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00:00
@Studentmath now i'm looking for a counterexample.
Counterexample of what you tried to prove?
i'm convinced it should be $(1-tz)^2$. it just works too well for that not to be it.
yeah. I think it's got to be a misprint.
$(1-t)^2z^2$ should be sharp for certain X's that could satisfy all your needs too, I think.
eh I hate having to work till 1 am
now I am full of caffine and cannot sleep
Say now if we take $X$ that is almost surely 1
Would it work?
Nah, it won't.
@Samuel I have a rather easy discrete counter-example.
I think so at least.
00:13
@Studentmath what's that?
Ah, wops. Scratch that.
@Alizter how many cups of coffee did you have?
Hmm: the crucial step in the $(1-t)^2$ proof is $(1-t)^2z^2<=(1-t)^2E(|X|)^2$ which has to be true. we want $(1-t)z^2<=(1-t)^2E(|X|)^2$ to fail, so we need $z^2>=(1-t)E(|X|)^2$. we already know $E(|X|)>z>0$ though, so $z^2<E(|X|)^2$, so we'd need for $1-t<0$. But we assumed $0<t<1$. Maybe this is it. i may be making a mistake.
@IceBoy redbull
@Alizter that stuff will get you wired, it has ginseng & caffine
00:28
ah that is the mistake, im being dumb we don't need $1-t<0$. ok
so we need $\frac{z^2}{E(|X|)^2}\geq 1-t$. we should pick $t$ to be near $1$ and $z$ to be close to $E(|X|)$.
Shouldn't be too hard...
Shouldn't it be $t$ close to 0?
Ah no, being stupid here
for an easy analysis question
I actually meant to give it 50 bounty points, don't know what happened :P
00:44
you'll get a lot of attention now
I never look at bounty questions lol
so, you're not a bounty hunter?
Nope. I am a will hunter lol
:D
hunting for good will or hunting for will power?
@Alizter You misspelled caffeine.
00:48
It seems it's not that easy at all to find a counterexample.
@IceBoy You misspelled caffeine.
caffine caffeine
sorry
please forgive me
@KajHansen Hi Matt Damon.
Hey there
00:54
Time for some coffee before seeing my psychologist.
$\text{caffeine} \subseteq \text{coffee}$
If only rep can buy coffee lol
01:00
LOL
01:28
Just by the way, makes me sad. L'Hospital (with an S) seems to be far too common a joke/typo these days.
01:56
@michaelb958 It is neither a typo nor a joke; the correct spellings are L'Hospital and L'Hôpital. If one omits the circumflex over the o, the s should be included. (This is why the s is included in the tag - you can't use special characters in tags.)
02:23
@MikeMiller I stand corrected. Thanks!
Sit down corrected
02:50
If an alternating series diverges, does that tell us anything about the series absolute convergence?
03:17
Yes @JessicaK: it must diverge absolutely. Why?
@TedShifrin, I've started my real early enough to TeX it this time ;)
With age comes less procrastination? @Kaj
did you figure out that connectedness ?
Not yet. I've spent all my free time today either tutoring or doing my Quodes homework.
I'll probably get some food and think about it some before I go to bed.
Very late for food!
But dining hall is right next to Boyd and on my way back to my room :P
03:22
Things are open now?
@TedShifrin I just wasn't 100% sure because I was trying to take the contrapositive of the alternating series test. I convinced myself it diverges just as I looked up to see your reply.
Oh yeah, I remember you guys pigged out at 2 am last spring.
@TedShifrin, one of the dining halls is open 24 hours during the week!
LOL
No contrapositive. Direct inequalities with partial sums, @JessicaK
@TedShifrin Thanks you
03:25
Sure :)
opps, I meant thank you
Hi
I have a question. Is there upper limit of points that we obtain in a say ?
My answer has two votes but point is not counted.
03:54
@HeeKwonLee Yes. The upper limit is 200 reputation points per day, with some restriction. Specifically:
"You can earn a maximum of +200 reputation from upvotes and suggested edits in any given day. Accepted answers and bounties are counted separately... Reputation "lost" from the reputation cap is not awarded on following days." Source
(Note that reputation from accepted answers does not count towards the limit. That's how you have 275 points from today.)
helloooo!!!!
