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12:08 AM
Hello!
When someone ask us to find the interval of convergence of a series in Calc 1, do that person also ask us to analyze at the extremes of the interval?
I know that analyzing the interval of convergence through, for example, $\lim_{n\to\infty}|a_{n+1}/a_n|<1$ is analyzing whether it is absolutely convergent or not. I think that we are not interested in this
 
12:44 AM
I say nothing, I get confused by the interval of convergence. Thanks btw!
 
1:16 AM
Is some1there
it is possible to always define a inner product?
 
Do you have a vector space?
 
in the field of R
 
you can define an inner product on any field as long as the inner product satisfies positive definiteness, linearity, and conjugate symmetry
and those conditions are satisfied in $\Bbb R$
 
so how cani prove the fact that in $\Bbb R$ i can always define an inner product?
is there a theorem or something?
oh i found something
25
Q: Is there a vector space that cannot be an inner product space?

HuyQuick question: Can I define some inner product on any arbitrary vector space such that it becomes an inner product space? If yes, how can I prove this? If no, what would be a counter example? Thanks a lot in advance.

but imtrying to understand the hamel basis
do you understand this part
"Unfortunately you need the axiom of choice to obtain such a basis, if X is not finitely generated."
Why he say unfortunately
 
 
5 hours later…
6:10 AM
Yo @Alessandro
 
Hi @BalarkaSen
How is it going?
 
Not bad, how about you
 
Pretty well, I'm back in Italy for a while now
I should study AG for an exam eventually but I'm reading somr cool set theory instead
 
@Alessandro Oh nice
 
 
3 hours later…
9:48 AM
TIL that there's a site called patents.google.com
How many sites does Google have??
 
10:29 AM
It will be cool if there are patent that actually go meta buy patenting on the blueprints themselves
or better, patent on a patent claim
or even better: 💥(patent)
> If a society gets too meta, reality will be broken because it cannot keep up with the meta memes
Speaking about broken reality...
 
11:25 AM
The existence of functional analysis implies the existence of nonfunctional analysis
or dysfunctional analysis?
 
12:13 PM
do groups, being an abstract concept, exist if there are no humans?
 
Is $ \frac{x+y}{x^3 y^3 - x^3 y - x y^3 + 2 xy + 1} $ a formal group law on the interval $[-1,1]$ ?

It is a lot of work to check on associativity imo.

Maybe there is a shortcut around checking associativity ? Or a way to check it faster ?

Is there an easy algoritm to check if a symmetric rational function $f(x,y)$ is a formal group law ?
0
Q: Is $ \frac{x+y}{x^3 y^3 - x^3 y - x y^3 + 2 xy + 1} $ a formal group law?

mickIs $ \frac{x+y}{x^3 y^3 - x^3 y - x y^3 + 2 xy + 1} $ a formal group law on the interval $[-1,1]$ ? It is a lot of work to check on associativity imo. Maybe there is a shortcut around checking associativity ? Or a way to check it faster ? Is there an easy algoritm to check if a symmetric ratio...

LHF ?
 
12:33 PM
@mick you can use pari/gp or wolframalpha, I guess
hej @Tobias
 
@LeakyNun Hi
 
I have no idea how to find the third simple char-2 rep of S5
actually I have some ideas
ok lemme tell you what I know
 
I assume you know where to look?
 
I know that there is the trivial rep
I also know that there is a 4D rep, which is basically the augmentation ideal of the algebra K^5 which KG acts on
let's call them $K$ and $M$
I know from looking at Brauer characters that $M \otimes_{KG} M$ contains the third simple module that I'm looking for, but that would be a 16-dimensional module
either I would need to look at that, or I don't know where to look
 
@LeakyNun You should look at the Specht modules and check which ones are reducible
 
12:36 PM
oh no
are they the ones related to the tableaux
 
I don't think they are taught in the lectures though
 
and they are all defined over the integers
ahh
Did you check that the $4$-dimensional rep is irreducible btw?
 
yes
it's irreducible by the previous question (which I did)
 
ok, so try some other permutation reps as well
By letting it act on cosets of Young subgroups
 
12:37 PM
what does that mean?
 
Well, you started with decomposing the $5$-dimensional one where you act on the cosets of $S_4$
 
oh...
 
