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01:20
Eikonla equation is such a meme pde
Eikonal
@ZacharySelk what?
why the hell am I not asleep yet
huh
I'm dumb, nevermind.
I really am dumb, I'm trying to show that straight lines are minimizers of Euclidean distance, and without using variational methods it seems to be pretty tricky.
Of course, the best way is to use that $\Bbb R^n$ is complete, use Hopf-Rinow, get a geodesic, solve the geodesic equation.
But to show it without that isn't trivial.
01:29
I am not going to entertain crank Riemannian geometry.
Crank?
I know this is possible, to use Hopf-Rinow is a mosquito-nuke.
I have suddenly got an idea on how to solve a very very old problem I never did.
@BalarkaSen I do have a reason for this
I want to introduce the length and distance functions as early as possible (page 1 or 2) and one has to show that the Riemannian distance on the plane is indeed the regular one
To wait until 30 pages in is ridiculous
@BalarkaSen Oh, interesting question: is there a 1-form $\omega$ on $\Bbb R^n$ such that $L(\gamma)=|\int_\gamma\omega|$ is the Euclidean length of a curve $\gamma$, for any $\gamma$?
Most certainly not. I'd have to think for a proof.
01:45
@0celo7 I mean, then $\int_\gamma \omega$ has to be parameterization-independent right? How can that ever be
@BalarkaSen Hmm? Line integrals aren't parametrization dependent, are they?
You're right, I should sleep.
@BalarkaSen Do you want to hear my idea?
Sure
If you can reproduce your idea in two or three sentences
The kernel of $\omega$ forms an integrable distribution (need to check that) with 1-dimensional integral manifold. Take a curve $c$ in that submanifold. $|\int_c\omega|=0$, but the length is positive.
01:50
I think that's way too much machinery for something that should be basic.
I agree.
@BalarkaSen It's an exercise in Lee, but way before the distributions chapter.
As stated in Lee, it's trivial.
He writes it as $L(\gamma)=\int_\gamma\omega$.
Simply reverse the orientation of $\gamma$ to see the absurdity.
With the absolute value...it is harder.
@0celo7 Right.
That's why I was thinking of parameterization. But that's useless.
I am fairly sure kernels of 1-forms are integrable, at least locally.
It's used all the time in $G$-bundle theory.
Let me check the errata, that might be a typo in Lee.
@BalarkaSen Not a typo. Should I email him? I'm fairly sure the harder problem has the same solution, I wonder which one he had in mind.
I don't know what you should do. Maybe figure out the harder problem first.
According to google, as long as $\omega$ is nowhere vanishing, the kernel is integrable.
I don't see anything wrong with it vanishing though.
@BalarkaSen Ah!
$\omega$ cannot vanish on any open set.
So on such an open set we have an integrable kernel.
And we can find curves in that open set with "length" 0.
02:08
@0celo7 Wait a tick. $\gamma_1, \gamma_2$ be two curves of the same arclength. Given such a form $\omega$, I can integrate over $\gamma_1$ clockwise, and then over $\gamma_2$ counterclockwise. That's $\int_{\gamma_1}\omega - \int_{\gamma_2}\omega$. By hypothesis that's 0 tho?
There's that awkward modulus there, yikes.
Oh well I give up.
@BalarkaSen Might as well generalize it to a general Riem. mfld. too.
02:37
If someone could answer my simple question on multivariable limits in the following thread, I would appreciate it. math.stackexchange.com/questions/1918645/…
user116211
03:13
Could anyone give me an example of a number where the number of significant figures is less than the number of correct decimal places?
03:27
@MAFIA36790 what?
user116211
@0celo7 I was reading about numerical analysis where the author wrote a theorem relating the relative error and the number of significant figures; the proof was given for three distinct cases; namely $(a) ~m\lt n, ~(b)~m= n$ and $(c) ~m\gt n$
user116211
where $n$ be the number of significant figures, $m$ be the number of correct decimal places.
user116211
While the first one is easy to guess, and the second one is proper fraction, I'm not getting an example for the third case.
03:48
Hello
 
1 hour later…
04:56
Can someone please answer this question: math.stackexchange.com/questions/1918645/…
its been around for a while a no one has answered :(
 
3 hours later…
08:18
1. Is it possible to have something that can be proved to be true, but attempt to prove by contradiction generated no contradiction because the case where it does not hold is not completely excluded from the structure in question?
2. We are lucky to find that the fundemental theorem of calculus holds thus allowing easy computation of integrals. What if we are not so lucky back then and found no fundemental theorem of calculus. How to construct a mathematical system to investigate this alternate possibility?
 
