Mathematics - 2011-12-19 (page 3 of 3)

Skullpatrol

15:02

Earlier you said "Some people think "n" is not a number.
but then how can n = 3?" would you care to elaborate on that sir?

QED

how?

N3buchadnezzar

2 is not a number, to the arabs, or the chinese.

Skullpatrol

@QED What did you mean?

@QED Was this a statement about the use of "n" for a variable?

QED

I've talked to people before who think there's something special about numerals

like 35 is in some way different than m or n

Skullpatrol

True

QED

15:05

but it's not

N3buchadnezzar

35 and m and n are just symbols, which we give meaning...

QED

yes

N3buchadnezzar

Qed I sort of hate you now

QED

why

N3buchadnezzar

Giving me too much to think about, before my exam tommorow..

QED

15:07

don't worry so much about exams

N3buchadnezzar

If we asume 2 and 3 are just symbols, which we say represent the quantity of two and three oranges.

QED

I tried supposing that x is of the form $\frac{A + \sqrt{B}}{C}$ and computing the RHS of $x = (x^2 - a)^2 - a$.

but the expression you get in the end is pretty complicated.

Skullpatrol

@QED As explained in the link the definition of a variable is circular

N3buchadnezzar

That is my defininiton of 2 and 3. 2 represent the quantity of two oranges.

QED

(we want to solve A,B,C in terms of a)

N3buchadnezzar

15:08

Now how would i represent some irragular number?

QED

@Skullpatrol, maybe that definition sucks? I use lambda calculus instead

@N3buchadnezzar oranges are irrelevant

and misleading

N3buchadnezzar

Well symbols needs to have a definition =)

Skullpatrol

@N3buchadnezzar With a variable it is a symbol used to represent one or more numbers

N3buchadnezzar

Thats a circular definition

Skullpatrol

@N3buchadnezzar books.google.ca/…;

QED

15:13

What am I saying is that n is a number

Skullpatrol

n is a letter, last time I checked sir

@QED A rose is a rose is a rose

QED

I think you need to learn lambda calculus to understand the point of view I am suggesting

I said you need to learn it

Skullpatrol

My apologies

QED

it's a very worthwhile theory to learn

Skullpatrol

OK, I'll give it a try.

QED

15:25

The best text I know of is this you only need chapter 1

Skullpatrol

WOW!!! thanks that's a great resource

QED

yeah :)

Skullpatrol

Before I go diving into the book could I tell you what an old teacher of mine used to say about "Some people think "n" is not a number.
but then how can n = 3?"

QED

yes

Skullpatrol

n = 3 is an equation that is true when only 3 is substituted for n

3 = 3 is a true statement

@QED How does that sound?

QED

15:35

that's fine

Skullpatrol

@QED Thanks again for the great reference ... bye

QED

bye

N3buchadnezzar

QED

this reminds me of a great picture I once saw on the internet

Ilya

@Asaf: are you here?

Skullpatrol

@QED Quod Erat Demonstrandum

N3buchadnezzar

15:38

Someone solved a second order differential equation, using his own symbols. Like dogs, rats. Rather funny.

QED

heh

N3buchadnezzar

2

Srivatsan

@Ilya, How you doing?

Ilya

@Srivatsan hi ) well, I'm almost ok. how about you?

Srivatsan

I'm good. In which part of the world are you in right now? Netherlands?

Ilya

15:43

in Old one )

I have a lame question in elementary set theory, would you help?

very lame

Srivatsan

Sure, go ahead.

Ilya

ok, there are two sets: $A$ and $B$

let $A'\subset A$ and $B'\subset B$

FreakEnum

@Srivatsan I've a Q in probability ,can you help pleaseee?

QED

I wish you would say question instead of Q.

FreakEnum

kk

Srivatsan

15:47

@FreakEnum Wait for a little bit. Middle of something, as you can perhaps see... =)

FreakEnum

There are 6 girls and 6 boys , what is the probability so that no girl sits together?

