« first day (1172 days earlier)      last day (4144 days later) » 

16:00
"If $f$ is not continuous at $x_0$, then some $\epsilon$ cannot be matched by a $\delta$. In particular, the choice $\delta = \frac{1}{n}$ will not do. Why?
16:28
@DonLarynx It's a pun -- a deliberatly convoluted way to say "often irrational".
I don't see how chat.se is irrational
$/humor = 0$
16:49
What happens when someone votes to undelete a question?
@MichaelAlbanese The undelete votes are collected in the same way as delete votes. When there are enough of them, the question gets undeleted.
@HenningMakholm But how do other users get to see the question? Is it via the Reopen Votes review queue?
@MichaelAlbanese I don't know whether it goes through the review system, but it's visible in the "delete" tab of the pseudo-moderator tools page for users with high enough rep. I forget whether it's 10k or 20k.
@HenningMakholm I can see it so it must be 10k. If a question gets undeleted, do all the answers automatically get undeleted or do they have to be done manually?
@MichaelAlbanese Good question. I think answer is not actually "deleted" in itself but only shown as such by virtue of the question being in a deleted state. For example, there's no deletion event to see in the answer's history.
16:58
@HenningMakholm Excellent. Thank you very much for your help.
@Pedro, could you go here and help Michael make his answer visible?
@HenningMakholm Day saved!
@PedroTamaroff Thanks. Do you know if the user could delete the question again, forcing us to restart the whole process?
@MichaelAlbanese Not now, since you have upvotes.
@MichaelAlbanese Now that there's an upvoted answer, the OP cannot delete the question.
17:03
@PedroTamaroff Thanks.
@HenningMakholm Thanks again.
Have you seen that video about tetration?
Google search: tetration youtube
Click Kasane Teto
There was a time when mathematicians were kind
When their functions were soft
And their numbers inviting.
There was a time when flags were blind
And the mse had.jokes
And the jokes were exciting.
There was a time ... then it all went wrong
The old say times are getting worse.
Times are as always.
The old are getting worse.
17:17
@MatsGranvik I have no idea what they are saying.
@PedroTamaroff You mean in the tetration video? But they are excited about tetration.
I don't understand japanese/korean either.
@MatsGranvik this a song for the musical "Les mathématiciens"
@Charlie Have you made it yourself? "...mse had.jokes..."
@MatsGranvik yes :)
@MatsGranvik it's a parody from "i dreamed a dream" , as you saw
@Charlie That is a classic. I have seen Les Miserables once.
17:27
@MatsGranvik wonderful!
@Charlie dunn,du,du,dunn,dunn,dunn,dunn... What song am I singing?
Apparently musical notation was invented in vain.
2
I am trying to find the best study material for the EPPP. Any help?
@MatsGranvik dunno
@Charlie Anyways I like your song though.
17:48
Give an example where $A, B$ are closed, their intersection is disjoint, and $D(A, B) = 0$ where $A$ and $B$ are sets in metric space $M$.
where $D(A, B) = inf D(a, b)$ spanned over all a in A and b in B.
I want to consider two sets, $[a_n, a]$ and $[b, b_n]$. But if I take a number b > a then $a < c < b$ since rationals are dense in $R$.
I have no idea how to solve it.
@DonLarynx: Closed intervals are not the only closed sets in $\mathbb{R}$
and $\mathbb{R}$ isn't the only metric space out there
(you can find closed sets as you want in $\mathbb{R}$ though)
Does this have to do with $x^2 - 2 = 0$?
Nope
Why would it?
@DonLarynx Consider $A=\{(x,y):x> 0, xy=1\}$ and $B=\{(x,y):x=0,y\in\Bbb R\}$.
An example in $\mathbb{R}$ would be $\mathbb{N}$ and $\{n+\frac{1}{n}: n>1\}$
18:18
@MatsGranvik :D
®Pedro is the $y \in \mathbb{R}$ in the first set?
