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9:52 AM
@TedShifrin, in the first excercise of your book...
user image
2
is $t$ the length from (-1,0) to (x,y), or is it the distance from the origin to where that line intersects x=0?
 
10:15 AM
am I understanding the question correctly if I read my task is to write an expression for a particle which travels around the circle starting infinitly close to (-1,0) and ends it's journy infinitly close to point (-1,0)?
 
 
1 hour later…
11:24 AM
Can I ask how to resize images when displaying?
 
How many homomorphism are there from $ Z $ to $Z_{n}$? I know that the kernel would be $nZ$, and then by first theorem on isomorphism, $ Z/nZ$ will be isomorphic to $Z_{n}$ and the number of automorphisms on $Z_{n}$ is $/phi (n) }, but the answer given is $n$. Where am i wrong?
 
the homomorphism is determined by where $1 \in \mathbb{Z}$ is sent, there are $n$ elements that it could be sent to
the kernel does not have to be $n \mathbb{Z}$, it certainly contains $n \mathbb{Z}$
 
oh, thank you :)
 
11:53 AM
in fact, $\operatorname{Hom}(\mathbb{Z},G)\cong G$ for any group $G$ by a similar argument
and this property almost characterizes $\mathbb{Z}$
 
Any G? Infinite order also?
 
yes
 
nice to know, thanks.
 
Can anyone please tell me why the number of linearly independent columns of a matrix doesn't change by row elimination
 
12:35 PM
There's a theorem in my lecture notes that says, "All piecewise continuous curves [in a closed and bounded interval] are rectifiable". Isn't that wrong? Counterexample: $f(x) = x \sin(1/x)$ for $x \ne 0$ and $0$ for $x = 0$
I was able to prove this for piecewise continuously-differentiable but I don't see in what sense of the term piecewise continuous does this theorem hold
 
I might be mistaken, but I share your concern
 
I did talk to the professor about this, and he is quite adamant. He asked me to think about the infinite broom and topologist's sine curve (which quite literally is a counterexample) and come up with an answer
Sorry, I didn't mean to say that it's a counterexample
 
1:10 PM
@leslietownes hi
 
Is it obvious that the convolution of a function and a measure is Lipschitz in Wasserstein distance (for a nice enough function)?
 
1:57 PM
Can anyone tell me if my working is ok ? I want to show $ \int ( V * f (x) - V * g(x) ) f(x) dx \leq C W_2^2(f,g) $ for distributions f and g. and $W_2$ the wasserstein metric
 
good morning
kashmiri this is a nontrivial result. sometimes shown by proving that A and A^T have the same rank, with 'rank' suitably defined.
it's clear that row operations don't change the row space. they can change the column space, but not its dimension.
 
2:52 PM
@AndrewMicallef it looks like the latter (where the arrows indicate)
 
@AndrewMicallef fields medalist and one-time employer of me as a grader for his abstract algebra class Richard Borcherds does some of the details of this calculation around the 6 minute mark of youtube.com/watch?v=JZKDmTIFR7A
 
. o O ( Weierstrass )
 
he does bring that up
weierstrass is in my family tree. he's like my great^7 grandfather.
mathematically. not in real life
 
3:18 PM
@AndrewMicallef it doesn't matter. he wants you to parameterise the circle less $(-1,0)$ by a scalar parameter $t$. however, the picture gives a very strong hint of one straightforward way of doing so.
 
3:29 PM
whats "less" in this context?
 
setminus, in latex speak
 
btw, is the answer $$(\dfrac{1-t^2}{1+t^2}, \dfrac{2t}{1+t^2})$$
 
dfrac, hadn't seen that before
i learn something new every day
could use some \left and \right tho
 
Yes @satan.
 
i'm beginning to think that almost any exercise worth doing is in one of ted's books.
prove me wrong.
 
3:42 PM
This is the famous rational parametrization of the circle. It also explains the famous $\tan(u/2)$ substitution we used to learn in calculus.
 
yeah, i realised this after solving
hmm i see, for the point $(-1,0)$, $t \to \infty$..
 