Now try acting on for example the cosets of $S_3\times S_2$
 
nice, I'll try that
10 is smaller than 16 :P
 
(note: I don't know precisely which is the correct one here)
 
12:43 PM
so I act on the cardinality-2 subsets of {1,2,3,4,5}
(123): 12->23->13->, 14->24->34->, 15->25->35->, 45->.
(12345): 12->23->34->45->15, 13->24->35->14->25.
so the char polys are (X-1)^10, (X^3-1)^3 (X-1), (X^5-1)^2
whose Brauer traces are 10, 1, 0
 
You should start by decomposing it over the integers, where you should have a copy of the trivial and the $4$-dimensional ones from before
 
the two existing traces are 1, 1, 1 and 4, 1, -1
which cannot produce 10, 1, 0
what do you mean by the integers?
(I was computing the Brauer characters to see if I would produce the 3rd simple module)
 
I mean considering this as a representation over the integers
 
you mean the complex numbers?
 
no
(though the result is the same)
doing it over the integers ensures that it will define a rep in char 2 as you want
 
12:48 PM
what tools do I have?
 
Well, you can surely find the trivial rep directly
 
I'm not very sure, seeing that 10 is divisible by 2
 
this is a permutation representation, so there is always a copy of the trivial rep in the obvious way
 
right, but it wouldn't be a factor
because it's part of the augmentation ideal here
I should look at the augmentation ideal quotient the norm ideal though
that would remove two copies of 1,1,1 from our Brauer trace
 
That makes no sense. You have a concrete representation here
 
12:51 PM
so it becomes 8,-1,-2
@TobiasKildetoft are you suggesting 12+13+14+15+23+24+25+34+35+45?
 
Ahh, your issue is that the decomposition might fail in char 2, where the images of the subreps might no longer be trivial?
 
I don't know abstract reasons, I just know that 12+13+14+15+23+24+25+34+35+45 is a part of the augmentation ideal
 
I am not working with the group ring at all here. I am saying that if you take the sum of the standard basis vectors, then that gives a copy of the trivial rep.
 
indeed
so now I quotient the augmentation ideal by that trivial rep
and get a 8D rep
with Brauer character 8,-1,-2
 
Hi, does someone know the Grunwald Wang theorem? I got an answer on Mathoverflow which uses it but I don't quite understand how.
As far as I understand, it says that if $K$ is a number field, then any element $x \in K$ which is a square in all but finitely many places of $K$ must be already a square in $K$.
 
1:09 PM
Dumb question: $1 \mapsto 2$ is an isomorphism of $\Bbb{Z}$ and $2 \Bbb{Z}$, right?
I should say, $1 \mapsto 2$ extends to an isomorphism.
 
You mean $(\mathbb{Z},+) \to (2\mathbb{Z},+)$, $x \mapsto 2x$ ? It's a group homomorphism because of the distributivity, injective because $2x=2y$ implies $x=y$ and its clearly surjective. So its an isomorphism of groups.
 
That's what I thought. Thanks!
 
@AkivaWeinberger dysfunctional analysis is just a subclass of nonfunctional analysis. Too many have underestimate just how large any class under the effects of the "non" operator is
Thus one can easily envision in mathematics, dysfunctional analysis is the analysis of pathological functions, spaces and so on, and their properties. In particular, their deviation from nice functions will be an important tool of study
 
 
2 hours later…
2:59 PM
any1 wanna talk abit algebraic sets?
Consider the $(A_k)^{n}$ ,$ k$ is a field an algebraic set is a subset such that there exists a set of polynomials such that for every point on the subset every polynomial gives zero.
now along with the zariski topology i define those sets to be the closed ones.
now i want to identify is a set is algebraic or not
if it is it must be equal to its closure with respect the zariski topology
also every algebraic set has a decomposition of irreducible algebraic proper subsets
now with all that said i think if you are trying to prove a set is not algebraic
these might not be good methods to do so and would be better to just prove there doesnt exist a polynomial such that it has its zeroes on the given set
 
3:17 PM
it's very hard to understand you without punctuation
 
3:37 PM
sorry
but i think i got it myself
 
4:06 PM
I'm looking for cases where changing the field of a finite-dimensional vector space changes its dimension.
I only know of one for the vector space of complex numbers
 
how can i prove $X^2-Y^2-1$ is irreducible
polynomial of 2 variables
nvm
 
Zee
4:29 PM
@FuzzyPixelz just take any field and change it to a field with a different dimension, that will change the dimension of the vector space.
 
heya
i had a question regarding continuity and differentiability
clay6.com/qa/21527/let-f-r-rightarrow-r-be-a-differentiable-function-and-f-1-4-t‌​hen-the-value-
in the 3rd step lim f(x) - 4/x-1 changes to f'(1) i cant understand why
hello :/
 
 
3 hours later…
7:31 PM
echoes
 
@BalarkaSen Hi
 
Hi @Tobias!
 