04:21
@anorton Thank you for your explanation.
anyone here?
04:38
Hey @r9m
r9m
r9m
@BalarkaSen Hi :)
What's up?
why isn't anyone answering my pde questions? T_T
r9m
r9m
@BalarkaSen nothing interesting :|
That's sad.
r9m
r9m
04:41
\ (-o-) / Yaaawnn ..
-.-
shakes everyone talk to me!!!D:
@Kaj!
Ah, this one is excellent :
r9m
r9m
hehe :P
r9m
r9m
is TheGame new name of Hippa ?
04:50
yeah
r9m
r9m
ah thanks !
@TheGame Have you seen this book .. Exercices corrigés de théorie analytique et probabiliste des nombres - De Gérald Tenenbaum, Contributions de Jie Wu ( Société Mathématique De France) ? .. please let me know if your school/college library has a copy of it ;)
Someone just referred that to me recently.
An english version.
Hey there
@KajHansen Are you still sticking to ODEs and PDEs.
or anything fun (e.g., algebra) lately?
Not PDEs. I'm studying ODEs and real right now.
04:54
Never liked them. Blech.
ODEs is kind of boring I agree.
Real can be boring, but I really enjoyed the topology section in Rudin. The problems are fun.
leo
leo
05:15
@isukidoll hello
05:29
wahhhhh
this site needs more pde tutors
06:03
0
Q: $-1.4\sin 3x - 0.2 \cos 3x$ in the form $R \sin (3x+\alpha)$ such that $R>0$ and $0<\alpha<2\pi$

Tharindu Write $-1.4 \sin 3x - 0.2 \cos 3x$ in the form $R \sin (3x+\alpha)$ such that $R>0$ and $0<\alpha<2\pi$ I found $R= \sqrt{(-1.4)^2+(-0.2)^2}= \sqrt{2}$ And $\alpha= \arctan \frac{0.2}{1.4}= \arctan \frac {1}{7}$ Now the problem is I could write this as $-\sqrt{2}\sin(3x+\arctan \frac{1...

Can someone help me in this problem? :)
@r9m: hey there... haven't seen you in a while (probably my fault)
Hello Robjohn, I'm looking for a book to learn number theory with, what book did introduce you to number theory, or is there any book you could recommend as an inttroduction to number thoery.
06:22
@Joao try number theory by george andrews.... my class is using that book and it's easy to follow...well most of the time... the author kind of is eh when it comes to the proofs
r9m
r9m
@robjohn hello :D .. I was afc for a few days :-)
@r9m that would explain it, too :-)
r9m
r9m
:)
@Joao If you use @robjohn, it will ping me and I will see your comments sooner. My number theory studies came from many books. There are different ones that are better for different topics. I now that Borevich and Shafarevich and Hardy and Wright are highly regarded beginning general books.
@robjohn do you know pdes?
06:37
@usukidoll a little, but I am not really an expert.
:/ it's about a theorem... the one after the max principle after my attempt wait let me get the link... I already figured out the other one with the heat equation Duhamels
@robjohn continuous dependence
http://math.stackexchange.com/questions/958928/proving-the-maximum-principle-and-the-continuous-dependence-on-initial-condition
07:27
I just returned from some psychotherapy.
@Joao Look at Alan Baker's Comprehensive Course in Number Theory.
yay for the rep points but still no answer T_T
@JasperLoy what's wrong with you?
@EricGregor Suffering from OCD for past 15 years, among other things. Not worked for past 7 years. That is just a summary of my shit life.
do you have a special diet?
07:36
i was once interested in the idea of Jungian psychotherapy
but it's a little far out there, and Jung was basically a cult leader. but there was something fascinating about it. though i imagine in practice it's usually quite banal
08:12
Hi @jay
@JasperLoy Hello, how are you?
@JayeshBadwaik When do you graduate?
@JasperLoy in coming June.
@JayeshBadwaik Good good. My current plan is to enter grad school in 2017
@JasperLoy Nice, not bad. Good luck. :-)
Will you start math again before it?