So $S^1 \cong \Bbb RP^1$.
 
uhh is that a response to me ?
 
Yes.
The projective line is what you get when you throw in $\infty$.
 
what dfrac?
 
3:51 PM
that borcherds lecture is really good, it almost gave me respect for algebraic geometry.
 
I see, although I have no idea what you are talking about XD
 
Too bad. ;)
Dfrac is displaystyle frac. I use it in-line lots of times.
 
dfrac forces display style. which you'd be doing anyway with double dollar signs although this is latex slang and not official.
 
You don't need it when you're displaying β€” then it’s automatic.
Damn, we're one again.
 
geometry is a scam and pictures are lies.
there.
back to normal.
 
3:56 PM
Don't knoe how @Andrew could ask his question. The $t$ is clearly indicated with the little arrow.
 
probably some incurable defect in the author of the textbook.
 
Indubitably.
 
it does say 'length' and not signed length. maybe people are uncomfortable with t being larger than 1. all of this reminds me of a funny comment on the dot product
 
Good point, since we need negatives below the axis. I should correct!
 
4:18 PM
Only so much you can do.
 
4:44 PM
@leslietownes and it is a double headed arrow, no direction indicated.
. o O ( picky, picky )
I've killed Ted again. As soon as I commented, he fell off the attendance bar
@TedShifrin I mentioned that earlier.
 
yeah, i'm at sea here. what is that diagram supposed to mean?
 
The one from Ted's book?
 
i'm joking. i know what it's supposed to mean.
 
Okay, but do you really need a seasick bag?
 
i did yesterday. that first vaccine shot really did me in for about 24 hours. now, i'm OK.
i've just set up a fairly unpleasant phone call for tomorrow. in my day job i play-act as somebody who is constantly raising objections, waving red flags in front of bulls, and looking for trouble. this is not who i am.
 
4:52 PM
It sure is who you are here!
 
i think you and my wife would be very good friends.
 
Difficult if we are in fact one, as Andrew insists.
 
@leslietownes Don't feel too bad. My son passed out right after and they hadn't made sure his car was in park. He drifted into the car ahead of him and tapped bumpers. They really should have made sure he was ready, especially since he had sounded uneasy.
 
i did see someone pass out at the vaccination site. needles are a weird thing. my wife is not that good with them.
they recommended that we sit for 15 minutes after the vaccine. i high-tailed it out of there like the jerk that i sometimes pretend to be. but then my arm began to hurt and the brain fog descended. it is better now.
 
@leslietownes we stayed there for about 30-40 minutes. There were EMTs and a big crowd around his car for a while.
 
5:00 PM
First time in a long while you've been so popular, @robjohn.
 
I drove home, needless to say.
 
i should have stayed a little longer. i think i set a bad example.
 
@TedShifrin Indeed! I should take the cue and pass out myself once in a while.
 
When I did my first shot at a drive-in, they made sure the car was off before they did anything.
 
@TedShifrin They did that when I got my shots, too.
 
5:04 PM
my wife had utterly no reaction to either of the shots. this seems unfair. i was floored by the first one. the second one is supposedly worse.
 
at both sites i attended they require you to wait for 15 mins.
 
@leslietownes I didn't even know that the first injection had been given. The person who gave it to me said "all done" and I was amazed. The second shot was given by a guy who was less gentle and I felt a bit of pressure and heard the squoosh of the hypodermic, but didn't feel any pain. My wife felt a bit on her first injection, but she had Moderna and got "Covid-arm".
 
my arm was kind of numb and tingly for about 36 hours after pfizer no. 1.
which is good. i want my money's worth, which was nothing, because i didn't pay for the vaccine. that was very weird.
 
@copper.hat At CSUN, I had to wait 15 minutes and they checked on you several times. My wife went to Hansen Dam and they told us to wait in a side parking lot. No one checked on us and we left with no one checking. I guess if you have a seizure, you have to go get someone to help.
 
at albany i stood around so they could see if something was going on, at the coliseum they lined all the cars up for each 15 mins group, so i guess if you didn't move they would check. hard problem with low frequency potentially disasterous events.
 
