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6:00 PM
Well, the $x^{1/(2n+1)}$ isn't real for $x<0$. Right?
 
Sure it is :)
 
Oh! Yes. Of course!
 
But what kind of function is $x^{1/3}$, $x^{1/5}$, etc.
 
Not a polynomial.
 
True. Think graphs/symmetry.
 
6:01 PM
It's not symmetric.
 
Hmm ...
 
I'm bad with graphs without computer aid.
 
Get past that. You need to have basic skills ;)
You should be able to graph $x^3$, $x^5$, etc.
And you should know about even and odd functions.
 
I was thinking about that.
 
OK, so what do you know about $\int_{-1}^1 g(x)\,dx$ when $g$ is odd?
 
6:04 PM
0
 
So apply that to this question.
 
$x^{1/(2n+1)}$ is odd. Thus, $\int_{-1}^1f(x)x^{1/(2n+1)}dx=0$.
 
For which $f$s?
It's certainly not so for all $f$s.
 
Certainly.
Even?
 
Right.
 
6:06 PM
So?
 
So you can't conclude that $f=0$ ...
 
Ah! Of course!
 
But I don't think you can do the original question without the Stone version of the theorem. If you guys didn't do it, presumably it's not on your exam.
 
Why didn't my previous method work for this case? Where I found some $g(x)=h(x)f(x)$ and showed that $g^2(x)=0$ so that $f(x)=0$.
 
Because you can't get combinations of $x^{1/(2n+1)}$ to be a polynomial.
 
6:07 PM
We did do the Stone-Weierstrass theorem. I though that it was the same as the Weierstrass approximation theorem.
 
Ah, well, so you're going to consider $\{x^{1/(2n+1)}\}$ instead of $\{x^n: n\ge 0\}$. Oh wait. We don't have constant functions.
Hmm ...
 
Okay. When I had $\int_0^\infty f(x)e^{-nx}dx$ I used performed a change of variables $u=e^x$. So I guess that I have to use a change of variables, or just try to manipulate it some other way to make it a polynomial, but why does it have to be a polynomial to begin with? Doesn't the Weierstrass approximation theorem say that we can approximate any function in $C([a,b])$ with polynomials? That feels backwards.
 
Yeah, I don't think you can do any clever substitutions here.
 
Okay.
Is there a difference between the Weierstrass approximation theorem and the Stone-Weierstrass theorem, or are they synonyms?
 
Approximating a continuous function with polynomials won't help you with fractional powers if you're trying to get $f^2$.
No, Stone is far more general than polynomials. But you need a collection of functions which (1) contains a constant function and (2) separates points.
 
6:11 PM
Why does it have to be a polynomial? Aren't we approximating a continuous functions with polynomials, not a polynomials with continuous functions?
 
We're fine on (2), not fine on (1) here.
Think about how your proof is going to finish using the hypothesis.
 
Hm...
 
I'll think about it a bit later.
 
Sure!
2 mins ago, by Oskar Tegby
Why does it have to be a polynomial? Aren't we approximating a continuous functions with polynomials, not a polynomials with continuous functions?
 
6:29 PM
Never mind! I figured it out. I'm so thankful for all of your help, @TedShifrin. Tomorrow morning will feel so much better thanks to how much better prepared I am thanks to your help, professor.
 
man this music is good
 
6:50 PM
I see that and raise etc etc
 
7:30 PM
-3
Q: Given straws of length $\pi$ and $\\e$, measure $3$

NickI give this question to my 12 year old brother ever so often and we find he always forgets how it's done. And yes, it can be done. Does it require many prior assumptions? Be my guest and find out for yourself. Take it as a simple challenge to prove. You are given two straws. One measures $3.1415...

I don't want this deleted.
How do I save it?
I think it's a really neat question.
Like if you had a 2cm length and a 4 cm length, you can so easily measure 3cm, right?
 
7:55 PM
that guy has a strange value for $e$
 
@mercio Why don't you say directly to him?
 
