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00:00 - 21:0021:00 - 00:00

00:05
@TedShifrin Hola
hi @PVAL.
Hi @Ted
@PVAL @MikeM: Interestingly, there's a guy trying to read Chern's Lectures on Differential Geometry and posting various questions on Pfaffian systems and their implications.
He had some interesting wording in his first question.
Did I miss the first question? He really was having issues with understanding what "an equation $df=0$" means.
hi @Axoren
00:17
"In most of these lectures, Chern is extremely clear and careful. Is there a particular reason he is not here?"
The implication being that the fault is Chern's.
Yo, @TedShifrin
Oh, right. Well, Chern is not the most pedantic writer on earth. People don't realize that he just "knew" what artillery of forms to write down to make his original proof of the Gauss-Bonnet-Chern theorem work. Amazing intuitive command of all the Cartan machinery.
At any rate, I did try to suggest to him that he needed to understand what an equation like $dx=0$ means. I think he's making progress.
@Ted: If you care about the question I asked about analytic regularity of mildly nonlinear PDE, one of the faculty members here told me he's rather confident it's true, but didn't have a reference off the top of his head.
One has to be very careful. I remember from grad school that Hans Levy had a very famous counterexample to some claim like that.
00:23
But his counterexample was dependent on the complex analytic setting, I think. I wonder if this is google-able.
Hi, @user19405892
I believe you're referring to a version of Cauchy-Kovalevskaya, which is an existence theorem for simple analytic PDE. I believe Levy disproved this in the smooth case.
how do you find the number of positive integer solutions to 5xy+y = m
of (x,y)
Yeah, @MikeM, you're right.
I'm surprised I haven't forgotten everything from those days.
That's a very strange looking equation, @user19405892.
In any case, my question is really about the distinction between equations that are linear and only mostly linear. I do have the same analytic regularity in the linear case.
Then I wonder if there's some sort of Nash-Moser implicit function theorem argument to be made, @MikeM.
00:26
@TedShifrin Yes, indeed but i am curious how or if it is possible to find a closed form for the umber of solutions and not just an upper bound
So, what happens when I add a quadratic term that doesn't use any derivatives? The rumor is I should still have analytic regularity.
@Ted: I'm talking real analytic. Does their work apply in such settings?
I think so, @MikeM. Double check.
Oh, interesting, I know how to coerce complex analytic results out of the smooth implicit function theorem, but maybe not real analytic.
I'm a little dubious nonetheless but I should understand Nash-Moser better.
I have no clue, @user19405892. If it were truly a quadratic on the left side, there'd be number theory types who are used to such questions.
@TedShifrin I am trying to solve 5xy+y-n = 1000 where n is the number of solutions (x,y)
00:30
Started going to the PDE course (in week 9) that I just learned existed. Looks pretty good and like I should be able to catch up before next quarter.
I have a feeling your Griffiths & Harris troop isn't going to make much progress, @MikeM :P
It's temporarily dead. We think we're resuming in the summer.
LOL ...
We were all just too busy this quarter.
Yes, I knew that would happen. That's a fearsome undertaking.
00:31
I need to go back and learn it to spite you.
I dare you to spite me! ...
I do my best work out of spite. :)
I know that. Out of spite, you can figure out how to do all those homework problems that I no longer know how to do, too.
As long as I'm not happy about it, sure.
And don't forget you still owe me a dinner.
00:36
What's this one from?
Ages ago ... Hell if I remember.
Who's to say I still owe it then? :)
I knew you had no ethics... just like a politician.
Yikes.
What should I teach tomorrow? I forgot what we decided on last time.
I suggested proving Gauss Bonnet for surfaces using $d\omega_{12}$. I have no idea.
00:49
Ah, yes. Good choice.
You can then tell them what the connection $1$-form measures and use the change-of-frame formula to see how the index of the vector field comes out. (This is done somewhat tersely in my on-line notes. I already gave you permission to steal.)
Yes, that's a good idea. Last week I told them my perspective: connections are generalized exterior derivative operators.
Of course, you can mention geodesic curvature, too :P
If GB doesn't fill up my time I can also talk about Newlander-Niremberg which says that complex geometry == dbar operators.
IMO, at least.
That's just the local analytic underpinnings. Definitely overtrivialization.