5:15 PM
yeah, not low enough frequency, it seems to me at least
I've learned my lesson. I'm driving my son to his second injection
 
5:33 PM
@leslie @robjohn I have revised my exercise to reflect your concerns.
 
@TedShifrin wow, that was fast.
 
I had to figure out how to import an Illustrator eps file into Inkscape to fix the double arrow, too. You guys are so much trouble.
 
we excel at that
 
Now, not having full Acrobat, I have to reassemble the file to post on-line.
 
Oh, so I just redownloaded the same file?
 
5:37 PM
what??? the problem was fairly clear surely?
 
Indeed, I see that I did
@copper.hat Ted got some negativity about the assumed positivity in the question.
 
there is some value to conciseness. ask any school kid trucking a ton of books to school :-).
 
Yes, I haven't uploaded to the UGA webpage yet.
 
@copper.hat y, Icn c that
 
I have mixed emotions that I apparently chased dc3rd away.
 
5:42 PM
how did you do that? I want to know in case I need to chase someone away
 
I think copper was here. I said that my book and Rudin were not realistic goals, based on how things were going.
You haven't chased RK away, @robjohn. He still shows up.
 
It is fair to be realistic.
 
Yeah, I'm sorry. I'll try harder
 
Polite is not necessarily nice.
in the broad sense of the word.
 
After 35+ years of advising, I just feel obligated to be realistic with students.
At any rate, I still feel a bit guilty.
 
5:45 PM
It just means you are human. I am a total wimp in that respect. Except with those closest to me/
 
Boy, I'm rusty at the games getting the book typeset the way I want it. I used to do this stuff several times a year, and now it's been 3 years.
 
I see that dc3rd hasn't said anything here since Thursday night.
 
copper, I do have to say that you were being more patient with him than you give yourself credit.
 
I am not consistent. It depends very much on my take of how hard they are trying.
In giving, I give to those who cannot help and to those who are willing to try. Perhaps selfish, but there you are. I will not help those who can help themselves and are not willing to try.
 
Oh, no question he was trying infinitely hard.
 
5:49 PM
Then he has my help :-).
I understand & respect. I have played chess for decades and still have not improved :-).
 
Hmmm, TeXShop must have changed something with how the book format typesets. I am having issues.
That should be device-independent. I have to hunt down the problem.
 
@copper.hat One can be polite and still realistic... "Let's find a better book for you. Here: Horton Hears A Who"
 
Better make it kosher/halal.
 
Well, yes, mostly. At some point with some folks you need to point out the tradeoff and that can hurt even though none was intended.
 
oh, no, still religiously insensitive
 
5:54 PM
Indeed.
 
better, except for the audibly challenged.
"What are you, deaf? I said integrate both sides of the equation. Oh, you are? Sorry."
 
You are in a leslie mood today, @robjohn. He's a bad influence. Summon his wife.
 
It is a tough problem to deal with the range of possibilities out there. At some point one needs to make choices purely from an energy perspective and those choices inevitable impact some.
And energy includes mental setup and thought processes which may be limited by many factors.
I am going to stop pontificating before I make Ted shout...
 
Ted is too busy trying to remove something unwanted from a running head.
 
6:28 PM
my wife said the coronavirus vaccine is no excuse for being in a foul mood. i withdraw 90% of what i've said since monday.
 
if i am not in a foul mood people get suspicious...
 
6:58 PM
if i bounty my question, will i have enough money left to eat
 
7:09 PM
@robjohn The new file is posted. I had to modify my file to get the headings right. Something changed somewhere in TeXLive, I guess.
tosses @shintuku a dime for food
 
@TedShifrin Thanks, I'll take a look.
 
It's hardly that scintillating :P
But I got to update the date from 2018 to 2021 :)
 
Maybe it takes a while to get to the server. I still see the same thing. I'll try again in a bit.
The one I got still says 2018
 
Oh, no, you need to clear cache.
I always double-check by downloading myself.
Hmm, English is such an odd language.
 
