« first day (2223 days earlier)      last day (3092 days later) » 
01:00 - 18:0018:00 - 00:00

01:08
Please help, i don't understand with my homework

I don't understand how to simplify product of sum function and i can only find in google how to simplify sum of product function

I understand how to simplify this function by watching a youtube video
https://www.youtube.com/watch?v=8jUN-w0yQSI
F = ABC + A' . B . (A' . D')'

but how do I simplify the product of sum function?
I can't find an example of question like this
F = (A' + B) . ( A + B + D) . D'

How should I do it? Please help me
um, I must do it with K map and not allowed using boolean algebra
01:40
It's even more confusing because it is not written in standared POS
02:08
Okay thank you I have solve it
 
3 hours later…
05:17
Can anyone help me with a linear algebra problem please? I've spent literally tens of hours on it and am desperate.
It is a simple problem but I have issues understanding the trigonometry aspect.
@ThePointer As the room description says: "Just ask; don't ask to ask."
Ok
Using the standard basis of ℝ2 to determine the matrix of the following linear transformation
Simply state your problem and maybe somebody will help maybe not. (And certainly link to the question if you posted it on main, too.)
1
Q: Using the standard basis of R2, determine the matrix of each of the following linear transformations

The PointerI've asked questions about these problems before but thus far, no one has been able to help me understand. I've been attempting these problems for tens of hours over a couple of weeks now. I'm desperate for some help. The problem are as follows: The issue is not the linear transformation aspe...