@PedroTamaroff How are those closed sets? There is no limit for $x$.
@DonLarynx What do you mean "there is no limit for $x$"?
$B$ is the $y$-axis. That is closed.
$A$ is the positive branch of the hyperbola $y=1/x$.
hello
Wassup @what'sup ?
boooooooooooring
18:32
@what'sup oooh
@Pedro: Do you know Amnesia: The Dark Descent?
@what'sup I'm not in a better situation hehehe
@FernandoMartin Sure, but I don't have the balls to play it.
18:34
Haha, oh
Well, its sequel just came out
@FernandoMartin Are you playing it?
Yup, I loved TDD
And I'm not even a casual gamer
I mean, it's hard for me to get hooked on a game but I really got hooked on TDD
@Charlie sorry youtube doesn't open i don't know why . what is it ??
18:38
@what'sup :/ it's a video about pointe shoes
@FernandoMartin But it is scary, right?
@PedroTamaroff yes .
18:46
@PedroTamaroff I don't understand the point of the exercise I guess.
@Don: revise the definition of 'closed'
@DonLarynx The exercise is showing you that the "distance" $D(A,B)$ may not distinguish closed sets. Which is bad.
Though it works fine with compacts.
@FernandoMartin How is $A$ closed? What is the limit point of $A$?
I don't understand what you mean with "limit point of $A$"
$0$ as the sequence of $y$'s approach $0$ as $x$ goes really high
18:49
@DonLarynx Hold on a second.
Is the $x$-axis closed in $\Bbb R^2$?
@DonLarynx Well, why?
Okay, it's not closed, which is why I'm confused.
It is closed
@DonLarynx It is closed. It is.
@FernandoMartin Do you have any fav. game?
18:52
Because any sequence of $x$ in $R$ approach some number?
@DonLarynx What is the definition of "closed"?
@Pedro: Not really. You?
@FernandoMartin Probably the NES games.
And Flight 1943.
Classics are classics!
If every sequence $\{x_i\}$ in a set $A$ converges to a point $x$ in $A$. @PedroTamaroff
18:54
Ah, I recall you mentioned that game back in Rosario
@DonLarynx No, that is not the definition of closed.
@Pedro: I'm not getting anything when I google "Flight 1943"
The $x$-axis is closed with the usual metric, but $(1,0),(2,0),(3,0),\ldots$ doesn't converge to any point in it.
@FernandoMartin "Flight 1943 game".
Can I try again @PedroTamaroff?
It's an arcade classic.
18:56
No luck either
@DonLarynx Sure! =)
@FernandoMartin Weird.
Oh, I was searching for "Flight 1943"
A set $A$ in $X$ is closed if a sequence $\{x_i\}$ of elements in $A$ converges to a point in $X$, then $x in A$.
I thought both words were in the title
@Don: That's more like it
@DonLarynx That is fine in metric spaces, say, but the general definition is that its complement is open.
I just don't want you to think that is the definition.
18:58
@PedroTamaroff I am just confused on how your set $A$ is closed
@Pedro: I remember about that game now!
@DonLarynx Why?
$x$ doesn't come close to any point, just positive infinity. $y$ approaches $0$.
but it doesn't come to 0
it just converges to it
but its not in the set
@DonLarynx Why should it come close to anything?
It needs to come to $0$ since $y$ is approaching $0$ as $x$ gets large
19:00
@what'sup what are you currently studying?
@DonLarynx The thing is that "$(\infty,0)$" is not a point in $\Bbb R^2$.
Have you taken a course in multivariable calculus? Say in $\Bbb R^2,\Bbb R^3$?
@FernandoMartin =D
Didn't you play it when going to birthdays or something of the sort? Like Wonder Boy.
Yes. Wonder Boy is another classic.
@FernandoMartin I was never good at it. I should give it another try.
@FernandoMartin Oh, I think I never played that one.