00:54
That's fair.
01:13
Hey @TedShifrin
Anyone know any relatively easy conditions on k so that $8k+1$ is not a square.
I got that one already
k=4 as well
01:31
Hi @Cbjork
@PVAL Is $k\neq\frac{\Bbb{Z}^2-1}{8}$ too complicated?
It's too stoopid :)
I don't see the motivation
Sorry @PVAL I don't know. I'm supposed to learn about L-spaces for the next hour instead.
@Ted I've been having trouble with one problem. The problem is: "From a cylindrical cake with chocolate icing on top, cut successive slices of a fixed angle x. Each slice is then inverted and inserted back into the cake. Find all angles x, such that after finitely many iterations, all the icing is back on top of the cake."
01:34
Just eat it all, Cameron.
@MikeMiller I don't know very many examples of those ( \Sigma (2,3,5),S^3, Lens spaces).
@TedShifrin This comment without further explanation deals a great blow to my sense of trust and respect
Thanks, Ted. The answer is all angles, but I don't know how to prove it. In other news, I learned what the $\frac{A}{\sin(\alpha)}$ means in the law of sines.
@PVAL: I think every surgery on the trefoil of slope greater than 1 is an L-space.
As a special case of the L-spaces are forever theorem.
Are you taking a class from Mo, Cameron?
01:38
@MikeMiller That's some surgery exact triangle thing using how simple HFK-hat of the trefoil is i think
One of the important circles' radius ...
It instantly yields 2 and 4, as well as 5, 7, 8, 9, 11, 12, 13, 14, 16, 17, 18, 19, 20, 22, ... I'll just judge harshly over here, oh well.
I'm ok with that, @MickLH.
@PVAL You probably know more about HFK than I do.
I'm not really, I'd rather an explanation
01:41
Well I can probably compute for the trefoil if I tried hard enough (doubt I could for any other knot).
figure-8 maybe
Computing HF for genus higher than 1 is tricky...
Tricky but algorithmic
Note +1 surgery on the LH trefoil is -\Sigma(2,3,7) which is not an L-space.
So you better specify right-handed.
Well... as you've only managed to say "It's stupid." I hope you won't blame me for settling on the conclusion that it's simply a petty, egotistical reaction to the non-standard notation.
Yeah yeah.
What's the maximum length of a huffman code for a single glyph in an alphabet of size 256?
01:46
Seventeen
Jeez, that's pretty big. Over twice what it would be normally.
Were it coded in binary, for example, each allotted 8 bits.
No class from Mo, Ted. He just leads the GRE review workshop I'm going to
In that case it's three hundred and forty
01:49
I doubt you could compute HF for n-surgery on the trefoil using that algorithm alone.
Sure.
But I bet if you asked my advisor he could compute it. I bet that about most things HF.
@MikeMiller 340 bits?
Or was that directed elsewhere?
@Axoren I have no idea what you're talking about and am being an idiot. Ignore both of my comments since there is no value to them.
@MikeMiller Seventeen was actually a reasonable answer. A huffman code for a single glyph can be nine, even though its original binary code is eight.
I just don't know where it stops.
I assumed when I said it that my answer was much too small.
And that you would immediately stop paying attention.
01:52
@MikeMiller You just told me what it was (at least modulo grading). I mean one doesn't prove something like that using something like Sarkar-Wang. One needs something extra about the invariant which allows it to be easily computed (pretty sure in this case its just the surgery exact triangle).
Unfortunately, shots in the dark sometimes hit.
But I picked the wrong number.
@PVAL: I told you HFred and HFhat. Are the other HFs of L-spaces completely determined by that and algebraic data? I doubt it.
But I guess you meant HFhat anyway.
I meant HFhat
without even considering the grading
Sure.
I guess the grading is in and of itself interesting but whatever
@MikeMiller Apparently, your 340 was a closer guess. The upper bound is alphabetsize-1, which would have been 255. $|255 - 17| = 238$, $|255 - 340| = 85$
I'm actually surprised it can get that big. Must be for that character that gets used once a year.
01:58
Yikes
I gave my undergraduate orderable groups in our undergraduate directed reading program.
@PVAL: Apparently HFL of an L-space link is determined by the alexander polynomial, which is interesting.
I told him (not knowing any differentiable topology) last week that he should try and learn about foliations.
That was too hard no?
Idk well see.
02:01
Order able groups should be accessible.
If the foliation thing works out let me know and let me know what you used for if.
@PVAL What's the inverse of foliation? Exfoliation?
A foliation is an object, not an operation, so it doesnt make sense to invert it
