@JMoravitz Unfortunately not. The identity came out something like $\idotsint_0^1f\left(x_1,\cdots,x_n\right)\:dx_1\:\cdots\:dx_n=\int_0^1 \ftrac{\left(x-t\right)^n}{n}$\left(\right)\:dt$ and I can't remember what went in the parenthesis, but it was something like that...
I'm curious to find out if the sum can be expressed in some known constants. What do you think about that? Is it feasible? Have you met it before?
$$2 \left(\text{Li}_2\left(2-\sqrt{2}\right)+\text{Li}_2\left(\frac{1}{2+\sqrt{2}}\right)\right)+\text{Li}_2\left(3-2 \sqrt{2}\right)$$
@KarimMansour I am looking again at the exercise http://physics.stackexchange.com/questions/179540/how-can-we-use-the-distances Are the $F_Z, s$ correct?? I am still confused how to find $F_H$...
no, like I had one friend in uni that I helped sometimes in math then when I ask him a question he never replies and tries to make me get confused and this stuff.
alright I will try that again first I got the general case I proved that lcm(a,b) = $bq_1$ by proving that a divides it and b divides it and I supposed that c = lcm(a,b) then I showed that $bq_1$ $\leq$ c.
the other direction is easy by definition of lcm(a,b) being c.
but I still don't see how to do it for gcd(a,b) = 1 @TedShifrin?
@TedShifrin, let's say I want to have a little box around my $\implies$ symbol, for when I'm doing the directions in an if and only if proof. Do you know how I'd go about it?
@evinda Probably not. The roots would have to be two numbers that multiplied to $b$ and added up to $\sqrt a$. Two numbers that add up to $\sqrt a$ cannot be rational.
But, seriously, @MaryStar, you are always in here asking many of us to help with each and every problem.
@Karim: I'm going to do dinner, but you should focus on proving that if $\gcd(a,b)=1$, then $ab$ satisfies the definition of lcm. And don't ask @Kaj for help.
Hey @DanielFischer Could I ask you something about the complexity of an algorithm?
http://pastebin.com/Eu4s3ht1
Could you help me to find the complexity of the algorithm?
How can we find the time that is required for the for-loop:
For each list x in X:
Add [v, x] to the set Y.
? :confused:
@evinda char** list[sizeKnownAtCompileTime_ActuallyANumber]; or char** list = new char*[sizeKnownAtRuntime_canBeAVariable]; /*do stuff*/ for(int i = 0; i < sizeKnownAtRuntime_canBeAVariable; ++i){delete list;} delete[] list;
@evinda The former has to be a number e.g. 5, 10, 12, 4 and the latter can be a number and/or an already-defined variable e.g. 5, 6, myNumber, thisLimit
I'm curious to find out if the sum can be expressed in some known constants. What do you think about that? Is it feasible? Have you met it before?
$$2 \left(\text{Li}_2\left(2-\sqrt{2}\right)+\text{Li}_2\left(\frac{1}{2+\sqrt{2}}\right)\right)+\text{Li}_2\left(3-2 \sqrt{2}\right)$$