If you have 6 projections $(x,y,0),(x,y,1),(x,1,z),(x,0,z),(1,y,z),(0,y,z)$ for $x,y,z \in (0,1)$ and you are given 6 congruent vector fields on the projection planes, how do you construct a vector field in $(0,1)^3?$ Would taking an average of the 6 projections to construct a vector for $(x,y,z)$ work?
 
8:09 PM
If $x$ and $y$ are uniformly distributed in $[0,1]$, what's the distribution of $\min\{x^2,y^2\}$?
independent
If $x$, $y$, and $z$ are independently uniformly distributed in $[0,1]$, what's the distribution of $\min\{x^3,y^3,z^3\}$?
I wouldn't ask these questions if I didn't think the answers were worth it
 
8:27 PM
perhaps you could compute the distribution of $\min_k x_k$ first?
$P[x_k \le \alpha \ k = 1,...,m] = P[x_1 \le \alpha]^m$.
 
That'd be $P[\max_kx_k\le\alpha]$, not $P[\min_kx_k\le\alpha]$
though you could calculate $P[\alpha\le\min_kx_k]$ instead
 
ahh, my apologies, but you can adjust
 
You get $P[\max_kx_k\le\alpha]=\alpha^m$ and $P[\alpha\le\min_kx_k]=(1-\alpha)^m$ I think
 
Deal with $1-x_k$ which has the same distribution.
$\min_k x_k \le \alpha$ iff $\max_k (1-x_k) \ge 1 - \alpha$.
some care needs to be taken with $\alpha$.
 
$P[\max_kx_k^m\le\alpha]=\alpha$, $P[\alpha\le\min_kx_k^m]=(1-\alpha^{1/m})^m$? Is that right?
I think I asked the wrong question lol
I wanted the answer to be uniform. So I think I should've asked about $\max\{x^2,y^2\}$
 
8:37 PM
whoa, ignore my stuff, i need to focus.
can't even blame wine at the moment.
which prob are you trying to solve?
 
I knew the answer when I asked the question
or thought I did, anyway
It was a puzzle
 
i thought the answers were worth it :-)
 
the irishman who made it to 1:30pm.
 
never drink before noon
noon somewhere
independence is a mind boggling concept.
not a political statement, more a measured response.
the orthopaedist said hip surgery was not imminent so he certainly played to my fears and made me happy.
 
In R (programming language), you can verify this empirically by doing
z=pmax(runif(1000),runif(1000))^2
plot(z)
 
8:43 PM
its not hard to compute if you can focus for more than 10ms which i am incapable of
 
pmax is "parallel maximum", it does maxima of vectors. runif(1000) is a vector of 1000 random variables between 0 and 1
On the other hand, if I try minimum instead of maximum
 
particularly since the are uniform on $[0,1]$.
 
z=pmin(runif(1000),runif(1000))^2
plot(z)
 
the distribtion is clearly related to the distribution of $\min(x,y)$
 
Good indication that $\max\{x^2,y^2\}$ is uniform and $\min\{x^2,y^2\}$ is not
(technically I did $\max\{x,y\}^2$ and $\min\{x.y\}^2$ but same thing)
Arright let's try three variables now
cubed
z=pmax(runif(1000),runif(1000))^3
 
8:46 PM
@AkivaWeinberger how can that happen?
 
Oh no I messed up
z=pmax(runif(1000),runif(1000),runif(1000))^3
is what it should be
OK this should be uniform and the last one shouldn't be. You can kind of see that
@TedShifrin If $x$ and $y$ are uniformly distributed from 0 and 1, so is $\max\{x^2,y^2\}$.
Proof: find $P[\max\{x^2,y^2\}\le\alpha]$
It's $P[x^2\le\alpha\land y^2\le\alpha]=P(x^2\le\alpha)^2=P(x\le\sqrt\alpha)^2=\alpha$
 
But min x = 1-max(1-x) or something.
 
