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01:00 - 22:0022:00 - 00:00

01:22
Hello!!

What does it mean that a linear map is invertible?
@anon do you have an idea?
@MaryStar does that just mean it's a bijection? I'm not really sure either.
A matrix is invertible when its determinant is non-zero. Does something similar stands in the case of a linear map? @idonutunderstand
01:41
My guess would be that if the linear map is between finite-dimensional vector spaces then it would have a corresponding matrix the determinant of which would be nonzero. But I don't really know what I'm talking about.
@MaryStar what's the context of your question?
I am looking at the following exercise:
and there is the following proposition:
@idonutunderstand
02:05
Is a more general result, where the curve is not necessarily regular and the diffeomorphism is not necessarily local, false?
@MaryStar
02:31
@MaryStar Just use the chain rule on $f \circ \gamma$ to show it is regular. The "proposition" is usually referred to as the inverse function theorem.
03:22
We have that $\frac{df(\gamma (t) )}{dt}=f'(\gamma (t))\gamma '(t)$, right? Since $\gamma$ is regular we have that $\gamma '(t)\neq 0$. How can we use the fact that $f$ is a local diffeomorphism? @PVAL
 
2 hours later…
05:05
@MaryStar A function is invertible if it has an inverse. Linear maps are functions. Given any choice of coordinates on a vector space, linear maps correspond to matrices, and the linear map is invertible if and only if its matrix has nonzero determinant.
When do you expect to get the results from the Putnam? @anon
spring break
 
2 hours later…
06:40
how did you do on your putnam exam @anon ?
I submitted four answers, so I'm hoping for 30 points
user174558
In the Putnam exam, just Put your Name on the paper.
Huy
Huy
no
user174558
Each time @OFFSHARING announces a discovery in chat, she is not bragging, just being excited. There is nothing wrong with being excited, so we should not criticise her for that. She has probably produced more theorems than any of us will ever produce this lifetime.
how is the exam graded the putnam exam ?
Huy
Huy
06:59
@MithleshUpadhyay: Why are you inviting me to a room?
to answer his question
which I've now addressed in a comment
Yes, I need special care for that problem. May be, I need to read given solution multiple time. I need a reliable reference :(.
Hello everyone
Guys, I was looking for some information about "Non-smooth manifolds with singularities"
Anyone knows some references about it?
In this page map.mpim-bonn.mpg.de/Manifolds_with_singularities considered the manifolds as smooth, and I'm trying to read about non-smooth manifolds
Someone can suggest me something?
07:17
It's probability problem. Would you want to check this, please?

http://math.stackexchange.com/questions/1544460/group-of-r-people-at-least-three-people-have-the-same-birthday
 