I gave him a set of lecture notes by Rolfsen for the orderable groups stuff. I want to see how forcing the student to find the source works out (much of the most useful sources for my own research I found myself).
@MikeMiller Shame. I was hoping to make a topical pun.
@Axoren I read in some survey that contact structures were the opposite of foliations.
02:04
@PVAL They should call those exfoliations, lest they waste the opportunity for humor.
@PVAL: I suspect the Eliashberg-Thurston paper/book begs to differ.
I think there are some places and situations in which it's better to tell someone to find the right sources. But sometimes one will find a source that's bad and since it's a source they'll stick with it.
Maybe he can prove that every 3-manifold with a left-orderable fundamental group admits a taut foliation and vice versa without ever touching these nonsensical modern homology theories...
@MikeMiller Hopefully I can tell him if a source is bad.
Well, @PVAL, that makes sense, since they're in some way optimally non-integrable.
@PVAL: Scandalous!
@TedShifrin Ya though I don't know what one is supposed to get out of this analogy.
I think that was the justification the survey used.
02:09
Nor I, but I'm not responsible :P
I'm fond of the modern nonsense.
<--- fond of ancient nonsense.
An ancient, fond of nonsense?
No, an ancient fond of ancienter nonsense.
In a very concrete sense plane fields are the derivatives of foliations.
02:14
But more general, of course.
Because most distributions are non-integrable.
I wonder what the space of foliations looks like. It's Thurston's theorem that the inclusion of the space of codim 1 foliarions on a 3-manifold into the space of plane fields is a surjection on pi_0.
That's a pretty weak statement. :)
And of course there's eliashberg' theorem that the space of overtwisted contact structures is homotopy equivalent to the space of plane fields.
I would quite like it if the space of foliations was indeed equivalent to the space of distributions.
I think that would make the world fall apart.
I don't.
02:21
Making everything integrable. There would be a total earthquake.
I disagree with the bit about a weak statement.
Well, @PVAL, it seems to me weak to say that every non-integrable distribution can be joined by a path to an integrable one.
I don't say that I've thought about how to prove it. Not insulting Thurston in the least.
I can construct lots of plane fields for you that can't be joined by a path.
I didn't say that. I just have to put in an integrating factor homotopically.
No, that's not right.
But it's close.
@Ted: Try to prove it! Actually for 3-manifolds it's not hard, but the general case for codim 1 distributions on n-manifolds was probably the theorem that people consider Thurston as solving foliations.
02:25
Yeah, I can see that dimension 3 is easier because $\omega\wedge d\omega$ is already top degree.
Actually I don't know how to do it for 3-manifolds. I only know how to prove existence of a foliation.
It should be something like write a surgery presentation for the 3-manifold, and make a foliation of S^3 such that that components in the link are all reeb components.
Yikes.
I think something like that should extend to the surgered manifold.
tunes out
02:35
Ya thats what it looks like Wood does here. jstor.org/stable/1970673?seq=8#page_scan_tab_contents Maybe it's a little different but I am pretty sure he gets a reeb component for each component of the surgered link.
Yea that's how I construct a foliation. I guess it's not much more work to homotope a generic plane field to such a thing.
@Ted: Foliations are hard.
?
I have no idea how you could restrict the homotopy class being realized.
how do i solve this integral? 0 / 2 (60 - 1/2t)dt
the next step is this: (60t - 1/4 t^2)
Plus, as I commented to that guy reading Chern, there's a big leap from local to global. I was just thinking about local.
i dont understand how 1/2 went to 1/4
02:39
@Adan, because the integral of t is 1/2 t^2.
ah
Now you're all set :)
@TedShifrin hi
hi Karim
thank you!
02:42
Sure thing, @Adan :)
OK, dinner time for me. Night, all.
Now I just wonder what $\pi_1$ of 2-plane distributions are on say $S^3$.
I guess that's just global sections of the trivial bundle $Gr_2(\Bbb R^3)\times S^3$
Is there a good way to revise this in a good way since i want to write a PHD mathematical thesis in topological accounting: math.stackexchange.com/questions/1677829/…
@MikeMiller - Cheer!
You could start by removing the screenshots. If you have any friends that are fluent English speakers maybe ask them if it is understandable.
02:58
@PVAL Can i get a little advise here?
03:21
hi what's velocity?
having trouble understanding displacement
velocity = position/time = displacement / time
 
