« first day (2312 days earlier)      last day (3006 days later) » 

08:00
@Jasch1 $f(c) = \sqrt c$ for the set of perfect squares
Yea and that returns 0
If you have vectors with 9 entries it doesn't matter whether you write them as row vectors or column vectors, you only need to keep the components in the right order, do you agree? @Steve
The density is zero because there are so few of them compared to how many natural numbers there are.
Essentially, they're on two different orders of magnitude.
@Alessandro yes
Its the same rules for both odds and evens, the sign of infinity is equal to the sign of the leading coefficient
I understand this well actually
Time to start writing
08:01
@Jasch1 Good luck
Onyl around 2:30 left to write a Macbeth paper!
Have fun! Or just, good luck :)
Maybe once you're done with this, you won't be able to wash the Math from your hands.
I'm still iffy about the $f(c)$ thing @Axoren
Not as a snarky doubt, just out of my incompetence
@Brody Probably not, the way I described it uses a lot of nuance which takes a bit to realize it's equivalent.
08:04
Is it formally provable? @Axoren
@Axoren Is the formula we were using for the natural density the same as another formula?
!!google "natural density" formula
@Brody Definitely, but requires more effort than I'm willing to do without cookies.
Do internet cookies count?
is there another formula name that I could search to get the same formula
@Jasch1 They are equivalent. They are exactly the same if you count the numbers in order from $0 \to$
08:05
because natural density formula only returns hair products
@Brody I'm going to hunt around in the kitchen. If not, I might bake some.
At 3am
is there another formula that is the same that I could find a pic of
$\displaystyle\lim_{c\to\infty}\dfrac{|\{1,2,\ldots, c\}\cap S|}{c}$
k
but that looks copied
because I have no idea what the fuck any of that means
08:06
Again, it's equivalent to the one I gave you if you count them in order.
i gotta find that
Find what?
@Jasch1 It really looks way too scary for how simple it is conceptually
nah but it looks like i just copied it, and most of my classmates wont understand this
$\displaystyle\lim_{c\to\infty}\dfrac{f(c)}{c}$
08:07
$S$ is the subset we're looking at it, e.g. the set of perfect squares
Then give a formal definition of $f(c)$
And explain what a limit is
i need apng of the formula tho
@Jasch1 Hmm, I think a bright high school student could grapple that no problem
but im lazy
Mathematics is not rocket science, but rocket science is mathematics.
08:09
You don't have to worry about that formula @Jasch1
@Jasch1 Write the formula in ShareLatex, render it, and then screen capture it
Anyways, go write that paper!
PrintScreen on your keyboard, Ctrl+V into MS Paint
Then, select the equation with a Rectangle Select tool and Crop it
Guilty confession... Sometimes, I keep an "Ask a Question" tab open to test LaTeX commands.
@Brody That's what ShareLatex is for tho...
08:11
@Jasch1 Use the PDF Zoom In feature
Lmao i just saw that
Also, don't be embarrassed about asking silly questions.
I'm pretty sure I've asked much sillier and felt terribly foolish
@Fargle I didn't know about ShareLatex before this, and staying on MSE seemed more convenient lol
your formula looks different in latex
@Brody I suppose that's fair. I just always have a tab open whenever I open my browser.
08:12
in sharetex
no divided by
so, @steve, forget about matrix multiplication or any additional structure, as long as addition and scalar multiplication are considered, is there any difference between $\begin{pmatrix} a & b \\ c & d \end{pmatrix}+\begin{pmatrix} e & f \\ g & h \end{pmatrix}$ and $(a\:b\:c\:d)+(e\:f\:g\:h)$?
@Jasch1 MathJax uses a different display style in chat for in-line equations
so what do I change
Post here what you have
"$\displaystyle\lim_{c\to\infty}\dfrac{f(c)}{c}$"
not in quotes tho
$\displaystyle\lim_{c\to\infty}\dfrac{f(c)}{c}$
08:13
Right, how does it show up in ShareLatex?
@Alessandro No
You can use the "upload..." function in chat for pictures.
Does the default ShareLatex template have the appropriate packages integrated?
where is that?
