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00:03
@TedShifrin $f(x, y) = x^2y^3/(x^3 + y^9)$, $f(0, 0) = 0$ works.
Oh. I've been stupid. A way more easier and systematic solution is $f(x, y) = 1$ when $y = x^2$ and $0$ otherwise. Very not continuous, and any line $y = mx$ through the origin will have a small nbhd on the line where $f$ is $0$, thus the derivative will also be $0$. Darn.
So much for nothing.
00:25
@BalarkaSen You ignored my warning. Note that this is undefined on the curve $x=-y^3$. Not cool. Yes, your ultimate example is good, but you can fix the other one to make it work correctly :) ... On to unbounded after sleep. :P
I have solved unbounded.
You're a very naughty boy, @Balarka. :D
$f(x, y) = 1/x$ for $y = x^2$, $x\neq 0$. $f(x, y) = 0$ otherwise.
Same argument shows dir. dervs all 0
But clearly unbounded on any nbhd of $0$
Ah, what if I want discontinuous only at $0$? :D
@TedShifrin Yeah, good point. I guess I'd just need to get my exponents to be even. I solved an algebraic equation to get at that, I'll plug in some other value tomorrow. I don't care about that ugly example anyway - can't be seen geometrically.
00:30
The intent of the problem, although I admit I didn't state it, is that I wanted the function good everywhere except at $0$.
Go to bed, now that it's morning, @Balarka :)
@TedShifrin yeah, don't think I can keep awake anymore. will think about the follow-up tomorrow.
G'night, @Balarka. :)
Byes. And you mean G'morning.
smacks Balarka
01:17
@Ted I have sent you an email.
01:36
Hey guys, does category theory have any real world applications? Has it ever been used in an industrial process, etc.?
Hey @TedShifrin
next semester they are offering applied algebra or lie algebra
which one do you think I should take ?
This is a course in applications of algebra to a selection of topics concerning enumeration, coding, finite state machines and cryptography. *** Prerequisite: MATH 223 or 323 with a grade of at least 60% ***
this is the course description of applied algebra
01:52
your grades given as percents?
yh
I think most canada is like that
02:13
@skullpetrol We get letter grades which correspond to percents.
02:28
Could someone list the topics of analysis beyond in R and beyond of functions of single real variable that a new math graduate student should be familiar with? Also could someone list the recommended/standard study materials for these topics? Thanks in advance! (redd.it/3ppxn9)
02:39
@0celo7 you mean you get letter grades that correspond to percent intervals, right?
@skullpetrol On tests? No, there we get a percentage. Report cards are letter grades.
No one says "I got a B on that exam."
And "at least 60%" is "at least a D."
Because the lowest D you could get is a 60%.
I meant for the course @0celo7
According to Karim, in Canada they give percent values for the course.
Hello friends.
@skullpetrol Well, I can tell you my grade in differential equations is a 100%.
And in physics 97%.
02:46
@0celo7 psh... humblebrag!
@SanicHodgeheg my linear algebra grade is like 101% :D
Some places give out GPAs of 4.5
lol your lucky that your grades in term of gpa
for example the highest grade I have is 99 that doesn't round to 100
@skullpetrol My high school GPA was like 4.4
out of 5
well, really out of 4
if you took nothing but AP classes all 4 years you could get a 5 I guess
but we didn't have AP PE, so dunno how that would work ;)
@0celo7 Have you not already learned pretty much all of ODE/undergrad physics/linear? Why are you retaking it?
02:52
no, no, no
not retaking what I don't know
knowing some GR does not make me a god, idk why some of you think that
"you" includes physics chat
you took GR?
Could someone list the topics of analysis beyond in R and beyond of functions of single real variable that a new math graduate student should be familiar with? Also could someone list the recommended/standard study materials for these topics? Thanks in advance! (math.stackexchange.com/q/1491747/275935)