1 hour later…
04:47
What are you having trouble with @Adan?
Try watching this
:-)
 
4 hours later…
08:24
Hello
can someone explain to me the classifications for linear equations? I don't understand what the terms mean. Consistent, inconsistent, and dependent and how a system of equations can be both.
09:05
Try reading this @XTImpossible
hi guys, im having some doubt on a question and apparently it has been posted so what should i do?
is there anyway to *bump questions here
or should i post the same questions and then close as dumplicate to get the attention
*deuplicate
*duplicatr
shit sorry *duplicate
 
1 hour later…
10:31
this question contains an error , 111 1011 is 123 in decimal, can anyone with high rep edit it ?
Hi guys
@Agawa001 sure thing
hi @enthdegree
11:01
What does $\Bbb C[SL_2]$ mean?
@Integral My guess would be the coordinate algebra of the group scheme $SL_2$ over the complex numbers
though it might also refer to the group algebra
@TobiasKildetoft what is the expression for finding out the order of a product of two cycles?
@TobiasKildetoft What is a group scheme?
@Paradox101 As long as they are disjoint, it is the lcm of their lenghts
@Integral a group object in the category of affine schemes (i.e. an algebraic group)
@TobiasKildetoft What if it were just a coordinate ring? does this have less structure than a coordinate algebra?
11:16
Ok thank you
@Integral those are the same thing. Being an algebra in this case just means it is also a vectorspace over the complex numbers
which it will definitely be with that notation
what about a case where they aren't disjoint?
@Paradox101 then nothing much can be said until you make them disjoint
@Integral But if you are not familiar with group schemes, what does $SL_2$ even mean?
I thought it might have been SL(2)
special linear group
And I thought $\Bbb C[SL_2]$ might have been SL(2,C)
@Integral writing $SL(2)$ is also pretty terrible. Over what field should that be intepreted?
11:20
Yeah that's why I thought $C[SL_2]$ might have been that
@Integral It is definitely not that (unless whatever you are reading uses really unusual notation)
Yeah it isn't, I think yours is right
in what context is this?
Just trying to understand what my tutor was saying to another student so I don't fall behind my class mates, but I think it was representation theory
11:26
@Integral Well, that might indicate either of the possibilities I mentioned
So $\Bbb C[x]$ is the polynomial ring in indet $x$, is $\Bbb C[SL_2]$ like a polynomial ring, in the elements of $SL(2,k)$?
@Integral More precisely, rational representations are comodules over the coordinate algebra, but representations (not necessarily rational) are modules over the group algebra
@Integral In some sense, yes, but only in a very vague sense
If it is the coordinate algebra, then it is actually a quotient of the polynomial algebra in four indeterminates, mod a suitable ideal
12:01
If $S$ is the set of one-to-one mappings of $S$ onto itself, and if $x_0 \in S$, what is meant by $H(x_0) = \left\{\phi \in A(S): x_0 \phi = x_0\right\}$? The element $\phi$ in $A(S)$ that maps $x_0$ onto itself?
Huy
Huy
12:37
@DeMoivre: do you mean that $A(S)$ is the set of one-to-one mappings of $S$ onto itself?
Oh, sorry about that yes.
Huy
Huy
@DeMoivre: and are you sure you want $x_0 \phi$ and not $\phi x_0$?
@Huy I've been figuring out what my book denotes $x_0 \phi $ means $\phi x_0$ almost everywhere else!
Huy
Huy
@DeMoivre: likely a typo
@DeMoivre: but yes, then, $H(x_0)$ consists of all one-to-one mappings $\phi$ from $S$ to itself that satisfy $\phi(x_0) = x_0$
is that group theory or what are you studying?
@Huy, it's intentional. I remember him saying something about algebraists preferring it that way in the earlier chapter. Yes, group theory (Topics in Algebra - Herstein).
Huy
Huy
12:45
@DeMoivre: weird, I don't think I've ever seen it that way. but then again I hardly know any algebra.
@Huy how would I show that it's closed under multiplication?
Huy
Huy
@DeMoivre: by multiplication you (or they in the book) mean composition
Yeah.
Huy
Huy
that should be fairly obvious then, where are you struggling?
you know what "closed under composition" means, right?
What I was trying to show is that if $a, b \in H$ then $ab \in H$.
Huy
Huy
12:54
that is what you want to show
maybe use the same notation
if $\phi, \psi \in H(x_0)$, then $\phi \circ \psi \in H(x_0)$ is what you want to show
what property determines whether or not a map belongs to $H(x_0)$?
That it sends $x_0$ to $x_0$
Huy
Huy
ok
now can you determine whether or not $\phi \circ \psi$ satisfies that property?
$\phi \circ \psi (x_0) = \phi (x_0) = x_0$
Should be $x_0 \phi \psi = x_0 \phi = x_0$.
Huy
Huy
I'd write it the first way but well
if you want to go the other way, you probably need to write $x_0 \phi \psi = x_0 \psi = x_0$
Yeah, you're right. I find that "usual" way easier. Even in my course we would write $\phi \circ \psi (x_0) = \phi (x_0) = x_0$.
Thanks, @Huy. I was lost in the notation on this!
Huy
Huy
13:05
np
13:17
Hello!!
0
Q: Approach on solving limit equation systems and finding some f given assymptotes?