@TedShifrin So that means $\min\{1-x^2,1-y^2\}$ is uniform, I guess
 
If x is uniform, isn't 1-x?
 
Yes, and?
 
8:50 PM
So it all seems symmetric to me.
 
The squares mess it up
 
$P[\max_k x_k^2 \le \alpha] = P[\max_k x_k \le \sqrt{\alpha}] = P[x_1 \le \sqrt{\alpha}]^2 = (\sqrt{\alpha})^2 = \alpha$.
For $\alpha \in [0,1]$ of course.
 
@TedShifrin $\min\{x^2,y^2\}=1\min\{1-x^2,1-y^2\}$. Yeah? But that doesn't tell us anything about $\min\{x^2,y^2\}$
 
@TedShifrin Ah ha, there was an ambiguity... i think? But now I think I have seen this one before. Though I wasnt paying close enough attention to how the answer was derived (dont tell me, this is for lunch time math)
 
@copper.hat Assuming there's only two $x_k$s
for that third term to be $P[]^2$ and not $P[]^m$
 
8:56 PM
Of course, if there are $m$ then the answer is $\sqrt{\alpha}^m$.
 
To be clear, $t$ could be any scalar according to @copper.hat, but I am going to think of it as the height of the intersection of the bolded lineseg and the yaxis
 
And then $P[\max_kx_k^m\le\alpha]=\alpha$.
 
i must confess the answer is a little non intuitive off the bat.
@AndrewMicallef are you familiar with the Reimann sphere?
 
Can someone help me with this? Thanks!
0
Q: Optimal test statistics for Pareto distribution

statwomanLet $X_1,...,X_n$ be the incomes of $n$ person chosen at random from a certain population. Each $X_i$ has the Pareto density $$f(x,\theta)=c^{\theta}\theta x^{-(1+\theta)}, x>c$$ where $\theta>1, c>0$. I have obtained th mean income $\mu$ in terms of $\theta$ as: $$E(X)=\int_1^\infty xf(x)dx=\int...

 
8:59 PM
Maybe under a different (no) name
 
its sort of related to the problem, if you were it would give some intuition. basically projecting (most of) the sphere onto a plane.
 
I recognise the excersice as the basis of Grant Sandersons explanaition of quaternions
Yeah i have heard of that (didnt know the name)
 
for intuition of quaternions i would look at rotations.
would have prevented gimbal lock on apollo 11
jk
the problem on apollo was mechanical gimbals.
 
I have to go, but this is where I came across it:
 
nice graphics but would take me awhile to wade through
 
9:03 PM
Just say gimbal lock in a serious voice, the audience will get it
Yeah, it does, it just starts with this problem is all
 
@AndrewMicallef Nah, no ambiguity at all. I put the $t$ next to an arrow for a reason :)
The correction that Leslie offered that I should have said signed distance is correct, however. When we're below the $x$-axis, $t<0$.
 
i think the pic is fine.
 
@copper @Andrew He's talking about stereographic projection. This is the lowest-dimensional case of it, yes.
 
@AkivaWeinberger The distribution function of $Z = \min\{X^2, Y^2\}$ is given by
$$F_{Z}(z) = \mathbb{P}(\min(\{X^2, Y^2\} \leq z) = 1 - \mathbb{P}(\min(\{X^2, Y^2\} > z) = 1 - \mathbb{P}(X^2 > z \wedge Y^2 > z)$$
 
${}=1-(1-\sqrt z)^2$
 
9:08 PM
No, it would be and. If you know that the minimum of two numbers is greater than a value, then it follows that both numbers must be greater than that same value
 
No, he has it right.
 
Yeah, he has it right
 
Although I realize my math isn't too reliable today :P
 
The reason it doesn't simplify nicely is that $P[X>z]=1-z$, not $z$.
 
LOL, English is so bizarre. No, yeah ... both for the same thing.
 