I am lazy
 
No. You're coward.
 
the first comment is almost as good at pointing out that his value for $e$ is very strange
it also wouldn't improve the question at all to fix it
 
Anyone know how to plot a set in Geogebra or Wolfram Alpha?
 
8:02 PM
I don't know. with wolfram alpha I would try maybe giving a list of coordinates
 
merci @mercio
 
de rien
 
merc @merci
mer @merc
me @mer
 
aaagh
 
$x_{n+1}=trunc(x_n): x_0="mercio"$
leakynu @LeakyNun
 
8:17 PM
> I have no formal education in pure maths.

I was gifted at maths at school (a long time ago), virtually all of which I have now forgotten. Then I read mathematical economics, econometric methods and the theory of statistics under Professor Pesaran and others at Cambridge University. Most of which I have also forgotten.
then what do you r e m e m b e r?
 
@LeakyNun bits of my school maths come back to me as I use it
But the theory of statistics I didn't enjoy and I have never used since
and I have no desire to remember it
Just equations about 50 characters long of strings of matrices
@LeakyNun school was 30 years ago!
 
I see
 
What's up, chat?
 
Yo
 
8:33 PM
hi @Daminark
 
How's it going?
 
it's going well
 
@Daminark any ideas how to plot a set of complex numbers say in Wolfram alpha or Geogebra?
@Fargle hi
 
Heya @Daminark, @Robert, @Leaky
 
@Fargle hi
you know how to plot a set of complex numbers say in Wolfram alpha or Geogebra?
 
8:39 PM
hi @Gargle
 
Fargoyle
 
@RobertFrost what complex numbers?
 
I'm not sure, actually, other than just treating them as ordered pairs and asking those programs to plot the ordered pairs.
Granted, I'm not very familiar with Geogebra.
 
I have the function $f(x)=x^{(2\pi\cdot i/\log(2))-1}$ and I want to plot for a range of odd positive integers $x$
@LeakyNun ^^
 
I'm not terribly familiar with graphing, but try putting in Desmos, I've used it to graph functions online
 
8:43 PM
@Daminark ok will try. I know what the plot $x\in\Bbb R$ looks like but want to see the spacing of $x\in\Bbb N$
 
@LeakyNun nice job. you have to zoom in to see it!
 
just change 59 to 29
hi @TedShifrin
 
Rehi @Ted!
 
@Oskar: It seems you need to use the general Stone result. When you have all the functions vanishing at $0$, then the theorem proves that the closure is that set of all continuous functions vanishing at $0$. ...
hi Leaky, Demonark
 
8:45 PM
@Daminark go read my LCFT stuff in garbology :P
 
I will at some point soon but right now Princeton Review owns my soul
 
is that related to the calculus thing?
 
@LeakyNun can teh points easily be labelled with their integer?
 
Yup, it's a source specifically designed for the GRE subject test
 
We like a soul-less Demonark.
Not just calculus. All sorts of stuff.
 
8:48 PM
@RobertFrost I don't think so, but I hope this makes things easier
 
Yeah it's got a bunch, true, though I'm mostly focusing on the calc/multi/ODEs chapters
 
@LeakyNun thanks
 
Yeah, the algebra/analysis/topology/probability stuff you should be good with.
 
much
 
@JasperLoy you know what, Loy sounds very Chinese to me
 
8:50 PM
@LeakyNun Yes, that is correct.
 
really? :o
 
If only that were 50% of the test instead... shakes fist at ETS
 
well I can't connect it to any Chinese surname
 
@LeakyNun I am by ethnicity. It is Li in Mandarin, the Li in dawn or LiMing.
 
The issue, Demonark, is that people take the GREs having had all sorts of different sorts of math backgrounds. So they have to spread the stuff beyond calculus over all the various topics, including applied things that some people might not know and pure things that some people definitely don't know.
 
8:51 PM
then why is it Loy?
 
@LeakyNun It is so in the Hainan dialect.
 
:o
 
awards points to Jasper
 
But as everyone knows, I am from Antarctica.
 
