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00:01
why is it that inverse of monotone function is monotone?
@heather you only proved that it is an injection
@DHMO one to one is another name for injection. bijection is both one to one and onto (surjective)
00:29
Hey guys
Can you guys please help me understand something
@DHMO Let $S$ be a set. Given a map $f$ is monotone means the image $f(S)$ is a partially ordered set. The inverse map is the bijective map defined to be $f^{-1}$ such that $f^{-1} \circ f = f \circ f^{-1}=\textrm{id}$. Therefore $(f^{-1} \circ f)(S)=S$. Now for all elements $a,b\in S$, monotonicity means if $f(a)\geq f(b)$, then either $a \geq b$ or $a \leq b$. Therefore $S$ is also a partially ordered set. Thus $f^{-1}$ must also be monotone
what @Jasch1
In set theory, Cantor's diagonal argument, also called the diagonalisation argument, the diagonal slash argument or the diagonal method, was published in 1891 by Georg Cantor as a mathematical proof that there are infinite sets which cannot be put into one-to-one correspondence with the infinite set of natural numbers. Such sets are now known as uncountable sets, and the size of infinite sets is now treated by the theory of cardinal numbers which Cantor began. The diagonal argument was not Cantor's first proof of the uncountability of the real numbers; it was actually published much later than...
In this
Kinda confused about this part
he constructs the sequence s by choosing the 1st digit as complementary to the 1st digit of s1 (swapping 0s for 1s and vice versa), the 2nd digit as complementary to the 2nd digit of s2, the 3rd digit as complementary to the 3rd digit of s3, and generally for every n, the nth digit as complementary to the nth digit of sn. In the example, this yields:
I'm a hs sophomore writing a paper on some stuff on infinity
@Jasch1 What's confusing you here?
I'm confused about how he goes from the infinite binary series to s = (1,
wait didnt copy right
s = (1, 0, 1, 1, 1, 0, 1, ...)
I put off a 10 page reserach paper until the night before
00:40
He's going down the diagonal, and finds (0,1,0,0,0,1,0,...)
Then he changes every one to zero, and every zero to one.
Now he has (1,0,1,1,1,0,1,...)
This can't be in the list. It can't be the first part of the list, because the first element doesn't agree.
It can't be the second part of the list, because the second element doesn't agree.
And so on.
So, he's constructed something that's outside the list, contradicting that the list had everything of that form.
hey @Fargle
Howdy @Adeek, and @Ted. How's it going?
good
hi @Fargle
I was wondering I think there is a mistake here
00:43
Now that I'm not qualified to answer. Going through D&F myself, as it were.
$\sigma$ should send the root of unity to $\omega^7$ and $\tau$ should send $\omega$ to $\omega^5$
yeah I am pretty sure there is a mistake here if I am not crazy.
$\sigma(\omega) = \sigma(\theta)^4(\sigma(1/2) + \sigma(1/2 *i))$
What is $\omega$? You mean $\zeta$?
yeah I don't know that letter.
$\omega^4 = e^{\pi * i} = cos(\pi) + i sin(\pi) = -i$
$\theta^4 = \sqrt{2}$
so $\sigma(\theta)^4 = \omega^4 * \theta^4 = \sqrt{2}/2 - i *\sqrt{2}/2$
They are correct, Karim.
why ?
00:48
Hi @TedShifrin
You should learn to question yourself more rather than assuming they're wrong :P
Hi @meow
haha yeah
$\sigma(\zeta) = \frac12\sigma((1+i)\theta^4) = \frac12(1+i)(\sigma(\theta))^4 = \frac12(1+i)(\zeta\theta)^4$
yeah that is what I got
$\zeta^4 = -1$, $\theta^4=\sqrt2$.
So we get $-\zeta$.
But $-\zeta = \zeta^5$.
Avoid distributing things out ... that is usually not a good thing.
00:50
ohh haha
distributing error lool
it is been a long time since I did college algebra
That is a totally unacceptable attitude.
yeah
You cannot do mathematics without doing high school algebra correctly.
@Fargle just saw your response, ty
yeah lol
00:51
Suppose I have a monotone map $f$ and an unordered set $S$. By definition of monotonicity $f(S)$ is a poset. Is this possible?
No problemo, @Jasch1.
@TedShifrin how are you using the plane to describe $\mathbb{P}^2$? are you using the $\mathbb{R}^2$ part of $\mathbb{P}^2$ (i.e. the lines given by $[1,x,y]$)?