@KarimMansour no
read some books
I see
nice
I'm a freshman
Currently reading Arnold Mathematical Methods of Classical Mechanics to get some proof writing skills
02:57
I am gonna take it next semester although it will be taught by physicists not mathematicians so it will not be covered in general way.
@KarimMansour check his answers on Physics stack.
the exercises are murder
@KarimMansour I just found out my school has a GR for mathematicians class.
I would rather go through actual proof book maybe munkres or something
that would be awesome to take
@KarimMansour eh, doing topology in school in a year
I know some basics, not really motivated to read a book on it (on my own).
Arnold is nice because it's applied math, but still has theorems and whatnot
and lots of exercises
@TedShifrin I found a copy of your book at my school's library, so I'll send that e-mail asking for HW problems. Thank you!
03:00
cool
yeah I have heard about that book
I might read it next summer
I have it on my pc
my reading list is 100 books and papers long
if I can touch it by the time I die, I'll be content
what is so special about his book?
@KarimMansour wait
Ted's book or Arnold?
Ah, yes. I like it.
Some sections are terrible, the two lines on cohomology will confuse you if you've never seen it before.
@KarimMansour This theorem. This theorem makes the book worthwhile.
oh I see
Fellow followers of Thoth. I am elated.
03:09
...welcome
Does $V^{\otimes 0}=\Bbb F$ by definition? Is there a mathematical reason for this choice?
Sorry if that's a dumb question
as someone who doesn't know algebra, what do you mean by $V^{\otimes 0}$
The $0^{th}$ tensor power(but that's kind of my problem haha)
Haven't really ever dealt with tensor products
@GaloisintheField well that I could have told you
how are you defining the $n$-fold tensor product
03:20
$V^{\otimes n}=V\otimes V\otimes \cdots \otimes V$ with $n$ factors
well, yes
what does the rhs of that mean
$\{v^{i_1}\otimes v^{i_2} \otimes \cdots \otimes v^{i_n}: 1\leq i_k \leq n\}$
dude, stop answering "what is $\otimes$" with more $\otimes$
because now I want to know what $v^{i_1}\otimes\cdots$ means
I don't know, it's a connective symbol for constructing bases??
I don't believe its an actual operation
It's a way of constructing new vectorspaces from a product of old ones
@0celo7 That's the basis of the tensor product of vector spaces
I know what it means...I was trying to do a socratic thing
only to discover my idea was wrong :P
ignore me!
03:25
Oh haha
That's alright, I thought it was an operation at first but couldn't find anything
Now I have no idea why a 0th tensor power is just the base field, although it seems intuitively right, I have no reason as to why
probably a definition
the geometric definition does not make sense with $n=0$ either
For some reason I feel it should just be the trivial vectorspace
Take it as an axiom and move on :P
@skullpetrol That sort of action makes me sad :P
@skullpetrol physicist!
son of a bricklayer!
03:28
I'll ask it on main, but I bet I will be downvoted
ask a prof or grad student
or wait until someone smart gets here
cheerio folks
gotta sleep
Later pal
03:48
@0celo7 Cya later. Also I found my own logic for my problem
The $n^{th}$ tensor power of $V$ has dimension $(\dim V)^n$
So the $0^{th}$ tensor power should have dimension $1$, i.e. the vectorspace being the underlying field
What does your logic say about $0^0$ in the set of real numbers? @GaloisintheField btw nice question :-)
@skullpetrol Thanks xD. My logic says that we define $a^0=1$(which is also how we have defined $0^0$) but I am not fully happy with it, since $0^a=0$ for all $a$ except $a=0$ :P.
@GaloisintheField There is a very natural reason if you are working with, say, algebras over a field.
1
Q: $0^{th}$ tensor power, $V^{\otimes 0} = \Bbb F$, definition, or mathematical construction?