1 hour later…
09:25
@Secret When I look at these questions I can only imagine that they are meant to be addressed to someone precisely. A long time ago I thought of calculating integrals in a totally different way. I never developed my ideas that much, and I don't know why, I could have do it (however I think I know how I might like to continue what I already did).
If I don't use @ in my messages and my messages end with a question mark "?" instead of "...?", it means I am asking the whole chat and have no particular person in mind. This often means should I become too deperate and after too many failures to experiment for the answer myself, it will become a MSE question
Sure. Agree.
However no one will share on MSE revolutionary ideas about mathematics that are (possibly in development), but talking about possibilities, sure, that wouldn't ever be a problem.
Well, actually there are a couple of examples of what you said above. At least in the abstract algebra sector, there are a lot of users who occassionally ask abotu whether their mathematical structure make sense and implications
http://math.stackexchange.com/questions/1775868/is-this-extension-of-the-real-numbers-a-field-it-involves-a-unit-of-infinity
I think any of us (referring to people that are passionate with mathematics) should think and invent mathematics in a personal way.
Perhaps it sounds crazy but this is what I do here.
I invent maths all the time in my spare time. For example just trying to break axioms so that I can get a division by zero I have been doing that for at least 3 years
When I actually share the results to others, however often we all spot some mistakes and it will be sent back into the drawing board
For example:
2
Q: Why $0 \cdot 0=1$ not allowed even in a set S that cancellation property failed to be applied?

SecretRecently I was studying a linear algebra class which introduce some basic concepts of fields, groups Once again I tried to divide by zero by constructing an algebraic structure from scratch using just a few axioms because I stumbled across this when browsing the site We knew that the important ...

However my communication skills is poor thus questions like these people usualy don't understood it. This question hwoever no longer matters since I have checked with my mathematician peer and he point out that I have not completely avoided the axioms to derive $0x=0$
09:41
@Secret those can produce some very good questions indeed.
(much of it boils down to what properties of $0$ and $1$ you require).
@Secret Interesting.
My single most highly rated question is actually from mixing mathematics and philosophy, which my linear algebra professor siad I gone too meta that I might lost my way in the vastness of mathematics
32
Q: Are there mathematical objects that have been proved to exist but cannot be described in words?

SecretThis might be a very stupid, and possibly philosophical question, but attempt to apply mathematics to everything plus inspired by this question caused me to ask this question Is there any mathematical object that has been proved to exist but cannot be described in words? If the answer is...

The primary reason why it attract so many upvotes is because there is a alot of dispute about what it actually means. IT also involve some MO answers there
Basically, ever since I become very interested in division by zero and understood from my professors how the do nothing technique works (aka cheating, trick, e.g. 0=x-x, 1=x/x etc.)I have a hackerspace like attitude to maths in addition to the ordinary one
You must love the Riemann sphere
I usually invent new algebraic systems to explore by taking known axioms, and then breaking them
Nah, the $0/0$ on the riemann sphere is not very interesting because it acts like an absorbing element if I recall
In fact, in a lot of systems, $\frac{0}{0}$ are additive absorbers
this include Wheels, probably the cloest thing we have to division by zero
Right now, one of my latest idea is to determine if there is some kind of continuous map between different logic systems so that analogous to how we change basis in linear algebra to make the maths easier, whether we can do something in a more abstract level by pulling the entire proof that "the permenent is #P" into a logic system so that it breaks down, then compute the permenent there, and transform back into the usual logic system to circumvert the proof
However, gut feelign told me that there must be some no-go theorem that prevent me from doing this. My current maths level is however not high enough to explore this idea
Under such hackerspace mindset, one will think of the following besides the usual demand of rigor and meaning of the mathematical objects:
1. The set of all possible ways to prove a given theorem, its optimisation
2. The weak points of the proof and how to break a proof to get something new
3. Theorems and constraints that govern counterexamples as a mathematical object
4. Strong affinity to pathological examples and trying to udnerstand them
This mindset also means any questions that pop up due to misreading of an exercise will be considered seriously, as long it is a geenralisation of what the exericse question is:
2
Q: Solving for the spectrum and eigenvectors of the "shift operator(?)" $T$ in $P_3(\mathbb{R})$?