The reason for this suggestion that without seeing the problem it is difficult to say whether I will be able to help you.
05:25
This is the problem. I am having issues with solving (2)
I have solved (1).
So to find a matrix of the reflection w.r.t. the line which has the angle $\theta/2$ to the x-axis.
How did you want to deal with the problem?
I was using trig ratios to try and calculate the values for (x,y)
Based on the image that was provided
I am not sure what you mean by values for (x,y).
sorry, (x,y) values for f(e_1) and f(e_2)
Ok, so you have $e_1=(1,0)$.
05:28
I calculated f(e_1) to be (cos(theta), sin(theta))
The you immediately see that $f(e_1)$ will have unit length and angle $\theta$.
Exactly as you wrote.
However, I am not getting the correct answer for f(e_2)
Now you need to find $f(e_2)$.
$e_2$ is at angle $\pi/2$. The line is at angle $\theta$. So the angle between them is $\pi/2-\theta$.
So to me it looks like we need the new angle $\frac\pi2-2\left(\frac\pi2-\theta\right)=2\theta-\frac\pi2$.
Is $2\theta-\frac\pi2$ the correct result @ThePointer?
I see a lot of $ symbols in your text, making it hard to understand. Am i doing something wrong?
$\frac\
To get math rendered, you can use bookmarklet from here: math.ucla.edu/~robjohn/math/mathjax.html (The link is both in the room description and in the rules of this chatroom.)
Anyway my results was 2*theta-pi/2. Is that what you are supposed to get?
Sorry, I used $\theta$ instead of $\theta/2$ as the angle of the given line.
So the result changes to $\theta-\pi/2$ if we use $\theta/2$.
05:38
Ok i see it now
working
The solution is
Not that :(
Well, that's exactly what we got, just written differently.
Ahh, I see.
We got $f(e_2)=(\cos\left(\theta-\frac\pi2\right),\sin\theta-\frac\pi2)$, right?
Le't have a look whether we can simplify it.
$\cos\left(\theta-\frac\pi2\right)=\cos\left(\frac\pi2-\theta\right)=\sin\theta$
$\sin\left(\theta-\frac\pi2\right)=-\sin\left(\frac\pi2-\theta\right)= -\cos\theta$
Ahh, I see.
So since we are reflecting both points on either side of the line
it creates an angle of pi/2?
between f(e_1) and f(e_2)?
No, that's not true. Why should it be $\pi/2$?
Just draw a few pictures and you will see that the angle between the two images can be various, depending on $\theta$.
05:45
You said e_2 is at angle pi/2
Yes, that's true.
And angle between $e_1$ and $e_2$ is $\pi/2$.
Oh, I see.
But the angle between $f(e_1)$ and $f(e_2)$ can be different.
I thought you were referring to f(e_1) and f(e_2) my apologies
Hmm
Is there any way to calculate these using trig ratios?
I don't know what are trig ratios.
05:51
That is how I calculated the previous ones but for some reason am not getting the correct answer for f(e_2)
sin(theta) = opposite/hypotenuse, ect
Isn't that what we just did? We found angle for $f(e_2)$ and then expressed it using cos and sin.
Unfortunately, I do not understand :(
BTW in this answer you have a different solution, which uses projection matrix.
@ThePointer So let us try once again.
Yes. However, I am not supposed to solve using the projection matrix.
If it does no help, maybe you can spend some time looking at other similar problems on the main, I listed a few here:
05:55
Ok will do
So we have $e_2=(0,1)$ and want to calculate $f(e_2)$, right?
Yes. It is in the 4th quadrant
First, the angle between x-axis and $e_2$ is $\pi/2$, do you agree with this?
And we have the axis of reflection, which is the line with the angle $\theta/2$.
05:57
Yes
So the angle between $e_2$ and the axis of reflection is $\pi/2-\theta/2$.
So far, ok?
In fact, let us denote $\alpha=\pi/2-\theta/2$ for simplicity.