Galois in the Field95% sure I will be told it's just a definition, move on etc: Is there mathematical reason why the $0^{th}$ tensor power is defined as: $$V^{\otimes 0} = \Bbb F$$ Where $\Bbb F$ is the field that vectorspace $V$ lies over. We define the $n^{th}$ tensor power of $V$ as: $$ V^{\otimes...

@GaloisintheField Does that mean you want me to answer it here.
there*?
03:56
@AlexYoucis Nono, I just posted it for the record
(obviously you can if you want haha)
Just maybe your answer is similar to Qiaochu Yuan's
@GaloisintheField It might be. I commented on Qiaochu's answer.
Proof by definition :P
Move on, don't waste time pal.
@skullpetrol I don't think that's a very enlightened approach. It certainly isn't something worth devoting copious amounts of time to, but it's still a reasonable question to ask.
I read this quote in an introduction to probability paper: "Pair-wise independence does not generally imply mutual indepen- dence. For example, suppose that A1,A2,A3 are pair-wise independent, p(Ai) > 0 for all i and A1,A2,A3 =∅, then p(A1,A2,A3)=0 and the factorization rule does not apply" - if A1,A2,A3 =∅, wouldn't they not be pairwise independent?
Ohh - never mind, they're saying that the intersection of all three A1 is the empty set, not that they all equal the empty set.
Agreed @AlexYoucis :-)
Haven't seen you for awhile pal?
04:11
Anyone here not horrible at probability?
@AlexYoucis You're at Berkeley right? I wonder if I've ever seen you...
Anthony - I'm pretty miserable, but I'd take a look :)
lol for some reason I have no intuition
if you pick two random numbers between 0 and 1, what's the probability their difference will be less than a half?
I realize there's some picture I can draw on $(0,1) \times (0,1)$, but I feel like there should be intuition that carries over from discrete probability.
In particular, I'd be interested in hearing the solution for the case of drawing numbers randomly from $0$ to $100$, and asking what the probability is that there difference is smaller than 50.
That's actually a good problem - and my intuition is pretty shaky as well ;). If it's absolute difference, I would probably parameterize over the first random number x and find the probability given x what the value of y would be.
For instance, if x = 0, P(E) = 0.5, whereas if x = 0.25, P(E) = 0.75. If you plot P(E|x=k) over k, you'll get a distribution that has two lines meeting at a sharp peak at 0.5. Then multiply P(E|x) * P(x) to get P(E) - it doesn't have much more intuition, but I'm picturing one number varying along a line, and the odds at different points that the other number is close to where it is. Hope that helps!
04:27
Yeah... Hmm. Thanks.
04:44
Anybody have any ideas for some interesting problems whose complexity I could analyze (that hasn't already been done before)? (I have an undergrad level knowledge of computational theory)
05:03
iirc If it "hasn't already been done before" it is called research :-)
Knuth gives some research level questions in his AoCP
05:27
@Anthony Yeah, do you go to Berkeley?
05:40
@AlexYoucis I heard Berkeley is the best state university in the country?
Hi @Alex. Long time! Anthony's a senior.
Hi professor
Hi skull. Oh, the comm college dept head answered my email.
That's good news.
I'm going to meet with her Monday.
Huy
Huy
05:43
what are you up to @TedShifrin?
Hi, sorry to barge in, but would anybody mind clarifying something about convergence/divergence with me?
Getting late here, Huy. Go ahead, @Andrey.
Huy
Huy
it's breakfast time !
If I'd like to show that a sequence diverges to $-\infty$, would it be enough to show that $x_n<0$ and $|x_{n+1}|>|x_n|$ for all $n>n_0$?
By like induction I guess.
No. Try $-1+1/n$.
05:47
Uh
Huy
Huy
evening @MikeMiller
That sequence satisfies your hypothesis.
Right, but it converges to -1
No, it increases.
Huy
Huy
^
05:49
Yup.
@AndreyKaipov: Ignoring my comment, that was his point.
I don't understand. As n gets large, the 1/n goes to 0. And so the sequence goes to 1.
Huy
Huy
no, to $-1$
Yeah, my bad, -1.
@AndreyKaipov: And therefore your conditions are not enough to show that the sequence diverges to $-\infty$.
But the sequence does what you want, yet does not go to $-\infty$.
05:51
OH!
Thanks, I got it now!
@Ted: Know how to do this? Some sort of modified Cantor fctn?
Professor @TedShifrin could you explain what you meant by "at-risk" students?
I meant less affluent, perhaps Latino or other less entitled students :)
