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21:03
they are losing me at 15:26
ah fields. starting to make sense again.
that's actually a pretty interesting idea, enumerating lattices in fundamental domains
Off topic: Instructions to my problem say "find the radius of convergence of the power series. Using the toot test is not necessarily the most efficient method." What other methods are there for determining the radius of convergence?
21:21
@MikeMiller Hi!!! I am looking again at the sentence.. So, when we take two elements $a,b \in \mathbb{Z}_p$, $a \cdot b=\sum_{n=0}^{\infty} c_n p^n$, where $c_n=\sum_{i=0}^n a_i b_{n-i}$, right? But how do we conclude that the product is different from $0$ ?
Hey @evinda
@BalarkaSen Hi!!!
nice to see you here
@BalarkaSen Nice to see you too :)
@BalarkaSen Could you maybe explain me how, when we take two nonzero elements $a,b \in \mathbb{Z}_p$, we conclude that $a \cdot b \neq 0$ ?
i'm a bit busy at the moment but cauchy product is the keyword
21:27
I just posted an exceptionally nice integral
0
Q: Finding the closed form of $\int_0^{\infty} \frac{\sin(x)}{y(x+y)(1+x^2)} \ dx \ dy$

Chris's sisI think I know how to tackle the integral with $\operatorname{Ci(x)}$ and $\operatorname{Si(x)}$, but the way is long and less friendly as far as I can see. Do you see any easy way to tackle it? $$\int_0^{\infty} \frac{\sin(x)}{y(x+y)(1+x^2)} \ dx \ dy$$ Mathematica says it evaluates to $$\appr...

@BalarkaSen Will there always be $a_i \neq , b_j \neq 0$, such that $i+j=n$ ?
sorry @evinda i'm listening to a lecture at the moment. i'll look at your question later.
@BalarkaSen Ok, no problem!!!! :-)
21:41
@robjohn It's not a book, it's just a sheet with independent exercises.
@evinda By definition, $a \neq 0$ means there's some $a_i \neq 0$, right? So pick one with $i$ smallest. Do the same for $b$; say $b_j \neq 0$ with $j$ smallest. Now look at $c_{i+j}$.
Hi all
@MikeMiller Will it then be like that?
$c_{i+j}=\sum_{i=0}^{i+j} a_i b_{j}=b_j+a_1 b_j+a_2 b_j+ \dots+ a_ib_j+ \dots + a_{i+j} b_{i+j}$

Or am I wrong?
You're getting confused by your coefficients
(You're using $i$ to mean two different things
Index the sum by $k$
Anyone hit my prob from a while ago?
21:47
@MikeMiller So, is it like that?

$$c_{i+j}=\sum_{k=0}^{i+j} a_k b_{i+j-k}=a_0 b_{i+j}+a_1 b_{i+j-1}+ \dots+ a_ib_j+ \dots+ a_i+j b_0$$
yup
err
the last two terms don't make sense
everything before that is right
latex error, dude/
ah I see
@evinda Now what happens to the terms for $k<i$? How about $k>i$?
@MikeMiller @BalarkaSen
$$c_{i+j}=\sum_{k=0}^{i+j} a_k b_{i+j-k}=a_0 b_{i+j}+a_1 b_{i+j-1}+ \dots+ a_ib_j+ \dots+ a_{i+j} b_0$$

We don't know what happens for the terms for $k<i$ and for $k>i$, right?

We just know what happens for the term $a_ib_j$, or am I wrong?
We know perfectly well what happens to them. Remember how we chose $a_i$ and $b_j$.
21:52
What's the particular solution i should be guessing for $x\sin^2 x$?
@MikeMiller We took the smallest $i$, fo which $a_i \neq 0$ and the smallest $j$, for which $b_j \neq 0$. What other restrictions did we take?
That's all we took. That's also all we need.
I just corrected my previous question
3
Q: Finding the closed form of $\int_0^{\infty}\int_0^{\infty} \frac{\sin(y)}{y(x+y)(1+x^2)} \ dx \ dy$

Chris's sisI think I know how to tackle the integral with $\operatorname{Ci}(x)$ and $\operatorname{Si}(x)$, but the way is long and less friendly as far as I can see. Do you see any easy way to tackle it? $$\int_0^{\infty}\int_0^{\infty} \frac{\sin(y)}{y(x+y)(1+x^2)} \ dx \ dy$$ Mathematica says it evalu...

