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20:01
Hey, guys, can you help me please. I need a direction: math.stackexchange.com/questions/2262833/…
@Smple_V Mr lion can you help me?
@MikeMiller what are you referring to?
(oh I see you put a comment on my question :=) )
@AlessandroCodenotti about time ;)
what opinion would you guys have of someone who is doing a PhD just for fun and interest? As in he may not be going into academics, and may go into industry and research?
@SoumyoB that is an incredibly common situation just so you know
wow really?
I've been thinking of pursuing a PhD purely for ego purposes
20:09
I'm so confused about my career at this point
Atleast in physics (fundamental, experimental, and theoretical)
I'd say that's a rather admirable way of going about things. And I imagine it can be pretty rewarding when you're not doing your PhD with all the fright about whether or not academia will crush you immediately upon exit
@Daminark I suppose that can happen, and I hope it does
my career choices were driven by some fundamental beliefs I had about happiness in life, but those beliefs were contradicted by research in psychology very recently
lol
life is so frickin convoluted
20:12
hey dami
everything's an illusion (disclaimer: not helpful)
...unless it is helpful
Mick, idk how much you're joking, but unsavory motivations like those are not so uncommon.
hahahaha are you calling me unsavory?
For instance, I'm finishing my 2.5-year blog project mostly out of spite
20:13
@BalarkaSen do you believe we're all a simulation?
Not you, your motivations
:P
And hey @EricS!
and that some computer geek sitting out there is our god?
don't worry I take it as a compliment, a convenience that goes with the territory I think
@SoumyoB i don't even know what that means, except that's the story in a pretty good sci-fi film
20:15
I've heard this several times on the internet-scientists concluding this
But yeah my idea is to do whatever you think will work out best for you. The main reason I want to do academia is that I like teaching (not babysitting or teaching to a test as high school teachers must do, real teaching) and thinking about clever proofs
simulation hypothesis : decent short story premise, pointless IRL
r/im14andthisisdeep
I think the polytheistic formulations are more reasonable
I mean come on, one engineer to look after the entire simulation?
20:16
@Semiclassical it may not be, after all
@SoumyoB I'm interested to know, what were your thoughts on happiness that have been contradicted?
@Semiclassical there has been so many stories based upon simulation that it's a bit boring now
can you prove that the universe is a simulation? No? Then the endeavor is entirely pointless.
Well I don't think you can prove that there is a meaning to life either but it's fun to look
20:16
for example if the universe becomes too complicated for the computer to handle, and we're close to that point at some time or other, the computer might crash and it's horrifying to think what would happen to us if that happened
@SoumyoB I believe this happens regularly
You would have no way to notice it unless they broke something or lost data
Well, thinking about it now will not decrease the horror that would come upon us if it does happen
I'm trying to find words that capture how much that makes my eyes roll.
20:17
But then clearly they would just rewind the sim and fix it
This is a much better science fiction short story, probably my all time favorite: trillian.mit.edu/~jc/humor/Ms_fnd_in_a_Lbry.html
@Semi Pull a Ted and sprout new eyes to roll
@Daminark not suited at all for this chat room. It will upset many in here
@SoumyoB Well now you have to share.
I find simulation hypothesis stuff to be more annoying than religion, tbh. At least religion has stories and mythologies and worldviews built into it. Simulation hypothesis manages to be both speculative and purposeless.
20:20
it's amusing crackpottery @SemiC
pseudophilosophy is good laugh
Depends on ones tolerance for such things, I think.
And how much one has been exposed to it.
Anonymous
It's just another type of conspiracy theory =P
yeah I'd expect a serious physicist to be really annoyed by that stuff :P
Yup.
Oh, I did run into a fun conspiracy theory the other day.
Yeah I find it funny if nothing else. And I mean, I haven't seen much of either type of mindset to be at all... intrusive?
20:21
What are we discussing ?
A guy holding up a selfie stick and the sign "Satellites do not exist"
3
Anonymous
I ran into a cube earther few weeks back on youtube :D
cube? holy hell
Anonymous
And plenty of flat earthers (as usual)
Anonymous
lol
20:22
Who, when the guy walking next to me was snickering after passing bye, complained about us mocking him but not engaging.
