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14:13
@Chris'ssis @robjohn is there a closed form for $\displaystyle \int_{0}^\infty \frac{cos(ux)}{x}dx$ and $\displaystyle \int_{0}^\infty \frac{sin(ux)}{x}dx$
@G.T.R the left one does not converge ($\infty$)
The right one has one using contour integration... $\pi/2$ for all $u$
@G.T.R Sure ... (for the right side one)
In mathematics, there are several integrals known as the Dirichlet integral, after the German mathematician Peter Gustav Lejeune Dirichlet. One of those is : \int_0^\infty \frac{\sin \omega}{\omega}\,d\omega = \frac{\pi}{2} This integral is not absolutely convergent, and so the integral is not even defined in the sense of Lebesgue integration, but it is defined in the sense of the Riemann integral or the Henstock–Kurzweil integral. The value of the integral (in the Riemann or Henstock sense) can be derived in various ways. For example, the value can be determined from attempts to eva...
14:30
@Chris'ssis @robjohn what about $\displaystyle \lim_{M\to \infty} \int_a^b \frac{sin(Mu)}{u^2}du$ ?
Anybody here a recommandation for a good book to study for my first course representation theory ?
@r9m Connecting stuffs is not very deep mathematics.
The real depth of mathematics comes when you develop everything from scratch, from basic observations.
r9m
r9m
@BalarkaSen I was only answering a simple question :) and found it convenient coz the OP had already proposed partial solution :)
@r9m Link?
r9m
r9m
@BalarkaSen [here](math.stackexchange.com/questions/822495/show-that-p-nx-rightrightarrows-0‌​-qquad-x-in0-1/)
14:40
@Chris'ssis for motivation, math.stackexchange.com/questions/825869/… and let $\displaystyle I=\int ^\infty_0 \frac{b\sin{ax} - a\sin{bx}}{x}dx$, and see what $I/(ab)$ look like. Rewriting the inside as an integral, I got the computation I asked you
@r9m Interesting. That's interesting.
r9m
r9m
@BalarkaSen how does epsilon-delta stuff interest BalarkaSen ??!!.. hmm interesting :D !!
Ian
Ian
Hey @BalarkaSen I've got a question for you (more of a reference request, really)
@Ian OK.
I think I have 3 windows with chrome running each with 50 tabs open >.<
"Oh, this is usefull. Will just leave that open for later"
14:43
how much RAM do you have @N3buchadnezzar ?
"PING. Oh I forgot where i put facebook / this chat. Better open a new one"
@G.T.R 8 ?
@N3buchadnezzar good
Ian
Ian
@BalarkaSen have you ever seen the concept of "expected number of different factorizations" in a non-UFD? Like, take $\{z \in\mathbf Z[\sqrt 5]:N(z)<M\}$. Calculate the expected number of factorizations for this set. Let $M\to\infty$ ($N$ is the norm)
@Ian "expected number of factorizations"?
Ian
Ian
@BalarkaSen yes. Some numbers have two different factorizations, some four, and so on. The mean could be finite in principle
14:47
Still frurstrating
@Ian Ah, you mean the multiplicative partition?
I need to start keeping sessions, one for cubing, one for mathematics, one for misc, and one for pictures of cute kittens
@N3buchadnezzar cubing ?
Rubiks
I avreage 16 :p
@N3buchadnezzar speedcubing ?
14:48
Yeah
@N3 Have you read the algorithm?
I got a weird cube I need to show you
@G.T.R Does the mean value theorem help?
@N3buchadnezzar search [rubik's cube group]
Ian
Ian
@BalarkaSen I think so, I don't know this nomenclature :-) For example, $6$ has two different factorizations: $2\cdot 3 = (1-\sqrt{-5})(1+\sqrt{-5})$ (sorry, I meant $\mathbf Z[\sqrt{-5}]$)
@Chris'ssis I don't know
@BalarkaSen Are you good at math because you know the formulas?
Are you good at driving if you know how the individual parts work?
@G.T.R That is $0$.