I don't need solution but why my method is wrong I want to know

Ilya

hell. let me think...

QED

@FreakEnum I think that question isn't specified well enough

you need to say more to define it

Skullpatrol

@AsafKaragila Ilya has a lame question in elementary set theory, would you help?

Ilya

if I can construct two injective maps $f:A'\to B$ and $g:B'\to A$ does it mean that $|A| = |B|$?

FreakEnum

15:51

@QED there are 12 seats total on which 6 G and 6 B are to be seated .

Ilya

@FreakEnum round table?

QED

It's still not enough

FreakEnum

@Ilya no

Srivatsan

@Ilya If that's all the requirements, then no, right? Take $A'$ and $B'$ to be singletons...

Ilya

@Srivatsan yeah, that's why it was delay and hell

@QED smth bothers you, doesn't it?

Srivatsan

15:53

@Skullpatrol Are you trying to irritate him (or for that matter someone else here)? =)

@Ilya My A would be Y. =)

Skullpatrol

@Srivatsan Not really

FreakEnum

@QED 6 boys and 6 girls sit in a row at random. Find the probability that the boys and girls sit alternatively

QED

@Ilya, yes

@FreakEnum, you can just count the ways they can sit alternatively (2) and then the total number of possible ways to sit

Ilya

@Srivatsan: thanks

Srivatsan

@Ilya For listening patiently? :=)

You're welcome, of course.

FreakEnum

15:56

ok , letme post my solution so that you guyz can help me what I did wrong

Srivatsan

@FreakEnum OK. First, I will state the question clearly for reference. There are 6 boys and 6 girls, they are made to sit in a line in a random order. What's the probability no two girls end up next to each other?

QED

@FreakEnum had you already solved it before asking here?

FreakEnum

@QED yes

@Srivatsan yes

QED

You shouldn't do that :/

Srivatsan

@QED - why not?

I can't tell if you're joking or serious.

QED

15:58

you should say you need to check your answer

rather than asking how to solve something

Srivatsan

- which FreakEnum did, somewhere in between...

QED

?

Srivatsan

See here...

FreakEnum

my solution :

Sample space = 12!;
now, Lets 6 boys sits first on 6 chairs , then no of ways = 6!;
now girls can be sit on 7 places i.e Boy= "*" , Girl="#" , Seat = "_" , so _*_*_*_*_*_*_
so girls can be sit in = 7P6 ways;

so my answer (6! * (7P3))/ 12!

Srivatsan

wait. This looks reasonable, but I somehow doubt every step of this...

What's 7P3 doing here?

QED

16:02

I'm happy to help people if they're stuck with something I can do, but I think it's unhealthy to get into the habit of checking answers

FreakEnum

@Srivatsan sorry , typing mistake = answer = so my answer (6! * (7P6))/ 12!

QED

also if you're in school you should let the teacher check your answers instead of people online

N3buchadnezzar

All the possible combinations of placing 6 persons on 12 chairs, $minus$ the possibility that they are evenly spaced

Srivatsan

@N3buchadnezzar Almost, but not that simple.

FreakEnum

@QED no I don't want to get answers to be checked but need help to know what I did wrong. Sorry if that hit in bad way

N3buchadnezzar

16:04

I figured =)

QED

it's fine, I'm just explaining myself

Srivatsan

@N3buchadnezzar What about #**# *#*#*#*#?

* = boy and #=girl, space is only for readability.

N3buchadnezzar

Why not simply label them B and G...

QED

There are 12! ways 12 people can sit in a row

Srivatsan

@N3buchadnezzar I did that before I posted. It wasn't easy to read a string of 12 letters clearly.

QED

16:07

There are 2 * 6! * 6! ways they can site alternating gender

Dylan Moreland

Best username

Srivatsan

@FreakEnum I don't know what's wrong with this. But can we try with 2 boys and 2 girls?