So $\alpha$ is the angle between the vector we want to transform and the reflection axis.
Now we should ask how the angle changes if we look at $f(e_2)$ instead of $e_2$.
We have to subtract the angle $2\alpha$.
05:59
well f(e_2) is in quadrant 4
Yes
Notice that if we rotate $e_2$ by the angle $-\alpha$, we get a vector which is in the direction of the reflection axis.
If we do it once again, it is the result of reflectoin.
So we need to calculate $\pi/2-2\alpha$.
Is this ok?
Now it is some simple algebraic manipulation $$\frac\pi2-2\alpha = \frac\pi2-2\left(\frac\pi2-\frac\theta2\right) = \theta-\frac\pi2.$$
We know that the angle is $\theta-\pi/2$ and the vector has unit length, which means
$$f(e_2)=\left(\cos\left(\theta-\frac\pi2\right),\sin\left(\theta-\frac\pi2\right)\right).$$
Now it only remains to simplify $\cos\left(\theta-\frac\pi2\right)$ and $\sin\left(\theta-\frac\pi2\right)$.
I got most of it
The part where you say rotate e_2 by angle -a
and then we do it once again, won't that be along the x-axis?
Not necessarily.
You probably drew the picture where the $\theta=\pi/4$.
Try to draw several picture, with various reflecion axes.
What you wrote is true only if the reflection axis is exactly in the middle between $e_1$ and $e_2$.
06:15
Yes
That is true
so pi/2 - 2a gets us to f(e_2)?
Hmm. This method is difficult for me to understand conceptually and generalise.
How would one do this using purely the sin, cos ratios?
And drawing the image?
I think that we did exactly what you said.
Hmm this must be the only way
Yes I think so
If you draw the image you could see that the the reflection works like this.
@ThePointer That is certainly not the only way.
I don't think you can say about any mathematical problem that there is only one way to solve it.
BTW I have posted an answer summarizing what we discussed here in chat.
06:23
Yes it is very elaborate thank you
I am reading it now
And I have also tried to retype your question. (It is better not to use images if possible.)
I was going well all semester
until I got to these two questions
I've spent literally tens of hours trying to understand these. There must be a deficiency in my previous knowledge
Feels very bad :(
Do you mind if I point out some things which I think the question you posted is lacking @ThePointer?
Yes please do
1) You knew what the solution is supposed to be. (You mention this in chat.) But you did not say so in the post. (That's why I have edited your question.)
2) You did not mention where the problem comes from.
It is always good to give all the available details which might be useful for answerers.
06:26
My apologies. I will do this in the future.
It might be useful to read How to ask a good question?. The things I mentioned are in the part about context
@ThePointer Why in the future. You can still improve this post by adding at least the source of the problem.
You can also remove the image if you are satisfied with the transcription.
@ThePointer I know looked at the list of your questions and I see that you have asked the same question as part 2 of this one here.
You should not post the same question twice.
Yes. I became desperate :(
I will not do it again
The only difference seems to be that the other question does not require calculation of the determinant.
Probably the best thing to do is if I delete my answer and post it to the other question - it is more suitable there.
06:33
Ok that is fine
Yes I am reading your answer and it is making complete sense now
:)
Ok, I'll have to go - I have other things to do.
Good luck with your studying!
Thank you very much!
You helped a poor student this day!
I will never forget :)
 
