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12:35 AM
@robjohn
@seaturtles !!!
Hello.
 
hello
 
What's up?
 
well
I must go for coffee , back in 15
 
ey yo
can some buddy help me understand continued fractions? i kno tha def'n and i am comfy with it n all. yet i still don't get what info about a number its continued fraction conveys
besides obvious ones like the ability to determine whether it is rational
 
12:58 AM
@PedroTamaroff yes?
 
@robjohn Still getting those daily downvotes.
=/
 
@PedroTamaroff oops.. I have to take my dog to the park... I will look when I get back. If I don't see anything, you should contact the community team. I'll be back in a bit.
 
rehi mr @pedro
hi @robjohn ... I just got some revenge downvotes, I do believe :P ... a few hours ago
 
@TedShifrin Hello.
So you won't be around July 28th to August the 8th?
 
I'll be back from CA August 1st.
 
1:01 AM
@TedShifrin we have a lot of that going around. For the most part, we have to bump these upstairs to the community team. I will take a look when I get back.
 
I don't recognize mr @seaturtles's new look.
Have a good walk with the dog, @robjohn :)
 
@TedShifrin What does that mean? Back in Georgia?
 
yes, @Pedro
 
Well, I'll be in NJ by that time, so I can go to Georgia, if you want.
 
oh, I thought you had ruled that out ... I was pondering flying up north, but I just have too much to do and too much traveling -- have to go to DC a month later.
 
1:05 AM
So... is that a good plan for you, that I buy a ticket and go there say August the 2nd? Or do you prefer some more slack time? I was thinking about staying three days or so.
 
@PedroTamaroff You realize NJ and GA are nowhere near each other, yes?
 
Heya @Mike
 
@MikeMiller Yeah, it is a 4h fly or something of the sort... not that much.
 
no, it's only 2.25 or so hours by plane ...
But airfares are totally ridiculous now. And I don't know if the train is much better.
 
I want to prove something cool and be famous
 
1:08 AM
Famous, mr @Com?
 
yeah thats why I do math
 
fame is overrated (speaking from experience)
 
I've done a bit of good math, but I'm totally NOT famous.
 
but it is not easy
 
@TedShifrin Do you think they'll simmer down a little, or should I buy the ticket now...?
 
1:09 AM
I dunno, @Pedro. The worse things get in the Middle East, the worse fuel prices will get. I honestly don't know.
 
@PedroTamaroff I didn't realize you could afford to take long distance flights on a whim :P
 
It's whimsy, @Mike.
I thought you were in NJ until August 20 or so, @Pedro.
 
yea send me sum money @PedroTamaroff
 
@MikeMiller On a whim? What do you mean? I've been saving money for this trip.
 
That sentence is perfectly valid, @Ted
 
1:10 AM
@TedShifrin I'm leaving on August 20.
I arrive on July 28th.
 
See, my memory is not totally shot :P
I know, @Mike ... I was editing for humor.
 
maybe Math needs to start over again. It was once easier to be famous I think, but now all the major foundational theorems are proven. If you can solve any new problem today, it seems it must be a very obscure, highly technical problem
 
@TedShifrin Ah, we won't have to fight about it then
 
We are no longer at the time of Archimedes and Euclid, @Com
Are you in a pugnacious mood again, @Mike? Just 'cuz you graduated?
@Mike: I saw someone else I've talked math with a bunch here (mostly through answers and comments) is starting his Ph.D. at UCLA in the fall (after masters at NYU).
 
Name?
 
1:13 AM
Oh oh, @AWertheim hath returneth.
@Mike: Eric Auld.
 
Hello, @TedShifrin!
 
@ComTruise just invent a new field
 
@TedShifrin No, I'm always in a fighting mood.
 
Um .... great.
 
@TedShifrin I'm pretty sure I recognize him from the visit day. If he's who I'm thinking, he was a cool guy.
 
1:15 AM
you are right, if I make up a new area, then I can prove the foundational theorems and be famous
 
We've mostly discussed multivariable analysis and geometry/topology stuff ...
Famous provided the area and the results are interesting, @Com
 
I don't understand the interest in being famous. Do math because it's interesting.
 
It is?!
 
@ComTruise yep, the kicker is that the new field needs to add insight to something mathematical that already exists
 
There are better ways to become famous...
 
1:16 AM
@MikeMiller wait, wtf?
 
I was so furious 5 hours ago ... The offender finally yanked his sketch of a solution of someone's takehome exam question.
 
@lolwut i don't understand wanting to do math for reasons of fame. is that rephrasing better?
 
@MikeMiller c gbe.poyrre
 
@TedShifrin Can we agree on something? =P
 
@Pedro: What do you want to agree on?
 
1:17 AM
Well, that person should not have posted their takehome problem here anyway
 
idgi, @lolwut
 
@TedShifrin On we meeting.
 
Of course, @Com, but that doesn't make it right.
 
@TedShifrin: were those downvotes reversed after all?
 
Oh, sure, @Pedro. I'd prefer some days to recuperate from CA ...
 
1:18 AM
@MikeMiller your foolishness makes me type in tongues
 
No, @AWertheim
 
@TedShifrin OK. We can do something like 4th to 7th.
 