@BalarkaSen Overhead the albatross hangs motionless upon the air...
 
Eeeh, Pink Floyd.
 
good ref
 
7:37 PM
Hi @Balarka
 
it's amazing how quickly the room fills w nerds
 
heyo Erico
 
how goes life
 
Life is good, learning math. Midsem starts in a week, which is not good, because I have to prepare for it rather than learning math for a few days now
 
7:40 PM
What classes are you taking this semester?
 
analysis-2, algebra-2, probability-2 and physics-1
 
rip
i have no time for learning math these days and it sucks
 
Sounds fun.
 
they're good subjects but the course structures are weird so
 
what do u do in prob
 
7:43 PM
so far its just been setting up continuous random variables and lots of examples of continuous distributions
 
When working in an industry do Mathematicians communicate directly with engineers? or is there some sort of layer between that separates the two.
 
i used to hate probability theory but now i think it's a sick subject
 
most of the course was measure theory without the details + a bunch of distributions without explaining why they are important, we only did some order statistics that was actual probability
 
@Rick that surely depends on what precisely the mathematician has been hired to do
 
7:45 PM
Measure theoretic probability is pretty cool
 
true
 
tbh i still hate working out all the measurability issues u get when u try to study processes but the theory comes out very nice in the end modulo those things
filtrations are my nightmare :(
 
idk much about processes
 
they're cool but they convinced me im no stochastic analyst
 
maybe you can tell me how to get brownian motion as scaled limit of random walks
 
7:49 PM
oh yeah that's a very cool exercise in knowing how things scale appropriately
 
@TobiasKildetoft let's say it's a graph optimization problem, they need to determine the optimal graph to encode a particular subset of data/problems.
 
Speaking of measure theory I went through the proof that the axiom of determinacy implies that every subset of $\Bbb R$ is Lebesgue measurable today, very cool stuff
 
something something CLT something something $\sqrt{\Delta t}$ something someting
 
iirc the simplest model for brownian motion is a 1-parameter family of (absolutely) continuous random variables X_t such that for all 0 < t0 < ... < tn < 1, {X_{t_k+1} - X_t}_k are all independent and X_{t+h} - X_t ~ N(0, h)?
Maybe X_t : Omega x I -> R is continuous in the I factor
 
almost surely yeah
 
7:54 PM
what does that mean? for all e > 0, there is d > 0 s.t. P(sup |X_{t'} - X_t| < e) = 1 for all t' s.t. |t' - t| < d?
 
Hello guys!!
I am wondering if the domain of this relation is correct:
 
X_t is continuous for almost every $\omega \in \Omega$
 
Prove that $R:\Bbb Z\times\Bbb Z:aRb\iff|a-1|=|b-1|$ is an equivalence relation
 
oh no that bit is fine, there is some continuity condition on the I factor though, isn't it?
 
@AlessandroCodenotti have you seen this? math.mcgill.ca/rags/JAC/124/comment.html
 
7:56 PM
maybe? honestly idr
 
For example the reflexivity: I know that if $a\in R$ then $aRa$
 
@manooooh how about something stronger: for every function $f : X \to Y$, the relation $R : X \times X : aRb \iff f(a)=f(b)$ is an equivalence relation
it's essentially the kernel of the function, and you can formulate the first isomorphism theorem using that
 
@LeakyNun probably, thanks. I do not how to interpret the start
In the reflexivity I do not know how to say "$a\in R$"
 
you say $(a,a) \in R$
or just $aRa$
 
@LeakyNun I hadn't, but it makes sense
 
7:58 PM
@LeakyNun yes, but we have to guarantee first that the element $a$ is in the domain
 
$a \in \Bbb Z$
 
@ÉricoMeloSilva I guess the continuity on I is implies by X_{t+h} - X_t ~ N(0, h)
implied
 
@LeakyNun but the domain is $\Bbb Z\times\Bbb Z$
 
@AlessandroCodenotti it's quite interesting that every finite subset is satisfiable... I think I've even seen the result that for every n, ZFC with only Σn replacement is satisfiable
 
I guess I cannot say "$a\in\Bbb Z\times\Bbb Z$"
 
7:59 PM
$(a,a) \in \Bbb Z \times \Bbb Z$
 
if h is small the distribution changes by a small amount
so its ok
 
@LeakyNun oh, yes thank you! And then we can say that $|a-1|=|a-1|$, so $aRa$
 
yes
 
@LeakyNun what about the transivity? We need $3$ elements
$(a,b)\in\Bbb Z \times \Bbb Z$ and $(b,c)\in\Bbb Z \times \Bbb Z$?
 
