What ways would you propose for getting the inequality below?
$$\sum_{k=2}^{\infty} \frac{k^s}{k^{2s}-1}> \frac{3\sqrt{3}}{2}(\zeta(2s)-1),\space s>1$$
The left side may be written as
$$\sum_{k=2}^{\infty} \frac{k^s}{k^{2s}-1}>\zeta(s)-1$$
but how do we prove then that
$$\zeta(s)-1> \frac{...
What ways would you propose for getting the inequality below?
$$\sum_{k=2}^{\infty} \frac{k^s}{k^{2s}-1}> \frac{3\sqrt{3}}{2}(\zeta(2s)-1),\space s>1$$
The left side may be written as
$$\sum_{k=2}^{\infty} \frac{k^s}{k^{2s}-1}>\zeta(s)-1$$
but how do we prove then that
$$\zeta(s)-1> \frac{...
What ways would you propose for getting the inequality below?
$$\sum_{k=2}^{\infty} \frac{k^s}{k^{2s}-1}> \frac{3\sqrt{3}}{2}(\zeta(2s)-1),\space s>1$$
The left side may be written as
$$\sum_{k=2}^{\infty} \frac{k^s}{k^{2s}-1}>\zeta(s)-1$$
but how do we prove then that
$$\zeta(s)-1> \frac{...