Anonymous
It is hard to differentiate between trolls and actual conspiracy theorists nowadays :D
@blue ...what balarka said lol
I mostly laugh at it, but
I have to add this (not brand new). I posted it on Facebook with the roll of 7 eyes. (They're not as used to my eyes as you are.) golfdigest.com/story/…
20:24
If I were to get bored/tired of thinking about simulation stuff, I could easily just stop engaging with it, so I never find it annoying, and when I do want, it's amusing. Just my 2 cents.
the extent to which such conspiracy theories deny the genuine achievements of physics, engineering, and technology actually does rankle me.
Anonymous
@MickLH He said that cube earth theory is only viable theory that unifies both the flat earth theory and spherical earth theory...and I was like...wtf :P
no lol
Anonymous
I didn't even dare to debate with him
Anonymous
lol
20:24
pretty good idea tho
"How would they know? Were they there?"
Well a cube does have the same topology as a sphere .. kinda
and it's flat almost everywhere
I sat down and specifically tried to reconcile it at all... the best I could come up with is a toriodal earth that the world governments conspire to masquerade as a sphere by not allowing anyone to realize the poles are connected
I guess fake history and fake geometry and physics are not quite the same ...
20:27
the other reason why conspiracy theories irritate me is best summed up by this bit of a "the moon landing could NOT have been faked" video: youtu.be/sGXTF6bs1IU?t=662
@Astyx: Same topology, different geometry.
(the rest of the video is good too, but that part in particular)
Anonymous
In case someone is running out of good jokes, use this (theflatearthsociety.org/home) :D
I guess I'm fast reaching the stage where it is beginning to feel like any sense of appreciation for even good people's amazing accomplishments feel like an expensive luxury, so the lack of which is becoming normal somehow? I dunno
20:29
@Ted Lol at the article and eyes
I dunno what's going on around here. We have numerous people posting essentially the same questions repeatedly (latest) ... and then some of these people try to remove them to remove traces ... Am I missing something on my snarky comment on this one?
Probably homework stuff
Beyond scary, Demonark.
Hi @Danu.
What did you learn today? :)
I've read they were people "trolling" and posting spam questions on MSE. However this does seem a bit too structured to be pure spam
20:30
@ted Eh, it sounds from the comments to the previous question that they wanted to split the two questions up?
Today I learned how to solve Calabi's conjectures
It sounds better than it was.
I mean, the comment from Daniel Fischer makes it sound like that was positively encouraged.
I am now pretty sure I don't want to do geometric analysis.
Actually, the OP just edited to make it slightly different, I guess, so I'll remove my comment.
0 insight 100% calculation :P
20:32
Isn't that effectively the edison quote?
Oh, I listened to lots of Yau lectures on that. It's very hard third-order estimates in PDE, as I recall.
Today was manifolds, so we finished the proof from last time about how transversality was a stable condition, and then did the proof where basically, if $X$ is a manifold with boundary, $f:X\to\mathbb{R}^m$, and $f(\partial X)$ intersects $Z$ transversally, then you can homotope $f$ to $g$ such that they agree near the boundary and so that $g(X)$ intersects $Z$ transversally
Well, @Danu, there's lots of room for other things. Look at some of Rafe Mazzeo's geometric analysis work. Lots of really cool geometry.
Yup, Demonark, important theorem.
Once we did that, we did a naive definition of orientable manifolds
Although it's more general than boundary. If you are transverse along a submanifold (in general), you can homotope away from that submanifold to make it everywhere transverse.
20:34
That's known as genericity by the way.
What exactly is being referred to by "that"?
@TedShifrin The one that we discussed explicitly was pretty bad but nothing really advanced, it seemed. Mostly just shitty calculations.
I think that was supposed to be "Calabi's second conjecture" in the case $\lambda\leq 0$ (hope that this terminology is standard). We did something like 1/2 or 2/3 of the proof explicitly.
@Daminark That you can homotope maps to be transverse to manifolds. The theorem you quoted.
You asking me, Demonark?
I actually don't know that, @Danu.
I was just not sure which of the two
20:37
What's the most flattering city in Hungary?