3 hours later…
r9m
r9m
09:10
@Idomathart pls check mail :-)
@r9m wait a second.
@r9m Ah, just read once again what was the point with the problem (otherwise I wouldn't have cared). I send you the email now.
r9m
r9m
@Idomathart I can take it down no problem .. just say the word!
@r9m No, it's OK. Anyway, such problems I can create in the future again.
@r9m I didn't want to have possible problems with publishing, that's all.
r9m
r9m
@Idomathart nah .. now that you mention it .. I should take it down. Btw you can check Tauraso's solution too .. the generalization ain't far from his approach either :-)
@r9m Anyway, let it there. Just in case anything happens, hope you can mention to the publisher one, two words.
Hope all will be fine.
r9m
r9m
09:19
@Idomathart I am taking it down with a note .. no worries. It's better to take it down now than to have publication problems later
them publishers are so annoyingly nitpicky about these things .. it's better
@r9m Only if you want. I would appreciate that a lot!
@r9m Yeah, that's the exact point.
r9m
r9m
@Idomathart I agree to the proposition wholeheartedly. The thought should have crossed my mind b4 .. sorry for causing annoying trouble late at night! :(
@r9m Please check your email and see that I told you in the past about that article I want to publish. Maybe you simply forgot.
@r9m Thanks a huge lot!
r9m
r9m
@Idomathart I edited my blog with a note .. see if it's agreeable now :-)
@r9m :D No need for that long comment. ;)
r9m
r9m
09:29
@Idomathart that's the least I should mention .. :)
@r9m I see ... :-)
09:51
@r9m almost forgot to ask you about the integral I posted here
Just to find it
Can you calculate without pen and paper $$\int_0^1 \left(\frac{\log(1+x)}{1+x}-\frac{\log(1-x)}{1+x}\right) \arctan(x) \textrm{d}x=\frac{\pi^3}{192}+\frac{\log(2)}{2}G$$ ?
It's not a joke or anything like that, it is simply possible.
Then there are other nice two versions you might like to try
$$\int_0^1 \left(\frac{\log(1+x)}{1+x}-\frac{\log(1-x)}{1+x}\right)^2 \arctan(x) \textrm{d}x$$
and
$$\int_0^1 \left(\frac{\log(1+x)}{1+x}-\frac{\log(1-x)}{1+x}\right) \arctan^2(x) \textrm{d}x$$
@r9m I'm sure you might like to try them all. And finishing them all in the spirit of the art. :-)
Just to say it is for Sunday a full of fun! :-)
Ah, I meant a Sunday full of fun.
The connections of these integrals with some class of series are simply amazing.
And as far as I know not-known to the present date.
10:35
@Alyosha 'Sup.
I've just woken.
What are you up to?
Learning some topology.
Good morning, by the way.
And the same to you, modulo time shifts.
11:38
Hi everyone :) "modulo time shifts" hah, hey I was thinking about this solution here math.stackexchange.com/questions/652721/… - very nice and helped me to understand induced mappings in M-V sequences, but I don't catch this final equality, that ends with Z^{k-1}\oplus Z / (2,...,2)Z = Z^{k-1} \oplus Z_2. Z^{k-1}\oplus Z = Z^k since it is finite product or am I wrong? And then it would be (Z_2)^k... where am I wrong??
r9m
r9m
@Idomathart should be doable with that fun transform ;) .. I will try later .. :-)
12:25
@r9m cool blog, i bet chriss will be owed mutual credits as in your blog in her book :)
12:57
Hello! Some hint about summation of i.a^i from zero to n?
13:14
@HiHello Consider the summation of a^i from 0 to n and then differentiate w/r/t $a$.
I was wondering...one usually proves "if $f,g$ are continuous, so is $f+g$" in analysis using sequential continuity. Can one prove it using topological continuity?
i.e. preimage of open sets is open
@Semiclassical The sum is the same that from 1 to n. What does it "differentiate w/r/t $a$" means? I differentiate the sum of a^i in a, and the result isn't the expected.
@0celo7 Adding two functions cannot be done just using the topology on $\Bbb R$.
what do you mean?
Also, it can be done using the $\epsilon$-$\delta$ definition.
13:27
I'm sure it can.
bbl, will explain
also, morning chat
@HiHello w/r/t means 'with respect to'
@0celo7 The epsilon-delta definition of continuity is not distinct from the topological defn of continuity (preimage of open set is open).
@Semiclassical Ok. That didn't work
the point being, you've got one sum that looks like 0+1a^1+2a^2+etc
and another that looks like a+a^2+a^3+etc
if you differentiate the second, you get 1+2a+3a^2+etc, which differs from the first one only by a factor of a
that's a pretty standard technique for this kind of problem.
@Semiclassical I got it. Worked. Now it seens so obvious... hahah Thanks
13:36
Please, help me write a letter to extend my job for more 6 months workplace.stackexchange.com/questions/75385/…
@HiHello no problem. another useful technique is to multiply by 1-a. this is handy here because (1-a)(a+2a^2+3a^3+etc) = a +(2-1)a^2+(3-2)a^3+etc = a+a^2+a^3+etc.
doing that again gives (1-a)(a+a^2+a^3+etc) = a+(1-1)a^2+(1-1)a^3+etc
If this was an infinite series, then that etc. of zeroes in that last expression would continue forever. for the finite case, though, it won't.
so you'll end up with something like a-a^m (i'm too lazy to figure out what m is here)
@BalarkaSen I know.
@0celo7 Then I don't understand your question.
13:51
@did, how to do next? Sorry for pin you.