QED

@DylanMoreland, you've not met VVVVVVVVVV then.

Srivatsan

@DylanMoreland Actually, this is the not the first user with such a name. There was a someone with a handle like "qqqqq*qq*qqqqqqq" (The *'s were actually two other letters. I don't remember the exact handle, obviously.)

FreakEnum

@Srivatsan sure :)

Srivatsan

16:12

@FreakEnum Forget dividing by 4!. Let's calculate the number of ways. Your answer is 2! x 3P2 = 2! x 3! = 12.

FreakEnum

@Srivatsan yes

Srivatsan

Check here: wolframalpha.com/input/…

Let's say A and B are girls, X and Y are boys.

FreakEnum

ok:)

Srivatsan

3 | 2 | 1| 3 | 3 , which adds to 12.

I don't know, seems to be right. =)

Your logic also seems right actually.

Why do you think there's a mistake?

FreakEnum

@Srivatsan because my answer mismatches book's answer :(

Srivatsan

16:20

@FreakEnum What is the textbook answer?

FreakEnum

for our 2 b and 2g's , it's 2* 2!*2!

QED

You should just ignore the text book answer

solve the problem in such a way that you know you've got it right

Srivatsan

@QED How do we know we got it right?

@FreakEnum Can you state it for a general $n$ boys and $n$ girls?

QED

write the answer out clearly using small logical steps

FreakEnum

voila , I got what's wrong :)

Srivatsan

16:22

@FreakEnum What is? =)

FreakEnum

@Srivatsan They must sit alternatively, but in my solution I'm also including this one GBBG also

Srivatsan

@FreakEnum Of course, that's allowed. You only said the girls should not sit together. Why should they sit alternatively?

FreakEnum

@Srivatsan in Q they must sit alternatively

Srivatsan

@FreakEnum And you stated a wrong question to us, then... =/

FreakEnum

@Srivatsan I really apologize for that , please forgive me :(

Srivatsan

16:27

@FreakEnum No problem. Just be more careful in the future -- for your own sake, more than anything else.

FreakEnum

Thanks to all of you who always help me anytime :)

@QED sorry for pestering you too :(

QED

you didn't pester me at all

I don't think you agree with my ideals though

which are that you should try to forget about checking answers and looking up things in the back of the book

I think it's best to solve problems in such a way that you know you've got it right

but I guess people don't like that because you don't have a safety net (although that's sort of the point) and it's harder

FreakEnum

True!, Thank you all again :)

Srivatsan

@QED For what it's worth, I disagree with this viewpoint. Actually, it does make a lot of sense, provided it works. However, there are many situations where you see things only hazily -- where one is forced to guess, to stumble, to err. It may not happen for such textbook problems, but I think it's inevitable when you start doing more and more nontrivial ones, let alone in research.

QED

I have no experience with anything like that

To be honest I don't really believe that math research is possible seeing how many centuries people have been working on it (but I'm obviously wrong because people are doing it all the time)

Srivatsan

16:38

@QED I don't understand. When you say "people are working on it", what is "it"?

QED

post graduates doing new math research

I would have thought all the stuff you could possibly do at that level would have been done already

It seems like the only way I could get to new mathematics is after at least a decade of work

of course the evidence is contradicting this but I don't understand what's going on

Srivatsan

@QED Can't say too much on that. =)

[Not experienced and all that...]

@Ilya, there?

N3buchadnezzar

There was a lst posted on the site, with the greatest mathematical discoveries during the last year.

I found that list interesting.

QED

can you link it please?

N3buchadnezzar

And it seems more and more concepts and ideals are developed in math, deeper and deeper abstract concepts.

QED

16:52

I didn't see this

N3buchadnezzar

It seems like math has moved on from being a practical tool for phycics into a realmn of its own.

Srivatsan

@N3buchadnezzar It seems? Oh, that one's a modest thing to say.