Same with cubing >.< Everyone can solve it, most can do it under a minute. A few under 20. Under 15 requires real talent
Thats a cool one
@G.T.R Riemann-Lebesgue lemma
@N3buchadnezzar well I can't solve it
@Chris'ssis right, how did I omit this ...
@G.T.R The challenge is to do it with high school knowledge ... (I think I have at least a proof in mind)
@Chris'ssis come on, here, Riemann Lebesgue is just integration by part
15:03
The generalized version too ?
no it's more troublesome
I have some big issues with my comp ... hmmm
brb
@G.T.R I saw a proof on site, but did not fully understand it
@N3buchadnezzar for which version of the lemma ? for $C^1$ functions it's easy, for just continuous, you need to use density of step functions on $[a,b]$
$$
\lim_{n \to \infty} \int_a^b f(x)g(nx)\,\mathrm{d}x
= \left(\int_0^T g(x) \,\mathrm{d}x \right)\left( \int_a^b f(x) \,\mathrm{d}x \right)
$$
I mean this generalization
15:10
what are hypotheses on $f$ and $g$ ?
Where $g(x)$ is a periodic function with period $T$ and $f(x)$ is piecewise continuous on $[a,b]$
Heh silly me
$$\lim_{n \to \infty} \int_a^b f(x)g(nx)\,\mathrm{d}x = \frac{1}{T} \left(\int_0^T g(x) \,\mathrm{d}x \right)\left( \int_a^b f(x) \,\mathrm{d}x \right)$$
Forgot to divide by the period
Subtract the average of $g$, and you're in the Riemann-Lebesgue department.
@DanielFischer Hmmm do not see it
15:25
@N3buchadnezzar Let $\mu = \frac{1}{T}\int_0^T g(t)\,dt$ and $h(t) = g(t) - \mu$. Then $\int_0^T h(t)\,dt = 0$, and you want to show $$\lim_{n\to\infty} \int_a^b f(x) h(nx)\,dx = 0.$$ You do that like Riemann-Lebesgue, assuming $h$ is bounded [e.g. if it is continuous]; take $f\in C^1$ and integrate by parts, approximate general $f$ in $L^1$ by $C^1$ functions. If it's unbounded, a little more care to show it would be necessary.
15:57
Hi @DanielFischer, I don't really understand your explanation here math.stackexchange.com/questions/825958/…
If we have some closed disc centered at $x$ with points $y \leq r$ from $x$, how can $||z - y|| > r$ not belong to that disk when $y$ is inside that disc and also inside the disc centered at $z$
@nablablah If a point is outside a closed disk (disk isn't important), then it never is "immediately adjacent" to the disk, it always has a positive distance from the disk. For an open disk, you can say that the boundary points (the points of the bounding circle) are immediately adjacent to the disk, but for a closed disk, it's either in the disk, or some distance away from it.
@nablablah Let's for simplicity look at the closed unit disk $D = \{ x : \lVert x\rVert \leqslant 1\}$. Then if $z \notin D$, that means $\lVert z\rVert > 1$, and $z$ is at a distance $\lVert z\rVert-1$ from $D$.
But if a point can be "immediately adjacent" to a disk, isn't that a positive distance of 1? Since the point is 1 "distance" over from the point on the disk?
Ok
@DanielFischer What if we consider something like the natural numbers in $\mathbb{R}$ and we have a like a closed set $1 \leq x \leq 3$. If we consider the point $4$, isn't that a positive distance from $3$?
16:15
@nablablah Yes, that is at a positive distance from $3$. But, in the integers, you can only move in discrete steps (of integer size), so one could then say it is immediately adjacent, since there is no integer between $4$ and the set. However, in $\mathbb{R}^n$, we can move arbitrary distances, so whenever we have a positive distance, we have lots of points in between.
Ok, so I think my issue is with the conceptual understanding of infinite points
Hi @JasperLoy
@nablablah Hi Bart.
I had a nightmare again.
About?
About being abused by some people.
People you don't like?
16:26
They are mostly distorted recollections of the past.
@Jas I have nightmares all the time. I found that looking at them as something exciting makes it easier
I only escape my nightmares when I sleep.