1 hour later…
08:17
please, what it mean: $I: W^{1,p}_0(\mathbb{R}^N})\rightarrow \mathbb{R}$ is rotationally invariant
How to see that a function is rotationally invariant
?
Hey @anon awake ?
yeah
I wanted to ask a question so I am showing that if $|G| = pn$ where p > n > 1. I am proving that sylow p subgroup of G is normal in G without using Sylow theorems.
my idea for this is to prove that $|N_G(M)| = pn$
after using Lagrange theorem and stuff I get that $|N_G(M)| = p$ or $|N_G(M)| = pn$
M is a p-sylow?
so I want to show that $|N_G(M)| = p$ isn't possible but I am don't have a idea about why its not possible
yeah
I can't use Sylow theorems
08:34
Well, if |normalizer|=p, then M has n conjugates, and G->Perm(conjugates of M) has image at least n (since the action is transitive) with kernel divisible by p (since the image is not), which forces the kernel to be a p-sylow P. Then PM would be a subgroup of order p^2 unless P=M.
well if $|N_G(M)| = p$ this means that N_G(M) = M, where M is the sylow p subgroup of G
oh I see
hm
also we can do it as follows
if |normalizer| = p, ofcourse we have $M \leq N_G(M)$ so we have $MN_G(M)$ is a subgroup of G of order $p^2$
what do you think ?
@anon
huh?
|normalizer|=p is the same as M=normalizer, so M*normalizer is just M
that doesn't work
oh yeah
09:04
hey guys
can someone tell me what a clifford algebra really is, in very basic terms
the free associative algebra generated by n anticommuting square roots of -1
so generated by{1, e_i}
yes
if you want indefinite signature, you can make some sqrts of -1 and the others nontrivial sqrts of +1
09:10
nice
I had encountered such in gamma matrices in QM
for Dirac eqns
I figured it might be best to look at them by themselves first
Clifford Algebras and Spinors by Lounesto, is a great book on the topic. also see: "geometric algebra" (recommended search term)
@anon I heard there is a topological proof of the fact that there exists infinitely many primes
Huy
Huy
@L33ter check Proofs from THE BOOK
sure, you use residue classes to form a topology on Z
I've read it before
oh cool
09:13
don't remember it though
THE BOOK ?
> Paul Erdős, who often referred to "The Book" in which God keeps the most elegant proof of each mathematical theorem. During a lecture in 1985, Erdős said, "You don't have to believe in God, but you should believe in The Book."
haha cool
omg lmao "the book" .. . . I thought it did not even exist, but this is real! lol
09:43
Has anyone here worked through Loring Tu's introductory book on manifolds?
Or have it on hand? I have a quick question about an example.
It says the differential of left multiplication on the general linear group is also left multiplication. It's done using curves. So we choose a tangent vector $X_I$ and find a curve such that $c(0) = I$ and $c'(0) = X$ which we've established we can find.
Then there is this line: $$(l_g)_*(X_I) = \frac{d}{dt} \bigg \vert_{t = 0} l_g \circ c = \frac{d}{dt} \bigg \vert_{t = 0} g c = g c'(0) = gX$$
It's the reasoning for this second to last equality I'm not understanding.
It says $d/dt \vert_{t = 0} g c = g'(0)$ by $\mathbb R$-linearity and Proposition 8.15, which states that $$c'(t) = \sum_{i = 1}^{n^2} \dot c^i(t) \frac{\partial}{\partial x^i} \bigg \vert_{c(t)}$$
@anon you here?
I can't see how that proposition comes into play here.
It seems to me that all that is being used is the definition of $c'(0) = \frac{d}{dt} \bigg \vert_{t = 0} c$ because we pulled out the $g$?
@Huy What're you studying?
Pseudo-Anosov maps? :P
hi
I have a system of partial differential equations
with many dependent and independent variables
is there any standard way that I may organize these variables?
For instance, one may write: Yx,x +Yy,z +Yx,z +Yy,y
and another wite: Yx,x + Yy,y + Yx,z + Yy,z
is there any standard guide on this? any reference or paper about this...
Huy
Huy
10:09
@BalarkaSen: Just trying to finish preparing my stats class for next year, after that I can study without distractions for a month or two.
Otherwise I have to alternate all the time which is really annoying.
Right.
What's the youngest class age you've taught at a school @Huy
Huy
Huy
10:26
@skillpatrol 14-15 year old kids
I only teach high school, and at the high school I teach at, students are at least 13-14 years old when they enter
10:54
do you guys see any easy criterion for testing the irreducibility of $x^4 - 2x^2 + 5x + 3$?
@BalarkaSen ?
rational root theorem
+ no quadratic factors
that's what I usually do.
otherwise, go Eisenstein
Eisenstein doesn't work
then do what I said above
yeah
I will do the above
11:08
Doubt on double integral; do you want check it, please?

http://math.stackexchange.com/questions/1579690/the-value-of-double-integral
 
1 hour later…
12:48
@BalarkaSen I haven't a clue, sorry.
 