N3buchadnezzar

So I see math as "discovering beautiful relations and beautiful things"

The analytic mathematicians tends to disagree on that one...

Srivatsan

@N3buchadnezzar "analytic" mathematicians?

I am not sure.

N3buchadnezzar

Numerical mathematicians? blaims bad english

Srivatsan

16:55

Out of curiosity, did you ask any of them and they disagreed?

If you don't mind, I think I will stay away from more of this discussion.

I just happen to like talking mathematics more than talking about it.

QED

Do you know any complex dynamics?

N3buchadnezzar

mathoverflow.net/questions/83290/…

QED

thanks N3buchadnezzar

I think that will be a good read

I guess I stopped studying complex analysis because I thought I probably wouldn't be able to learn the complex dynamics

I should just continue

N3buchadnezzar

17:11

Timeline of mathematics

A timeline of pure and applied mathematics history. Before 1000 BC * ca. 70,000 BC — South Africa, ochre rocks adorned with scratched geometric patterns. * ca. 35,000 BC to 20,000 BC — Africa and France, earliest known prehistoric attempts to quantify time. * c. 20,000 BC — Nile Valley, Ishango Bone: possibly the earliest reference to prime numbers and Egyptian multiplication. * c. 3400 BC — Mesopotamia, the Sumerians invent the first numeral system, and a system of weights and measures. * c. 3100 BC — Egypt, earliest known decimal system allows indefinite counting by way of introducing n...

QED

"Tomas Rokicki, Herbert Kociemba, Morley Davidson, and John Dethridge proved that diameter of the Rubik's cube group is 20."

I'm not sure how this is a significant result

Is there anything to that, other than having a powerful enough computer?

Srivatsan

group theory?

QED

17:27

Since it's not that fun when you don't know the rigor behind it

Srivatsan

@QED I don't get you

QED

What is it?

Srivatsan

@QED I didn't understand your previous comment. Are you saying that group theory is not fun?

QED

I was still talking about complex analysis

Srivatsan

Oh =)

Rajesh D

17:37

hi folks

N3buchadnezzar

This is the first dinner I have made

that I am not able to eat

Srivatsan

@N3buchadnezzar How did it come to to be?

Why not?

N3buchadnezzar

it tastes soo bad..

Tried to hide the hhorrible taste by using hot spices and spices in generall

Srivatsan

You're the first person I've heard who didn't like their own cooking =)

N3buchadnezzar

Only made it worse...

Dinner was all the remaining food in the fridge

QED

17:43

I don't really know much group theory at all

I liked that composition series

since it gaves another proof of the FTA

unique factorization

Jordan–Hölder theorem

That's probably the deepest group theory I know..

QED

18:00

:/

Asaf Karagila

18:12

@Ilya I'm here now...

QED

18:24

Why are you trying to be mean

Srivatsan

QED: Well, what's your explanation for what Skullpatrol was trying to do?

Asaf Karagila

Are you both asking me?

Srivatsan

@AsafKaragila No, I was asking QED. I didn't like what S. did either. E.g., see chat.stackexchange.com/transcript/message/2760799#2760799.

Asaf Karagila

I see.

anon

Anybody know the natural density of squarefree numbers congruent to a modulo b?

Srivatsan

18:44

@anon Did you try to make a probabilistic calculation?

anon

I did last night but I don't remember what I did.

Srivatsan

=)

anon

(I'm working on a q-problem over on mse..)

Daniil

Hello, everyone!

Srivatsan

hi Daniil

anon

18:47

gah, I absolutely loath time constraints on doing math

Srivatsan

Hey, btw, what happened to your job? I don't think we've met for some time...

anon

The friend who hooked me up has disappeared off the face of the Earth, kicked out by his wife, and the place said they have no idea who he is. And he took some of my shit, which really pisses me off.