9:09 PM
You're disagreeing with Copper; I'm agreeing with you and Clarinetist
lol
 
i'm $\max$ed out for the day
 
Dammit, ahwell...also what are you doing using inkscape for your graphics @TedShifrin. I would gladly offer my services as an amatuer artist to render bueatifull geometry drawings in tikz/latex
 
It makes sense from an intuitive sense as well that you'd want to max it rather than min it, because squaring (and cubing) makes things from 0 to 1 go lower, so you need something to make it go back higher
Squaring and minning would both lower it
 
@Andrew: I did the graphics for all four of my books using (Mathematica and) Adobe Illustrator. However, Illustrator no longer runs on my computer and I'm not willing to pay $30 a month or whatever outrageous amount Adobe demands. So if I need to change my graphics, I need to do so in Inkscape. In this case, Leslie and copper convinced me that I should have a one-sided arrow rather than two-sided in that figure, so I changed that.
 
Of course, no reason to restrict ourselves from 0 to 1
Oh, does that mean that if $x$ and $y$ are uniformly chosen from $0$ to $10$, then $\max\{x^2,y^2\}$ is uniform from $0$ to $100$? I guess so!
 
9:13 PM
It took me 10 years to get good with Illustrator, and this is the first thing I actually had to use Inkscape to do. First have to save the .eps file as .pdf and then import it to Inkscape, blah, blah, blah.
 
I mean, so are $10x$ and $10y$, so it's not too surprising, I guess
 
Actually, it is surprising to me, DogAteMy.
Square bunches small numbers and spreads large numbers, so it feels non-uniform to me.
 
Let me try it in R
 
Very non-uniform.
 
z=pmax(runif(1000,0,10),runif(1000,0,10))^2
 
9:15 PM
So what do we have here... the density is $$f_{Z}(z) = 2(1-\sqrt{z}) \cdot \dfrac{1}{2\sqrt{z}} = \dfrac{1-\sqrt{z}}{\sqrt{z}} = z^{-1/2} - 1$$
for $z \in (0, 1)$.

My guess is that this is some sort of generalized beta distribution.
 
I guess it reduces to asking if $x^2$ is uniform, and it certainly does not feel so to me.
 
Seems good
 
Probability is too subtle for me. But it seems like the max is $x^2$ half the time, and $x^2$ is not uniform.
 
Don't even need the minimum to be 0; I could pick them from [1,100] and it should still work
@TedShifrin Are you surprised that $\max\{x,y\}$ (no exponents) is above 0.5 75% of the time?
 
9:18 PM
Little nuance that I ran into for my homework: try the same problem, except restrict $x + y \leq 1$
That was a fun problem that I'm glad I knew how to solve
 
Neat not-unrelated fact: if $x$ is uniform in $[0,1]$ and $p$ is uniform in $S^2$, then $\sqrt[3]x\cdot p$ is uniform in $B^3$
essentially because we need $P[\sqrt[3]x\le R]$ to be the volume of a radius $R$ sphere over a radius $1$ sphere, which is $R^3$
 
Yeah, because the area of the stuff under 1/2 is only 1/4 of the "half-square" and what's left is 3/4.
 
So the max of two uniform things is nonuniform (ununiform? iform?), and the max of two nonuniform things can be uniform
 
Ugh.
 
LaTeX test: $\med$
Hm
 
9:24 PM
What is that supposed to be?
 
does operatorname work? or mathtext
 
If ${\rm med}(a,b,c)$ is the middle one
 
I never have bothered with mathoperator. I just use \text.
I've never seen that in my life, DogAteMy.
 
then for what function $f$ is ${\rm med}(f(x),f(y),f(z))$ uniform
Yeah I'm making it up
 
9:26 PM
$\operatorname{geometryislies}(f(x), f(y), f(z))$
 
or ${\rm med}_if(x_i)$ for short
 
people
I must inform you
it is of the utmost importance:
 
there was a good double use of the index i this morning or last night. i forget which. i almost gave a speech about it.
 
