I really love that $$ \int \tan x \tan 2x \tan 3x \mathrm{d}x = \int \tan 3x - \tan 2x - \tan x \, \mathrm{d}x $$
@KannappanSampath Belief ? Eh, tricks are not really tricks after having seen them enough times. If I have a short introduction, explaining different methods. Like symmetry and f(x)=f(a-x) and so on, these problems should be solvable.
It is not like these problems are solved by introducing a new variable, then differenting twice, to obtain the answer either :p
@Skullpatrol When I first saw how to integrate $(x^2+1)/(x^4+1)$ I was a little depressed. They divided top and bottom by x^2 and factored the denominator into $(x+1/x)^2+2$ or something.
I felt that this was taken out of thin air, and way to specialized to be useful for anything else.
Later I found atleast 4/5 other integrals that could be solved by applying the same method ;)
@leo I am sorry I have to ask you this: We are planning to discuss topology with ample help from resident topologists here. So, would you be doing topology with us/ helping me do it?
Hi, all. I was wondering if someone could help me how to understand how to convert pi (or any irrational number) from the numerical base-10 to the alphabetical base-26? (like here: cadaeic.net/picode.htm)
Does there exist an enumeration of the rationals $\{r_n\}_{n=1}^\infty$, such that the complement of $$\bigcup_{n=1}^\infty\left( r_n-\frac{1}{n},r_n+\frac{1}{n} \right)$$ in $\mathbb{R}$ is non-empty?
@leo I like Robert Israel's deleted solution best:
> Let $\alpha$ be some irrational number that you want to be in that complement. For each positive integer $n$, consider the rational numbers $p/q$ (in lowest terms) with $|p/q - \alpha| > 1/n$, and choose one with $|p|+|q|$ smallest that has not already been chosen as $r_j$ for $j < n$.
> Somewhat more generally, you can get that complement to contain any set of irrationals with no rational accumulation point.
It was basically calculating the power sums $p_1$, $p_2$, $p_3$ and $p_4$
Sometimes it's hard dealing with things like that, especially when the degree you're enrolled in says you have to maintain an 80% average every semester
Hm. It is very hard for me to say anything sensible (I only know part of your side of the story)... But given that the lecturer will talk to the tutor, I wouldn't get too worked up about this right now.
@BenjaminLim Not really, no. There was one course where I wasn't interested enough to do the boring homework, so I didn't quite fulfill the requirements. So in order to be admitted to the exam, the prof wanted me to pass an extra exam. I told him that this was too stupid and chose another course.
Suppose $T=-\tan(\beta)\left(\tan(\alpha)-\tan(\beta)\right)^{-1}$ where each $\beta$, $\alpha$ and $d$ have some error in measurement, what is the err in T?
Well, the actual cleaning will be my job, of course, but he has to fix the things he destroyed... This is so silly. They had to deactivate a power plug because it was too close to the shower (there apparently is a law saying that it may not be closer than 90 cm, they measured and it was 85...). I told him that he could as well leave it because I'm going to re-install it as soon as he's gone. He didn't listen :/
Interesting. Is this law new? Sounds like we're turing into an English speaking country. There they assume people are too dim to handle dangerous things with care and sockets are banned from bathrooms completely.
@MattN No, they had an official check of all electrical installations and I don't know what else in the entire neighborhood. The socket is in a mirror cabinet, and it worked just fine for 20 years, but when he measured the distance, he measured the distance to the shower head...
That's what I'm saying. Anyway, he took the opportunity to smash up the lamp shades and one mirror of the cabinet, so he's got to come today and fix that...
@Skullpatrol Because I actually want to use it.
And I see no reason why I shouldn't except for this silly law that doesn't make any sense.
@Skullpatrol yeah, right. I want to use it now and it takes me 5 minutes to re-connect the thing, so I won't waste 5 weeks of my life for fighting against the windmills of the local administration.
@MattN maybe we should file a petition that as soon as there are people living closer than 50 meters to a church, the bells must be turned off. It's too dangerous to let all those people go crazy. We need to protect them...
@Skullpatrol Yes, thanks skullpatrol but I don't have enough patience. I really need to read the book. You see I've also had a brief look at video lectures but I just can't listen. I need a book : )
@KannappanSampath Minus 18 out of 20 total for the entire exam for making 1 mistake? What the...
Where did you learn linear algebra from? (You can assume I have had a first look at most of the concepts. Now I am interested in getting the connections and geometric ideas right.)
@MattN Did you know that youtube has a feature in it that if you move your mouse pointer over the "time line" of a video you will get small images of what happened there?
Yes, I think. But I haven't read the book, to be honest.
There is a narration of the book on youtube, but I don't like being read to.
@anon The video has lots of autobiographical info in it and appearances by famous scientists of today, you should check it out, when you get a chance, and let me know how it compares to the book ;-)
Well, I read the transcript and don't get some of the comments related to "For me as well". Let me clarify: Skull said it does not work on all videos. So, I asked for one where it works. Anon said, the feature worked for him and I said it worked for me as well.
@Skullpatrol That Hawking sells himself this way. He's neither an Einstein nor a Newton. And he doesn't tire of mentioning the fact that he has the Lucasian chair, etc... It's not like he's a bad scientist (as his almost namesake Dawkins is) but he's selling highly controversial interpretations as "the truth".
Is there a better way to show $p$ prime element, $p \mid x^n$ then $p \mid x$ than applying the definition: if $p \mid x^n$ then either $p \mid x$ or $p \mid x^{n-1}$ etc. until $p \mid x^2$?