I think that's related to Hokkien
 
8:52 PM
@AbdullahUYU I was able to show that if x = p/q for coprime p, q, then pq|(p+q)^3
 
@JasperLoy now deducts points
 
@JasperLoy indeed lôi is a reading of 黎 in Teochew that is used for surname
 
@micsthepick I don't understand. How does $x$ figure in here at all? Are you suggesting that $pq|(p+q)^3$ when $p,q$ are coprime?
 
@TedShifrin Haha. Oh after doing more research I think there is no graphical way to typr equations in pages. One needs to key in the latex himself unless he installs something called mathtype.
 
@TedShifrin I learnt Gram-Schmidt today :P
 
8:54 PM
@Jasper: Yes, I typed LaTeX into the equation editor yesterday. What do you mean by a graphical way to type?
 
@LeakyNun Yes, that is the correct character.
 
Good @Leaky. Now you can prove some interesting things about the topology of $GL(n)$.
 
@TedShifrin Point and click, like in Microsoft Word.
 
@TedShifrin also, how many equivalent statements does your version of invertible matrix theorem have? (yes, this is a competition)
 
@TedShifrin There is a question in the background.
 
8:55 PM
OH UGH @Jasper ... you mean like off a menu of selected symbols? I HATE that.
 
@TedShifrin the one in my notes has 18
 
@Leaky: Totally absurd waste of time.
 
@TedShifrin I mean, if one doesn't do that, one might as well just use latex all the way.
 
I'm not playing this game.
 
:(
lighten up
@TedShifrin such as?
 
8:56 PM
@LeakyNun I think I have seen only five or so, not 18.
 
supposedly
 
@Leaky: It deformation retracts to $O(n)$.
 
ah!
that is very interesting indeed
 
@Jasper: I'm fine with using LaTeX all the way.
 
does that not mean that p and q share the same unique prime factors?
 
8:57 PM
I remember the textbook I had in my linear algebra class a long time ago had a similarly long list of statements that are equivalent to invertibility. I don't necessarily like that style of presentation.
 
The linear algebra version is the $QR$ decomposition of nonsingular matrices, Leaky.
 
so QR is continuous?
 
Heya @Fargle !!! :)
 
@TedShifrin Yeah, you use it to type letters even. By the way, in case you didn't know, latex does have a letter document class, but it is seldom used.
 
indeed, Leaky.
 
8:58 PM
that is very interesting!
 
Howdy @Ted, how goes it?
 
I have my own, @Jasper. But I did originally start using the letter document class.
Hope you weren't too upset by my email, Fargle ...
 
@TedShifrin Then there is also the minimal document class that is used for troubleshooting.
 
lol, not at all
 
So, my professor didn't state it at the beginning and then go and prove it out or something but one day he did just kinda walk in and to get us talking he was like alright give me a bunch of characterizations of invertibility that we'll list on the board
To get us talking and also because he was about to start talking about eigenvalues
 
8:59 PM
Sure, I like that for a classroom discussion/game, Demonark. Just not for a textbook.
 
textbook is dead, what can I do
I'm revising things on my own
 
@LeakyNun See this; desmos.com/calculator/pwzbwjdf5n I added the even numbers. Now how do I plot a line on top between two numbers?
 
school starts on October
 
@LeakyNun Make the book come alive.
Use some spell from Harry Potter.
 
@RobertFrost 1. you haven't saved 2. what do you mean a line on top
 
9:00 PM
@JasperLoy I think that would require the use of the Book of the Dead Books.
 
So he wanted to have the stuff written on the board so that he could immediately talk about char poly, multiplicity, etc. For textbooks... Yeah probably not the best of ideas
 
i just mean a line between two points sorry
@LeakyNun I didn't save :(
 
@Jasper: You have a good answer for this?
 
@JasperLoy li e hiao gong min nam weh?
@Daminark I think the number of statements in the invertible matrix theorem is the hallmark of a successful book
 
@LeakyNun I guess I need an account to do that
 
9:01 PM
(don't be triggered Ted, I'm just joking)
@RobertFrost sure
 
Demonark: Did I tell you my GRE story about getting an integral of a 2-form over the unit sphere on my exam? The dopiest thing I ever did (because I was so used to teaching undergrads the classical way) was translate into $\vec F$ and take divergence ... rather than instantaneously taking $d$ of the 2-form. I laughed hard at myself after that one.
 