19:13
Hey guys. I needed help proving that if a group G has order 2n where n is a odd integer then G has only one element of order 2. Proof: We first show that there is at least one element with order 2. Suppose there are no elements of order 2. We also know |G| is even. Let a in G where a≠e then a,a^-1 must be distinct and occurs in pairs. But since |G|-{e}=odd # a contradiction. There exists a element of order 2. Suppose there exists a group G with two elements of order 2.
so anyone else take the math gre this morning?
let a,b in G such that a^2=e and b^2=e. But if we remove {a^2,b^2,e} from G we are left with a odd number of elements => There exists a third element of order 2 a contradiction.
Not sure if this would be correct
@PedroTamaroff I don't see what that means?
@user60887: Disregard this
@user60887: Is your group abelian?
@user60887 you mean if we remove {a,b,e} you would have an odd number. the problem is you wouldn't be left with a group, so your previous lemma (odd order group implies elt of ord 2) does not apply.
19:26
If not, some dihedral groups are a counterexample, I think
@anon hi, anon
@Charlie hello
@anon hows your saturday?
pretty good so far
@anon excellent
19:42
oh yes my group is abelian
@user60887: Then you can study $G/\langle a\rangle$
I think instead of saying remove {a^2,b^2,e} is should say G-{a^2,b^2,e}=> odd number of elements.
In general, if you remove some elements from the group, you're not left with a group, as @anon pointed out
Hey, I'm trying to show that sum from -infinity to + of cos(2 \pi n t) equals to the same sum of \delta(t-n) (n in N and Dirac's delta of course :) ), Any one has a hint?
nevermind
19:52
oh ok. ill have to find another way of explaining it then.
Suppose $a^2=b^2=1$ and $a\neq b$ and see what happens with $\overline b$ in $G/\langle a\rangle$
though that this might be clearer :)
Oh how about if I create a group instead. Let G=(e,a,b,ab} such that $a\neq b$. That I think would give me a contradiction?
what would the contradiction be?
(it would give you one, but how is the question)
Since 2*2=4 and 2 is even which contradictis n is odd
19:57
I don't see why "2 is even" needs saying
you need to mention Lagrange's theorem
oh ok
Since 4 does not divide 2n where n is odd it contradicts lagranges theorem
That's nicer than the argument I had thought
could someone help me getting an idea why for commutative rings the following are equivalent: For every Ideal $\mathfrak{ab}\subset \mathfrak{p}$ implies that $\mathfrak{a}\subset \mathfrak{p}$ or $\mathfrak{b}\subset \mathfrak{p}$ and on the other hand $ab\in \mathfrak{p}$ implies that $a$ or $b$ are elements of $\mathfrak{p}$
which direction of implication do you want to do first?
well one is trivial (from the second to the first) or wait is it ?
20:09
yeah where I said "remove {e,a,b}" I noticed that I could create a subgroup out of it just by adding element ab to it.
i got 1,027 reps in 2 months . is this good ? :-)
@what'sup better than nothing, I got about 10 k in my first 2 months :)
@DominicMichaelis oh i don't solve many questions . :-)
@what'sup: what's important is the quality of your answers. There are some folks who post fewer, high-quality solutions. I look out for their input and hope to emulate that behavior.
@RonGordon like sos440
20:14
@what'sup Yes, he is one. O.L. is another.
@anon oh i thought one implication is trivial but seems like it isn't to me
i would like to make from the first to the second at first
@RonGordon there are many
@what'sup I am sure. Anyway, the challenge on this site is to find the wherewithall to post high-quality, easy-to-follow solutions that take on a life of there own, in the face of pressure to be the first to post.
@RonGordon of course .
@DominicMichaelis Suppose $ab\in{\frak p}\Rightarrow a\in{\frak p}\wedge b\in{\frak p}$. Further suppose $\frak ab\subseteq p$ but $\frak a,b\not\subseteq p$. Pick a pair $a\in{\frak a\setminus p},b\in{\frak b\setminus p}$. Then $ab\in\frak p$ so...