@Brody It might need \usepackage{amsmath} and \usepackage{amssymb}
08:15
the fraction isnt showing up
ok, this is in fact an isomorphism of vectors spaces, so those $2$ matrices on the left are independent in $\mathbb{R}^{2\times 2}$ iff those $2$ vectors on the right are independent in $\mathbb{R}^4$
@Jasch1 Add these two lines to the beginning of the file, after documentclass
@Axoren Alright, that might be the issue. But you know more than me regardless
\usepackage{amsmath}
\usepackage{amssymb}
that worked
08:16
@Brody Wanna learn something neat? I don't think you were around for this silly answer. I still tell people about it because I like bragging about ridiculous things: math.stackexchange.com/questions/1817522/…
I just re-found this earlier.
@Axoren how could I easily explain limit
In laymen's terms, it's the closest number that a sequence approaches if you were to do something forever.
@Alessandro Oh, I see. Nvm, there is a difference
But its a sum right
what do you mean
08:17
@Axoren Is it $1,-1,-1$ repeated?
@Axoren is it a sum tho
or not
@Jasch1 A limit is not a sum. The limit of $2, 2, 2, ...$ is $2$
value of function approaches some values of domainns?
yea but we were adding together all of them
@Steve have you seen that vector spaces are determined, up to isomoprhism, by their field and dimension?
08:18
nah i get what limit is
@Brody Close, it's $1, -1, -1$ repeated.
So, it's a 3-periodic sequence.
@Axoren i dun ged it
Wait so for getting the natural density, is it just the limit?
I managed to relate a very simple high school-level problem to Euler's formula.
I'm also hungry at +3 am.
08:20
hello, i need help for this
Let's bake cookies together, @Brody
0
Q: Convergence in Orlicz Spaces

VrouvrouI have that $(u_n)\subset W^{1,\Phi}(\Omega)$ such that $u_n\rightarrow u$ and $f:\mathbb{R}\rightarrow \mathbb{R}$ is continuous . How to prove that $$\int_{\Omega} |f(u_n)-f(u)| |v| dx \rightarrow 0, ~\text{for all}~ v\in W^{1,\Phi}$$ thank you

@Axoren before you were describing it as the sum of ratios
@Jasch1 Yeah, the natural density is a limit of all those ratios.
@Jasch1 Not the sum, it was the limit. I don't think I ever said sum.
that's a very complicated way to say that the fibonacci numbers are twice odd, then once even, then twice odd, then once even and so on
08:21
@Axoren Too long. Me hungry
Are you sure about this?
@Alessandro Thanks for the explanation, but I need to sleep on it. I think I got the main idea of what you're saying though
@Jasch1 If it were a sum, after 2 summands, you'd have over 100% density of any subset that contains both $0$ and $1$
no problem, I have to run too now, just ping me if you still have problems with this, I'm often here
true
08:22
Oh @Axoren, I see the formula in your comment. Lol applauds
Because you'd have $\frac 1 1$ and $\frac 2 2$
@Alessandro Alright :)
I missread something from before
test: $\huge\text{Hello world.}$
2
@Jasch1 Until you learn techniques for computing limits, you're going to have to imagine what the "last" element of an infinite sequence is.
The limit is the value which is the closest thing to the "last element" if one would exist.
08:24
:33863134 $\Huge\text{Huh?}$
i undertsand what it is, i just misread an old post, i though some commas were plus signs
@Brody is this the giant language?
@Null No, dwarven.
They're quite loud and rambunctious.
@Brody hahaha
It's compensation
Your formulation is going to bother me all night @Axoren
08:26
@Brody I got distracted while writing "overcompensating?"
@Brody Which?
$a_n = (-1)^{F_n} = e^{i\pi F_n} = \cos(\pi F_n) + i\sin(\pi F_n)$?
@Axoren Can you explain why f(c) < c
13 mins ago, by Jasch1
$\displaystyle\lim_{c\to\infty}\dfrac{f(c)}{c}$
@Jasch1 $c$ is how many you've seen, $f(c)$ how many of those $c$ that you've seen that were in your subset.
Bother me... at least for the few minutes I remain awake until keeling over
You can't have found more numbers than you've seen
08:29
Can you explain the formula to me
I get the limit
But what does c respresent
i have to go to the doctor but i don't feel like it. unsovlable problem
@Jasch1 How many of the naturals you've checked so far.
Taking the limit means that you've reached the point at which you've checked them all
and func(c) represents?
@Jasch1 First let me ask you a question. You remember what you're calculating the density of, right?