In general you'd prove if $f : X \to Y$ is so that $f|_{\partial X}$ is transverse to $Z \subset Y$ then $f$ can be homotoped to $g$ fixing boundary such that $g \pitchfork Z$
I was asking Balarka :P
Demonark: $f\colon X\to Y$, $Z\subset Y$, $W\subset X$ (both closed). If $f$ is already transverse to $Z$ at all points of $W$, we can perturb $f$, keeping it the same in a neighborhood of $W$, so that it is globally transverse to $Z$.
howdy, DogAteMy ...
The way to do it is to compose with an embedding $Y \to \Bbb R^N$, perturbing that inside $\Bbb R^N$ by your theorem to be transverse to $Z$ carefully so that everything's happening inside a tubular neighborhood of $Y$, and then projecting back.
(Embedding comes from Whitney)
20:38
@TedShifrin Hmm? The proof, or the statement?
@Balarka: You are not addressing this particular theorem.
@Danu: Either.
@TedShifrin Which particular theorem??
I have no idea what you are referring to.
The one Demonark and I are discussing. You're doing the general case without any submanifold in the domain.
@TedShifrin From Wikipedia: "[...] states that if a compact Kähler variety has a negative, zero, or positive first Chern class then it has a Kähler–Einstein metric in the same class as its Kähler metric, unique up to rescaling. This was proved for negative first Chern classes independently by Thierry Aubin and Shing-Tung Yau in 1976"
@Ted No, I have boundary on the domain.
20:40
I'm talking about what G&P call the Extension Theorem.
This is the one we did most of, explicitly. Then we also discussed the one that the Wikipedia page takes as the main topic: en.wikipedia.org/wiki/Calabi_conjecture
I don't remember G&P's names. I just quoted my theorem here: chat.stackexchange.com/transcript/message/37120297#37120297
It's a generalization of what Daminark said with codomain $\Bbb R^n$.
@Danu: That theorem I know (and I saw Yau's proof). But you were mentioning a $\lambda$?
On now we aim to discuss the Fano case in the coming days. There have been big breakthroughs in the early 2010's by Chen, Donaldson, Sun (and Tian; there is a controversy regarding priority claims)
@TedShifrin $\lambda$ is just the constant for the Einstein metric :P
You have to do partition of unity games in the case of boundary or what I'm talking about, @Balarka.
Oh, never mind, @Danu
20:42
I know, Ted.
Yes, this is going to be the famous differential geometry Chinese mafia fight, @Danu.
...right :P
I wonder if there has been any resolve
shiing-shen wins
I just know that thing Chen put on his webiste and Tian's response.
@wellynaught ?
"A guy holding up a selfie stick and the sign "Sattelines do not exist"
20:43
You're decades out of place, @wellynaught.
You're not talking about Mark Peeters are you? :O
Chern was dead by 2012
his lineage prevails
However, I know stuff about how S.T. Yau treated Chern, which I'm not going to talk about in here.
Mafia fight?
20:44
Chinese math mafia, yeah, Demonark. I'm not going to elaborate.
@TedShifrin I've also heard some stuff regarding some students of Yau and the Poincare conjecture...
@Ted @Balarka remember that I asked you a few days ago whether I can just plug in a complex variable in a real power series and hope it converges? I'm pretty sure it even has the same radius of convergence as the real series now
That's... an interesting way of putting it
Yeah fair
Yes, @Alessandro.
In fact, it's singularities in the complex setting that usually explain odd radii of convergence in the real case.
@Danu Yup... One of the reasons Perelman "quit math"
20:44
Because that should always be $1/\text{limsup}(a_n)^{1/n}$
@Danu: Despite our being essentially mathematical brothers, I'm not a fan of Yau's (his brilliance notwithstanding).
@Ted I have a silly question. $G$ be a Lie group acting smoothly on $M$; how do I prove $f : G \to M$, $f(g) = gp$, is an immersion?
"Manifold Destiny" is an article in The New Yorker written by Sylvia Nasar and David Gruber and published in the August 28, 2006 issue of the magazine. It claims to give a detailed account (including interviews with many mathematicians) of some of the circumstances surrounding the proof of the Poincaré conjecture, one of the most important accomplishments of 20th and 21st century mathematics, and traces the attempts by three teams of mathematicians to verify the proof given by Grigori Perelman. Subtitled "A legendary problem and the battle over who solved it", the article concentrates on the human...