08:18
Yes, I am going to study math next year, take the GRE in 2016
Good, good.
I will try to finish my 12 holy math books either by end 2015 or end 2016
Depends on how long each book takes
12 books in one years seems ambitious unless you have studied quite a few before?
Okay, I have a class in 10 minutes now. Gotta go, bye. See ya around.
Greetings
08:21
Hi @Chris'ssis you vanished last night after I asked you your age lol
@JasperLoy I had some things to do like now
@r9m $$\sum_{k=1}^{\infty} \frac{(k+1)^s}{k^{2s} (k^s+(k+1)^s)}>\frac{1}{2}\zeta(2s)+\frac{1}{8}, \space s>1$$ As far as I know, you love these questions. :-)
09:10
@Studentmath!
09:51
@robjohn I went further and I developed a new integral
$$\int_0^1\log^2\left(\frac{x}{2}+\sqrt{\frac{x^2}{4}+1}\right)\frac{\ dx}{x}=\frac{\zeta(3)}{10}$$
10:15
My intuition tells me that $$\int_0^1\log^n\left(\frac{x}{2}+\sqrt{\frac{x^2}{4}+1}\right)\frac{\ dx}{x}=C \zeta(n+1),\space C \in \mathcal{Q}$$
What is $\mathcal{Q}$, @Chris'ssis?
@BalarkaSen Q
Oh you mean rationals?
@BalarkaSen Yeah
@Chris'ssis Standard notation is $\Bbb Q$
But the context is clear nevertheless.
10:19
@BalarkaSen Well, I don't always use the standard notations. Actually I don't care too much the standard notations.
@Chris'ssis That'd only make stuff hard to read.
@BalarkaSen Not in this case.
Fair enough.
But $\mathcal{Q}$ sure looks ugly :P
@BalarkaSen lol. I like it that way pretty much. :-)
How about $\mathfrak{Q}$
Eugh
10:22
@BalarkaSen not bad ...
10:52
@BalarkaSen cute hat
@BalarkaSen I like to write $\mathcal{C}$ for my constants in integration, and C and B for my continouos and bounded spaces functions eg $f \in C^1$
Just answered a lhf.
I have yet to learn proper LaTeX.
@JasperLoy low five
@N3buchadnezzar No meat, no pudding.
@JasperLoy Start with a whip, and then slowly add a gag ball. And then the suit when you are up for it.
11:49
The user X likes to make stupid edits on other people's posts...
However, it is good that the silly comments have stopped.
If I read a paper written by X, I will throw it into the dustbin because of its poor formatting and punctuation.
@JasperLoy Someone who enjoys blue colors?
@N3buchadnezzar Well, shh...
@JasperLoy He tried to pull that on one of my posts. I really pulled his nut, and kicked his dog.
Anyway, many people like blue here.
@N3buchadnezzar Are we thinking of the same person? The username has 5 letters.
@JasperLoy A single name, not a double name?
11:56
@N3buchadnezzar Yes, single word with 5 letters.
Mmm, not the same.
12:12
Hi @JasperLoy
@nablablah Hi Bart.
Just answered a lhf.
@Chris'ssis That looks an awful lot like an inverse hyperbolic function
@robjohn Yeah, sure. :-)
@Chris'ssis I think looking at it that way, we might get your generalization
@robjohn I think getting the generalization is a very hard thing to do.
12:24
@Chris'ssis okay. I would have to look closer.
@robjohn You are up very early
@JasperLoy You are up very late
@N3buchadnezzar LOL
@BalarkaSen It does look like a hat, fit for a cat.
Rather crumpled.
Hat for hats : $$\widehat{\mathcal{Q}}$$
r9m
r9m
12:43
@Chris'ssis Nice !! :-)
typo $\widehat{\mathfrak{Q}}$
@r9m Yeah, it's awesome. BTW, how are you doing?
r9m
r9m
@Chris'ssis trying to survive somehow :-)
@BalarkaSen thats hatception, a hat on a hat. The second one looks more like a sloopy triangle than a hat though
LOL @N3buchadnezzar
12:46
@r9m I understand your point. :-)
@r9m How's analytic number theory going?
r9m
r9m
'survive somehow' .. thats how its going ..
