Let $0\leq f(x)\leq x$, and for $0<x<x_0$ $$f(x)=x-ax^k+bx^\ell+x^\ell \varepsilon(x)$$ with $\varepsilon\to 0$ for $x\to 0$. Here $b,a>0$ and $1<k<\ell$. Define for a fixed $0<x<x_0$ the sequence $$v_0=x_0\\v_{n+1}=f(v_n)$$ Then $$\lim_{n\to\infty} n v_n^{k-1}=\frac{1}{a(k-1)}$$
@dfeuer i didn't review that flag but i assume the mod that did probably read the question, disagreed with the flag, but still marked it helpful because he thought it was worth considering
@dfeuer So I looked at the log, and robjohn cleared that flag. What I suspect is that he asked the CrossValidated mods if they wanted the question, and they said no
I get so discouraged sometimes...I think I'm going to have to spend less time on math.se...It has become "too" important to me (too much time) !! Okay...now let's see if I can manage that...I don't want to have to pull a "jasper"!! ;-)
@amWhy What is "lingo"? I guess you don't mean "...a comprehensive software designed to make building and solving linear, nonlinear and integer optimization models faster, easier and more efficient."
@PeterTamaroff I have to watch my slang (lingo is a "slang" term)...on such an international site...I've found myself needing to explain my usage of "slang" a few times now.
@amWhy Hmm, I know a little slang, and sometimes I fish out words from my head I didn't even know I knew. It is kinda weird, because I don't speak English on a daily basis, but I have studied English for a long time, so many many stuff has sunk on meh brainz.
But what do you think about this concept: Splitting a math book, in small parts, and making a blog of it like this. Then you have comment section where people can help each other out to understand the math book better
coz people from all over the world might b reading the book, and they can be in different chaptersl. so there must be a way for them to interact chapter by chapter
says person 1 is in chap 4, person 2 is in chap 1
so person 1 can leave a comment and share something. and by the time person 2 jumps to chap 4, they can interact.
that way, records on how people treat a chapter will be save, and can be viewed later.
overall, people will go to it and add ideas.
ideas will add up, and be consolidated overtime. so new people can go and view it, and after they finish the chapter, check their answer, verify the results and share something
@AlexanderGruber I really wish that moderators would stop dismissing flags-to-close as helpful while leaving the question open. Flags to close are in a category separate from flags for a moderator attention. Questions flagged in this way automatically go into the Close Vote queue for 3K+ users, who decide what to do with them. That is, unless a mod clears the flag, preventing the peer review from happening.
One problem with moderators handling flags to close is a bias for inaction: moderators prefer not to use their binding votes (and rightly so). Leaving the flag in place allows the decision to be made by five reviewers, who are not constrained by having a binding vote.
@anon \mewikis " It has been rejected by the mainstream scientific community because the original experimental results could not be replicated consistently and reliably, and because there is no accepted theoretical model of cold fusion."
no, but an hour in the chatroom is not a big deal otoh. it's the mainsite suspension that's more curious and more significant - I don't know what the reason was.
@MarianoSuárez-Alvarez are you around? I have a question about pure dimension
somehow I am not able to prove that if $Y$ is an algebraic set of dimension in $\Bbb{P}^n$ of pure dimension 1 and of degree $1$, then it has to be a linear variety. I know that $Y$ is irreducible though.
I can see this is true in $\Bbb{P}^2$
I tried inducting on $n$ and then like projecting onto a hyperplane
there was a newspaper article about a nine year old who wants to go to university and study
and they said he is a over genious and they took a picture of an integral problem on a blackboard which he solved in "a few minutes" and the solution is plain wrong
hey, short question: considering the differential quotient $\frac{f(x+h)-f(x)}{h}$ for $h\rightarrow0$ can $h$ be negative and positive, right? And also in a neighborhoud of e.g. 1 we can't assume $h>0$, right? thanks!
@DominicMichaelis I was watching MIT's differential equations videos a while back and according to the professor in one of the videos half the class made the same mistake on some part of an exam
differentiating instead of integrating
and in one video he asks what the antiderivative of $\frac{1}{1 + x^2}$ is and there's a dead silence for 15 seconds as nobody answers
@ˈjuː.zɚ79365 the only time questions should be flagged to close is if they are very clear cut cases, e.g. obvious duplicates (user asks the same question over and over), contest questions, racist rants. stuff where unilateral moderator close votes are needed. normal grey area close votes should be left to the community.
@AlexanderGruber I agree: normal closing should be done by community, not the moderators. Which is why flags to close are not called flags for moderator's attention. They automatically put the flagged question into the Close Review, where the community of 3K+ decides what to do with them.
The flag is automatically dismissed when the reviewers vote to close. No moderator action is needed at all.
In mathematics, a Taylor series is a representation of a function as an infinite sum of terms that are calculated from the values of the function's derivatives at a single point.
The concept of a Taylor series was formally introduced by the English mathematician Brook Taylor in 1715. If the Taylor series is centered at zero, then that series is also called a Maclaurin series, named after the Scottish mathematician Colin Maclaurin, who made extensive use of this special case of Taylor series in the 18th century.
It is common practice to approximate a function by using a finite number...
In mathematics, a Taylor series is a representation of a function as an infinite sum of terms that are calculated from the values of the function's derivatives at a single point.
So .. how do I calculate that for Complex Numbers ?
@JohnDoe746 That question is hard to understand. The formula you are looking at is a formula from CoV, but the question about $F$ does not appear to have anything to do with CoV. $F$ is dependent on the functional being minimized and whether $F$ is convex in the third variable is dependent on the functional.
@robjohn well, $\cal F$ is the usual functional you use. Now you know that $\cal F$ is seq. weakly. l.s.c. and we are in $\bb R$ so this is equivalent to $F$ being convex.
Can you gimme some problems to solve ? on derivatives of complex numbers ?? :)
I never expected it to be this easy, sir. I was expecting to have to rummage through a tome with some cryptic Greek symbols trying to get my head around this :)
@robjohn so by extension , integration is also the same ????
@robjohn Could you take a look on another proof of mine to a problem we discussed in the past? I wonder if there are some shortcuts to the way I used this time. I'd appreciate some feedback from your side. :-)
@LittleChild you need to be careful. Antidifferentiation is essentially the same (with some caveats), but contour integration has other considerations.
@LittleChild for the most part. It depends on how you extend the functions to the complex numbers. But if you use polynomials, the formulas stay the same.
hmm... and if I can do that on real functions, the procedure stays the same for complex functions ??
what I mean is ... I am working on reducing my steep learning curve here :)
Let me sum it up: **derivatives** stay the same for complex and real functions *work reduced* **Taylor's Series** remains the same *work reduced* **integration** has its subtleties. *work*