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robjohn
11:18 PM
@Charlie probably more closely related to the
Kronecker delta
leslie townes
boo
robjohn
@leslietownes: Hey, dude!
how are you feeling?
AMDG
Looks like leslie has returned to haunt the chat in the form of a ghost.
If he were copper, instead of saying "boo", he'd just say $-\frac{1}{12}$.
geocalc33
f(x)=1/x has a multiplicative structure
leslie townes
not super, but better
geocalc33
11:26 PM
from a group perspective?
Jakobian
11:40 PM
what do you mean?
leslie townes
he's asking me if i'm super from a supergroup perspective. like blind faith or the traveling wilburys
geocalc33
I'm waiting for more information, but someone said to me: "due to the multiplicative structure of the function 1/x"
copper.hat
are you wearing a mask rn?
leslie townes
nope
geocalc: they probably just mean f(ab) = f(a) f(b) (because 1/(ab) = (1/a)(1/b)). people often say just 'multiplicative' as an adjective for this
AMDG
Here, take a mask.
copper.hat
11:47 PM
spooky
robjohn
don't take that off: what is beneath looks scarier
AMDG
hide_the_pain_harold.jpg
copper.hat
i verified my identity with id.me to access my irs account. the process does not breed confidence.
robjohn
@AMDG
ouch
AMDG
More like GOTTEM
Das rite. Get roasted, me.
Ted Shifrin
11:54 PM
@leslie welcome back from the lost. Did you have fun with the ducks?
geocalc33
$f(a)=e^a$
$f(b)=e^b$
$f(ab)=e^{a+b}=e^a\cdot e^b=f(a)f(b)$
AMDG
Someone should post the above out of context somewhere.
Ted Shifrin
$ab=a+b$?
You don’t write addition as multiplication.
leslie townes
ted: you know i haven't been to a duck pond since i went away. it pains me to say it
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