I suspect that I will be on a lot tonight
@meow: I explained carefully that $\Bbb P^2 = \Bbb R^2 \cup \Bbb P^1_\infty$.
that is, is there exists a monotone map that impose a partial order to an unordered set?
00:53
So what are you asking me now?
yes i understood that
what im asking is
when you use a coordinate plane to describe points in lines in $\mathbb{P}^2$
is the point $(x,y)$ on that plane corresponding to $[1,x,y]$? or something else
Any of you written math research papers before?
I'm not understanding what you're saying. A line in $\Bbb P^2$ is given as the solutions of a homogeneous linear equation $ax_0+bx_1+cx_2=0$, for example.
yes @TedShifrin
let me get an example, one second
00:56
When declaring a set in a proof
Should it be italicised?
Not generally. You mean, defining a set while you're doing the proof?
what do you mean?
LaTeX italicizes things. What do you mean with your question, @Jasch1?
Not using LaTeX
wondering if I should
you definitely should
what are you using right now?
00:57
Lets say I have 6 hours to do this
But your question is ... you're babbling along in a proof. And you say "Let $A = \{x\in\Bbb Z: x\equiv 3\pmod 7\}$."
What are you wanting to italicize?
is the hastle of downloading and learning it worth it
Not with only a few hours, no.
I have to finish this and a 5 page english paper by the morning
But in the long term, yes.
Ah, typical college student rolls 9 of 9 eyes
00:58
Nope
HS Soph
LOL, high school ... even worse
@TedShifrin when you smack me, do you use your 3rd or 4th arm?
Anyhow, I asked you a question about your question?
But a very, very competetive high school
LOL, @meow ... all arms that are required.
00:59
@TedShifrin The mathematician's answer.
@Fargle: I'm retired, not dead (yet) :D
The slap is unique up to a permutation of arms...
Except when you leap.
If a Ted-smack is executed in the middle of a forest, and I leap to avoid it, am I still ashamed?
"executed" is such a violent term and sends a mixed message.
01:01
so @Ted, in this figure, you use a plane to represent $\mathbb{P}^2$
Yes. That's true. Sometimes I put the three axes in the plane, sometimes not.
would that plane be the "$\mathbb{R}^2$ part of $\mathbb{P^2}$?
No, no, that's all of $\Bbb P^2$.
It's a schematic, not literal, picture.
Now I understand your question ...
how would we represent the $\mathbb{P}^1$ at infinity though?
It's no different from any other line in that picture. But look at Figure 4.
The line $x_0=0$ is "the line at infinity."
G'night @MikeM.
For the purposes of Figure 8, @meow, there was no need to think about specific coordinates — just geometry as a whole.
@meow: Are we OK now (temporarily)?
01:06
yes
today i taught a kid some basic trig stuff; the unit circle, what radians mean, and what sine and cosine really means in terms of the unit circle
@meow, if you want, I'll send you a handout I wrote for my calc theory class years ago with a trig review (and some nonstandard derivations).
@TedShifrin that'd be great, thank you. you can send it via my gmail account :)
@meow: Sent.
01:17
quick question
just about how stuff is named
In set theory, Cantor's diagonal argument, also called the diagonalisation argument, the diagonal slash argument or the diagonal method, was published in 1891 by Georg Cantor as a mathematical proof that there are infinite sets which cannot be put into one-to-one correspondence with the infinite set of natural numbers. Such sets are now known as uncountable sets, and the size of infinite sets is now treated by the theory of cardinal numbers which Cantor began. The diagonal argument was not Cantor's first proof of the uncountability of the real numbers; it was actually published much later than...
s is a list right?
Not a set
it's a sequence
well
Because I know a set generally uses {}
k
what ted said
01:18
a sequence is like an ordered set
how old are you guys?
that's confusing, @meow, because you index by the positive integers, not by the order of the real numbers
@Jasch: Add 50 for me :P
50 years the wiser
how true. :D
01:19
40+ years of torturing math students :D
teacher?
I used to be a professor ... retired.
@Ted likes to make a smooth connection between "tutor" and "torture"
In that same example
of all infinite binary sequences
01:20
@meow: I don't throw the word "smooth" around lightly.
No, no, @Jasch1, only a very few binary sequences.
The point is that you cannot list them all. It's an uncountable set.
Yes I understand that
That's what Cantor's argument shows.
