep count you can see the upvotes and downvotes individually on each question and answer.

Skullpatrol

Was it +2 at one time?

anon

robjohn

@Skullpatrol no, but one of the +10's was capped to be +2

It's not about the points, I just want to know what they found objectionable. It is essentially a state machine, and everything looks right to me.

Kannappan Sampath

19:38

@robjohn You know some guys go mad here! They vote crazy. We cannot predict!

There is likely to be no reason other than they felt like it! obnoxious

robjohn

@KannappanSampath I know, but I thought that on the off chance this was a sane person, I would like to know what they thought was wrong :-)

Skullpatrol

@anon Thanks for the screen shot.

Kannappan Sampath

@robjohn Hmm. We cannot entirely waive that either!

robjohn

@KannappanSampath :-)

Skullpatrol

@robjohn Did you get a chance to look at this question to try and figure out what he is asking for?

@Gigili Hi, how's life?

robjohn

19:46

@Skullpatrol It seems that the OP has accepted the first answer, which seems to answer the question as I interpreted it.

Skullpatrol

@robjohn There seems to be some confusion about what is Physics and what is Mathematics.

robjohn

@Skullpatrol That could be. There are some physicists and mathematicians that have some uncertainty in this area as well.

Skullpatrol

@robjohn Indeed at the more advanced levels there is uncertainty.

Matt N.

Cheers!

Skullpatrol

Bottoms up!

@MattN Your're not drinking "alone" (internet excluded) are you?

Matt N.

19:55

@Skullpatrol My girlfriend isn't drinking at the moment. So yes, I'm drinking alone.

Skullpatrol

@MattN ;-)

Daniil

If I have a random variable $A$, which image is $\{-1,0,1,2\}$, and random variable $B$ then $E(B | A > 0) = E(B|A=1) + E(B|A=2)$?

Where $E$ is expected value.

Kannappan Sampath

Yes @Daniil You're right!

Transcript for

$Mathematics$ Mathematics