@MikeM: Sure, if you think of it on the unit interval, precisely a Cantor function does it.
@TedShifrin: That's not a homeomorphism.
06:02
Oh, homeo.
@TedShifrin Hey.
As you know Berkeley gets busy.
But IMO if you just make the slope of the normally horizontal lines 1/2 and cut the rate of increase of the nasty parts by half you should get something that works fine.
Welcome back @AlexYoucis
Integrate the Cantor function?
@skullpetrol Yo.
@MikeMiller Don't we know something about $\mathrm{Homeo}(S^1)$?
06:04
@AlexYoucis: Nothing that has to do with this question.
@TedShifrin: Oh, that works.
Still hope to meet you one of these days, @Alex.
@TedShifrin I'm in Evans 93% of the time. So, if you wander around it long enough you're bound to find me.
@TedShifrin Or Main Stacks, actually. It's now open until 2AM with the Free Speech movement being a bountiful source of coffee and trail mix bars.
I didn't go into Evans in Sept. But I did meet up with Anthony.
@MikeMiller Yo, so suppose that you have SES of Lie groups.
Then, by the homotopy sequence and the fact that $\pi_2$ is zero
I'd rather set a time and treat you to lunch, @Alex
06:06
you get an injection of the fiber's fund. group into $\pi_1$ of the total space.
Is this obvious without using $\pi_2$ is zero?
@TedShifrin Sure, any time you're around send me an email! It's [email protected]
Hey guys
Hi @Julian: I will answer your email eventually.
@AlexYoucis: Well, this implies that $\pi_2 = 0$.
So I don't think so.
@MikeM: Not sure it collapses measure. I doubt it, in fact.
@AlexG!!
What's up y'all?
06:11
Hi pal
Both Alex's are back :D
AlexG, I read you need surgery soon. I'm so sorry!
@Ted Alright
@TedShifrin Thanks. It's okay. Hopefully this will finally put the whole thing to rest. :)
When did you become a mod?
april 2013 i think
06:14
Wow ... I never noticed the blue ....
Just after robjohn, right?
I was elected with arthur and mike
So, yeah, I think so.
I guess I Didn't pay attention then.
I suppose I don't tend to act very stately. :P
I was new ...
I'm also less active modding recently. It's hard to beat the Fischers to flags, they are so fast.
Most of my participation is axing people behind the scenes, and participating in the meta site.
Maybe you're the one axing me :)
Nah, you'd know. ;)
Axing? Sounds like an executioner :P
What's been up lately? Enjoying the (sorta) new location?
06:22
I got banned the other night for calling a rude ass a rude ass. Do I get banned now?
Pedro thought it might have been automatic, but evidently not.
@TedShifrin Nah if I chat banned for that I'd have to do it to myself
Well, someone got me banned super fast.
Yes, Alex, enjoying it ... Except for the chain smoker living under me :(
To be honest most of my chat bans have been when people link questions on the main site to advertise. That annoys me.
Perhaps a mod from another site?
Oh yeah that's a bad place for a chain smoker to live
06:25
Little did I know :(
Have you never smoked?
Never. I'm allergic ...
@AlexanderGruber: I bet he'd like it if Ted would get off of him now and then
@MikeMiller Hahahaha
There should be a by-law about this somewhere @TedShifrin
06:27
Everyone says the guy is an ex-military asshole.
Nope.
@skullpetrol I used to smoke. I quit a few times. (Per day.)
Me too.
Managed to for real quit last year though, after breaking up with my girlfriend, who smoked. It is hard to not smoke when your girlfriend smokes.
My regrets on your breakup.
06:32
@TedShifrin It's alright. I loved her but she was crazy and impossible.
@MikeMiller, it's starting to look like I'm going to dissertate on TDA.
And this coming from a crazy math geek :)
@AlexanderGruber: Cool. Do something useful with it, I hope.
@TedShifrin Well, I mean, we have to have SOME common ground. :)
Topological data analysis
homology and whatnot
Oh, very cool.
06:34
the finite part has been intuitive and there are some groups in algebraic topology so i like those parts
Sounds like a lot of computer work?
but on the other hand I still suffer from analysis discalculia so there is a bit of staggered progress
@skullpetrol Yeah somewhat. I do implement the things I'm building. It's not really complicated, though, by programmer standards.
that can be a little boring though for example i spent about 6 hours today trying to figure out how to take pointwise averages of piecewise linear functions in a way that did not take for god dang ever
07:27
hi
08:00
Hi can anyone answer a question?
askaway
0
Q: How to prove complement of generalized Cantor set is dense in $[0,1]$