And @JyrkiLahtonen ?
@Semiclassical Yes. a-(a^(n+1))*(b+1)+n*a^(n+2)
right.
the details are easy enough to work out if you're not careless when multiplying by 1-a.
@BalarkaSen My analysis book defines continuity in general topological spaces and then asks the reader to show $f+g$, $fg$, $f/g$ are continuous, something that was not mentioned in the section on continuity.
So I'm wondering if there's a really slick way of proving this using open sets.
hence, that sum ends up being some rational function whose numerator is a polynomial in a and whose denominator is (1-a)^2.
I'm fine with the sequential proof or $\epsilon-\delta$, but the book makes it seem like there's a third proof
14:00
No, there is no abstract way to do it. You have to get your hands dirty.
Ok, just checking.
Addition, multiplication etc of functions to $\Bbb R$ cannot be done just using the topology on $\Bbb R$, is the reason.
You need the vector space structure of $\Bbb R$. Hence, get your hands dirty using epsilon-delta whenever you try to use that.
Ok.
@BalarkaSen Do you have access to Helgason?
@r9m OK. There I used a new tool I created. Not sure what you want to use, but let me know if you did it using your way.
14:04
@Semiclassical After first (1-a), it works fine, I guess. Because appears (a+a^2+a^3+...+a^n) - na^(n+1). Putting (a+a^2+a^3+...+a^n) as a(a^n -1)/(a-1) I get the answer dividing a(a^n -1)/(a-1) - na^(n+1) by (1-a). No?
that should be right.
i'm not really checking the details, tbh, just signaling that one needs to
@Semiclassical I really liked the differentiation. haha. I've never aplied that on some problem like that, I'm starting university. So, thank you so much.
@BalarkaSen some definitions and a theorem. I'm miffed as to why this is important.
glad you like it, heh
both of them are nice tricks for summations like that.
@BalarkaSen Helgason is in the same vein as Kobayashi-Nomizu, geometry in the Bourbaki style.
They both have weird theorems that don't pop up anywhere else.
14:13
@0celo7 What's $u(\varphi_1, \cdots, \varphi_n)$?
It says that $u$ is a diff. function on $\Bbb R^r$.
Oh, missed that.
If you take $r$ smooth functions on $M$ and plug them into a smooth function on $\Bbb R^r$, you get a smooth function on $M$.
@0celo7 These are important because it's an alternative definition of manifolds.
Essentially it says a manifold is something which locally admit the coordinate functions of $\Bbb R^n$.
Ah, that's how Bredon defines manifolds.
But why is that better than the usual definition?
14:21
Because the usual definition doesn't take account to the information about the smooth functions on the manifold, @0celo7.
But why does one need that?
Why does one need smooth functions on a manifold?
No, why does one need this weird definition?
Need? You probably wouldn't need this.
It's simply of a pedagogical importance, is all.
15:14
hello
15:33
Hello, Carry on.
@Idomathart which tools you have created ?
@Agawa001 I'll share some of them at some point.
@Idomathart you code ?
@Agawa001 No. I did that in high school. Turbo Pascal, some FireFox.
15:48
lol lool firefox isnt a language lmfao
php / css / html ?
ok nvm
just asking about what kind of tools you create
@Agawa001 There is not much to describe in these circumstances, but to show. Let's say there are some special identities that connect some integrals and some series in a very nice helpful way.
i didnt ask you to make them public, just wondering about their usability/ language created by
with mathematica ?
@Agawa001 I suspect they are not known. Mathematica couldn't invent such identities. :-)
me also i create some tools that help me in my work
@Agawa001 Researching you discover all you need. Well, sometimes it takes a lot to get where you want.
15:54
and my coworker wanted them for gold lol they are not available in internet
@Agawa001 don't you share them? :-)
after they become outdated
evil me
:-)
@Agawa001 I would need a whole team for all my ideas, no jokes at all. I'm excessively tired these days, I cannot handle with all the stuff I have anymore.
That means that I have to neglect a lot at least for a while.
noone would handle working solo
4, 5 people would be a good start
15:58
btw that reminds me of AI program i designed in my teens, it integrates by part
@Agawa001 Really? Did you have such stuff?
some intelligent stuff working by decision tree (branch and bound)
@Agawa001 Cool!
oh it is amateur work, i can now design cooler things
@Agawa001 In the past wolframalpha implemented something like that, showing you all the steps, including the variable change.
16:01
@Idomathart you could be twice overwhelmed if you studied AI, better than maths
@Agawa001 Maybe. :-)
well they are deeply and drastically connected
but regarding innovativity and creativity, AI can hand you many many doors
and ways
@Agawa001 Also in mathematics I like much much more to create than to solve, but I admit that at the same time I love to attack some crazy classes of integras, series that seem impossible and humiliate them a bit. :-)
Or classical problems that seemed impossible by elementary means, never done in history like that.
16:08
but the mathematics area lacks innovations and contemporary discoveries, it is abandoned relating to computer science, AI is the science of the modern age
(by the way, I have some issues with my network connection, I can't even edit what I type here)
not underestimating it, because maths stays eternal
once maths stops progress, i assume dozens maybe hundreds other fields stop in parallel
@Agawa001 Maths never stops. :-)
they may hold some years but finally become very infertile without maths
16:13
it's also true that certain instances of mathematics have been forgotten/rediscovered over the years
stuff which some classical mathematician may have considered a century or so ago, say
16:42
@Semiclassical like?
i'll confess, i don't know a lot of examples off the top of my head.
but it's inevitable, given the sheer plenitude of publications over the decades
This MathOverflow question has some examples: mathoverflow.net/q/176425/55904