Srivatsan

@anon Oh, I'm sorry to hear that.

anon

19:16

Hmm, well, if you sum $n^{-s}$ over squarefree integers equal to $a\mod b$ you get $$\sum_{\chi\mod b}\frac{\overline{\chi}(a)}{\varphi(b)}\frac{L(s,\chi)}{L(2s,\chi)},$$ that's something at least.

Srivatsan

Sorry, I don't follow this subject...

anon

Do you know what a Dirichlet character or L-function is?

Srivatsan

No. =) // I corrected my previous comment.

anon

Well, that's what you'd need to know. :)

Srivatsan

Heh. "A set has no structure. It’s just a collection of things, all of them equally unimportant."

But if I must make a guess, I would do the following. For simplicity, let's first assume $b$ is a prime number, and $a$ is nonzero modulo $b$. Then $n = a \pmod b$ is square free if for every prime $p \neq b$, $p^2$ does not divide $n$. There is no condition imposed by $b$. So this gives the probability
$$
\prod_{p, p \ne b} \left( 1 - \frac{1}{p^2} \right) = \frac{6}{\pi^2} \cdot \frac{b^2}{b^2-1}.
$$

Asaf Karagila

19:25

He's back, and he's got arak with him! Watch out!

Srivatsan

anon: Does this make any sense?

@AsafKaragila Is this the boogeyman?

Asaf Karagila

@Srivatsan He cannot boogie, man.

anon

Bah, that's annoyingly straightforward. I presumed a would come into play somehow but it doesn't, really.

Anyway, I have to go now. Later.

Srivatsan

@anon Um, does that mean that you believe what I just said? =)

Dependence on $a$ does come up: for instance, when $a$ is zero mod $b$, then this expression now changes...

I presume that this gets multiplied by $\left( 1 - \frac{1}{b} \right) = \frac{b-1}{b}$, instead of $\left( 1 - \frac{1}{b^2} \right)$.

All this get more complicated if $b$ is a composite number...

robjohn

20:18

Back from the doctor. Well, I stopped off to answer a question first $\stackrel{\circ\ \circ}{\smile}$

reading backlog

Matt

Hey robjohn, plus one for the complex analysis thing that you just answered. I wonder why Byron deleted their answer.

Can I ask you guys here in the "pub" a question about uniform convergence?

Srivatsan

@robjohn, can you explain to me what the following excerpt is trying to say:
Hardy's "Course..." I'd need to investigate years-of-publication and such, but I know the provenance of that thing needlessly well. My father (a high school math teacher in the U.S. required to obtain a higher degree [sic] in mathematics) endured a night-school course whose text was Hardy's. I was not very old, but old enough to be ... stunned... by the tendentiousness of that text. I had a fair understanding of analysis in the late 1960s, and/but Hardy's text effectively expressed doubt that its reader "had a brai…

I am especially stuck at the word "tendentiousness". Dictionary search says something like "having a tendency", "biased". But that doesn't make much sense to me in this context...

This para is from this answer.

robjohn

@Srivatsan Sorry, I accidentally closed the chat window. Let me read...

Jonas Teuwen

Whoah, tomorrow I've got an appointment to discuss a mortgage!

Srivatsan

20:33

I wonder why people write answers that make me browse through dictionaries... =/

robjohn

@JonasTeuwen sign on the dotted line, and all your problems will disappear...

Srivatsan

@JonasTeuwen Mortgage? What's that about?

robjohn

@Srivatsan I have to, as well, so don't feel too bad.

Jonas Teuwen

@robjohn Or I will get new ones for the coming 30 years? 8-).

@Srivatsan A house! Well, apartment.

robjohn

@JonasTeuwen I was recalling what Rumpelstiltskin said in Shrek 4

Srivatsan

20:34

@JonasTeuwen I don't get it. You are mortgaging a house? Or renting it?

Jonas Teuwen

@Srivatsan No, I want to buy one.

Srivatsan

@JonasTeuwen Oh, that's nice.

Jonas Teuwen

And I don't have 120k lying around.