@LeakyNun Nope, I mostly only know the Mandarin dialect, not the other dialects.
 
@JasperLoy but you did understand my question lol
 
@Jasper: Be warned. Leaky gets extremely competitive/obnoxious at times.
 
9:02 PM
@LeakyNun Hence the word mostly, precisely speaking.
 
I think he knows me
 
Oh, I thought you mostly started living in here after Jasper disappeared the last time.
 
Don't worry I know everyone cos I am crazy.
 
And look at you now, he who bears the flag of moving frames in the face of a lot of people who don't seem to like it as much
 
If you are bored or need someone to talk to, just email me. My email is in my profile.
 
9:04 PM
@JasperLoy be warned. I get extremely competitive/obnoxious at times.
@RobertFrost what do you mean a line on top
 
No problem. I can handle all obnoxiousness.
 
also, the road not taken
 
And I also don't compete with anyone over anything.
 
@LeakyNun Just take two points and plot a line from one to the other. E.g. from f(3) to f(10)
 
MSE chat: We Might As Well Call It Levity StackExchange
 
9:06 PM
@RobertFrost still don't undersatnd
 
@Jasper bet I compete with fewer people over fewer things
 
@LeakyNun pick any two dots on this: desmos.com/calculator/yj8s3fzgjs and draw a stright line from one to the other
 
I can't just pick any two dots
this isn't an interactive graph
 
@ÍgjøgnumMeg lmao
 
Demonark: That's been true my whole mathematical life. But Chern, Griffiths, Bryant and their students were/are largely in the camp. :)
LOL @Fargle
 
9:07 PM
lolol hi @Daminark @Ted @Leaky etc.
 
hi @ÍgjøgnumMeg
 
Tag
 
I sure wish you had a short name/nickname we could type.
 
Hmm
@Igjo does this ping you?
 
9:08 PM
Yes it does okay perfect
 
oh no
will I be Igjo now
 
@LeakyNun Then draw a straight line from any n to any n+1
*every
 
@Ig
 
Did not
 
@Igj
 
9:08 PM
Igj works
lol
 
Okay you need at least 3 letters
 
Would I read that as something close to "Iggy"?
 
Actually speaking of moving frames, among probably hundreds of things in the "meaning to do at some point" file, I have considered trying DG once more. Let's say that even though I've done some stuff in the bootcamp, it's been a while and I struggled with that stuff even then
 
@Fargle however you like!
 
9:10 PM
@LeakyNun you beauty
 
What would you say is the best avenue for me to try and reapproach it?
 
@ÍgjøgnumMeg i'll just call you "through me"
 
How would I pronounce the whole thing, @Igj?
 
Demonark: I'll be happy to discuss it with you (as, I'm sure, will Eric) whenever you're interested.
 
@Fargle something like "uy-jugnon meh"
@Leaky go for it
rofl
 
9:11 PM
Let's save this discussion for after GRE :)
 
That's true
 
Thanks! I find it's easier to remember names if I can pronounce and spell them.
 
@Igjy, is this an actual name in some language?
 
[ʊiˈdʒœɡnʊn] [meː]
 
9:11 PM
me too, @Fargle, me too.
 
"through me" in Faroese @TedShifrin
 
whoa ... what's Faroese?
 
Spoken in the Faroe Islands, I would imagine.
 
I pronounce it ÍgjøgnumMeg
 
9:12 PM
@Ted no it's just a phrase I heard in a song that I liked so I put it into Faroese (which is my dream language) lol
 
it's a North Germanic language related to Norwegian
spoken in the Faroe Islands
 
Was at one point Norwegian land, I think?
 
@Daminark nise
 
oh wow ... we should really become the linguistics chat.
 
hahah
Faroese and Icelandic tend to be referred to as "Insular Scandinavian"
lol
 
9:14 PM
@TedShifrin I'm in total support of that idea
 
@Daminark I've been meaning to give DG another shot as well, now that I have free time.
...Then again, I, too, have to take the GRE.
 