Ah, yes, Nasar writes math history so well.
It's probably false without further hypotheses, @Balarka?
Free action, I am sorry.
20:46
Oh.
Oh btw
something more topological/geometric for you too, @Balarka
So consider an oriented surface of say genus $\geq 2$ and take $\Sigma\times \Sigma$. Remove a tubular neighborhood of the diagonal.
Now a friend of mine is interested in the homology of the boundary of "what's left".
It's an $S^1$-bundle over the surface.
The boundary is the unit tangent bundle of $\Sigma$.
Sure
Or the unit normal
In any case
Normal bundle of diagonal $\Sigma$ in $\Sigma^2$ is tangent bundle.
So $H_1$ is pretty easy to understand. Just the usual circles plus one from the $S^1$ bundle
20:48
@Balarka: I guess the point is that if you have $X\in\mathfrak g$ in the kernel of the derivative, then you'll get a trivial action of the one-parameter subgroup you get by exponentiating $X$.
@BalarkaSen ...which is why I said that.
But what to picture for $H_2$? All the products of the usual circles with the $S^1$-circle (ha-ha) are not so bad to imagine. But what about the class represented by the fundamental class of the surface.
How does that look? It seems like, if we were able to make a surface like that, i.e. something like $\Sigma\times \{p\}$, $p\in S^1$, we'd get a globally nonvanishing section of the tangent bundle...
The fundamental class of the surface self intersects at $\chi(\Sigma)$ many points I think.
Correct. There is no global section.
So how to picture it
(By Poincare-Hopf)
20:51
But Danu's asking how even to get that class "lifted" to the bundle.
I know there is no global section, obviously. I just want to understand how to look at this
We have to take the Poincaré dual of a fiber. What is that?
What does the Leray-Hirsch spectral sequence give us for $H_2$?
A fiber, for you, is an $S^1$? Or a copy ofthe surface?
$S^1$.
@TedShifrin I don't know spectral sequences. But I'd hope you just have it being the same as $H_1$.
20:52
Well, let's try an example. We all know the unit tangent bundle of $S^2$.
Right?
ok
What is it?
am I supposed to say somehting? :P
(I think you're supposed to say what it is)
20:53
LOL
smacks Astyx for fun
I know that one.
but i won't say it
"It's the set of $(x,v)$ where $x\in S^2$ and $v\in T_xS^2$ such that $\|v\| = 1$"
lmao
@Balarka: You saw my off-the-top-of-my-head answer to you?
OK, Demonark. What well-known manifold is that?
Didn't you have homework on this, actually?
Not yet, but I am bookmarking to read that after this conversation :D
20:54
Nah we did $S^1$ and $S^3$, I think
don't want to miss out on this
Along with $S^1\times S^1$
I thought you had an exercise on $SO(3)$.
Proving that it was homeomorphic to $\mathbb{RP}^3$
I haven't seen this before but I guess you can just go through the clutching construction and see there aren't so many options. It should n't be trivial.
20:55
Uh huh ...
@Danu: $SO(3)$ is the frame bundle for $S^2$, hence the unit tangent bundle.
@Danu It's not trivial, by hairy ball.
It's RP^3, topologically
@BalarkaSen duh balarka
So, now, let's do homology of $SO(3)=\Bbb RP^3$.
And here's where I back out
I should probably get back to my pset anyway, I have a lot to do for tomorrow
So see you guys around!
Yes, integrals to do. Bye, Demonark.
20:57
(Only one integral, the others are again, theoretical problems)
:P
@TedShifrin OK that's just a standard result
@Ted Can you describe the unit tangent bundle of $\Sigma$ as a mapping torus of some diffeomorphism? What would that diffeomorphism be?
polynomial ring over one generator with $\Bbb Z_2$ coefficients
I don't want $\Bbb Z_2$ coeffs, @Danu.
Every student taking a topology qual in the US has to know this :P
Cellular homology?
Still the same I guess
just 2-torsion generator
20:59
Huh
It's not Z[a]/2a?

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