Grumph.
You need to have fun with the subjects, @r9m, seriously.
r9m
r9m
_ /\ _ _ /\ _
@r9m Weird boobies, or cat hats? Can not quite decide
r9m
r9m
12:48
neither
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.………\;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ;;;;;;;;;”-,………………¸~””)
Well that failed misserably, poor attempt at hat.
r9m
r9m
if that's a poor attempt .. hats off =P
@r9m The topp part is fine though!
r9m
r9m
ya .. and I just took it off !
             _
           /`_>
          / /
          |/
      ____|    __
     |    \.-``  )
     |---``\  _.'
  .-`'---``_.'
 (__...--``
┌─┐
┴─┴
ಠ_ರೃ
12:55
-2
Q: Welcome back Brian M. Scott!!!

Ice BoyFirst of all thank you for coming back. We missed you Professor.

@IceBoy More drama lol
13:26
Someone told me they would integrate my face, I had no idea what they meant.
r9m
r9m
can someone help me with a problem involving Fourier transforms .. if $\omega$ and $\hat{\omega}$ are both ${\ell}^1(\mathbb{R})$, where, $\displaystyle \hat{\omega}(\tau) = \int_{-\infty}^{\infty} \omega(t)e^{-it\tau}\,dt$, then for $k > \sigma$ ($\sigma$ being the abscissa of convergence of the dirichlet series $\displaystyle F(s) = \sum\limits_{n=1}^{\infty} \frac{a_n}{n^s}$) ..
$$\sum\limits_{n=1}^{\infty} a_n (\frac{x}{n})^k \omega(\log \frac{x}{n}) = \int\limits_{k-i\infty}^{k+i\infty} F(s)\frac{x^s}{s}\hat{\omega}(\tau)\,ds$$
this is a problem from the second chapter exercise of Tenenbaum's book .. Intro to analytic and probabilistic NT
typo .. sorry $\displaystyle \sum\limits_{n=1}^{\infty} a_n (\frac{x}{n})^k \omega(\log \frac{x}{n}) = \frac{1}{2\pi i}\int\limits_{k-i\infty}^{k+i\infty} F(s)x^s \hat{\omega}(\tau)\,ds$
@N3buchadnezzar you should have asked them with what?
r9m
r9m
13:41
my confusion is in $\displaystyle \frac{1}{2\pi i} \int\limits_{k-i\infty}^{k+i\infty} x^s \hat{\omega}(\tau)\,ds$ .. should it be $\hat{\omega}(s)$ inside there instead ?
@IceBoy with by fish!
@N3buchadnezzar so he wanted to slap your face with a fish
@IceBoy I didnt say tthat (and fish souns more amusing)
@N3buchadnezzar you are typing like you are drunk
@IceBoy hic
13:48
@N3buchadnezzar :D
@robjohn If I'm able to find that $\displaystyle \int_0^1\log^3\left(\frac{x}{2}+\sqrt{\frac{x^2}{4}+1}\right)\frac{\ dx}{x}=C \zeta(4)$ and then I manage to get that $C$, I think I'll be the first one that have ever managed to answer a certain mathematical problem (I cannot share it now).
dont drink and derive, kids
9
r9m
r9m
@Chris'ssis oho !! an open problem at your mercy ! Lord have mercy on its 'soul' :D
@N3buchadnezzar MADD = Mathematicians Against Drunken Derivations
@r9m What do you mean? :-)
@r9m Did you figure out the problem I was referring at?:-)
r9m
r9m
13:55
@Chris'ssis I prayed the to the Lord to have mercy on the 'soul' of the problem (assuming it has one) 'coz I think it won't have any form your part :D
@r9m lol:-))))))))
r9m
r9m
@Chris'ssis homeworks at hand ! will try it later please ! ^_^
@IceBoy I 2 week old superstrong coffe, har mercy on my typing capabilities
@N3buchadnezzar I have been 2 weeks without drinking coffee.
@MatsGranvik I was too. Yesterday the last bits of cofeein ran out of me.
r9m
r9m
13:59
haha !! @N3 good one !! :)
@N3buchadnezzar Not funny, lol.