Yes
An infinite sequence
08:32
@Jasch1 Not exactly.
which is the same size as the set of natural numbers
@Jasch1 Natural density is defined on subsets of the natural numbers.
yup
While infinite sequences of natural numbers can be seen as sets of natural numbers, this also includes finite sets.
which are of the same size (if infinite)
correct?
08:34
That's a matter of definition and isn't really relevant.
It is true that if they're infinite they're the same cardinality as the naturals
So lets say we are checking somethign that returns something greater than c
$f(c)$ is part of an iterative process.
You're checking numbers from your subset one number at a time.
$f(c)$ is how many numbers you've found after checking $c$ numbers.
$\frac 1 1,\frac 1 2, \frac 2 3, \frac 2 4, \frac 3 5, \dots$
so this
08:35
Those are the values of $\frac{f(c)}{c}$
nah they were something/2
Specifically, those are the ratios for the set of even numbers.
yes
"nah they were something/2"?
sorry lmao
08:37
In that case, $f(c) = \frac c 2 + 1$
That may be what you're confusing.
You don't actually need a function expression for $f(c)$
It just represents a quantity related to the process
Having one allows you to calculate the limit easily.
At least for the primes, we've actually denoted a counting function
@Brody With a closed form?
$d(\mathbb{P})=\lim_{n\to\infty}\dfrac{\pi(n)}{n}$
No, just a symbol
Meh.
f(c) can be replaced with a linear expression correct?
08:39
If I remember correctly, that density is non-zero.
@Axoren it is zero
@DHMO That's a shame. I might be thinking of a proof that uses partial densities.
Well, any counting function on natural numbers has a closed-form expression, depending on the definition
@Jasch1 It's not so much that $f(c)$ can be replaced by linear expressions
08:41
modified linear expressions
And more that the counting functions of some nice sets happen to be linear
$\displaystyle\lim_{c\to\infty}\dfrac{2c}{c}$
@Jasch1 You need to be careful with doing things like just picking an equation for $f(c)$
You get $f(c)$ from a description of a subset, not the other way around.
it would need to be m/2c right?
lets say we want to get all even numbers
@Jasch1 Constructing $f(c)$ for $2\mathbb N$ would result in $f(c) = \frac c 2 + 1$
08:43
$\displaystyle\lim_{c\to\infty}\dfrac{\dfrac{m}{2c}}{c}$
You're confusing me a lot here
$f(c)$ is a counting function of a set. If you check $c$ natural numbers, you'll have found $f(c)$ of them in your set.
Lets say I have the linear expression 2x + 1 and I want to find the density of the generated sequence
What would the equation be then
you could drop the +1
and thenwhat else would you do
So you're trying to compute $f(c)$ from a sequence $a_n = mn+b$, right?
yes
As I was telling Brody, earlier, the inverse works sometimes.
08:47
Generally that works
Which is to do the following:
$f(c) = \frac{\frac c m - \frac b m}{c}$
Roughly.
However, the limit is equivalent if we drop the $\frac b m$ term
If the fractions are round, things don't work
This transcript is gonna be looong
@Brody I can't explain why $f(c)/c$ is equivalent to $a(n)/n$ tonight
08:51
Can you help me out and write something in LaTeX
@Brody Do you still have gripe with it?
@Jasch1 What specifically?
@Axoren Their respective limits you mean?
@Brody Of course
Set builder notation
@Jasch1 $\{ x \mid P(x) = 1 \}$
08:52
@Axoren Is it just the case that your inverse function approximates the counting function at large numbers?
Use \$\<space>\$ for spacing things out a bit
@Brody It has to do with the fact that the sets of counted numbers at each step are subsets of each other.
@Axoren Okay.
If $A(n)$ are the sets counted in order, $B(c)$ are the sets counted in an order you choose.
$B(0) \subset B(1) \subset \dots \subset B(n) \subset \dots $
is there a sign for natural density?
@Jasch1 A nice letter to use is $d$
That's what they use on the wiki
@Brody So, now consider the fact that that sequence of $B(c)$ converges to $\mathbb N$
You have a convergent sequence of sets of natural numbers.
08:58
What do you mean by an "order you choose"?
@Brody I want to check if all the evens are in the set first, then if all the odds.
If that's the order you pick, it's not possible.
@Jasch1 Do you mean notation or positive/negative?

« first day (2312 days earlier)      last day (3006 days later) »