Hello @TedShifrin
Let $u(x)$ be harmonic in $\Omega$ and over an open smooth part of $\partial{\Omega}$ it holds that $u=\frac{\partial{u}}{\partial{\mathcal{v}}}=0$, $\mathcal{v}$ is unit external normal in $\partial{\Omega}$.
How can we show that $u(x) \equiv 0$ in $\Omega$ ? Could you give me an idea how we can show this?