SecretThis is a "reverse" question of finding the asymptote of a function Recently, I am interested in doing some sort of modelling which involve equations of the form $$@(t)=1-f(t)$$ where $f(t)$ is required to satisfy the following properties $$1^*:\left\{\begin{matrix}f(0)=0 \\ \lim_{t\rightarro...

@MaryStar do you know any algorithmic ways to solve a system of limit equations?
Does it stand that $$\lim_{x\rightarrow \infty}\frac{(1+x)^p}{1+x^p}=1$$ for $p>0$ because we look only at the terms of highest order of the numerator and the denominator?
@Secret Not really... Sorry...
@robjohn do you have an idea about my question above?
I think the x can be pulled out as usual
$$\lim_{x\rightarrow \infty}\frac{(1+x)^p}{1+x^p}$$
$$=\lim_{x\rightarrow \infty}\frac{(x(\frac{1}{x}+1))^p}{x^p(\frac{1}{x^p}+1)}$$
$$=\lim_{x\rightarrow \infty}\frac{x^p(\frac{1}{x}+1)^p}{x^p(\frac{1}{x^p}+1)}$$
$$=\lim_{x\rightarrow \infty}\frac{(\frac{1}{x}+1)^p}{(\frac{1}{x^p}+1)}$$
$$=\frac{1^p}{1}=1$$
since p is real thus it is distributive in multiplication
I see... Thank you!! :-) @Secret
13:55
morning
15:06
morning
15:22
morning
@Semiclassical any algorithms or approaches you know of that can handle systems of limit equations?
not that i know of
@MaryStar Secret'a method is what I would have used.
Ok... Thanks!! :-) @robjohn
for any fans of generating functions out there, i posted this question just now
0
Q: Does the functional equation $p(x^2)=p(x)p(x+1)$ have a combinatorial interpretation?