Secret This question is inspired from accidentally misreading this question in my tutorial exercise in my linear algebra course because I forgot the 3 in $P_3(\mathbb{R})$ (The actual question can be easily solved by considering the matrix of $T$ and then the eigenvector is found to be the constant p...

(This is how I got my first taste of functional analysis in the chat)
10:15
@Secret At some point I'll get through your questions with great interest, I like how you think.
You can't be a simple user, I see some kind of special spirit around. ;)
I encourage you to share your ideas more with the community. It is true that some of them might be too publishing quality that you might don't want to share directly until they are published on a journal, but for some work in progress ideas, you can choose some of these to shre how you came up your methods and let the community to contribute to your ideas to make it better
I have read previosu chat logs and I have seen you already done some when you explain about the symmetry properties of some integrands with robojohn and others, so keep it up!
That's my point.
(re deleted) that's too sad, but if you have made your decision, then proceed
(re not deleted) ok
(NB: I am ok with $P\text{ and not }P$, thus yes I am kinda crazy. But with justified craziness comes diversity)
Speaking about inconsistent mathematics, here's some reference for those interested
user116211
10:36
@Secret It sounds like of Law of Excluded Middle of Aristotelian logic.
Nah, accpeting that is to reject the principle of explosion, and you enter the domain of inconsistent/paraconsistent mathematics
which is actually a well defined discipline, but progress in the axomic construction is slow
The good thing in inconsistent mathematics is godel 2nd incomplteness theorem will break down, thus in some sense more questions will have answers
the bad thing is still young, and that paraconsistent logic is still a subset rather than an extension of classical logic
11:08
@robjohn have you ever tried is one? $$\int_0^1 \left(\frac{\log(1+x)}{1+x}-\frac{\log(1-x)}{1+x}\right) \arctan(x) \textrm{d}x=\frac{\pi^3}{192}+\frac{\log(2)}{2}G$$
I gave it to more students and professors, and no one did it. The idea is to finish it elegantly in a very easy way, such a proof would be required.
Uh, If my memory serves, aren't you already asked robojohn this already around a week ago. I also remember he wrote soemthing about series closed forms afterwards and another user also joined in the discussion?
My questions is relatively simple and that's why I don't want to create an independent post for it.
Basically, for proving in maths, can observation be used? Once the same step has been shown to work for many numbers, and it's evidently clear why it happens, can it thus said to be proved? Thanks
@Secret As far as I can remember no solutions has been provided. I'm not aware of such a series being posted.
@Secret Then I mean a very elegant solution (in the spirit of the mathematical art).
Hello!!!
ok I must be seeing some other infinite series back there then
@MihirChaturvedi Here's a counterexample for your case math.stackexchange.com/questions/111440/…
11:13
@ThePointer Your approach is fine, but as mentioned, you should write down $\lim_{x \to 0} \sin(x)/x$ and $\lim_{x \to 0} \sin(x)/(2x)$ explicitly than just writing down "$0/0$" which is not really an answer.
Basically unless you ensure the pattern holds with mathematical induction, you cannot really prove the pattern holds
Suppose that we have the function $f(x,y)=\left\{\begin{matrix}
\frac{xy^2}{x^2+y^4} &, (x,y) \neq (0,0) \\
0 &, (x,y)=(0,0)
\end{matrix}\right.$.

