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14:02
@ABeautifulMind OK. That's going to sound ridiculous, but how do I do that?
(via flagging?)
@ClementC. It does not sound ridiculous. Ping one in chat, like @robjohn. Or flag one on the main site. I might be wrong.
tHANKS!
Oops. Thanks!
@ClementC. If the question has not received any answers, you can delete it and repost.
@ABeautifulMind @robjohn Well, that's maybe petty, but I am reluctant to do so because of the +200 bounty I put on it... if in any case it is to be lost, then I will go for that option.
14:24
Nice question, @ClementC..
@ClementC. We can't migrate it because of the bounty. As soon as the bounty has been given out, it can be migrated.
@robjohn Can the question be deleted keeping the bounty?
14:50
Wow that killed the conversation.
@ABeautifulMind I'm interested in the answer :) if it's not possible, I'll delete my question and incur the loss of the bounty: not too big a deal, I reckon.
@ClementC. Or you can wait.
(you mean, wait until the bounty ends? That's the crux: I am asking this as I need this to try and improve a proof in a paper in submission, for the full version that we plan on posting on arxiv. 5 days is a long period, under time constraints.)
Huy
Huy
I haven't done any calculus for years. How do I compute $$\int_{0 \leq \tau_1 < \tau_2 \leq \tau} d\tau_1 \, d\tau_2,$$ is it just $\tau^2/2$?
@Huy $t^2/2$
Huy
Huy
15:01
@iwriteonbananas: Ok, so my reasoning was correct.
Huy
Huy
@iwriteonbananas: If I have that integral, but as integrand some product of functions $f(\tau_1) \cdot g(\tau_2)$, can I also seperately compute the integral wrt. $\tau_1$ and then the integral wrt. $\tau_2$, multiply and divide by 2?
it's just the area of a triangle
if you want you can split that into a double integral with multiple bounds
@Huy yes, separate it into a double integral like mike said
it's the same as $\int_0^t \int_0^{\tau_2} d \tau_1 d \tau_2$
15:33
@ABeautifulMind @robjohn Funny thing -- I cannot even delete the question myself until the bounty ends. I assume cross-posting, even under these circumstances, would be frowned upon?
@ClementC. I am finding out from MO whether it would be accepted there. If so, we will see what we can do.
Thank you!
@ClementC. It is migrated. Go there, and make sure the tags are good.
I just saw it; thank you again. :)
15:56
Has anyone here worked trough "Essential Results" by Robert Zimmer?
"Essential Results in Functional Analysis"
do you have a particular question about it?
nothing in particular
just wanted to see if anyone had worked through it and see how long it took them
I like to have a basic timeline for how long a book should take (Even though I know this varies from person to person)
ah, can't say anything then, sorry
16:16
is the sequence has a convergent sub sequence ? please
16:29
@robjohn can you help me please
someone here ??????
@Vrouvrou They will help if they can, relax.
16:59
@ABeautifulMind i juste want know now why this sequence has a convergent sub sequence
@Vrouvrou Sorry, I cannot help you. I am only a banana. =)
@Vrouvrou Are you doind a masters degree in math or something?
yes but i'm a big banana
@Vrouvrou can i write on u?
@robjohn Hi, Did you have time to look into my problem ? :)
17:08
Hey guys, any idea how I could prove the following:
Let W be a subspace of Rn and x_1, ..., x_k be vectors in W. Show that span(x_1, ..., x_k) is contained in W.

Sorry about no LaTeX but I think it's still readable.
@ta3920 This is trivial. Use the fact that W is a subspace and is closed uner linear combinations.
Right, I kept thinking about how to establish that fact that these vectors won't leave W and forgot about W being a subspace. Thanks!
We often forget what is most important to us in life.
@ABeautifulMind Brains
@MikeMiller trying to prove: if $X$ is a path-connected space such that any map $S^1 \to X$ is null-homotopic, then $X$ is simply connected. if $f:S^1 \to X$ is any loop in $X$, how do we construct a homotopy to the constant path which leaves the base point fixed?
17:17
two elements of the fundamental group are freely homotopic iff they're conjugate
prove that and use that
what do u mean by freely homotopic?
homotopic but not necessarily preserving the basepoint
Freely X means X in a free way.
@MikeMiller once we've established that, do we use the isomorphism $\Phi: [f] \mapsto [ \bar{h} f h ]$ ?
17:27
that's one way of phrasing it
the point is that the only element conjugate to the identity is the identity
so anything freely null-homotopic must be basepoint null-homotopic
kk got it
17:39
@Theorem No. I am not sure how to proceed on it.
@MikeMiller if f, g are freely homotopic via $H: S^1 \times [0,1] \to X$, then $[ \bar{h} \, f \, h] = [g]$ where $h(t) = H_t(1)$, right?
sounds reasonable
i cant figure out the other implication
that's the one I think is easier
draw pictures
18:03
man oh man im retarded
Hello!!

