@Sawarnik not that much different. my hair is darker. gained a couple pounds in college. this photo is two years old. my current profile pic is a little less than a year old.
@DanielFischer I was wondering if for a given continuous real function on a given closed interval it was possible to a find a sequence of Lagrange polynomials that converges uniformly to this function. More precisely, if I interpolate $n$ points of the graph of the function with the degree $n-1$ Lagrange polynomial, why would this sequence of polynomials not converge uniformly to $f$?
@DanielFischer I think the answer is probably no, otherwise Bernstein polynomials wouldn't exist :P But how to disprove uniform convergence with Lagrange polynomials then?
@Sawarnik i was too focused on my studies for friends. i sat with people at lunch but never spoke. i dunno, the only time i ever talked was at my youth group or with the debate team
@meer2kat I don't understand why but I can't much talk to girls unless its something necessary, unlike all my classmates. This shyness extends to speaking infront of large audiences too :(
@Drazick math, poetry, writing, fighting for a cause, debate, guitar, piano, music, reading, sewing, cooking, warm hugs, walks on the beach, sand on my toes, staying up late, going on adventures, hiking, etc.
I'd say it's rather elementary :P I have some flaw in my logic, or lack of understanding. There's this statement: Every graph G that is 1-factorizeable, has no cut vertex. I know it's true, as it makes sense.
I mean, in general other proofs.
But I keep thinking of the example of a path, say, $P_4$. It has even number of vertices, check on that. It decomposes into 1-factors, if I have it right. And it has two cut-vertexes. I have some faulty here.
I will try to give the motivation behind this problem and later the math formality.
Given a grayscale image (1 Channel - M by N Matrix).
Someone marks some pixels as anchors.
Now, you need to interpolate the other pixels (Which are not anchors) by minimizing a given cost function s.t. the end res...
for example $\{a, b\}$ with no edges, is a set of two elements, or a $|G| = 2$ group $G$, with the operation completely unspecified. While $\{a, b, a \to b\}$ says the group $G$ has an element $c$ such that $ac = b$. OTOH that last part might completely specifiy $\Bbb{Z}_2$.
What's a really beautiful mathematical symbol that would fit in a 50px by 50px avatar? @EnjoysMath @Sawarnik @Drazick @Studentmath @GabrielR. @meer2kat
