well

there are 3n^2 squares

so it is "feasible"

suppose that it were possible to cover if n = 3q + r where 3 > r > 0

if r = 2

then 2 squares can be left at the end so that the bandaid can wrap around to another side

@AkivaWeinberger if n is not divisible by 3, then what is the remainder when n^2 is divisible by 3? I happen to know. :-)

@TheGreatDuck $1$, always

mhm

$0^2=0$, $1^2=1$, $2^2=4\equiv1$

(or, $2\equiv-1$ so $2^2\equiv(-1)^2=1$)

therefore, when $n$ is not divisible by 3, exactly 1 square on the final face must be shared by the other faces

What do you mean by "final face"

you fill up two faces

the last face will only miss one tile due to overlap

you can also easily force it to be the corner tile

refer to #6 for the final conclusion

Well, could be four or something

no

$1\equiv4$

but only 1 has to be from overlap

pretty sure that can be forced

I don't understand what you mean by overlap

fill up one face with band-aids that only sit on that face

OK

1 piece remains

So if it's a $4\times4\times4$ size cube

then I can cover everything but a corner

yes

then the next face will have two lost due to overlap

fill it all up

2 pieces remain

OK?

So you're saying you can cover it when $n=4$? Can you draw it?

no

hold on

the final face will lose one in a corner

I need you to draw this scenario, I'm having trouble visualizing what you're saying

do you have a tool i can use to draw it?

Also, this all fails for $n=5$, where it's impossible to cover the $5\times5$ face minutes one corner

of course

@TheGreatDuck Pen/paper plus camera? Or sketch pad on iPhone or Paint on computer I think

ugh no thanks

@AkivaWeinberger I think #6 can be extended to being true for whenever an edge piece is removed. That will in fact lead to the final conclusion in general.

Hi, have s simple question in algebra

as you can then claim that at least one of the faces will lose one piece due to overlap

@ManishKumarSingh fire at will.

Mn(D) is left semisimple of D is a division ring, agreed

*if

instead of 'of'

define Mn(D)

Matrix with elements from D

this is not a simple question of algebra

this sounds like ring theory

@TheGreatDuck Here's a picture

yes

do you know where should I ask such questions?

You can't finish the tiling, as you can check

I started on the bottom-left face

awesome drawing skills by the way

sounds more like a semisimple question in abstract algebra

and moved to the top face

yes are you intreseted

@ManishKumarSingh idk

(you may groan now)

nope.

Groan

:-)

@ManishKumarSingh [Main]

Mathematics

wow what

Mathematics

problem is my account wont accept new questions

[xkcd]

vov

Open a new account

Why wouldn't your account accept new questions

(yeah call me weird, xkcd comes to mind right after mathematics)

weirdo

possibly beacuse they dont find my question of high quality

@ManishKumarSingh It's because you have been caught posting homework.

which one

have you deleted any questions?

@ManishKumarSingh it looks like all of them are homework exercises.

@BalarkaSen xkcd

@TheGreatDuck None were downvoted or put on hold

yes every1 of them is because i am currently studying, so naturally i will always have doubts (sometimes silly)

@AkivaWeinberger moderators can vote to question ban at their own discretion

Manish: your questions are not great, but they're not worth locking the account.

@ManishKumarSingh you are currently question banned on math stack exchange. You will be unbanned upon investigation into whatever shady activities the moderators believe you are engaging in.

(I don't have 10k+ so I can't see what's been deleted, if anything)

@TheGreatDuck I looked at some of the questions, they look fine

also, stop ignoring answers when you receive them and accept them.

could some1 ask it from my behalf

@ManishKumarSingh I will not aid you in bypassing a question ban

and I will report anyone else who tries to do so

report me then

@ManishKumarSingh if you open a new account you risk being sitewide banned for evading a ban. Mods can check IP addresses

Hey everyone

@TheGreatDuck Where is this from

^

@AkivaWeinberger it's an assumed fact on any website. The website has the right to ban any user they decide to for any reason or no reason.

rehi @Daminark

Manish, can you please finish asking your question? $D$ is a division ring, and...?

Duck, I'm advising you as a friend to stop talking.

^

please

@EricStucky I'm just advising the user to not bypass a ban. I'm not saying the ban was reasonable. If anything, I'd encourage going above the mods heads if it really is in error.