@robjohn have you ever seen before that $\zeta(2)$ representation?
@Hippalectryon well, from the answer I saw to your question, it seems to be a bit harder than easy.
@Chris'ssis I don't think so, but I wonder if it is equivalent to another that I know.
@robjohn Do you have some strong evidence to believe that? I'd be curious to know since I don't know which integral you have in mind. I have never seen before something like that.
@robjohn hehe, it's pretty hard to discover something new these days, I'm used to that :-)
22:32
@Chris'ssis How is the progress of the book?
Am I going off the deep end here? I don't see what's wrong with this... math.stackexchange.com/questions/1004854/…
Hello @Kaj
Hey there Balarka
@JasperLoy The only thing to do is to add my stuff to my book ... I have all I need, but still ...
@JasperLoy I want rare gems in my book ...
It's not for my publishing things just for the sake of publishing things.
Hi @KajHansen
22:41
Hey there @Alizter
@robjohn I guess I'll have to ask my teacher tomorrow :)
@Alizter Yo yo.
@Kaj I've figured out how the inverse limit looks like.
22:42
@Chris'ssis Don't put too many rare gems :/ I can't afford a $1M book :P
Hi @JasperLoy
@Hippalectryon :D
@Alizter Any news from Sarah?
You'll have to tell me about it in a bit. I'll be back soon after I get dinner.
@JasperLoy no
22:44
@Kaj I need to sleep. It's 4:14 AM =P
@Alizter I think I will go running later. I am trying to compare the standards of OCR and CIE maths. On the CUP website, the CIE books are for single math only while the OCR books are for double math.
@JasperLoy Did you go running on the first?
@Nick That's for you :D i.imgur.com/2pNnoN5.jpg
@Alizter I had flu the past few days, so I mostly stayed at home.
22:48
@JasperLoy :O EBOLA
@Hippalectryon I seriously don't mind dying, considering my future this life is terribly uncertain.
@JasperLoy Dun say that :/
We need a Banana in this chat :D
@Hippalectryon France and Germany are still my top two choices for my rebirth location.
@Hippalectryon Let us know what you learn.
It seems I'm done with this one $$\int_0^{\infty}\int_0^{\infty} \frac{\sin(y)}{y(x+y)(1+x^2)} \ dx \ dy=\frac{\pi}{2}\left(\gamma-e \operatorname{Ei}(-1)\right)$$
22:52
@robjohn sure
@Chris'ssis :D
@Hippalectryon I had a bit of luck ;)
What kind of luck ?
You found the answer in a Cereal box ? :D
@Hippalectryon The luck of having in mind the proper ideas ... :D
@Hippalectryon lol, not yet :D
@Chris'ssis That's the way it is with some problems.
@robjohn Yeah, I know ... I remember a 3 nightmare days when I worked on a triple integral. I suffered like a whole day to finish the last part of the proof since I reached a terrrible dead end.
It was about this one ... $$\int_0^1 \int_0^1 \int_0^1 \left\{\frac{x}{y}\right\} \left\{\frac{y}{z}\right\} \left\{\frac{z}{x}\right\} \ dx \ dy \ dz $$
23:02
@Chris'ssis Oh I remember I think
@Chris'ssis Didn't you generalize it ?
The last day almost depleted me totally, but I couldn't give up, and then ... the brilliant idea came to mind ...
@Hippalectryon Yeah, I have some stuff ... :-)
The interesting fact is that that day was a terribly cloudy day like my frame of mind before finding the key, I could barely see to write things on paper. I won't forget that last day.
@Chris'ssis Don't you have electricity ? :P
@Hippalectryon lol, I prefer the daylight.
It's 0:10 AM here :c
No daylight
Moonlight maybe ? :D
There is no daylight here during the day. It is just cloudy.
23:11
@Alizter every day?
@Hippalectryon Did you know that the moon absorbs light and emits it during the night?
Because I did not know that seeing as it is not true.
@Chris'ssis When november started >:(
@Alizter Wut ?? How does it absorb light ? Do you mean that it absorbs heat, and emits light ?
There is no heat or light
just electromagnetic waves
@KajHansen How is dinner.
Wut wut then how does it absorb light
And hello @MikeMiller
23:13
How do you 'absorb' a wave ?
@Hippalectryon Read the sentence after...
I thought the moon reflected them
@Alizter I had rice, egg, chicken, and spinach as usual.
@Alizter Interesting sentence indeed :P
41 secs ago, by Alizter
@KajHansen How is dinner.
@JasperLoy I had rice, cottage pie and a salad.
23:14
It's almost breakfast time here, lol.
@Alizter I did not know they eat rice in the UK, lol.
@JasperLoy It is not uncommon
2 mins ago, by Alizter
Because I did not know that seeing as it is not true.
@Alizter When you go to Cambridge in a couple of years, you will eat math every day.
r9m
r9m
ah ! I haven't had rice in like 2 years :P
@Alizter >:C
@Hippalectryon That is for trolling ted.
C:>
r9m
r9m
23:16
@Chris'ssis nope .. I haven't yet :(
Hi guys, I'm trying to prove a fact and I have a doubt with this: having N independent events, all with the same probability p what is the average number of events that will happen?
@newbie Do you mean expected number of events?
@Hippalectryon When I sent that solution to Ovidiu he confirmed I was the first one that did it.
@newbie How many different ways can N events happen?
It's one of my greatest achievements along with other cases, other problems, and of course Au-Yeung series proof.
r9m
r9m
23:21
@Chris'ssis which one ? :D