1 hour later…
13:48
hmmm ramanujan formula applied one of my favorites
user174558
Hi @SohamChowdhury Sayan has deleted his account.
Huy
Huy
14:24
@DanielFischer: sorry to bother you with this but will I need complex numbers to teach differential equations for anything apart from computing roots of the characteristic polynom (HS level)? trying to figure out what to teach in which order.
@Huy Not really. Of course it's convenient if you can use functions like $x \mapsto e^{\lambda x}$ for arbitrary $\lambda\in \mathbb{C}$, but not essential.
Huy
Huy
@DanielFischer: if you had the choice, which would you teach first? it seems more elegant but I don't know if it's that much of an advantage
(those are the last two topics I teach)
on the other hand, teaching it the other way around doesn't have any obvious advantage, but for some reason most teachers do diff eqs before complex numbers
14:46
I'd do complex numbers first (we're not talking about complex analysis here, I suppose).
Huy
Huy
no, just basic complex numbers :P
@JohnNash why all of a sudden?
15:01
hello
Huy
Huy
16:00
@DanielFischer: do you know of any super-elemental way to show Euler's formula? my students don't know Taylor and the trigonometric functions were obviously not defined as power series.
@Huy One way to do it would be to recall polar coordinates.
user174558
@Huy Do you mean super elementary?
@Huy i think this is elementary without taylor or power series definitions of trig functions math.stackexchange.com/questions/1079121/… is that what you looking for?
Huy
Huy
@BalarkaSen recall?
Not sure what the question is.
ok, I have to go.
16:09
@BalarkaSen balarka, could you please send the link i posted to huy, maybe he blocked me and can't see it
@JohnNash could you please send the link i posted to huy, maybe he blocked me and can't see it
@Anubhav.K hi
@Huy Introduce power series and define the functions by their power series. That makes it really simple. Of course it's not quite simple to show that the thusly defined sine and cosine are the same as the ones they saw in trigonometry. ;)
16:47
hey @Ramanewbie comment ca deroule
Bjr @Agawa001!
How come you speek French.
im known french speaker in this room
17:05
@user153330 hii
17:19
I'm going to bump this here:
1
Q: When is a vector in the image of a bilinear map?

Alec TealIn this case I have a bilinear map defined as: $\varphi:V\times V\rightarrow U$ with: $$\varphi(x,y)=x_1y_1c_1+x_1y_2c_2+x_2y_1c_3+x_2y_2c_4$$ Here $\{c_1,\ldots,c_4\}$ is a basis of $U$ and $V$ has dimension 2 with basis $\{b_1,b_2\}$ (so you can think of $x:=x_1b_1+x_2b_2$ and "" for $y...