The problem is I don't have a neat way of figuring out $P[{\rm med}_if(x_i)\le\alpha]$
 
a rotation of pi of the riemann sphere about the real axis produces complex inversion
 
9:28 PM
On the Riemann sphere, the real axis is a circle
How do you rotate about it
 
the real axis passes through origin, it isn't a circle
well
it is a vertical circle
well
 
It's the blue circle here
I guess you want to rotate about the line between -1 and 1
 
ok, perfect, now think stereographic projection, for a plane cutting that red line
the plane through the red line there, that's the complex plane
the axis of this complex plane is the line through -1 to 1
 
and -1 and 1 are precisely the two points that don't change under inversion (z -> 1/z) so it makes sense
 
isn't that absolutely amazing
rotate the riemann sphere $\pi$ about the axis through $-1, 1$
 
9:32 PM
Now find formulas for all the other rotations
How do I rotate 180 degrees about p?
Given a complex number $p\in\mathbb C$
 
no clue, in the sense that you want to apply complex inversion to it?
 
I don't actually know the answer
 
no clue how it would behave in that case
but if you set the axis of rotation to be the real axis, then it would do complex inversion sunglasses
 
oh, is this the maths thread?
 
wow, it might be. I wondered why I was getting sleepy.
 
9:37 PM
:-)
 
zzzzzzz
 
Stated this question on chat a few days back, finally posted it as a question on the main site:
0
Q: Convergence of a random harmonic series with Poisson gaps

SemiclassicalThe divergence of the harmonic series is familiar: the partial sums of positive integer reciprocals grow without bound. A less familiar but still well-known result is Kempner's series: If we only use integers whose base-10 expansion contains a 9, then the sum of reciprocals converges. The intuti...

 
i am as useless today as i was a few days back, but i like the question. i am partially dozing because i ate sushi and a number of dumplings.
 
10:01 PM
i am consistently useless.
except when being useless is useful.
whoa, irelands daily rate > california's > uk's.
 
yikes. don't blame me, i stay home most of the time.
 
i could be the super spreader, with my daughter as the uk proxy
sars-covid-cu
 
10:17 PM
@Leslie I am looking forward to good sushi for lunch Friday.
@robjohn: Did the cache clearing help?
 
@TedShifrin I haven't had a chance to check, I got called away by my employer. The gall!
 
You should quit in a huff!
 
I may
or at least retire in a huff
 
The huff is the essential element.
 
indeed
I have been looking closely at retirement. It's looking better all the time.
 
10:21 PM
I miss my teaching (as you can usually tell in here), but I'm relieved that I retired almost 6 years ago before COVID and before bureaucracy in GA got even worse.
 
I have the new version. I had to wait, I tried clearing any caches associated with uga.edu, but that didn't help.
 
Ah.
 
the page layout of the first page is a bit different
 
The tricky thing is that I had to go deep into the college website where these pages are stored to remove my old version so that the new version would have the same name (rather than .0 or .1), because I have links to that page on MSE, for example. Technology can be a pain.
I changed the date. What else changed?
Something had to change in the TeXLive implementation of stuff, as I ran into running head issues with my index.
And the typesetting of the answer section added some space. I didn't change the file at all. But I ended up with a longer section there.
 
Just the spacing, there is more empty space in the new version. No biggie
 
10:26 PM
i thought tech was supposed to make these things easier...
 
It also no longer says "Preliminary Version"
 
i want the mean value theorem to be called the angry value theorem. it will be easier to remember.
 
Oh, I took off the "Preliminary Version" β€” at least on my computer β€” a while ago. That changed the spacing, of course.
 
@copper.hat and do away with those pesky employees
 
what happened to my promised automation?
 
10:27 PM
I decided that after 15 years it couldn't be called "preliminary," since I am more or less done playing with it.
 
no retirement, pensions (not that i have one), etc?
 
@copper.hat I will not change to the Angry Square
 
it does look angry though
the eyebrow angle is beyond critical
 
the mask kind of mediates the mean-ness
makes it look more evil than mean
 
true
 
10:33 PM
Soon Andrew will allege that all four of us have become one. Scary.
 
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