For the other direction pick ${\frak a}=(a),{\frak b}=(b)$.
20:23
what's important is the quality of your answers. There are some folks who post fewer, high-quality solutions. I look out for their input and hope to emulate that behavior.

@RonGordon i forgot you sorry :-) .
you're one of them :-)
@anon oh thanks the other direction is clear now, but do you really mean $ab\in \mathfrak{p} \implies a\in \mathfrak{p}\wedge b\in \mathfrak{p}$? This seems to be wrong, let $a$ be $0$ and $b$ be anything
$\vee$ sorry
(even did it again, heh)
How would you create a more challenging problem to this question (that uses the same concepts): Find the measure of an angle if 80 degrees less than 3 times its supplement is 70 degrees more than 3 times its complement.
if it uses the same concepts it will not be more challenging
Well, it could use more word logic and more algebraic steps to get there.
20:27
good bye now .
Or maybe challenge the answerer in thinking of supplementary or complementary in a different way.
@what'sup You are too kind, I do not think so. I hope to emulate that behavior, but I too often give into answering too many gimmes.
anyone take the gres this morning?
oh how is the general gre? anyone take it yet? The english section is tough on it
general should be fine
the subject test is pretty brutal
20:35
I heard the subject test is brutal.
@anon I don't see where we used that we are in a commutative ring, but we surely used it somewhere, because of in non commutative rings those things aren't equal
For example taking the $n\times n$ matrices, $\{0\}$ will surely fulfill property 1 but not the other
what kind of ideals are you talking about in noncommutative rings?
left, right, or two-sided
well $(a)(b)\subseteq\frak p$ doesn't follow from $ab\in\frak p$ with two-sided ideals in the noncommutative setting
and we used that in the easier direction
the reason being that $ab\in\frak p$ doesn't tell us what happens if we put something in between $a$ and $b$, like $axb$ for example
@user60887 If you're a native English speaker, your English aprt score is basically going to be the same as the Verbal part scor eof your SAT
20:44
@anon ah right the ideal they could generate may be awkward
Thanks a lot it is a bit late for me I will go sleeping. Have a nice day
20:57
@anon I found the vegas reference a good one :).
thanks
This is a lovely question as well. Compute $$\sum_{m=0}^{\infty} \sum_{n=1}^{\infty} \sum_{p=1}^{\infty}\frac{1}{n p(1+m+p)(m+n+p)} $$
Or the following one that is very cute $$\sum_{k=1}^{\infty} (-1)^k \frac{k^3}{8k^4-4k^2+1}$$
21:28
@anon White chocolate!
hi all, i'm trying to ask a question, but i have noticed that my equations come out ugly and hard-to-read. how do you create "beautiful" math formulas on this site?
ugly, hard-to-read is point A, "beautiful" is point B. go from A to B.
How helpful :)
are you asking how to typeset equations in LaTeX markup code like the rest of the site?
@TedShifrin Erm.. yello.
21:33
Erm, jello to you, @Pedro
The ISC is telling me my number is given by a function: sr(2)
does anyone know what funciton this is?
@KevinDriscoll Serre Rapalli, probably.
@TedShifrin I wonder.
@Pedro ... If ...?
@TedShifrin I'd like to see if I can construct an iso $\Bbb C[t]\otimes \Bbb C[s]\sim \Bbb C[s,t]$.
@Pedro A google search turns up nothing obivous
21:36
@KevinDriscoll I'm just messin' with ya. =D
Didn't we do this before, Kevin? =)
Depends on your defn, of course, @Pedro.
@Pedro....... damnit.......
@TedShifrin Well, I don't know what the definition is for infinite dimensional spaces.
@anon, i guess. also how do you get to LAtex markup in the first place
30
A: FAQ for math.stackexchange

Tom StephensQ: How do I type math in my question/answer/comment? A: For simple formulae, you can use <sup></sup> to write superscripts and <sub></sub> for subscripts: y<sub>1</sub>=x<sup>2</sup>+3becomes y1=x2+3 For more complicated formulae, you can use TeX markup. To type inline TeX equations, surround...