Could it hold that $D_{\overline{a}} f(0,0)$ exists for each $\overline{a}=(a_1, a_2) \in \mathbb{R}^2$ with $||\overline{a}||=1$ or $||\overline{a}||=2$ and that f is not continuous in (0,0) ?
Can anyone show me why this is true: Let $a,b,c$ and $d$ be real numberssuch that $a^4+b^4+c^4+d^4=16$. Then $a^5+b^5+c^5+d^5=32$ if and only if one of $a,b,c,d$ is $2$ and others are zero.
@BalarkaSen the second limit is written weirdly. Why not $1/2\lim_{x \to 0} \sin(x)/x$?
@TobiasKildetoft Hey!!! Do you maybe have an idea?
11:15
@Secret Ahh I see. Thanks!
@Idomathart Sure, sure. I didn't have ChatJax on when I wrote it, that's indeed better.
The function written by Evinda might be related to the "windmill saddle function" $\frac{x^2}{x^2+y^2}$,, which is known to have discontinous first derivatives at the orign
@Evinda Why don't you try working it out? $f$ is not continuous at the origin is easy to see (approach by different curves). It is possible that every directional derivative exists but that the function is not continuous.
sorry mistake
11:24
Gotta run.
A ok. And how can we check if $D_{a} f (0,0)$ exists for all $a=(a_1, a_2)$ with ||a||=1? @BalarkaSen
11:37
@Secret discontinuity is immediately got by using direction $x=my^2$ and noticing the dependence by the variable $m$.
$$\frac{m}{m^2+1}$$
ok I definitely suck at mutivariable limits because of the lack of experience to see the relevent directions (I often start with y=mx, but it almost always fail for the "windmill saddle" and its relatives)
@Secret What did you use to generate the graph?
These multivariable calculus continunity exercises are excellant is demonstrating how vast the number of possible paths one can approach any point in the function, which is why multivariable limits are a pain to calculate without experience or sandwich theorem
I use google
If you type any functions of x and y, google will plot them
Cool. I didn't try that yet.
The issue is that all these paths are located in the space of functions, one of these being $\mathcal{C}^{\infty}(\mathbb{R})$ and there are simply uncountably too infinitely many elements to test them all
11:45
@Secret In general these exercises are about proving/showing the discontinuity ...
yeah, but without prior experience, it is hard to guess where the ridges are in order to show the limit is discontinuous
For example in the above function, you will get continuity for any paths except $x=\pm my^2$
this is why proving discontinuity in the windmill saddle and its relatives are such a useful exercise
This is the windmill saddle, it is such a classical problem of multivarable calculus
(actually it has no name, I made that up, why don't they give a name to such an important counterexample to continuity of derivatives...?)
11:54
@Secret Maybe because no one thought of giving a name to it?
@Evinda You have to compute a directional derivative. Use the definition.
$\nabla f \cdot \vec{a}$ give zero unless I must have done something wrong (I might need to read my notes again on how to take the gradient in piemeal functions
@Idomathart Eaiser; $x = y^2$ and $x = 0$. But yeah, doesn't matter.
@BalarkaSen Can you take $x=0$?
You're approaching by the $y$-axis.
11:58
@BalarkaSen @Idomathart How do you guys know where the ridges are when just staring at those expressions without graphs? (It's just like the magic when figuring ou how to integrate something)
@BalarkaSen It doesn't matter, you have to stay away from $(0,0)$, or I misunderstand you now
Sure, you're taking limit as $(0, h) \to (0, 0)$ I meant. Sorry for being unclear.
@BalarkaSen That's fine.
@Secret Practice.
ok
---
(NB, actually that thing is not a saddle, better just call it the Windmill surface)
Some time later I might ask or experiment whether you can make a function of the form $\frac{P(x,y)}{Q(x,y)}$, where $P,Q$ are polynomials and get a ridge that is not a simple power of x or y
Otherwise, letting $y=x^n$ for $n \in \mathbb{R}$ will guareentee a solution for multivarable limits for these types of functions
12:25
@robjohn that pumpkin is pretty cool!
I have to finish some math stuff now (also waiting for some mathematical books to arrive here).
12:53
serious
business
Why is this closed ?? Reopen !!
2
Q: Find $ ? = \sqrt[3] {1 + \sqrt[3] {1 + 2 \sqrt[3] {1 + 3 \sqrt[3] \cdots}}} $

mickI wonder about a closed form for $ ? = \sqrt[3] {1 + \sqrt[3] {1 + 2 \sqrt[3] {1 + 3 \sqrt[3] {1 + 4 \sqrt[3] {1 + 5 \sqrt[3] \cdots}}}}} $ I tried solving the related equation $ f(x) ^3 = 1 + (x+y) f(x+1) $ for various fixed values integer $y$ , but I failed. It appears $$ ? = \sqrt[3] {1 +...

apparently
you should specify the sequence of coefficients more clearly
1,1,2,3,?,?,...
It is clear ! 1 , 2 , 3 , 4 , 5 , ... :/

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