OK, so don't say all :D
k sorry
ty tho
No need to apologize. Just trying to make sure you say stuff that's right :)
hey @TedShifrin I was wondering why is determine the lattice of subgroup of this group G is straightforward ?
01:21
@TedShifrin There's a "smooth operator" joke in here somewhere.
I have to say, listening to Chance the Rapper helps so much while writing
off a nice speaker
so calming
how do they get the lattice so fast ?
The subgroups are pretty obvious (because you know the symmetries of the square), Karim. The intermediate fields are not all. That's what I was telling you to do.
@Jasch1 I can't listen to rap while I write, though I love Chance. I listen mostly to instrumental stuff.
im going to upload a new picture
my hair is wet in this picture
01:22
Nah none of Chance's kinda hard stuff
@Fargle: But a singular operator is so much better.
oh I see @TedShifrin
@TedShifrin :I
@Fargle Just a repeat playlist of Juice, Cocoa Butter Kisses, Favorite Song, Angels, and No Problem
Harder rap is harder to write wit
@Jasch1 I just get distracted by words in general, is what I mean. Can't listen to Cocoa Butter Kisses without rapping the whole thing.
01:23
lmao it is fucking amazing I see what your mean
@Karim: In particular, you know about conjugate subgroups and so it's pretty easy to write everything down correctly.
What time zone you guys in?
Plini, Sigur Rós and Explosions in the Sky are my go-tos.
Central, @Jasch.
Thats 2 hours behind EST right?
nah 1
Mountain is 2
01:24
i am in EST right now
All I know is between here(NYC) and LA is three hours
Then we good guys in CA are 3 hrs behind. (Although I spent 44 of my years in EST.)
boooooo
NYC is the best
amazing public high schools
@TedShifrin have you proved any neat theorems in your life time? :P
My sleep schedule is somewhere in the Pacific, however.
Not the time-zone, mind--the ocean.
01:25
I think so, @meow, yes.
I think you, Brody, and Balarka all need to move to the moon, @Fargle.
What'd I do? :O
time zone issues
I've gotten 3 hours of sleep each day this week
probably none today
You'll end up very sick, @Jasch.
Stop chatting and work.
I am
01:27
@Jasch: I went to college with many, many kids from Bronx High School of Science.
In low-level research papers would it be acceptable to use diagrams from wikipedia
Ooooo
Stuy life
NO, it would not. But in a high school paper ...
Its a draft too
@TedShifrin I've been considering dual enrollment, but i dont think it would work because
1. may be too much stress
2. costly
I know in a real paper, it would not be, but solely for portraying what I am saying and not for the intent of publishing
01:28
@meow: I keep telling you it's ok to slow down. Seriously.
@TedShifrin what do you mean by conjugate subgroups ?
Only worth joint-enrolling if you go to a school with good classes for you.
That's a standard term, Karim.
of course, @Ted
$gHg^{-1}$ for fixed $g$.
@TedShifrin My school has a big rivalry with BxSci
01:29
oh ok I see
the adjoint of $\frac {1}{2i}$ is just $\frac {1}{2i}$ correct?
No, the conjugate of $-i$ is $+i$.
oh yeah that it is...I really need to brush up on my basic linear...
the context of classical mathematics, this is impossible, and the diagonal argument establishes that, although both sets are infinite, there are actually more infinite sequences of ones and zeros than there are natural numbers.
From the wikipedia article
This isn't linear. It's complex numbers :D
01:31
How can this be derived from the fact that T is uncountable
true! Im more a statistics person
"Uncountable" means "more than there are natural numbers" :) @Jasch1
just realized that
Algebra and Trig are my bread and butter
Not much experience with sets and sequences
Prepare for large text paste
wait il post imgur link
imgur.com/a/4suYt anybody has the time to review this paragraph I would be greatful
01:37
ok updated picture
@Jasch1 umm the first sentence is kind of incomprehensible
It still looks like a grim mug shot, @meow :D
whops meow-mix
i can do the math, just me no grammars
@Jasch: I'll be your English teacher and say grateful.