I want to show that Insetion Sort is stable...
Is the invariant the following??

At the beginning of each iteration of the for loop, if $A[a]=A[b], a<b \leq j-1$, then $A[a]$ appears before $A[b]$.

Initialization:
We have to show that the invariant holds before the first iteration of the loop where $j=2$. In this case, the subarray $A[1 \dots j-1]$ consists of only the element $A[1]$, so there are no $a<b \leq j-1=1$. So, the invariant holds trivially.

Maintenance:
We have to check if the property maintains at each iteration. The body of the outer for loop shifts the elements $A[
@AndrewThompson Are you familiar with the time complexity of algorithms?
@evinda No, sorry.
A ok, no problem @AndrewThompson
18:47
@iwriteonbananas :3
hi @iwriteonpeoplewhowriteonbanana
@iwriteonpeoplewhowriteonbanana Can I ask something simple. I just want to confirm the following basic fact of limits of a function:
$\lim\limits_{x \rightarrow a}f(x) = c \text{ iff } \lim\limits_{x\rightarrowa}|f(x)-c| = 0$
please put one '$' on each side of the equation so that I can render it
yeah that's true
@Chris'ssis If someone (say a woman to a man ) offert a Mărțișor what does it means ?
18:58
Thanks
@iwriteonpeoplewhowriteonbanana Encore un nouveau pseudo, j'espère que tu vas bien, je ne fais que passer :p.
Mărțișor (Romanian pronunciation: [mərt͡siˈʃor]) is a Romanian celebration at the beginning of spring, on March the 1st in Romania, Moldova, and all territories inhabited by Romanians. Alike, though not identical customs can be found in Bulgaria (see Martenitsa), while similar ones exist in Albania, and Italy. The name Mărțișor is the diminutive of marț, the old folk name for March (Martie, in modern Romanian), and thus literally means "little March". It is also the folk name for this month. Mărțișor, marț and mărțiguș are all names for the red and white string from which a small decoration is...
@Gato Ca va et toi ?
@Gato It's about offering a Martisor.
@iwriteonpeoplewhowriteonbanana Je sais, mais entre ce que wiki dit et la réalité des fois..
@Chris'ssis ?
@Chris'ssis I ask for the meaning of offering a Martisor.
:-)
@Gato " the one who wears the red and white string will be strong and healthy for the year to come"
19:08
@Chris'ssis I was not sure about the fact that it was the 'reality'
thanks
@iwriteonpeoplewhowriteonbanana Lastly, would you say that the limit of $\frac{y^{2}-3}{y}$ does not exist?
19:27
@JohnJack what does that mean?
what's the limit?
oh ur talking to someone else
damn you hippa
@iwriteonpeoplewhowriteonbanana you just might be the next best thing but not quite me
@ABeautifulMind that's pretty creepy
@iwriteonbananas Sorry typo. $\lim\limits_{y \rightarrow 0}\frac{y^{2}-3}{y}$.
@JohnJack it doesnt exist
Thanks.
but run it by @Chris'ssis just to be sure. he's a world class integrator/limit finder
19:46
Chris'ssis is a woman
hi bananas, @teadawg
Hello @Ted!
do we really know for sure, teadawg? :D
Fair enough
I see Hippa is continuing his obnoxious habits :P
19:54
@Ted Any ideas for how to evaluate $\sum_{n=1}^{\infty}\frac{1}{16n^2-8n}$?
Partial fractions?
Nvm, nvm. Yeah, partial fractions and recurrence relations of the digamma function
It comes out to be... $\frac14\ln(2)$ I believe
You know lots more special function stuff than I do, but I bet that, knowing about Euler's constant, I can get it.
@Ted You mean $\gamma$, right?
Yuppers.
Hmm ...
Yes, I get $\log(2)/4$, as well. Nothing too fancy.
That probably is one Chris'ssis would have done literally in her head in milliseconds.
OK, back to grading, since it's so silent in here ..
20:04
Cya later @Ted
Someone has an idea for this :math.stackexchange.com/questions/1184270/…
@TedShifrin can you see my question please
@iwriteonbananas That sounds nice. As regards math I'm in a competition with myself only, so this kind of recognition doesn't make much sense. I'm the person I wanna beat every day in the area of integrals, series and limits .
hi there boys and girls, and ted
Hi @TedShifrin
Do you still teach probability?
Hello @iwriteonbananas.......
20:17
hey user
do you still use?
@iwriteonbananas Of course! Do you still write on bananas?
@Chris'ssis How fast can you prove my simple (for you, anyway) series above?
@Chris'ssis well well, sounds like you should team up with some other integratorz and get to the next lvl
@iwriteonbananas Not really. I dream to become like Ramanujan, and keep in mind Ramanujan is from other world, no one can compare to him (so far).
@user159870 yes, thanks for pouring salt into the wound. i live in a remote rainforest area and my circumstances force me to use bananas as writing material
20:20
Why is true that $|\cos(tx)-1| \leqslant t|x|$ for $|x|\leq N$ and $t$ small? I can't see...I'm too tired
