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10:22 PM
@AkivaWeinberger. No idea why $\frac{(a^2+1)}{(a^2+2)}=\frac{(b^2+1)}{(b^2+2)}$ is not one to one!
The original function is $f(x)=\frac{(x^2+1)}{(x^2+2)}$
 
Is $x^2$ one-to-one?
 
If we subtract both sides, we will get $a^2 = b^2$
so taking square root of both, we will have -+a = -+b
I multiplied (a^2+1)(b^2+2) = (a^2 + 2) (b^2+1)
I got a^2 = b^2
 
Does a^2 = b^2 mean a = b? @Avra
 
what's the domain of your f, avra
there was a guy named jonah who was drowning, and god sent a smale to evert next to him so that the water would be on the outside and he would be on the inside
there's some confusion around the scripture in this because it was translated in a way that makes it sound like a sea creature did it
 
@AkivaWeinberger. I see it as -+ a = -+b
@AkivaWeinberger. :/
 
10:30 PM
@Avra What does that mean
 
@leslietownes. R to R
 
can you find an example of a and b with a^2 = b^2 but a isn't b
 
@AkivaWeinberger taking square roots of a^2 = b^2
leave -+a = -+b :|
 
can you find an example where a = -b but a isn't b
 
uh I think you wrote that wrong @leslietownes
 
10:31 PM
2 not equal -2
@leslietownes. this is a counter example so a not b thus not one to oe
 
so maybe f(-2) is f(2) although -2 isn't 2
 
@Avra So what about your original function
What happens when you plug in 2 and -2
 
akiva, ? did he send a smale to drown jonah?
 
$$
f\left( x \right) =\frac{x^2+1}{x^2+2}
$$
$$
\vdots
$$
$$
a^2=b^2
$$
$$
\pm a\ \ =\ \pm \ b
$$
 
@Avra If $f$ is not one-to-one, all you need to do is find two unequal numbers $a$ and $b$ with $f(a)=f(b)$.
What happens when you try $a=2$ and $b=-2$?
 
10:34 PM
you mean -+a = -+b have 4 pairs!
(a, -b), (-a, -b), (a, b), (-a, b)?
@AkivaWeinberger
 
Yes - it means a=b or a=-b or -a=b or -a=-b.
But answer my question.
 
so, in all cases they are equal !
That is what I see :|
 
2 mins ago, by Akiva Weinberger
What happens when you try $a=2$ and $b=-2$?
What is $f(2)$?
 
it will be equal toooo
f(2) = f(-2)
 
10:36 PM
so one to one!
That is why I did
 
What does one-to-one mean?
 
but the solution here says it's not :(
one-to-one means f(a) = f(b) iff a=b
for all a,b
 
Right. f(2)=f(-2) but 2=/=-2
therefore it's not one-to-one
 
you mean since a ~= -b?
 
Since 2 ~= -2. We don't need to be general when we're disproving this. We only need one example.
 
10:39 PM
DogAteMy: Stop this anti-ChatJaX blasphemy!
 
got you @AkivaWeinberger Prof
@AkivaWeinberger. Tnnnx
 
@TedShifrin $h{\Big m}{\Large m}{\Huge ?}$
why didn't that work
 
you're rusty
 
$\Big a$
Is Big not a thing?
 
the chatjax skills have diminished with disuse
 
10:40 PM
$\Large a$
$h\Large m\Huge m$
@leslietownes This is true
 
I suppose I deserve this.
 
i tried to get a thing going a while ago to use oo for \infty. i thought it would catch on but people just kept telling me to stop doing it
 
I will smack for less.
DogAteMy, \big and \Big are for things like parentheses and brackets.
 
1/oo=00
 
I H8 you all.
 
10:43 PM
31 in OCTAL is what in DECIMAL?
 
oh, that old chestnut.
 
'Tis the season
Well, one of them, anyway
 
speaking of dec 25, the red portion of my daughter's strawberry costume finally arrived.
 
I'm waiting for pics.
 