Let him finish asking the question here :-)

(Did you mean "stop squawking"? That would have been really funny)

I'm not preventing him from asking in chat

ok so if Mn(D) is left semisimple with one component (basically left simple), the my assertion Mn(D) should be division ring because and Ra = R and hence I can find left inverse. But If you consider E11 (ie 1 at (1,1) and 0 everywhere matrix) it has got no inverse. So I now I am making a mistake but dont know where exactly

https://math.stackexchange.com/help/question-bans

i was merely saying that someone shouldn't make dupe accounts or ask other people to post on their behalf. :p

It says it's an automatic thing

few typos

I've heard people say it can also be non-automatic

Let the policy makers enforce their policies

It does say that deleting lots of posts can get you banned

^^^

ok so if Mn(D) is left semisimple with one component (basically left simple), the my assertion Mn(D) should be division ring because and hence Ra = R and hence I can find left inverse. But If you consider E11 (ie 1 at (1,1) and 0 everywhere matrix) it has got no inverse. So I know I am making a mistake but dont know where exactly

Is R=D, Manish? or is it something else?

Also, you should probably use Latex. see the link in the room desc

e.g. $M_n(D)$.

ok guys give me 5 minutes to post it properly and clearly

@user314159 fair enough. It's just that in my experience, trying to avoid a ban generally results in a worse one.

True dat pal

@user314159 well telling someone to make a duplicate account is exactly against that idea. XD

:O

people can see IPs

What about tor?

that's just absurd

–.^

wat

Eh, people do.

unless they're up to no good

Not most people, I imagine.

WAT

(or in IT)

More broadly: If someone -wants- to subvert the MSE dupe policies, they probably can if they put enough work in. But most people don't care that much.

@Semiclassical true but then they are probably in it to cause trouble

Well, yes.

well if someone is here to cause trouble, they're not going to complain about bans

they're going to make 5000 accounts using a bot and flood the entire network

True.

R = Mn(D) where D is a division ring then we know that R is left semi simple with one component (see weddernburn structure theorem). Now if I choose a random element 'r' in R, then the left ideal generated by it is whole of R. so I can say 'r' has a left inverse. But I know for example E_(1,1) ie 1 at (1,1) and 0 elsewhere is non invertible. So there is contradiction and hence some mistake in my reasoning, so can anyone point out it to me. (sorry couldn't find a way to use latex in chat)

let me know about some clarification

With regards to Tor, I have no idea to what extent people use it.

@Semiclassical I've always understood that Tor is primarily used by criminals and trolls.

(unless it is needed for technological purposes)

Or Chinese

The Tor project, naturally, gives a far more idealistic description of who uses Tor on their website.

@Semiclassical I'm currently working on an intricate plan involving five hundred and thirty two bots and three hundred and eighty nine users to execute mutual upvotes ("upboats") and get millions rep points in a week, thus breaking the SE server. Wanna help me with it?

@Semiclassical well of course

Libgen uses it

lol @ upboats

@Ezze or Russian

The truth is likely somewhere in between those two poles, but I think it's probably true that most of its use is for unscrupulous ends.

@Balarka sounds like a plan

Well libgen might be cathegorized as criminal...

@Semi but what if they're essential singularities?

@Daminark I assume you are joking, correct?

Of course

you've brought down a mod flag requesting an IP ban and a normal flag

No, he's serious. I am.

please clarify you're joking next time, no matter how obvious it is

This sounds like being asked if you've got a bomb in a airport.

It might seem funny, but uh

lol

Don't jokingly say yes.

It's just going to make trouble.

This is all my fault @Riker

Sorry

why?

...

nah.

@Semiclassical also don't say yes when they ask if you have goat in luggage because then they'll confiscate them ;_;

...what have I wandered into?

I brought it up @Riker

You may have been the one to nominally bring up the subject, but you're not the one who made the joke.

@user314159 ah ok

Fargle: just a casual conversation about semisimple division rings, can't you tell?