right
 
8:01 PM
I cannot say $(a,b,c)\in\Bbb Z \times \Bbb Z$
@LeakyNun ohh thank you!
$\ddot\smile$
 
Problem: Let $F_2 = \langle a,b \rangle$ be the free group on two generators. Let $\phi : F_2 \to \Bbb{Z}_2 \oplus \Bbb{Z}_3$ be defined by sending $a$ to $(1 + 2 \Bbb{Z}, 3 \Bbb{Z})$ and $b$ to $(2 \Bbb{Z}, 1 + 3 \Bbb{Z})$. Draw a cover of $S^1 \vee S^1$ whose fundamental group maps isomorphically to $H$ under the homomorphism induced by the covering map.
Okay. I was able to determine that the desired covering space must be a six sheeted cover. When I was speaking with my professor about this, he said that this means you should draw a graph with 6 vertices. Why does six sheeted cover correspond to 6 vertices? What's the reason?
 
what graph?
 
Not entirely sure. He said that the cover you want to draw will look like a 6 with six vertices connected in a certain way.
 
what is $H$?
 
if its a six sheeted cover of S^1 v S^1 then the wedge point has six preimages
those are the vertices of the graph
 
8:07 PM
Preimage of what? The whole space $S_1 \vee S_1$?
 
@BalarkaSen lol i didnt even read this message when i responded but i imagine this is true for the reason u said about distribution of increments
i dont wanna think about it tho
 
preimage of the wedge point
 
@ÉricoMeloSilva yeah whatever man, something something
i dont know any probability
 
Oh, because the number of sheets the is the cardinality of any fiber. So any point in the space must pull back to 6 different points in 6 disjoint spaces?
 
i preferred to think of brownian motion as a measure on the space of trajectories bc then i wouldnt have to think about how it looks and i could just prove bullshit about PDEs by appealing to abstract nonsense tbh
bc i have a dumb brain that no work good
 
8:10 PM
mu_t(-) = P(X_t^{-1}(-)) being the 1-parameter family of measures on Omega?
is that the idea
 
u think of the measure on the space of trajectories rather
 
Omega x I being that space of trajectories?
 
cuz a process gives u a function $\Omega \to \mathbb{R}^{n}^{\mathbb{R}}$ e.g.
$\omega \mapsto X(\cdot, \omega)$
and pushforward the prob on $\Omega$ by that map
the space of trajectories being the space of maps from R to R^n e.g., or w.e. spaces u want
 
ah ok
 
continuous maps etc
prob dudes call that the law of the stochastic process
 
8:17 PM
different currying
i see
 
and frequently one only cares about things up to the probability law of a process so it's a convenient way to redefine processes if u wanna do PDEs over the space of paths or something where the solution in question should be some probability law
 
im scared of what the appropriate sigma algebra on Map(I, Omega) is. Maybe generated by measurable functions or whatever
gotchu. its a nice way to think about it
 
the sigma-algebras are horribly behaved generally :(
working w them is a mess
 
eek
 
just geometry for me thanks
 
8:27 PM
(fwd) they should rename real analysis to applied triangle equality
 
What would be theoretical triangle equality?
 
personally I like ultrametrics more
 
I find myself mildly amused when prefixes like "ultra" or "super" are used to modify a mathematical term.
 
or hyper
 
whats your favorite module you've taken so far guys?
 
8:40 PM
the 6-dimensional simple module over $\Bbb C[S_5]$
 
lmao
I meant subject
:p
 
9:07 PM
An easy breezy intro to knot dynamics
 
9:30 PM
Check out this video by mathematician and dancer Nancy Scherich
I met her at Mathcamp several years ago. She specializes in braid theory. She won the "Dance your PhD" competition in 2017 (https://youtu.be/MASNukczu5A)
 
9:49 PM
That's a pretty fun video. You can tell they're enjoying themselves.
 
Guys, can eigen lines be points?
 
@topologicalmagician: What are you asking?
A line is a collection of points (satisfying certain properties).
 
hey Ted! Welcome back, you've bee missed
been*
 
LOL, I doubt that.
 
I've missed you that's for sure
 
10:02 PM
LOL, thanks. Remember that eigenvectors must be nonzero vectors. Any nonzero scalar multiple of an eigenvector is an eigenvector, so you get a whole line (at least), except for the zero vector.
 
oh, I forgot about the multiple part
that means my eigen lines should just be the multiples of my eigenvectors
i'm exhausted, I only slept for 2 hours
 
looks in all directions
It's nerdville!
But yeah how's everything going for you guys?
 