 
2 hours later…
19:01
I wanted to change the username to Monica, but I still need to wait (a few days) ... @JohnNash
19:17
@Agawa001 Francophone?
@FrankScience sometimes
@Huy What's the definition of $e^z$ for $z\in\mathbb C$?
@FrankScience why are you asking one person that?
@AlecTeal That's context-specific.
@OFFSHARING you're a girl? in that case "Damn gurl, you love 'dem integrals" and "integral slut" makes sense! :P (this is an inclusive teasing)
@FrankScience but other people know $x^{a+b}=x^ax^b$ too :P
19:26
@AlecTeal You can click the arrow before my question to see what happened before.
$e^z$ doesn't require me to do that
if you take $n$ steps on a symmetric random walk on the number line, what is the probability distribution called for the position you end up at?
You mean, the probability distribution of $S_n=X_1+\dotsc+X_n$ for i.i.d. $X_j$'s?
@FrankScience exactly
@FrankScience you should see an arrow by what Dorothy said.
19:31
@FrankScience also.. am I right that as $n$ tends to infinity this distribution tends to the normal distribution with std \sqrt{n}?
@dorothy Central limit theorem.
@FrankScience yes :) So about the name?
@dorothy just compute the variance: maths.kisogo.com/index.php?title=Variance it's easy for the sum of uniform variables.
@FrankScience is it a shifted binomial distribution?
@dorothy it's just called "symmetric random walk" you don't have to name every distribution.
No
19:34
@AlecTeal what is the relationship to the binomial distribution?
Consider $2^{-n}(X+1/X)^n$.
@FrankScience trigonometric amount ? like sin(sthing) or cos(sthing)
@Agawa001 He needed a proof for Euler's identity, so I need to ask for his definition to clarify. / Il avait besoin de une demonstration pour l'identité d'Euler. (My French is very bad)
i can understand english
19:42
tbh, i think euler id or demoivre or whatever based on that is just a shot at random
@FrankScience was that for me?
@Agawa001 But what if he defines $e^z$ as $\lim_{n\to\infty}(1+z/n)^n$?
that is with absolute real numbers
z,n defined as real
19:46
But it works for complex numbers $z$.
limit for an imaginary number ? never saw that
Limit could be taken in any Hausdorff topological space.
Dans ce cas, $z_n\to z_0$ ssi $\Re z_n\to\Re z_0$ et $\Im z_n\to\Im z_0$. @Agawa001
for example , what is $lim_{x->\infty} xi$
Quel est $\lim_{n\to\infty}n$? Est-ce que c'est bien défini?
n*i
ya -t- il une chose telle $\infty*i$
?
19:54
@AlecTeal I'm a girl, of course!
En fait, il n'est pas bien défini dans $\mathbb R$ pour $\lim_{n\to\infty}n$
reste un point de vue personel
$S^1\cong\mathbb R\cup\{\infty\}$ is a compactification of $\mathbb R$, but not the only one.
@AlecTeal You can call me Monica.
@OFFSHARING wish u never read that,such wierd tense accented language
20:01
@Agawa001 :-)))
@FrankScience ur point is $\infty$ doesnt belong to R ?
@Agawa001 The point is that, convergence to $\infty$ is not convergence in $\mathbb R$.
i know its divergence
So when you want to determine $\lim_nin$ in $\mathbb C$, you need to check whether it's convergent.
@robjohn Hey. I wanna send you something in db. Are you around? Let me know when you're available.
20:08
@BalarkaSen am now
@robjohn I sent to you the very little file.
@anon how often do you laugh a day? Not decided yet how the major part of the mathematicians are in terms of the sense of humour.
I have a lot of fun and laugh a lot while playing with my stuff.
Maybe I should have also addressed that question to @BalarkaSen.
@Agawa001 how is your sense of humour?
(category theory)
I've shown that there exists a family of maps, but can't tell if it's a natural transformation
NVM
someone answered
20:26
@OFFSHARING i laugh as much as i haircut myself
@Agawa001 lol :-)
the sad part is i rarely take a haircut (maybe once upon two months)
@OFFSHARING depends on what I do that day. If I see coworkers I laugh at a few jokes here and there, and make some in return, mess with some of the people I work with in the lab. I enjoy a number of comedy shows regularly that always get laughs out of me, and laugh with friends regularly.
@anon Nice. Well, often the internet can create a wrong image of the other person, you seemed to me more serious, and less inclined to laugh (for some reasons).
20:34
Anyone here know what the : in j:i∈T_j might mean?
@OFFSHARING in my infinite boredom it takes less trivial things to make me laugh. when people type lol on the internet, it's usually with a straight face, since their laugh is just on the inside. such is desensitization.
@anon hehe, whenever typing lol or anything like that means that I laugh (that's true for me). It's hard to type lol in other conditions. :-)
@Thijser : means such that, especially in set-builder notation. would help with more context.
Ok so it would mean j such that i is in T_j?
Thanks @anon
I assume you're missing {} around it as well, @Thijser
20:37
@anon It's written under a summation
why don't you tell me your full question
it annoys me when people leave out potentially important context in their questions...
I have a condition that increase y k until there exists an i ∈ T k such that j:i∈T j y j = c i
