then to find equilibrium I need to figure out what values make these equations 0
Y = x
X = 1/K e^{-bY/X}
setting both equations to 0 I have
0 = x
0 = 1/K e^{-bY/X}
If x and y and both 0. I will have a problem. Although the first equation is satisfied, the second one leaves me with a one unless I take the e^ln and then it will work.
Y = x
X = 1/K e^{-bY/X}
setting both equations to 0 I have
0 = x
0 = 1/K e^{-bY/X}
If x and y and both 0. I will have a problem. Although the first equation is satisfied, the second one leaves me with a one unless I take the e^ln and then it will work.