Jessy CatRelated to a question I asked earlier.: Let $F$ be the subset of $[0,1]$ constructed in the same manner as the Cantor set except that each of the intervals removed at the $n$th iteration has length $\frac{\alpha}{3^{n}}$ with $0 < \alpha < 1$. I need to show that $F$'s complement, $[0,1]\backsl...

I have to solve $dy/dx+ sqrt(\frac{1-y^2}{1-x^2})=0$. How do I substitute $y$? @skillpatrol
trig function?
make a socahtoa triangle with sides with lengths 1, y, x.
sohcahtoa. sorry, i can;'t spell tonte
tonite
@JessyCat I thought about a trig function first but how do we incorporate x into it?
08:21
Anyone?
08:50
Hi @DanielFischer
Hi @skill.
@DanielFischer have you used the "highlights" option at the top of the chat page yet?
@JessyCat Take an interval of arbitrary length $\varepsilon > 0$ and show that it can't be contained in $F$.
@skillpatrol No. What does it do?
I think I figured out how the program selects the "highlights." It uses a combination of starred messages and if there are no starred messages then it uses the specific user requesting for highlights @ messages to highlight.
@skillpatrol should I take y=sin t?
08:57
I would ask on the main site :-)
@Paradox101 1- try to use all functionalities of latex 2- begin from $dy/dx=- \sqrt{\frac{1-y^2}{1-x^2}}$
@skillpatrol I've done that too. Just wanted a hint because i have very little time
@Agawa001 ok thanks :)
@Paradox101 cant move further but are we alowed to square ?
@Paradox101 or cos(t) , this should simplify the numerator and pull it out the square-root
@Agawa001 yes that would simplify the numerator but what about the denominator?
dunno
$d(sin(t))/dx=cos(t)*t'=-cos(t)*\sqrt{\frac{1}{1-x^2}}$
by simlifying $d(t)/d(x)=-sqrt(1/(1-x^2))$
hmmm
i saw that before
deja-vu
maybe arcsin or arctan
09:18
1
Q: How do I solve the following differential equation?

Paradox 101 $\frac{dy}{dx}+ \sqrt\frac{1-y^2}{1-x^2}=0$. How do I substitute $y$? Any help would be appreciated thanks.