Wait are you taking it in September?
 
Either Sept or Oct, I have to check
October
 
Ah, good luck
I'm doing it in September. I'll retake in October if September doesn't go as hoped but I'm sorta hoping it doesn't come to that since I won't really have much time to study then
 
I always encouraged my advisees to take it earlier so that they could retake once, if necessary, before graduate applications are due in December/January.
The problem, Demonark, is this: Do you find out the score on the advanced exam soon enough to sign up for the second test? I think the answer is no. The deadline for October comes very soon.
 
9:21 PM
@TedShifrin I just proved that $\operatorname{proj}_{U_1+U_2}(\vec v) = \operatorname{proj}_{U_1}(\vec v) + \operatorname{proj}_{U_2}(\vec v)$ when $U_1 \perp U_2$ as subspaces of $\Bbb R^n$ lol
 
Yeah that's the problem, I think I only have a week after taking the first test to sign up for the second
 
That's why I tried to get my kidlets to take it in the preceding spring for the first time.
 
So I'll either have to be confident that I did well enough in September (what does that usually entail anyway? 75th percentile?) or pre-emptively do October
 
Leaky, are you using the characterization of projection in terms of the subspace and its orthogonal complement, or are you using some matrix formula for projection?
I actually don't know about percentiles. That's very dependent on which schools you're aiming at. Harvard/MIT/Princeton want higher GRE scores than Georgia.
And it's very competitive because so many foreigners do better than US students, to be honest.
 
Yeah I was considering that. At the time I didn't feel it was worth it because my classes were real heavy and I thought I'd just burn 150 dollars and likely not do well enough to not retake anyway, though in hindsight I might have to pre-emptively burn $150 anyway in case I'm not sure it was a good idea
Gah
 
@Ted would you say it's reasonably common for people to take some time out before grad school, and does it seem like it has a negative effect on performance?
 
I've been looping this a day
@TedShifrin the more algebraic one, i.e. the former :P
 
@Igjy: It happens, but I wouldn't say it's reasonably common (in the US). People forget stuff quickly ....
@Leaky: A matrix formula is more algebraic.
The former is more geometric!
 
I see
 
@Ted that's kinda what I'm afraid of lol, I basically have to take 6 months out because I'm poor... hoping I don't end up forgetting too much
 
9:25 PM
But I have exercises in my book that ask students to use the definition to prove things, so I like that.
@Igjy: 6 months or a year aren't that big a deal at all. Several years is a bigger deal, I imagine.
 
well the latter requires an orthonormal basis right
or at least orthogonal
 
No, Leaky.
Not at all.
 
@Ted well that's the kind of reassurance I was looking for! lol
 
It's rather a cool idea, actually. If $A$ has columns giving a basis for the subspace, then $A(A^\top A)^{-1}A^\top$ gives projection onto the subspace. Prove it.
 
:o
I learn something new from you every minute
 
9:27 PM
Including while you're asleep! :0
 
yep
 
smacks Leaky and Demonark
 
ow
 
so I need to prove that $x^\top A (A^\top A)^{-1} A^\top x = x^\top x$
 
@LeakyNun Turns out you can put e.g. ${n} in the label and make dynamic labels as here: desmos.com/calculator/76fzd8hewo
 
9:30 PM
I'm also learning something new from you @RobertFrost
 
G'Night chat
 
@LeakyNun even the one legged man kicks ass sometimes
 
Whoa. No, @Leaky.
 
@TedShifrin right nvm
 
You need to show that $A(A^\top A)^{-1}A^\top x$ satisfies your definition for the projection of $x$ onto the subspace.
 
9:32 PM
I need to prove that $\langle Av, x - A(A^\top A)^{-1}A^\top x\rangle = 0$
 
@LeakyNun I need to plot the collatz graph on these numbers because then good things will happen
 
And, ultimately, it's cool to understand where this comes from.
That's half of what you need to prove. Admittedly, the other half is trivial.
 
$v^\top A^\top A (A^\top A)^{-1} A^\top x = v^\top A^\top x$
yeah ok proved
so where does this come from?
 