@Semiclassical in that same vein, AFAIK diff geometry was a relatively obscure field until Eisntein "discovered" it in ~1910
I wonder why it wasn't more popular
Perhaps because we didn't have a good definition of manifold until ~1935
The foundations were pretty shaky
17:19
one way to get a feel for the timeline of a subject is to look at the names associated with it
So, for instance, Levi-Civita's book on tensor calculus was published in 1900, and as I understand it that's the text which Einstein used to master the subject
@Semiclassical I can name like 4 geometers before Einstein.
Riemann, Levi-Civita, Ricci, Christoffel.
After Einstein the field exploded
I presume you mean 'differential geometers'
@Semiclassical Yes.
17:22
@Semiclassical the fft was introduced by ptolemy as far as i know
I thought it was Gauss, at least in some sense
I haven't seen any reference to Ptolemy having a sense of it
@Semiclassical guass developped it, but talking about the first time it was abandonned
That was to Agawa, though I think an argument can be made for him re: differential geometry
He worked on curvature of surfaces, for instance.
@Agawa001 cool. I would like to able to stay like that, however my belief in the power of these exercises tends to $0$.
lol, me i can, im somhow flexible (at a limited point)
17:25
Religions spread too much BS during the time, and this is like a religion.
@Semiclassical who was the first scholar who discovered the true earth rotation (double-sin motion) isnt euclid
What?
Do you mean, the fact that the earth rotates about its axis and also revolves around the sun?
@Agawa001 Science gave people back the power to look at themselves with dignity.
forgive my lack of knowledge, i forgot
who discovered the double-curved motion of earth
yes around itseld + around sun
@Agawa001 However it is clear (for me) that people also live in a spiritual dimension which the science cannot feed. It's complicated.
17:29
@Idomathart yes indeed, but earlier philosophers like socrates paid for their knowledge
@Semiclassical It was Riemann who first dreamt of $n$-manifolds.
The tricky thing is that there's a difference between someone proposing that the earth both rotates and revolves, and someone offering evidence thereof.
But his treatment was very handwavey, akin to an undergraduate GR text really.
@0celo7 Have to start somewhere.
17:31
Looks like Aristarchus is generally credited with the first suggestion of heliocentrism
@Agawa001 Does the science answer to the question Who are we??
:32109438 Just typing too fast.
@Agawa001 is that the retrograde motion of mars?
religions have propositions and they force humandkind to consider it true with no right to criticise, philosophy tries to set some dogma-free assumptions and they are considered false until proven right, science gives experience based facts which are considered true until proven wrong
ahh, metaphysics
this is a general overview about where we come from refering to many sources
and i priorize science then philosophy then religion
my brain does it in this order, while my heart force it in counterclockwise order
@Semiclassical i guess this is the solar system map as firstly proposed by ptolemy
17:46
@Agawa001 Here is something interesting related to any system that (in my view) also has a spiritual side. If you have a friend which is doctor and you can stay and talk to him/her, just asking him/her: Is it true doc that many of the truths in the medicine 20 years ago are not truths anymore? And we talk about science, to be clear.
Depends on what one means by 'truth', I suppose :)
Let me find a relevant article.
If one means a fact that is supposed to be in literal correspondence with reality, then probably most of the things we take to be 'truths' are not so and never were.
Low-salt diets may not be beneficial for all, study suggests
Salt reduction only important in some people with high blood pressure
But eh. Most of the time it doesn't matter if there's a perfect 'mirroring', so to speak, of reality by thought.
What matters is whether those facts are reliable within some domain.
17:49
Eating too LITTLE salt may INCREASE your risk of a heart attack or stroke, claims controversial new research
Please if you have time check how things were treated for many years related to the salt intake!!!
well, you're assuming that the new research is right and the old was wrong.
maybe so. maybe the reverse. maybe it's more complicated than either.
It's all over the place just science!
Just because one source claims it, doesn't mean it's true. Doesn't mean it's false either, to be sure.
No, medicine is full of such situations, and possibly in 20 years, what was considered good is then bad.
Considered good/bad by whom?
17:51
@Semiclassical Accepted as recommended in medicine based upon studies.
@Semiclassical Really, it's a waste of time before you talk to a doctor, maybe you have a friend which is doctor, and then we can continue.
what is common is taht salt increase the exposability to blood flow diseases
Before it was Eating too MUCH salt may INCREASE your risk of a heart attack or stroke, but now we have other titles in papers (based upon studies) Eating too LITTLE salt may INCREASE your risk of a heart attack or stroke
It's science!
wierd
I think that points to the lack of consensus on the subject and the difficulty of actually testing it
17:54
but cholesterol is never contestable
And how easy it is to make a bad study in either direction
The other example of this that circulated fairly recently was flossing
i know what is the general sight is, science is prone to change anytime, but as science changes, circumstances change also, like food,life instruments transport etc, many things change that makes this morphological nature of scientific statements reasonable
Dentists recommend it, but a study came out saying that they didn't find a statistically significant effect from it
01:00 - 18:0018:00 - 00:00

« first day (2223 days earlier)      last day (3092 days later) »