Guys, what's offensive about:
"Have the 10 upvoters done ANY linear algebra at all?"
and "Oh crap. I trusted dot product. thanks for finding this exception! Maths would be better if we proved stuff."
and "This isn't well researched, it's just not read. 0!=10!=1 and 1010 is 11. The numerator is 01=001=0 so this is 00 - WTDuck is the problem?"
and "The question itself is phrased like a manual from something that one buys off ebay and ends up arriving from China."
and "Have you tried using a search engine for the definition of "Cartesian product" and "set intersection" - seriously, lazy."
@AlecTeal where are you finding these
expect that there should be a sum written above the j:i but I can't seem t ocopy that over
20:39
@Brennan.Tobias I've been suspended for these comments.
ok do you want advice to not get suspended again?
the first one was a question about "why do we need span in linear algebra"
How can we show that every commutative unitary ring has a prime ideal using ultrafilter lemma?
20:51
@OFFSHARING I just got your file. Sounds good to me.
@OFFSHARING any idea when your book will come out?
so does Σ{j:i∈T_j }y_j = c_i mean that for every j where there is an i inside T_j sum up y_j until the sum is equal to c_i? Or do I also have to sum up the c_i?
@Thijser i is a constant relative to the expression.
The sum is over all j such that this particular i is in the set T_j.
The equation is a claim: that the sum actually turns out to be equal to c_i.
@KarlKronenfeld alright thanks
21:16
@BalarkaSen (Re: Logic + Topology) This question may interest you: math.stackexchange.com/questions/262654/…
@robjohn Glad for that.
@robjohn If all is fine, next year. I cannot give you now more details, but later on.
@OFFSHARING I don't laugh.
@OFFSHARING Just wondering if there was a plan, that's all.
@robjohn Sure. There is always a deadline one must to respect but from the point of sending the final form of the manuscript to the moment the book is published it may take some months.
@OFFSHARING of course.
21:22
@KarlKronenfeld Cool, thanks.
@anon ok, let's penrose.
@robjohn The nice thing was that I contacted a genius, a person I talked to a long time ago, it was a very nice person, and I had talks to him in the past about other kind of math, and he was so suprised when I told him about my proposal to him. He immediately accepted. :-) That is we didn't keep in touch for long periods of time, he was interested in other kind of stuff.
if you're free that is.
@robjohn The thing is that I never forget the precious (or say, nice people) people. ;)
Perhaps he will think for a long while to what I said to him these days, he was so pleasantly surprised. :-)
@OFFSHARING Sounds nice. It's nice to catch up with old friends.
@robjohn Yeap.
@robjohn When I met him first he was like a machine to me (at that time I never met anything like that before). I wished much to do things like him.
Nice stories anyway (all that happened a long time ago).
21:34
@anon Ok, so you're here?
humph. apparently not.
@OFFSHARING how long u v been here ?
@Agawa001 Oh, I met that person in a different environment. I'm here since the summer of 2012 if I'm not wrong.
ok ok i could see that thru one's profile :p
@Balarka: Remind me, are you done with whatever exercises I posed you recently?
I don't remember any exercise you told me recently.
I am done with all the Diff(S^n) exercises you set me.
21:47
Last month, say. But I'll take that as a yes.
Anyone here know how to see if a primal dual solution has zero slackness?
Even though I know you're talking about linear programming, you still have to be more specific @Thijser
Prof called today. Heard of things called "stratified spaces". Sounds fun.
Here's more, in increasing order of difficulty. 1) Consider $\alpha \in H_2(\Bbb{CP}^2)$, corresponding to CP^1. (So a generator of this group.)
a) Find an embedded copy of $S^2$ representing $2\alpha$. b) Find an emvedded surface representing $3\alpha$. c) Find an emvedded surface representing $n\alpha$. This should recover your answers to a and b. These should be done in order.
d) Calculate the genus of your answer to c. Can you rhink of any ways to make it smaller?
I remember you told me (a), but didn't get to think about it in the flurry of Diff(S^n) problems.
I am doubting if there is such a thing as in (a).
21:52
2) (This requires you know a very famous result in 4-manifold theory, which I will not name.) Let $P$ be the Poincare sphere.
I am quite confident that I have made no error above.
2a) Prove that $P$ does not embed into $S^4$. b) Prove that $P \# P$ doesn't embed into $S^4$ by essentially the same technique.
c) See why your technique does not work for $P \# \overline P$.
d) (Much harder than the rest) Prove that $P \# \overline P$ does not embed into $S^4$.
2), even given what theorem I'm referencing, is probably harder than 1).
Whoa. That'd be a month's worth of problems. Thanks!
When you finish 1) and if you've worked a bit on 2a), feel free to ask what theorem I'm referencing. G'luck.
Definitely. Thanks again.
01:00 - 22:0022:00 - 00:00

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