@skillpatrol so it is arcsin , iknew it
09:40
Your message @BalarkaSen has just as many stars as the Chat guidelines :P
I have noticed. Very uncool, I posted it there to let people know of a fact. Starring that was unnecessary.
well, she did say "let the audience decide"
that's asking for it
Gah, I missed Alexander, Alex Youcis and Mike. Grumph.
Well, so much for calculus and non-fancy things.
10:36
@skillpatrol that is because there is not the star-"down" option
for not saying "downstar"
i dont usually see this chatter so i dont know how rude was she
this comment
2 days ago, by Gigili
@TedShifrin Did I ask for your opinion?
is hard to not consider as aggressive
oh thats almost rude, ted is a good guy he helps at-risk teens and has a rich history of youtube free-lessons
10:51
a harmless comment by ted was labeled as an "opinion" by her @MatsGranvik
@robjohn that usually piss me off all the time, especially when the op dosnt pay any upvote
refering to this
Oct 17 at 3:36, by robjohn
@MickLH unfortunately, the OP unaccepted my answer and accepted a later answer.
what if a later answer is better?
@skillpatrol so why the op dosnt wait for it at first place
lack of patience, perhaps?
the standard is, admitting the oldest right answer, not the better one
11:01
@Agawa001 of course we can transform it.
upvoting the better and good-detailed one is another thing
@skillpatrol The later answer was not any better originally, but later they added a lot of reference material. However, even if the reference material made the answer better, it was not there when the acceptance was changed.
@robjohn hmmm...interesting plot twist :-)
@sajjad how, to which interval ?
@robjohn some people think they are competing not giving help
@Agawa001 I have no problem with the other answer. It provided another approach to the same result. I don't really have a problem with the OP either; they are free to choose whichever answer helps them the most.
11:11
the OP makes the quality call
@robjohn if we forget codegolf and maybe other sections i dont know about, answering isnt a competition, when you help the op it is enough, i deleted some answers of mine when the op unaccept them thinking this way "if you dont need it, i have no will to leave it here anymore"
but you could help others with the same question, no?
@Agawa001 Answers are not only for the OP. The purpose of the site is as a repository of mathematical questions and answers. It is intended that other users will use the answers on the site, and to this end, various methods of solution can be quite beneficial.
@robjohn what if the next answer is just a build-off from your own
isnt it pissing off ?
The chatjax + chat guideline thing needs pinning again. Anyone wants to post it?
11:26
How does one integrate over a singularity?
@BalarkaSen seems that your message dethroned it
@BalarkaSen
@MatsGranvik What do you mean by integrating over a singularity?
11:28
Like there is a Zeta Zero and I integrate a function past it. But the program complains about the accuracy and lists several reason that are possibly contributing to the inaccuracy.
Well, if the integrand is not well-defined in your domain of integration, then how can you integrate it? One thing you might try is Cauchy principal value.
This is real integration we're taking about, right? Integration on $\Bbb R$?
@BalarkaSen Integration along the critical line 1/2.
If your singularity is good enough, then you can use Cauchy PV.
I tried that now. Approximately the same error message this time also with the Cauchy Principal value.
NIntegrate::slwcon: Numerical integration converging too slowly; suspect one of the following: singularity, value of the integration is 0, highly oscillatory integrand, or WorkingPrecision too small. >>
Then you singularity is bad enough so that the integration is not really possible. Consider a function which runs parallel along the x-axis, then suddenly blows ups at 0, and then comes back in the negative axis.
The area under this curve is just not finite.
11:34
ok
 
1 hour later…
12:57
Hi, could someone help me out with my last question I aske on mathematics? It is about calculating the correct interval between two limits.
@kimliv Do you mean this question of yours: math.stackexchange.com/questions/1492058/…
?
I am going out for a walk now.
y exactly (I forgot how to link it here)
13:17
Could someone list the topics of analysis beyond in R and beyond of functions of single real variable that new math graduate students are expected to be already familiar with? Also could someone list the recommended/standard study materials for these topics? (math.stackexchange.com/q/1491747/275935)
HELP!
1
Q: How to prove complement of generalized Cantor set is dense in $[0,1]$

Jessy CatRelated to a question I asked earlier.: Let $F$ be the subset of $[0,1]$ constructed in the same manner as the Cantor set except that each of the intervals removed at the $n$th iteration has length $\frac{\alpha}{3^{n}}$ with $0 < \alpha < 1$. I need to show that $F$'s complement, $[0,1]\backsl...

13:33
@Agawa001 If it is really another method, then it is not building off, but if it is just building off, then it is not nice.
13:49
@robjohn dats my point
 
1 hour later…
14:51
@MathMan thomas edison would rather have to say "Genius is 1% inspiration and 1% perspiration and 98% dispossession"
That's why he's not considered a "true" genius :P
@Agawa001 did you mean disposition?
Hello!!! @DanielFischer

According to my notes:

$f(x,y)= \sin y$

$|f(x,y_2)-f(x,y_1)|= |\sin{y_2}- \sin{y_1}| \overset{\text{Mean value theorem}}{=} |\sin{\xi}(y_2-y_1)| \leq |y_2-y_1|$

Don't we get from the Mean value theorem $|\sin{y_2}- \sin{y_1}| \overset{\text{Mean value theorem}}{=} |\cos{\xi}(y_2-y_1)| \leq |y_2-y_1|$? Or am I wrong?

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