10:47 PM
0
Q: Curves and smooth functions on manifolds derivative

monoidaltransformLet $f: M\rightarrow \mathbb{R} $ be a smooth map at $p\in M$ and let $\gamma:(-\epsilon,\epsilon)\rightarrow M$ be a smooth curve with $\gamma(0)=p$. Let $(U,\phi)$ be a chart at $p$. Set, $(\phi \circ \gamma)(t)=(x_1(t),......,x_n(t))$ We claim: $\frac{d}{dt}|_{t=0}(f\circ \gamma)=\frac{\partia...

 
my wife and i had different conceptions of the top of the strawberry. i was thinking a green hat. she was thinking a green fringe around the neck. i think that's unrealistic and confusing. strawberry with a head on top?
is that an einstein convention or something? there should be a sum
 
yeah, I added the sum @leslietownes
 
oh, you edited. that looks reasonable to me.
 
Oh, I thought you meant Einstein summation for strawberries.
 
she gave up on wanting paws, which was good, it's hard to find paws that fit a 3-year-old, or paws separate from an entire cat costume generally.
 
10:55 PM
That would give one paws.
 
if i gave out smacks...
bought my first and only tank of gas of 2021 today. maybe could have made it to the end of the year, but i was tired of the suspense.
 
Ok, thanks @leslietownes I just wanted to make sure, really
 
Wow. I don't drive much, but I fill up at least once a month.
And I average close to 40 mpg.
 
i drive maybe 2-5 miles/week. day care is 15 miles round trip but i handle only a few days a week and often use my wife's car because it's easier to get the munchkin into
 
Oh, you really don't drive. I typically do 80-100.
 
11:00 PM
@TedShifrin I typically have to spend about $50 on fuel every week. It is 30 miles each way to my office every day, and the vehicle I have is not efficient. I dream of someday actually owning a car. In that dream, the car gets better than 24 mpg.
 
Yeah, I insisted on buying a hybrid when I retired and moved here.
 
@TedShifrin Yar. Right now, I have my father's car (he died, so he isn't using it). When my mother needs a truck, I use her car, which is a not-terribly-old Prius. I much prefer that vehicle.
 
I’m not fond of Prii, but yes.
 
priuses are great cars.
not as a driving experience, and not much to look at. but very reliable and fuel efficient.
 
11:04 PM
I prefer my Civic hybrid
 
does my back hurt if i drive more than 2 hours in my tiny prius? yes. do i barely fit in it? yes.
 
@TedShifrin Once upon a time, I owned a Leaf. I frickin' loved that car. But that was one of the many vestiges of middle-classness that I lost in the divorce.
 
Understood.
 
the civic hybrid is actually fun to drive. it was rocky on reliability when they first came out with the hybrid option. i might have got one.
 
Everyone I know who’s had one has done fine.
 
11:05 PM
I really want a Volt, but they stopped making them. :\
I test-drove one once, and really, really liked it.
 
Yup. Revolting.
 
oh, there's a guy at my work who has a volt. loves it. raves about it.
to the point of annoyance. but i do gather that they are great.
 
Jealousy is green, leslie.
 
the only issue he mentioned was long road trips to the east (up and down california is fine). if you break down in the middle of nowhere in nevada there will be nobody who can fix it.
but that's kinda true for all cars if you're in the middle of nowhere, and it hasn't broken down, so i dunno.
i didn't ask what he was doing out in the desert. best not to know.
 
Probably burying a body.
You must not be a real friend.
(I friend will help you move. A real friend will help you move a body.)
 
11:10 PM
all i know is, his basement smells like bleach and there's no washing machine down there.
 
does anyone have halloween plans? trick or treating isn't a thing in my neighborhood because there are almost no kids of the right age around. so i was thinking just some mild vandalism.
 
Okay, I'm tired. I'm going home.
 
keep on truckin, xander.
 
11:55 PM
Is the relationship between bijection and invertibility is important since if a function is not bijective for not being one to one, then that means if we are to invert it, then a value in the range that takes 2 values become a value in the domain that now takes 2 values, which contradicts the definition of a function? Not sure if this is a correct understanding
 
that makes sense. you can formally invert any set of ordered pairs, including a function, but you won't get a function if the function you started with isn't one-to-one.
 
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