@Riker balarka sen is threatening to bring down the MSE server by coordinating a mass posting and rep manipulation.

yea

there's pretty much no way he can do that >_>

This is sort of funny.

he claims he is serious

Absolutely nothing regarding how we shall crush the serv... I mean, uh, crush this problem! /s

I'm just going to go ahead and say that this entire conversation is pretty dumb.

it's good man

it's helping my fever go down

There's no server that can't be DDOS'ed. It's just that the necessary capacity may be out of reach :P

That's true and also rather chilling @Steamy

@JannikPitt It should probably be clarified, but that's how I'd interpret it

there is no number that cannot be factorised either

namely, that the 0's are really column and row vectors of appropriate size.

Also @Riker were you joking about the flags or did they actually take this seriously?

@Riker if you look back, @user314159 tried to convince @ManishKumarSingh to create a second account to try and bypass a question ban. Then, @EricStucky offered to post the question for them to bypass the ban.

@Daminark nope, flags were there

still doesnt change the fact that encryption is safe

well, yeah, again: the lack of the necessary capacity

@Daminark I'm loling right now. :P

@EricStucky : I tried but couldn't understand where I am going wrong.

whoever is flagging, please stop

I think you're entirely overestimating the seriousness of the conversation, but

@Semiclassical Oh okay, thank you! The book I'm reading normally uses boldface for vectors. but it doesn't for the zeros.

no

I think that joking about policy manipulation is pretty stupid as well.

@EricStucky language

@TheGreatDuck not cool, but not flag worthy

On the "don't joke about bombs at an airport" principle.

let this be a lesson for all of you: it's a sunday afternoon (in america at least). people want to relax

^

some people are killing time and joking around

@Riker a guy came in complaining about a question ban and people were trying to tell them to ignore it...

¯\_(ツ)_/¯

"Yelling 'fire' in a crowded theater" comes to mind...

@Fargle severity levels are rather different

Instead, let's talk about [insert your favorite controversial political topic here]

@Fargle that's actually considered a threat.

Claiming to ddos Stack Exchange or something similar is not offensive, so please don't flag it. Actually doing it will result in some response by SE (and probably won't work anyway).

@Semi no no plz not politics

@Semiclassical what do you think of the president of antarctica /s

Lol jk

I'm aware, just talking about the principle.

@Riker I like that topic

@MadScientist they were trying to recruit people to help...

@Fargle that is a very symmetrical avatar

very nice

What's the point of announcing you're going to DDOS MSE anyway.

If it fails, you make a fool out of yourself

@TheGreatDuck you can laugh at that or ignore it, doesn't really matter

It it works, well, chat is gone too

@Riker I think he's a [very good guy / right bastard / nonentity ]

@Riker I think President penguin is mean he said sheep is better than goat :( :P

we should totally start political movementt

I mean, that's considered inciting chaos, when jokingly talking about DDOSing a server gives basically no reason to fear anything. People talking about it will have no influence on any later actions

I think every avatar has a $\Bbb Z/4$ symmetry, but some have reflections to?

@Riker I know, I really like it. Though I don't think it's necessarily more symmetrical than any other--every avatar has symmetry group $\Bbb Z/4\Bbb Z$, no?

@Riker Oh the president of Antarctica sucks

Please ban me @Riker and end this nonsense :-)

@Fargle I have no clue what that means

I am not good at that kind of math ._.

I'm just finishing precalc now >_>

@SteamyRoot well, i am getting to munch popcorns on this completely ridiculous discussion. that's a personal gain

@user314159 nah it's good ;p

@s.harp So... we determine what the possible avatar symmetry groups can be?

@Fargle plus I don't have mathjax atm ;p

All [hail / curse / ignore ] the [good people / incompetant fools ] in [insert political organization]

@BalarkaSen If I were a little more drunk I'd probably be the same, heh.

@Daminark to quote the scout

@Semi you have now absorbed all political statements into 1

Lel @Riker

That was fantastic

yes

@Riker wait what you can take precalc in 8/9th grade in CA? O_o how u do this :O

scout has great voicelines

Dihedral group of the square at best.

Also, the room desc has a mathjax-in-chat link

@Downgoat homeschooled remember ;p

@Semiclassical yea it breaks some userscripts I have though

ahh

I don't spend enough time here for it

@Daminark do you play tf2?

@Riker brb dropping our of HS to homeschool

Not quite @Riker

ah

David Cronenberg thinks the book for next generation postconsumerist neo-Marxians is "Labor Gore: Marx and Horror".

it's fun, first person shooter with a silly tone to it