16:46
@chris'ssis well
And there chat died
@N3b deep
rollin in the deep
I can't be arsed to write down the code.
17:00
Homework assignment. Have to do this one, then five more, than have ten days to hand two more and study for the first test..
Heya @Studentmath ;) Miss chemistry?
@Studentmath As a wise man told me once. Life is a poop eating contest, the one who can eat the most without giving up wins.
Wise words, @N3b, and I would want, Prof. @Ted, 'sadly' done with all the chemistry courses already. it's a coding course for the math major
Major tom to ground controll
I know too many songs and too little mathematics
17:18
I don't know enough of either
I know, @Studentmath; that's why I asked if you missed (longed for) chem :)
Ugggh @N3
Oh, funny, I read it as 'Miss. Chemistry" as in "Lady Chemistry" - doing this course, very very much so, yeah..
You do not like the song @Ted ?
I just had a delicious Subway sandwich.
It was not the song, @N3; it was the previous comment. :D
17:22
@TedShifrin Well it's true. You live, you die, and it's up to you to make the most out the part in between.
They have Subway in Singapore, @Jasper? Ugh @American fast food everywhere.
They are the best @Jasper
They have Subway in Israel, Prof. @Ted. And we don't have Subways.
@TedShifrin Yes, although we are quite conservative, we are quite Americanised.
Bah @Americanization = dumbing down
Yes, just look at the math, lol.
17:24
You are still the biggest power in the world though
Hebrew math all the way
@Studentmath Biggest in several ways ;)
@N3b Is it the Aleph or the Nebel?
I must remark again I am very surprised so few people are using Cohn's algebra books.
Regarding the Hebrew Math
17:27
Nebel
I just deleted an answer because someone posted it 6 seconds earlier and got upvoted but mine did not.
This voting thing is so stupid.
Every second counts.. I gave a very tiny hint and someone got the answer from it today, was really happy. Felt helpful in a good way.
Site is read-only. AGAIN ?
17:29
Offline for maintenance again?
Wow, the developers ought to be fired.
Just as I was commenting on someone who followed the first part of my hint and pisted a separate answer ... Although he may have been typing as I posted.
Back again
Salut, @Gabriel
Because I threatened to fire them.
@Ted salut, alors t'as regardé la finale ?
17:33
Bien sûr. J'ai même posté VAMOS, RAFA sur mon Facebook :)
@TedShifrin I would like to ask your opinion. Do you think it is important to teach Krull Schmidt theorem and Maschke theorem in a grad algebra course?
Don't ask me. The only grad alg I ever took was a comm alg course when I was an undergrad.
Then I took a bunch of alg geo, and a year-long course on Lie groups/algebras in grad.
Gonna force myself to work. Good night @Ted, @N3b!
@Studentmath See you in your dreams!
Hello @ant, why this username?
17:52
night, @Studentmath
@TedShifrin May I ask which differential geometry text you use to teach a grad differential geometry course?
18:20
@Jasper: My taste is not typical. I have never followed any single text, and much of what I do is more differential-forms based than any of the standard texts. These days, doCarmo and Petersen are the two most-used texts, but neither fits my personal taste. This last time I proved Chern-Gauss-Bonnet, which is not standard; the previous time, I taught some complex geometry because the students (all undergrads) wanted to see that.
If I get totally bored when I've retired, I may get inspired to TeX up my various grad course notes, but I doubt it.
Ant
Ant
@JasperLoy I'm Italian, and my full name is Antonio. Hence Ant ;-)
I didn't really realize the connection with and, the insect :)
*with ant, the insect
Ciao, @Ant. :)
Ant
Ant
Saluti a tutti da Milano ! I have to leave now ;)
@Ted is there an intuitive explanation of why the Fourier coefficients get smaller as a function is differentiated ?
Ciao, @Ant :)
Well, it's more like the smaller they are the more differentiable the function is. @GTR
18:31
@TedShifrin hello?
@N3buchadnezzar Am I even good at math? But that wasn't the point : I simply asked if you know the theory. It's interesting, but not of much use.