21:38
What about the universal property? That sounds nice. Though not constructive, @Ted.
@Pedro btw remember we were talking about twin primes the other day?
@KevinDriscoll Were we?
@Pedro Tao et al just released another update
@KevinDriscoll Ah, that.
Let's see.
Not constructive, but good for proving isomorphism :)
21:38
@anon. I don't know how to type math formulas anywhere not only this site (only through Word which takes ages)
@KevinDriscoll CURSE YOU.
@TedShifrin Well, yes.
@darkblue see the faq link above
What is another definition?
21:39
Ugh @Word. I don't know a basic primer for LaTeX ... i learned it 25 years ago.
@ anon, I did that first before asking ;) thanks anyways
you can click "edit" on people's questions and answers to see how they write equations using latex and learn it yourself.
What you learned in Spivak generalizes, @Pedro, and there's the formal algebraic defn which basically declares the bilinearity properties.
@anon, thanks! this sounds like a great start. @Kevin, thanks!
21:41
@TedShifrin What did I learn in Spivak?
Specifically?
Multilinear maps ...
@Ted It is humorous watching a quantum information theorist and a complexity theorist try and convince a group of black hole physicists by proving rigorous theorems
And then he applied Alt ... To get alternating tensors and wedge.
@TedShifrin Yes, yes.
So you're saying that $(V^{\otimes k})^\ast\simeq \text{Multilinear } k \text{ forms over } V$?
Not forms, as those are alternating.
21:44
@TedShifrin I didn't say alternating.
Just $\sigma:V^{\oplus k}\to K$; multilinear.
$k$-multilinear maps on $V$ is $(V^*)^{\otimes k}$.
@TedShifrin Well, I was close.
=)
But yeah, duh.
They're iso. The word form can be used in the sense of alternating or not ... Very confuzling.
@TedShifrin Well, at least now $\otimes$ makes a little more sense to me.
Wait, that symbol has a meaning?
I thought it meant "I want to define an operation, but I'm using *,+,- and /"
21:48
@AlecTeal It has the meaning you want to give it.
When we do tensor product of modules (at least finitely generated) it's analogous. With your poly question, we have to worry about double duality, and I actually don't know the answer.
@anon You don't like white chocolate?
Not really @Alec@Pedro
I hate white chocolate :)
@TedShifrin What are you pinging now?
Yes I like white chocolate. More than normal choco in fact. Why?
21:49
The any meaning, silly.
@TedShifrin White chocolate is great, remember it like racism, white is right.
Yeah, right.
Also by transitivity of "remember it", bathroom furnishings colour. White is right!
White chocolate is a misnomer ... It ain't chocolate.
@anon Because you missed my first ping.
21:50
Who has gone "I'd like an olive green bath please!" Where do they go?
You should see the colors I had my house painted, @Alec
@PedroTamaroff your first ping was just the phrase "white chocolate" no? how am I supposed to respond to that?
@TedShifrin Well, a symbol can take the meaning you give it. Don't you agree?
No that exists in many forms, but those horrible green bathrooms? Who does tat!?
Are we arguing bathrooms now?
Really?
21:52
No @Pedro, unless you specifically say it can denote any binary operation.
@anon Dunno.
I have a forest green bathroom and a purple one :)
Nothing white in my house except ceilings and trim.
I think I'd enjoy @Ted 's interior decorating
sounds adventurous
@TedShifrin My room is grey/green. I don't know what the name of the colour is. =)
I've forgotten the number of colors ... Something like 8.
21:56
@TedShifrin Silly, four should do.
@PedroTamaroff four would do.
Four colour theorem.
Nah, y'all can come see for yourselves.
I was expecting that.
21:57
@Pedro what is that cartoon's name?
@KevinDriscoll South Park.