SemiclassicalA recent question asked about polynomial solutions to the functional equation $p(x^2)=p(x)p(x+1)$. Subsequently, Robert Israel posted an answer showing that solutions are necessarily of the form $p(x)=x^m(x-1)^m$. What I had hoped to do myself was provide a solution by interpreting $p(x)$ as a g...

15:26
@robjohn any algorithms or systematic approaches you know of can handle system of limit equations? (I am not even sure if there's a fiel of study for them cause I rarely see limits appearing in systems of equations)
@Secret I don't know of anything in general. Do you have examples of what you're looking for?
1
Q: Approach on solving limit equation systems and finding some f given assymptotes?

SecretThis is a "reverse" question of finding the asymptote of a function Recently, I am interested in doing some sort of modelling which involve equations of the form $$@(t)=1-f(t)$$ where $f(t)$ is required to satisfy the following properties $$1^*:\left\{\begin{matrix}f(0)=0 \\ \lim_{t\rightarro...

Not sure if it is concrete enough ,but I am interested in given some asymptotes, find some functions that basically describes the decay of a population\
That is, I am interested in given a starting value, find as many functions of t such at at the limit of infinite time, it decays asymototically to zero

and then I am wondering for more complicated systems of equations where the assymptotes are functons of t themselves
So for the population example in the question, there happens to be an easy graphical solution. However I am not really sure if finding that solution can be expressed algebriacally
@Secret so you're trying to find functions that satisfy a given set of conditions?
yup, and that the constraints involve limits
I am aware of constraints in functional equations, differential, integral equations, but i found almost nothing that mentioned about systems of limits
which is why I am stuck on how to approach the probelm in the first place via an algebraic approach
correction: I am aware of handling constraints in
15:51
I continue to see questions that are "homework" question with little effort. May I add a comment to those closed question referring them to algebra.com, a free math tutor site? I post there to practice my HS math teaching, but am otherwise not affiliated. Asking here, because I don't want it being considered spamming. (It's just one every couple days, no intention of going back to old ones) Simple questions are welcome there and for these questions, it would help the OP.
@Secret I think that this gives to vague a condition in most cases to present a unique solution. That is, there are too many solutions to give a good approach.
@JoeTaxpayer Perhaps get them to put a blurb in the sidebars. They will have to contact the StackExchange community managers to get information about that.
That would be better than a user advertising for the site.
Thx - I'll suggest that to the site owner.
I see
16:15
@robjohn If there is a matrix $W$ such that $W={ A \in M : A_ij =0 i>j}$ where $M$ is an $m$ by $n$ matrix, then I can say that $W$ is a subspace of $M$ right?
@Paradox101 I think you are asking about Triangular Matrices.
@Paradox101 and the product of two lower triangular matrices is a lower triangular matrix.
@robjohn kind of, although I have to prove that the direct sum of two matrices, an upper triangular and a lower triangular is equal to the matrix $M$. for direct sum, the triangular matrices have to be a subspace of $M$ right?
16:32
@Paradox101 In the context of inner product spaces, that is usually true.
@robjohn so then in this case, I can take it to be true and then proceed to finding the direct sum right?
@Paradox101 usually one speaks of a space being the direct sum of two disjoint subspaces, not a single element being a direct sum of two other elements.
@Paradox101 of course, diagonal matrices are both upper and lower triangular.
so then in this case, won't an upper and lower triangular matrix be disjoint subspaces?
so for two such matrics $W$ and $A$ i can say that their intersection is ${0}$?
There is a hierarchy of upper triangular matrices that have the diagonal $0$ and then the next diagonal above that $0$, etc. I forget their names...
@Paradox101 So you could take the direct sum of lower triangular matrices and strictly upper triangular matrices
so in this case, we have an upper triangular matix which is $W$ and then a strictly lower triangular matrix $A$ so I can then take it's direct sum?
how would I write their intersection though? @robjohn
16:46
@Paradox101 Intersection? the only matrix which is upper triangular and strictly lower triangular is the zero matrix.
trivial intersection is counted as disjoint
@robjohn yes. In the book I'm reading a direct sum is described as follows: A vector $V$ is called the direct sum of $W_1$ and $W_2$ if they are subspaces of $V$ such that intersection is ${0}$ and $W_1+W_2=V$. That's why I was asking about the intersection. since 'the only matrix which is upper triangular and strictly lower triangular is the zero matrix' then it follows the definition of the direct sum
I thought we needed two condition for $H \subset G$ to be a subgroup of $G$. (i) $a,b \in H \implies ab \in H$, and (ii) $g \in H \implies g^{-1} \in H$. However, my tutor said we need a third condition; (iii) $e \in H$. Isn't this contained in (i) and (ii), i.e. $ g \in H \implies g^{-1} \in H$ thus $gg^{-1} \in H$?
17:04
He gave us a counterexample to my claim: $H = \left\{[3]_{13}[6]_{13}[9]_{13}\right\} \subset \mathbb{Z}_{13}^{\times}$ O_o
I'm not paying much attention because your claim has no counterexample. If a subset is closed under product and inverse and is nonempty, it's a subgroup.
I mean, I guess that's the real point of (iii). It guarantees your subset isn't empty.
Uh, that's clearly not a counterexample, anyway, because it's not even a little bit closed under product.
Oh, that it guarantees the subset isn't empty makes sense!
17:41
Hi everyone, I'm a gambler and I start with $x$ money, i put down a dollar and get 2 dolalrs back with p=0.5, and lose my dollar with p=0.5. I am interested in how long it will take me to either A) go broke or B) reach N dollars. Take T to be this stopping time.