@iwriteonbananas Ramanujan is the god of all.
@Chris'ssis everyone is a ramanujan lurking as i always say
After writing on them do u eat them? @iwriteonbananas
@iwriteonbananas But I'm not everyone. ;)
@user159870 no i eat them before
@Chris'ssis you're just an average joe
20:21
@teadawg1337 $$\sum_{n=1}^{\infty}\frac{1}{16n^2-8n}$$?
could be working at burger king, spittin on my onion rings
but you compute integrals and series all day
trying to be like Ramanujan
@iwriteonbananas aha, I see your point. Are you Romanian (btw)?
@teadawg1337 Well, partial fractions and then add 2 more partial fractions and grup all into 2 sums. All will very nicely flow.
20:23
I already solved it
It's $\frac14\ln(2)$
@teadawg1337 $$\sum _{n=1}^{\infty } \frac{1}{4} \left(\frac{1}{2 n-1}-\frac{1}{2 n}\right)$$
@iwriteonbananas Because, you know, if you were a Romanian I'd meet you and show you there in front of you if I'm good or not. (without pen and paper)
@Chris'ssis Yes, and from there it's simple using recurrence relations of the digamma function
@Chris'ssis 99% of the time i dont understand the comments you make
tthis is another one of those times
i believe u that ur the great :D
i dont need u to show me in person "without pen and paper"
@Chris'ssis Keep an eye on me, I might surpass you one day :P
@teadawg1337 Well, that would be great. I love to learn from those that know more than me. Really!
It's hard to do all alone, without learning from anyone, it's crazy hard. Ramanujan had almost no knowledge on complex analysis as Hardy mentioned.
20:31
I also have hardly any knowledge of complex analysis, but I'm no Ramanujan... Far from it
I should get back to my work
Why is it useful to have differentiability imply continuity? I am reading about the motivation for the total derivative in Apostol and he points out an example where the existence of all partial derivatives doesn't imply continuity. But I don't see why that matters.
@Chris'ssis It would be good for a binary fireplace
@robjohn :-)
@iwriteonpeoplewhowriteonbanana you're not on tox ?
20:44
@Chris'ssis a quarter of a log is just about right
@Ramanewbie hard connection problems
@iwriteonpeoplewhowriteonbanana ok ok
@robjohn $\log(2)/4$
@Chris'ssis That is what I meant :-)
@Chris'ssis Oh, I didn't see that you parted the fractions :-)
MMMy screen is white, I see nothing.
20:47
@iwriteonpeoplewhowriteonbanana you quit already... :( hi @Chris'ssis
DoDo you see anything?
@Ramanewbie I told you, bad connection
@Vrouvrou yes
Interesting. I have 272 answers with a score of 0.
@robjohn Now compare with the German Doctor
20:50
@TedShifrin One hundred people line up to board an airplane. Each has a boarding pass with assigned seat. However, the first person to board has lost his boarding pass and takes a random seat. After that, each person takes the assigned seat if it is unoccupied, and one of unoccupied seats at random otherwise. What is the probability that the last person to board gets to sit in his assigned seat?
@iwriteonpeoplewhowriteonbanana which user?
@iwriteonpeoplewhowriteonbanana Is that for the question?
@iwriteonpeoplewhowriteonbanana How did you change your name
@Ramanewbie You can do that from your profile page
20:52
I had to restart my comp.
@iwriteonpeoplewhowriteonbanana Work it out and be suprised
@robjohn math.stackexchange.com/users/175066/dr-sonnhard-graubner
@iwriteonpeoplewhowriteonbanana He has 290... just a bit above me
@robjohn And with negative score ?
20:54
@iwriteonpeoplewhowriteonbanana he has 272 with positive score
Which leaves a lot of negative ones :/
@iwriteonpeoplewhowriteonbanana and 60 with negative score
@robjohn What about his average negative score ?
:20473737 There is no search for that. I'd have to use the SQL for that, and that has some delay
@PedroTamaroff why is it useful to have differentiability imply continuity? I am reading about the motivation for the total derivative in Apostol and he points out an example where the existence of all partial derivatives doesn't imply continuity. But I don't see why that matters. Any ideas?
20:57
@Chris'ssis How about this one? $$\sum_{n=1}^{\infty}\frac{\sum_{k=1}^{2n}\frac{(-1)^{k-1}}{k}}{16n^2-8n}$$
@Chris'ssis: I just computed the first three terms of the Laurent expansion for $\Gamma$ at negative integers for an answer.
@teadawg1337 How can you write the numerator? What's the natural way to do it?
@PedroTamaroff and just to be clear, the total derivative is the multivariable version for which differentiability implies continuity. And its the gradient for scalar fields and the Jacobian matrix for vector fields. Am I correct?
@Vrouvrou nvm sry what i did is wrong

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