Nor spelling.
lmao I also have to do that
A 5 page paper on macbeth
I'll leave @meow to be the editor. I've done that my whole life. :)
01:39
i feel like if i edit this im going to end up telling you "say this instead" and i don't want to write your whole paper for you, so im only going to be giving little nudges like that one :P
LOL, @meow sounds like me. (Sorry to insult.) :D
K thats what I need
I dont want you to tell me what to write instead
I need to understand what is wrong, I figure out how to correct it
Good boy :)
Better for me to do that
Because the rest is gonna be a pain in the ass if I don't understand this part
sees Ted wink with his third and seventh eyes
01:41
The extra eyes only roll. Do they wink too?
not sure. maybe you can train them to?
@Jasch1 umm not sure what you mean by "infinite binary set"
you mean a sequence? or what do you mean
yes sequence
infinite set of binary decimals?
i forgot to change them back from when you corrected me on the terminology
Oh, sequence of binary decimals
01:43
As an inexperienced writer of research papers, would it be expected of me to include a subsection on the history of this discover?
its not necessary, but you could include it in say the abstract of the paper
Abstracts are short.
or you could add a footnote
This is actually some complicated history, I think.
My intro goes over the history of infinity
Started by mentioning Zeno's Achilles vs. Turtle paradox
01:44
tortoise :P
oh, no, it's the tortoise and the hare. Never mind.
lmao uk what I mean
yea
The Achilles one is with a Turtle
@Ted What do you think about the Mattis appointment? That has to be really positive news for our foreign policy.
(considering possible alternatives)
I haven't seen the nightly update yet, @PVAL. I need more and more martinis to read the news.
it is quite chilly here
@PVAL: Every appointment is about as regressive, inexperienced, and right-wing as you can imagine. This one doesn't seem all that much better.
@meow: You got the email?
01:49
@TedShifrin yes, i did.
@PVAL: I do see a few of the "better" points in the NYT, though.
@TedShifrin Well he certainly isn't inexperienced, and seems to have been vocal against "questionable interrogation techniques", and relatively non-partisan.
yeah, and skeptical about getting into bed with Russia.
But after you've picked Petraeus and Palin and all the rest homophobic, misogynist, racist, and xenophobic, it's not hard to look "better."
I found something rare in America!
a moderate!
@PVAL: Did you pursue that discussion of the integral with function limits with your student?
where did you find that, @Jasch1?
01:52
@meow-mix So your question was to find a bunch of four-cycles, no two of which leave the same numbers fixed, which satisfy $\sigma_1\dotsb\sigma_n(1234)=\rm id$?
you
(I don't have a solution, I just want a clarification)
no, I'm pretty far left, @Jasch1.
@Ted No they were completely satisfied with the geometric interpretation.
Same
but at least you have hope that he will do well
01:52
You made me work that hard for nothing, @PVAL? :D
@AkivaWeinberger well $\sigma_n \sigma_{n-1} \dots \sigma_1(1234) = \mathrm{id}$
@Jasch1: Maybe you missed all my sarcasm.
Probably
Well it was a case of a student unintentionally asking a much harder question.
opposite direction
01:53
Same thing but in reverse, then
either way it shouldnt matter since you can reverse it
pretty numb to sarcasm now
whats your solution :D
I'll think about it, sounds interesting
I understand, @Jasch1.
01:53
As I said, I don't have a solution
@meow, DogAteMy: what are we solving?
I posted it two minutes ago
Most of them have difficulty understanding what the notation means, and don't want to spend "even more" energy on math thinking about possible applications.
(2345)(3451)(4512)(5123) id imagine it would be like something cyclic like that
that might even be a solution, idk
2 mins ago, by Akiva Weinberger
@meow-mix So your question was to find a bunch of four-cycles, no two of which leave the same numbers fixed, which satisfy $\sigma_1\dotsb\sigma_n(1234)=\rm id$?
01:54
@TedShifrin i posed a little permutation question :)
@PVAL: No one had ever asked me the question before, so I was pleased.
@AkivaWeinberger you forgot a restriction; none of them may be "congruent" (as i described) to (1234)
Is there something special about 4?
yes, that its not prime :D
and not 1
Gotcha.
01:56
"No two of which leave the same numbers fixed"
im pretty sure this "theorem" has been proved for prime cycles
I think its a really good question, because while I can believe students understand that being able to calculus with products, exponentials, trigonometric, sums etc is reasonable because these are such natural operations.
Bye, DogAteMy.
But that operation isnt really natural.
01:57
@PVAL: Well, moving targets aren't so unnatural, especially in applications.
Oh, @PVAL: Good point.
In fact, the problem I gave you that's true.
My fault.
I didn;t mean to delete that whoops

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