Srivatsan

@robjohn So, she wasn't actually honest when she asked me to sign on the dotted line!? ;)

@JonasTeuwen Good luck anyway.

Jonas Teuwen

Thanks 8-).

@robjohn Oh, I should see that movie.

Srivatsan

20:39

You know what, I think that word was thrown around just like that. Perhaps p.g. assumed no one would be jobless enough to check a dictionary... =)

robjohn

@Srivatsan I don't exactly know what he is trying to say in that passage. Provenance means origin; he knows the origin or source of the book?

Srivatsan

@robjohn did he mention the word provenance?

robjohn

And what bias is he referring to with tendentiousness?

Matt

I assumed he meant to say the bias towards making the reader feel like a brainless idiot.

Srivatsan

@robjohn was ... stunned ... by the «attention to detail or thoroughness» of the book. makes sense. But tendentiousness?

FreakEnum

20:46

I'm stuck on problem , May I ask the Q?

Matt

Sure.

Srivatsan

=)

Jonas Teuwen

From now on I would like you guys to address me as: "Dear Leader, who is a perfect incarnation of the appearance that a leader should have". Thanks in advance!

Matt

Now what triggered that?

robjohn

@Srivatsan This guy is disappointed with the lack of exercises in the book, and he is ranting about everything he can, it seems.

FreakEnum

20:48

Q: There were 32 students in a hostel. Due to the admission of 7 new students the expenses of the mess were increased by $42 per day while the average expenditure per head diminished by $1. What was the original expenditure of the mess?

Srivatsan

@robjohn Yes, that's the overall context. But this para -- which put me off quite a bit on first reading -- is a bit off, it seems. Agree?

Sorry for putting you through this, @robjohn =)

robjohn

@Srivatsan It may be that either we are incapable of understanding, or he is using words beyond his paygrade.

Srivatsan

@robjohn Hey, no way we are conceding the first possibility. So... :)

robjohn

@Srivatsan $\stackrel{\circ\ \circ}{\smile}$

Srivatsan

@JonasTeuwen I am quite amused at how you are an incarnation of an appearance. =)

Jonas Teuwen

20:51

:(.

Srivatsan

@FreakEnum You should perhaps show some work. (Nod to what QED said a few hours back.)

FreakEnum

@Srivatsan I've no idea this time how do I solve this :(

Q is bit twisted , that's why want to learn the steps or procedure

Matt

@FreakEnum First introduce a variable for what you want to compute:

Let E denote the expense for $32$ people per day in the hostel.

Now collect the things that you know on a list.

FreakEnum

ok:)

Matt

You have the expense E for 32 people per day in the hostel.

You have the expense E + 42 for 39 people per day in the hostel.

(Correct me if I'm wrong.)

FreakEnum

20:56

no , you seem right

Matt

Now you only need to write down one more fact i.e. you need to make an equation containing E and the information of the minus one dollar per day on average.

Average here means price per person which is the expense divided by the number of people.

I think this should get you started.

FreakEnum

give me min , letme now try please

Matt

Now, @robjohn, sorry for being so persistent but do you have any idea why Byron deleted his answer?

robjohn

@Matt Because it was the same as my answer, but referenced outside pages.

Matt

Ok. I just had a glance and then it was gone. : )

robjohn

21:04

Matt

Thanks!

FreakEnum

@Matt my answer comes 215

robjohn

@Matt And the here is the link

Matt

Aces. Thanks.

@FreakEnum hold on, let me calculate it.

@FreakEnum I think I get something different but I might have got the sums wrong. Can you tell me the equation containing the one dollar difference information?

(Does really no one fancy a very short uniform convergence question? T_T)

FreakEnum

@Matt tell me answer? mine came wrong I just checked

Matt

21:11

@FreakEnum Tell me your equation.

FreakEnum

@Matt my second equation was (x+42)/42 = y-1

Matt

x + 42 looks good. I'm not sure about the 42 in the denominator. You started with 32 people and you added 7, how many do you have?