Hello @AmericanLuke
@AmericanLuke self-ping :P
1 hour ago, by Ted Shifrin
They have Subway in Singapore, @Jasper? Ugh @American fast food everywhere.
Hahahaha
Ha..oof...heh... ahem
Hullo @TedShifrin
@GTR, if $f(x)\sim \sum c_ke^{ikx}$, then $f'(x)\sim \sum ikc_ke^{ikx}$, so they're not getting smaller when you differentiate. But if $f$ is $d$ times differentiable, that tells you that you need the $c_k$ to decay sufficiently rapidly for $\sum k^dc_k$ to converge appropriatley @GTR
hello @Balarka
18:34
@TedShifrin I got through that problem.
Oh, which problem, @Balarka?
Did you mean to ping me?
@TedShifrin $L/\Bbb C(z)$ and $L'/\Bbb C(z)$ be galois extensions. If the galois groups are isomorphic then is $L = L'$?
@AmericanLuke, to the best of my knowledge, I only pinged you after you'd said hello? to me ...
ohhh, that one @Balarka.
that one... :P
18:36
@TedShifrin You wrote @American fast food in a message to Jasper. That pinged Luke.
Oh, crap. Thanks, @DanielF. I should have left a space after the @ ... My apologies, @AmericanLuke.
Yeah, and that's why I laughed.
Well, you're a big help, @Balarka.
Luke probably is a majority stockholder in McDonalds or something ...
how many letters does it take to earn a ping, @DanielF? (Note that I now always put the F in your name so as not to incure DanielRust's ire.)
That was NOT star-worthy.
18:39
@TedShifrin I wish :P
@ted
@te
@t
three it seems
so it takes three, huh?
Hi all
hi @use
does someone here know how to use mathematica?
(Now all people with name @user..... will get pinged. GOOD.)
I hate to admit knowing anything in here, but, yes, @user322222222184.
18:40
@TedShifrin I'm not sure about chat. In comments, you need at least 3, and if there are several matches, the least recent contributor is pinged.
sorry for interrupting your conversion, because I got a quick question. If you have x+y=x^2, how do you solve in terms of y in mathematica?
A college kid bitched at me when I commented on his comment that made absolutely no sense. :) He told me he wasn't done editing. Geez ... @DanielF
@user322...: Solve[x+y==x^2,y]
Oh, wait, in terms of y? You want to solve for x. Then put x at the end, not y. Sorry.
@TedShifrin I wonder what became of the custom to finish editing before posting.
Especially in comments, where one only has milliseconds @DanielF
@TedShifrin You have more time for editing there than in chat.
18:43
@TedShifrin, thank you
Of course, the OP had garbage in his post, which I kindly corrected in my comment :) $(\operatorname{Col}(A))^\perp = (\operatorname{Nul} A)^\top$, eh?
? No comprende.
@TedShifrin I noted that $\Bbb C(z)$ is the function field of $\Bbb P^1$ and $G = \text{Gal}(L/\Bbb C(z))$ is the deck transformation group of the (branched) galois covering $X \to \Bbb P^1$ for some Riemannsurface $X$. Another covering is $X_0 \to \Bbb P^1$ corresponding to $L'$. One has $\Bbb P^1 \cong X/G$ and $\Bbb P^1 \cong X_0/G$ so $X \cong X_0$.
That was the garbage. But then the kid told the OP to do that in his "comment." Sigh. After I said it was nonsense, he said he hadn't finished editing. @DanielF
Whoa, in general, that can be subtle, @Balarka.
I don't think $X/G = Y/G \implies X=Y$ without something.
But I don't want to think about it now. I have to go back to the kitchen and finish decalcifying my espresso machine :D
@TedShifrin Hmm. Counterexamples?
@TedShifrin Okey-dokey.
18:46
I don't have one off the top of my head, @Balarka. But I think I've fallen in that trap ... years ago.
I'll ponder later.
:15976286 So?
You're assuming $G$ acts freely and properly or something? Otherwise, I can take $G$ acting trivially in one case and not in the other, for a stupid counterexample @Balarka.