Too many cartoons/videos here! Where's semi-serious (not white) math?
@Kevin: Even I used to be a South Park devote.
@TedShifrin Devotee.
@Perdo I meant the character
No, that's female :)
22:00
@TedShifrin Not for me.
@Ted You should still be! The most recent 2 seasons have been among the best
In fact, they even did an episode about how college sports is basically just a new version of slavery
it was quite clever
@KevinDriscoll Name?
@Pedro Ya the name of the character
@KevinDriscoll Captain Hindsight.
Ok, dévoté, just to be clear :) in stupid English, the feminine extra e is added so it looks different from devote.
22:01
Ah! Okay, cute
Yeah, @Kevin, I should be.
@TedShifrin I think the "ee" is added for the "iiii" sound. Else it is "devote" as in "I devote time to my children."
When I retire I'll have time to be erudite again :)
Right @Pedro.
@Ted I thought you might identify with that given your stated opinions (which i find myself more and more drawn to, particularly today as I saw the South Carolina quarterback who has earned the school millions (I'd bet) in ticket sales and alumni donations possibly blow out his knee ending his career without ever being paid 1 nickel.
Yikes ... And UGA is going down the tubes due to injuries, too, although presumably not life-ending. Glad you're adopting a sane — if anti-Southern — attitude.
Ok, time to cook dinner. Bubye.
22:30
0
Q: Trigonometry and complex numbers

pourjourSuppose $z_0=e^{i\theta_0}$ a complexe number as $\theta_0\in ]-\pi,\pi[ \setminus\{0\}$. For $n\in \mathbb{N}$, we pose $z_{n+1}=\frac{|z_n|+z_n}{2}$ and $z_n=r_ne^{i\theta_n}$ with $(r_n,\theta_n)\in \mathbb{R}^+ \times ]-\pi,\pi]$. The first question was determine $r_{n+1}$ and $\theta_{n+1}...

@anon can I ask you something?
yeah
@anon what motivates you to wake up everyday?
@Charlie hi
@pourjour hi Sofian
22:35
waking up is not a conscious action. deciding to get up is due to knowledge of the consequences of not doing so. only on some days do I actually want to get up - for example, if I have something cool to do that day.
@Charlie how are u?
@anon interesting. I'm fine @pourjour
@pourjour what have you been doing?
Hi @ethan how is it going ?
bad
@Ethan oh no, whats wrong?
lol
debating whether to cram for a physics SAT test offered by collegeboard on november 6th, I have already taken the highest test they offer in mathematics
22:44
Oh
Oh, I crammed for the physics sat when I took it
I know I can get perfect marks on there math tests, I think it might be better to just leave it like that
@Ethan you often do it
I think it was two evenings of studying.
What did you study with?
22:46
Only 2?
I haven't taken a course in physics sense 9th grade
I just looked up some stuff online. I think past exams.
@Charlie yea math 2
@KarlKronenfeld Had you studied physics during your senior year?
@Charlie preparing a maths control
@Ethan I took a physics course my junior year.
22:49
What did you get on the test?
@pourjour interesting
I did the same thing for my chemistry sat/ap chem except I worked for a couple of weeks learning the material for the ap exam.
No, my school didn't offer an ap chemistry class.
I don't really want to come off that 'well rounded', I wanted to just focus on my interest in mathematics, do you think it would be a bad idea to take the Math 1 test? Even if I could get a perfect score on it?
I have already taken there Math 2 test and got 800 on that, I don't think I could get 800 on the physics
I would imagine it's not a good idea to take two math exams, but I don't really know.
22:53
what school are you going to now?
@Ethan How many SAT2's have you taken? Most of the big schools require 3 I think
@KevinDriscoll its 2 now usually, and only 1, the math 2 test
Ah okay
I took Physics, Math 1(or 2 I cant remember), and like American history or something
I bet that was short :P

« first day (1172 days earlier)      last day (4144 days later) »