I am also a second hand drinker.
I need to be careful as regards coffee, it affects your Calcium level in your body, not necessarily for bones, but also for other parts of the body.
@r9m Do not use the Lord's name in vain, lol.
@r9m you need at least 3 characters after the @
r9m
r9m
14:01
@IceBoy o ! I see .. thanks !
np pal :-)
r9m
r9m
@JasperLoy so you are a believer in 'The Book' ? :-)
@r9m No, I am a semi-Buddhist and an ex-Christian.
"The calcium level in blood can be moderately low without causing any symptoms. If levels of calcium are low for long periods, people may develop dry scaly skin, brittle nails, and coarse hair. Muscle cramps involving the back and legs are common. Over time, hypocalcemia can affect the brain and cause neurologic or psychologic symptoms, such as confusion, memory loss, delirium, depression, and hallucinations. These symptoms disappear if the calcium level is restored."
@Chris'ssis Where does it say that coffee affects calcium levels?
14:05
@JasperLoy from my doctor
@Chris'ssis Is it because of caffeine?
@JasperLoy Perhaps.
@Chris'ssis I drink a lot of coffee these days. Oh no!
@JasperLoy Be sure the great companies take care such information are not clearly put in some studies. They recognize there is a small loss of calcium, but just a small that has no importance.
@JasperLoy Now that might be true for some, but not for all. I felt these effects many times.
14:11
@JasperLoy Just also drink milk or eat cheese.
@r9m
r9m
r9m
@Sawarnik yes
@r9m after a looong time?
r9m
r9m
@Sawarnik not that long ,, I was only away for a few days
@r9m where, why
14:17
Anyone here smokes?
I am just trying to see whether math people smoke.
i smoke the fools who try to smoke
r9m
r9m
@Sawarnik just away from the chat .. thats all
@r9m good work .. it must have saved you alot of time
r9m
r9m
not really =P .. I waste a lot of time anyway :P
:18054421 Well, it was off-topic, wasn't it?
14:22
yes
Users here are too serious, they downvote congrat posts on meta.
Such seriousness is not conducive for the production of high quality mathematics lol.
2
I will try not to come to chat anymore after this year. This will be my last year in chat.
Such seriousness is not conductive of a user-friendly place.
Kids like to remove things they say.
Hey, I removed somethings
@IceBoy Did you like it?
14:27
@DanielFischer what?
There are two barber shop in a small town – one located in the eastern market and the other on the northern market. The shop in the eastern market is quite untidy and the barber has a shabby haircut. While the shop in the northern market is quite neat and clean and the barber is sporting an excellent haircut himself.
Which of the two shops should you opt for?
@IceBoy Did you like removing the somethings?
@Sawarnik The one of the guy who cut the hair of the northern barber.
@DanielFischer :) You are intelligent we know.
14:28
@IceBoy Then you're safe. Nobody will call you a kid.
In fact, although I will keep my account for life as promised, I think I won't visit the site or chat after this year.
I should devote all my time to mathematics alone.
@JasperLoy You blabber a lot.
Kiddish behavior, I should add.
and you don't?
Who says I am not a kid?
The purpose of this chat is for us to blabber lol
14:41
@JasperLoy chat log
@IceBoy I do.
@Sawarnik what is your problem?
@N3buchadnezzar There are many different definitions of kid lol
@IceBoy None.
@JasperLoy IWTBTG
14:42
@N3buchadnezzar :D
@Sawarnik ok np pal :-)
I have not been following the Millennium Problems. Has any of them been solved other than Poincare?
@JasperLoy Yeah, google gives two. 'a child or young person' and 'a young goat'.
@JasperLoy Two of them have been solved I think (quite sure)
@N3buchadnezzar Ah, which one?
14:44
@JasperLoy Google.
@Sawarnik he has a mental illness
don't be mean
@JasperLoy I was wrong
@Sawarnik He is not a kid.
I am going to take a nap.
later pal
in Mathematics Educators, 3 hours ago, by Joel Reyes Noche
So what is a math warrior to do?
Many analysts answer this with a slogan: When all else fails use a computer. If that fails then use a bigger computer.

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