Yeah, not the same group.
@TedShifrin $G$ acts freely on the fibers of the cover, right?
So free action.
@BalarkaSen Problem at branch points.
18:48
Yes ... Just saying we need hypotheses for starters. But I still think it might be wrong. What if we have an example with $X/G \cong X$?
@DanielFischer What problem?
@BalarkaSen Not all points above $p(\text{branch point})$ need to be branch points.
(In general, I don't know about the specific situation)
@DanielFischer Hmmm.
@TedShifrin Perhaps start by the fact that $X \to X/G$ is always a galois covering whenever $G$ acts on $X$ properly discontinuously.
Yeah, you're doing covering spaces (well, branched). I'm thinking more generally, just in terms of homogeneous spaces. I am pretty sure it's wrong.
OK, outta here for now.
Bye @TedShifrin
18:58
There are not enough lhf for me.
@JasperLoy you missed one of mine earlier today
@G.T.R Nah, your questions are too hard for me, I have forgotten all the math I learnt, except high school stuff, lol.
@IlanAizelmanWS Nice haircut, lol.
@JasperLoy Oi!
@IlanAizelmanWS After my basic military training, I was a clerk in an office most of the time. So military service was not too bad for me.
@JasperLoy Awesome.
19:05
Who is from Canda!?
@JasperLoy What do you tell the girls when they ask you what you did in the military?
Anyone here from CANDA?
@JasperLoy Oh wait, nvm.
NO CANADIAN>
@IlanAizelmanWS I tell them the truth, lol.
19:05
?
Not many Canadians in this chat.
@JasperLoy The truth they want to hear?
@user3222184 The user JessicaK is
@IlanAizelmanWS Just the truth and nothing but the truth. I try not to lie.
19:06
@user3222184 What is the video about?
@G.T.R I have searched in vain for a brand new copy in English of all the volumes of Dieudonne's Treatise On Analysis.
The last time I saw it was in my university library, six big books.
The problem with SE questions is that many of them have redundant commas. Commas trip up even native speakers.
There seems to be a slight problem with chat.
@JasperLoy Which?
@DanielFischer Oh I keep having to refresh my browser. Maybe it is just me.
@G.T.R What book do you use in France for analysis course?
we don't have iconic recent books like they have in the US, but this one has a good rep amazon.fr/Analyse-MPSI-Jean-Marie-Monier/dp/2100498371 @JasperLoy
19:22
I just answered a lhf.
19:41
I finally got 1200 rep.
@mike I still think you are going to UCLA, lol.
Wow, the user I hate most has cast over 1500 downvotes...
A @BalarkaSen
@JasperLoy Mr.hungry /angry ?
@JasperLoy How'd you know?
19:52
@G.T.R No idea who that is.
@BalarkaSen From his user profile.
@Jasper: You'll respect me more when I downvote more :D
@TedShifrin Nah, I have reached the conclusion, somehow, that downvotes should be abolished from SE.
Stupid conclusion.
@MikeMiller Flag, lol.
19:54
Did you find any counterexamples, Professor @Ted?
Yeah, I disagree, but I use them sparingly. There are too many people posting wrong stuff, including me from time to time.
Need to discourage bad questions and bad answers somehow.
@G.T.R OMG, only downvotes, no upvotes!
I haven't been thinking, @Balarka.
I never downvote. I am barely active in MSE. Not enough questions of my type.
19:55
@JasperLoy I think he favorites things instead of upvoting
@G.T.R I think he is a nutcase, lol.
Hmm, 1/4 of my votes are $\downarrow$
I have cast 0 downvotes.
@TedShifrin How'd you get that?
19:57
Basic arithmetic @Balarka
@Jasper: Have you ever seen Wedding Banquet?
I'm surprised, mine are about 1/6 downvotes.
@TedShifrin No, if that is a show.
Movie ... Early Ang Lee ... One of my favorites
I know I need to be downvoted sometimes. I told someone on Reddit the other day that if $U = e^{i x}$ then $U U^* = I$ for any $x$ in $\mathbb{C}$ facepalm

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