I showed $(X_n^2-n)$ is a martingale and that I reach N dollars with probability $x/(N+x)$, but now how do I get the EV of how long it takes to finish the game?
I used the optional stopping theorem to say that E[X_T^2-T]=E[X_0^2-0]=x^2, so that E[T]=E[X_T^2]-x^2=x/(N+x)*(N+x)^2-x^2=Nx
But the answers say its supposed to be x*(N-x)
Where did I go wrong???
18:00
Hey @DanielFischer

Do you have an idea about the following?

http://math.stackexchange.com/questions/1678826/find-the-smallest-number-of-linearly-dependent-columns
18:45
I need to find the equation in cylindrical coordinates $(r, \theta, z)$ for the sphere of radius 2 centered at the origin. I said that $r=2, 0 \leq \theta \leq 2\pi, -2 \leq z \leq 2$. Apparently r = 2 is wrong, but i don't understand why. Is it actually wrong?
@Pallas That is correct for spherical coordinates but not cylindrical.
what should r be for cylindrical though?
i don't understand because in rectangular coordinates, then it is $\lange 2\cos\theta, 2\sin\theta \rangle$, so in cylindrical it is $r = \sqrt{x^2 + y^2}$, so that is 2
So $z^2= 4-x^2-y^2 = 4 - r^2$
How did you get that?
From cylindrical coordinates you always have r^2 = x^2 + y^2 and the sphere equation in cartesian coordinates is x^2 + y^2 + z^2 = 4. Then just substitute.
18:56
oh ok
so x^2 + y^2 + z^2 = 2^2
and z can be 0 to 2 \pi
19:26
@Clarinetist hi! Are you about?
@Clarinetist I have a much simpler entropy question this time :)
 
1 hour later…
20:35
Hello
20:49
Suppose that we have a set X. Can we say that X is a coset of X?
@Evinda cosets are either something to do with groups (so you need a group) or something in the dual category of the category of sets (this is not what you mean I think)
I have a code , that it is a linear subspace of $\mathbb{F}_q^n$. @TobiasKildetoft
@Evinda that sentence does not really make sense
@TobiasKildetoft It's from Coding theory... And we said this proposition.
@Evinda You really need to include all necessary context to have any chance to get an answer
2
20:55
@TobiasKildetoft Ok... I am sorry...
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