For dx\dt=-2x and dy\dt=-y, sketching just gives me the plane, right?
 
10:19 PM
What do you mean by that, @topologicalmagician? What are you sketching? The integral curves (solutions of the differential equation with a given initial condition)?
hi Demonark ... I take it you're still in a decent mood.
 
yes, but no initial condition has been given
 
Hi @Ted @Dami
 
So are you supposed to sketch the vector field or the solution curves?
heya, italic Alessandro — done with your topology exam?
 
solution curves
 
Yeah that was on the 2nd of the month! The last exam was set theory on the 16th
Well I'll also have algebraic geometry on the 18th of March, but there's plenty of time for that
 
10:22 PM
Fairly. Quarter is sorta heavy so I'm in a scramble to do psets and learn things
But the biggest source of stress/emotional drainage is gone
So that's nice
 
@Ted hey
I'm having a bit of trouble finding subrepresentations...
 
You know not to ask me about algebra, Leaky.
 
I'm reading a book from the dark age before LaTeX now, I'm so glad I'm studying math in the 21st century
 
Milnor Morse Theory
 
@TedShifrin where does linear algebra stop and representation theory begin?
 
10:24 PM
The typesetting makes my eyes grow eyes and cry
 
your eyes grow eyes?
 
Lots of wonderful books from the antediluvian era.
 
@Daminark Holy **** Dami I think you just figured out why Ted has so many eyes
 
:0
 
How I can check if my answer to a solution for an ODE using power series is correct or not?
 
10:26 PM
@IPAddress wolframalpha / desmos
 
Alessandro: Have you explained the transcendental number of eyes, though?
@IPAddress: Just by differentiating and verifying it satisfies the equation.
 
Maybe you read a lot of books
 
transcendentally many?
 
@TedShifrin hahahaha - I should've thought of that
 
@Leaky: I just don't think much about representations or character tables or anything like that. I've taught a little bit of it, but I really don't remember anything useful.
 
10:29 PM
I guess that's possible if you give up on a book after reading $1/\pi$ of it?
 
Maybe so, @Alessandro. I think I needed more eyes to dodge your dangerous driving.
Note the alliteration.
 
That might also explain it
 
10:43 PM
So any group action (everything finite) can be composed into $\bigoplus_{i=1}^n (G/H_i)$ where $H_i$ is a subgroup of $G$ and $G/H_i$ is the left cosets of $H_i$
 
I have no idea what you're talking about, Leaky. I have a group acting on a set. What are you decomposing? Orbits? So each orbit is the quotient by stabilizer subgroups. OK.
 
and the orbit-stabilizer theorem is more than just a bijection?
 
it's a $G$-set isomorphism.
 
the orbit of x is actually isomorphic to G/Stab(x) as G-sets?
I can't believe I only realized it now
 
I emphasized that a lot when I taught algebra, actually. To me group actions is one of the central topics.
 
10:48 PM
and $F_5$ is the galois group of $X^5-2$ over $\Bbb Q$ right
it's a group of order 20, so it has 6 cosets
 
Hi yall
@TedShifrin Can I send ya small email ? :D
 
"central"
:smirk:
 
:P
generated by (12345) and (1243)
 
Leaky !
 
goddag
 
10:52 PM
Can I send you a question in email ?
 
well I'm not controlling your email account
 
goddag you say it when it is day time =p
:D
 
vad sag jag?
 
okay it is a small question i did not quite get
Vad sa jag ?
you dont just put the G and think it would work always
 
We actually touched on that exact statement in class today. (The $orb(a)\cong G/stab(a)$ statement)
 
10:54 PM
vad säger jag?
@KasmirKhaan I actually don't think it would work
 
@LeakyNun I know it was just me joking =p
btw leaky
in cantenese
how do you read whole texts without any comma or point
 
no idea I just do it
 
but is there a sign
 
we do have punctuations
 
that the meaning has ended?
 
10:56 PM
just not spaces
 
hmm
that is not what I though ><
but still, having no space is kinda hard if not used to it
 
I mean, when you say things out loud, you don't have spaces either, words get smashed together, you only have punctuations
and we have way more than 26 letters
 
yeah true but when we talk ,the tone differs so one gets what is hapning
anyway
I sent ya email
plaease answer me there not here
@LeakyNun Are you planning to visit Sweden?
 
maybe not
 
it is getting super hot these days
i mean if you like the snow
you should visit the north side
stockholm has no snow left -.-
 
10:59 PM
sad
 
i know right
it used to be like -25 this time of the year
 
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