@ÍgjøgnumMeg Hey, me too, lol
 
@Fargle sleeping or taking time out? lol
 
9:36 PM
@Leaky: It comes the fact that the kernel of $A^\top$ is the orthogonal complement of the column space of $A$.
 
@ÍgjøgnumMeg Taking time out, haha. It is not my bedtime yet.
Sorry to keep you, and goodnight
 
@Fargle that's cool! Hope it all works out in the end, down with money!!!
 
Night, @Fargle :P
 
lol
Goodnight
 
@TedShifrin :|
 
9:37 PM
LOL
night, @Igjy.
 
I can smack back, you know.
 
Night @Ted :)
 
Such threats, @Fargle.
 
@TedShifrin sorry I still don't understand how that fact leads to that formula
 
Write $x=Au + w$ where $w\in V^\perp$.
Now use what I said.
 
9:41 PM
The column space of $A$ is $V$, so $w$ is in the kernel of $A^\top$, so $A^\top x = A^\top A u$
 
OK, go on.
 
$A^\top A$ is invertible (I don't actually know why), so $u = (A^\top A)^{-1} A^\top x$, so the projection is $Au$ which is $A (A^\top A)^{-1} A^\top x$
very interesting
 
Now what hypothesis did I make relating $A$ and $V$?
 
V = span(A)
 
GRR
 
9:44 PM
the columns of A form a basis of V
 
Okey dokey. So why does that make $A^\top A$ invertible? Maybe you can use one of your 18 equivalent reasons :P
 
If $A^\top A x = 0$, then $A x \in \ker (A^\top) = (\operatorname{im} A)^\top$, but $Ax \in \operatorname{im}(A)$ also, so $Ax = 0$.
Since the columns of $A$ are linearly independent, $x = 0$
 
There you go. Except you have a typo. You mean $\perp$ ...
 
indeed
 
OK, my lesson is over.
 
9:48 PM
thank you for your lesson :P
 
This stuff is actually applied to giving least squares solutions of inconsistent equations.
hi @Jake
 
I see
 
@TedShifrin hi
just the man I was looking for
 
hides quickly
 
I’ve been trying to understand matrices from the linear transformations. I think I get most things just not why matrix multiplication isn’t commutative. We haven’t done linear transformations or anything further at uni yet so I was wondering if you could give me a hand?
 
9:52 PM
@TedShifrin what is your favourite proof of JNF?
 
$f\circ g$ is usually not $g\circ f$, @JakeR. But you should be able to write down some very simple $2\times 2$ examples to demonstrate.
Module theory, of course, @Leaky.
 
what does the circle mean?
 
composition
 
@TedShifrin is that also the one you teach?
 
what does composition mean?
is that just a way of saying something acts on something else?
 
9:54 PM
No, I only have taught it a few times, Leaky. Not in my linear algebra courses.
 
Can anybody help me? I suspect I use the equations of structures, but I can not ... math.stackexchange.com/questions/2896776/…
 
@JakeRose: $\sin(x^2)$ is the composition $(f\circ g)(x)$ where $f(y) = \sin y$ and $g(x)=x^2$.
@JakeR: So notice that $(AB)x = A(Bx)$ whereas $(BA)x = B(Ax)$. So, yes, acting on something else.
@Mancala: I know all about structure equations, but I cannot decipher your question unless you give me the book. You'll have to provide all the notation. Your question is otherwise hopeless.
 
@JakeRose because moving your body forward and then rotating it by 90 degrees isn't the same as rotating it by 90 degrees and then moving your body forward
 
@Leaky: But moving your body forward is not a linear map.
 
oh nvm
p r o j e c t i v i z e :P
 
9:57 PM
LOL, ok.
 
@TedShifrin Ah, fine. ;|
 
@JakeR: Try $A=\begin{bmatrix} 0&1\\1&0\end{bmatrix}$. Try $B=\begin{bmatrix}1&3\\2&4\end{bmatrix}$. Compute $AB$ and $BA$. Notice what multiplying by $A$ first does and what multiplying by $A$ second does. :)
 

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