sorry I've solved it was a stupid question.. It's so late here! thanks the same @Alizter
@r9m I was referring to the triple integral above.
@Chris'ssis You achieve too much. Set your goals higher!
Hi @Studentmath
@Chris'ssis Don't forget to tell me when you publish the Au-Y one !
@alizter How did you do for your GCSE?
23:22
Heya @Alizter @Hippa
@Studentmath Heya
@Hippalectryon OK
How's it going?
@Studentmath :C
@Studentmath Revising for a chem mock oral exam tomorrow
Thau halt beant trolled.
r9m
r9m
23:23
@Chris'ssis oho !! the n-variable one marked as an open problem in Ovi's book !! :D
What're the subjects?
@Hippalectryon There are many ways to discover things, but one of the most powerful ones is to do research on a very small area, and dig there more and more. The Au-Yeung proof was possible due to the reasearching spirit and the fact that I studied a whole family of logarithmic integrals.
I have some results there completely crazy awesome, the way they look is just WOW!
I need to return back to some of these ones and exploit them for being able to use them for solving other very tough series.
All these things are related to each other, there is nothing to miss.
r9m
r9m
Is there a nice way of computing $\displaystyle \int\limits_{0}^{1} \frac{\log^3 x \log^2 1-x}{x}\,dx$ ? :-)
@r9m $\log 1=0$ so your integral is $-1$
;)
@r9m Beta function? It's the thing that instantaneously came to mind.
23:29
@Studentmath Thermodynamics, accumulators, biphased diagrams
@Chris'ssis I wish I had time to do that
@r9m On a more serious note $\mathrm B_{x, x, x, y, y}(0, 1)$
Or something similar
@r9m or combining the variable change with the integration by parts?
I am too tired and lazy to check
r9m
r9m
@Chris'ssis I'm not quite used to the beta function :o
@Hippa sounds nice actually
r9m
r9m
23:33
@Chris'ssis tried that for a while .. but couldn't manage much :(
@r9m Ah, done.
@r9m Just use series ...
r9m
r9m
growl !! I was trying to avoid that :P (I wanted to compute the series by computing the integral independently)
@r9m How can you write $\log^2(1-x)$ in terms of series?
@r9m In the end all gets reduced to computing $$\sum_{n\ge 1} \frac{H_n}{n^5}$$ and the rest is a piece of cake. :D
@Studentmath It's hard >:c
r9m
r9m
@Chris'ssis omg !! then I must have made an error in calculation .. :( I was trying to figure out what $\sum_{n\ge 1} \frac{H_n^2}{n^4}$ is !!
23:37
@r9m That is also a piece of cake for @Chris'ssis :)
@r9m haha, did you relate that series to the integral above ?:D
r9m
r9m
@Chris'ssis no no .. its can't be .. must be a calculation mistake :( sorry
@r9m Even great people make mistakes ! Proof : I make mistakes :P
@r9m If you know to do that series then ... you also know to do $$\sum_{n\ge 1} \frac{H_n^3}{n^3}$$
r9m
r9m
oh !! I do ? :O what am I missing here ! God help my soul !!
23:45
@r9m Talk to God for help then. :-)
Plz god @Chris'ssis pray pray
@Hippalectryon lolll :-))))
r9m
r9m
SIGH
Gimme @Chris'ssis's book early for Christmas pray pray pray
@Hippalectryon :)))))))))
@robjohn did you find something similar to that integral representation of $\zeta(2)$? Anyway, if you find anything similar just let me know. I'll investigate that stuff next days and if it's really new I'm going to publish it in a paper.
23:48
Ugh I still have Furudui's book to read
I never have time for it
@Chris'ssis I haven't been looking... Consider it unique until someone shows you otherwise.
@robjohn Yeah.
@Hippalectryon Then why did you buy it?
@Chris'ssis I have a formula for that...
@r9m do you have a long paper with double integral representations of $\zeta(2)$?
@robjohn hehe, I know :-) You also said one day you have a kind of generalization there for $H_n^{(k)}$...
r9m
r9m
@Chris'ssis :O IDK for sure ..
23:52
@Chris'ssis For when I have time :)
@r9m If you don't have a certain math paper then I'm sure that paper simply doesn't exist. :-)
@Chris'ssis For when I have time :)
@Chris'ssis Next year if I pass my exams
r9m
r9m
@Chris'ssis am I supposed to be a paper collector of some sort ? -_- ...
@Hippalectryon The exams for professionals? :-)
@Chris'ssis I already told you, I'm only 16 >:C
Your fault if you don't believe me -___-
23:54
@Hippalectryon lol, but you believe what you say there? :D
@Chris'ssis I have some approaches, but the full calculus still requires a bit of work, if indeed it is possible at all.
I do !!
@robjohn Help me convince @Chris'ssis :C
@Hippalectryon How? The only way we know anything on the net is by being convinced. I don't really have any information about your age other than what you might put in your profile, and that is put there by you. So, whatever I say is only what I have heard from you. Why would that convince her?
@Chris'ssis How can you not believe that I am 16 when @Anastasiya-Romanova is better than me at integrals, and younger ?
@robjohn What kind of pro asks the kind of questions I ask on main :/
@Hippalectryon Age does not mean anything.
23:58
What Alizter said ^^^
@Alizter Still, it's weird that @Chris'ssis thinks I'm a pro
@KajHansen How was dinner?
@Chris'ssis You never told me why you thought that btw, other than intuition
I want to know how Kaj's dinner went

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