FreakEnum

@Matt no we started with 35 people

Matt

Then 32 was a typo?

FreakEnum

my god , my initial Q has typo , initial number of students are 35

Matt

21:17

Well then using the following equation
$$ \frac{E}{35} = \frac{E + 42}{42} + 1$$
I get $E = 420$

FreakEnum

@Matt you're answer is perfect. How did you solve that?

Matt

What do you think of this? Is it right?

FreakEnum

aah I got it

you compared the averages directly

Matt

Yes. Do you think that's correct?

FreakEnum

@Matt Yes it is, That seems correct answer even to me :)

Matt

21:21

Good : ) Let's hope the signs are all correct, too : )

Matt

21:40

I can now answer my own question: I saw the uniform limit theorem stated with the condition that the $f_n$ be bounded. That's not needed.

Asaf Karagila

21:56

I can't believe that I'm that close to the 20k and it's gonna take me yet another day!

Matt

Are you capped?

Asaf Karagila

Not even close.

Just nothing to answer...

I can't even think of something to edit...

QED

Hi

Matt

Hi there.

QED

How's it going?

Matt

22:11

I had a nice day today, thanks. And yourself?

QED

Thinking about printing out lectures notes or buying a second hand book

Matt

(All memories of yesterday's set theory failure suppressed. : ) )

What topic?

QED

complex analysis

but I haven't been able to find a text I like yet

Asaf Karagila

LOL at my comment :-P

Matt

: )

Jonas Teuwen

22:17

@AsafKaragila You must be the funniest guy I have ever met. Really.

QED

I don't understand it

Asaf Karagila

@JonasTeuwen You only say that because you're living with the Dutch... :-P

Jonas Teuwen

:P.

Asaf Karagila

22:33

Well. If that is the case, I am going to sleep.

Goodnight chumps and chumpettes.

Matt

Good night Asaf.

robjohn

22:58

@AsafKaragila you forgot the grandchumps.

Matt

23:21

Good night folks.

robjohn

23:37

@Matt g'night

I'm left here with the user without a page...

@Skullpatrol: how are things?

Skullpatrol

@robjohn Fine thanks and you?

I'm a pageless user?

robjohn

@Skullpatrol Pretty well. I answered a pretty simple question and almost got 10 votes already $\stackrel{\circ\ \circ}{\smile}$

@Skullpatrol If I try to see a page for you, I get the does not exist sign.

Skullpatrol

@robjohn How do you load this Math Latex thing?

robjohn

See the starred comment "MathJax Support For The Chat!!"?

Skullpatrol

Its' too complex for me

all I see is dollar sign symbols etc

robjohn

23:43

Try the alternate link at the bottom.

Do you see the starred comments at the right of the page?

Skullpatrol

^^^drag this^^^ to your bookmark bar or right click on it and add it as a bookmark.

robjohn

@Skullpatrol can you do that?

Skullpatrol

I'll try...

done, now what sir

@robjohn Where is the book mark bar in chrome?

robjohn

@Skullpatrol I don't have Chrome, so I am not sure.

@Skullpatrol Does right-clicking bring up a menu in Chrome?

Skullpatrol

Yes, but no bookmark

robjohn

23:51

Are you on a Mac or a PC?

Skullpatrol

PC

robjohn

and you can't find a bookmark bar on the window?

Skullpatrol

Intel with windows vista

robjohn

Take a look here

Skullpatrol

There is no bookmark bar on the chrome browser if I use the IE browser it has a big star on it

robjohn

23:55

@Skullpatrol look at the link I gave above

http://support.google.com/chrome/bin/answer.py?hl=en&answer=95745

Skullpatrol

@robjohn Ok

robjohn

did that help?

Skullpatrol

@robjohn So now I have a bookmark bar across the top.

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$Mathematics$ Mathematics