Hmm, that's not cool. :(
 
I can afford the 10 downvotes, @AWertheim; it just pisses me off.
 
it seems like Graph Theory is still a hot field, but frankly I am just not interested in it
 
1:19 AM
Sure, it's not so much about the rep, it's just really childish and petty. Sad to see from a contributor whose posts I ordinarily very much enjoy.
 
Sure, @Pedro, that's fine. Communicate with me about times, though, because ATL rush hour traffic is horrendous, and it's 85 miles from my house to the airport.
 
@TedShifrin 85 MILES!!!!!!!!!!!!!
Shouldn't I choose a better arrival spot?
 
Well, @AWertheim, I'm just suspecting he did it because of the timing. But it could be totally unrelated. (Hmm.)
 
that's the size of a block in the us
 
There isn't one, @Pedro. The US is huge.
 
1:20 AM
a few more exclamation marks and that sentence might be 85 miles long, @PedroTamaroff
 
LOL
There used to be flights into Athens on US Air, but those stopped 10 years ago.
 
@TedShifrin Woah. OK. I'll try to give you all the info.
 
I have been to Athens, GA
small world
 
Oh yeah? @Com ... And you didn't come say hi?
 
hehe, it has been several years
 
1:22 AM
I've been here 33 years so far ...
But not planning on being here too much longer ...
 
you are professor at the university?
 
Yuppers.
 
@TedShifrin: where to next?
 
in what area?
 
I'll decide this summer, @AWertheim, but I'm seriously thinking of retiring to San Diego, where I have some very good friends.
@Com: Differential and complex differential geometry
 
1:23 AM
Ah, San Diego... lovely!
 
I'm tired of the South, to be honest ... although the whole country sucks rocks, if you ask me. ...
 
oh I was interested in diff. geometry at one time, working through general relativity. I did not make it as far as I wanted because it seemed to be heading into differential equations
 
Heh, I can understand that. I loved Duke, but the south in general... a different story, sometimes.
 
There's a lot of hard analysis/PDE in parts of diff geo, but that isn't the sort of stuff I did, @Com ...
Yup, @AWertheim. I spent 18 years in Berkeley and 10 in Boston, so after 34 in GA, I'm ready for a change :D
 
:) How were your years in Berkeley?
 
1:27 AM
it seemed like a beautiful theorem to me
 
@AWertheim: kidhood and then grad school ...
Yes, @Com: I actually have not read Brendle's proof.
That's very deep stuff ...
 
Happy times. It seems like a great place to be.
 
Things have changed a lot over the years, @AWertheim. I'll be back visiting the Bay Area for a week this trip, so I can report back to you.
 
Haha, I'll be waiting! :D
 
its one of those odd things... why 1/4? mysteries of the universe
 
1:31 AM
Because $\Bbb CP^n$ has sectional curvature between $1/4$ and $1$ (suitably renormalized). @Com
 
well
 
well?
 
1:46 AM
well well well
 
:-)
 
Well, fuck.
 
jumps down the well
 
1:49 AM
Do we need to resuscitate you, @Pedro?
 
Rules stop Peter from posting the third picture.
 
rules are meaningless
thats why i just ignore them
 
I don't have vertigo, but that picture gives me it.
 
it looks like there's a path on the mountain to the left
that is obscured from view
 
1:52 AM
@lolwut You do look both ways right?
 
Cagey, putting it at the back to sucker you into thinking that ...
That looks like Buenos Aires driving, @Pedro.
 
@PedroTamaroff i only look to da righ
 
its the car's fault
shoulda swerved left
 
@PedroTamaroff a shoe flies off, but also something white, not sure what that is
 
did that person live?
 
1:56 AM
I don't know.
 
@PedroTamaroff There was enough evidence that I've kicked the case upstairs.
 
@robjohn Mine too?
Thanksies.
 
@PedroTamaroff That was mistakenly sent to Ted
 
Ram
Hi all, is intersection of open affine set and closed subvariety is closed?
 
@PedroTamaroff I don't think they will reverse the downvotes, but they are keeping an eye on the people responsible. The thing is, that people are allowed to vote as they see fit, and it is hard to tell them they are acting inappropriately. However, some people have a downvote/upvote ratio that is greater than 1, when the average ratio is quite a bit smaller than 1.
 
2:01 AM
@robjohn Well, I do have a complaint to make, while we're at.
There is a group of people in the site that happens to have a "buddie upvoting" kind of mechanism, i.e. one in the group posts stuff and the others compulsively upvote and leave comments such as "+1 great answer" religiously. I don't know how far that goes or what other behaviour they endorse, but I don't like it at all.
 
Those people whose downvote/upvote ratio is greater than one must see this place as below their standards. I suggest they either leave, as this site obviously is not helping them, or leave helpful comments along with or in place of their downvotes to help improve the site.
@PedroTamaroff The moderators have been complaining about these people to the community team as well, but for the same reasons, it is hard for them to act. However, they do act on the directed voting that happens in these groups, but it does not seem to be enough.
 
@robjohn Have they thought of tougher measures?
To be honest, their contributions are usually on low level questions anyone can handle.
 
@PedroTamaroff I have noticed this as well.
 
@PedroTamaroff: worse yet, some of these contributions seem to be redundant, verging on plagiarism.
 
2:08 AM
@AWertheim I'd agree, but that might give away whom I am talking about :-)
 
@robjohn: I have a pretty good idea myself. :)
 
We all know who we're talking about!
 
It is dinner time... gotta go for a while... BBL
 
Have a nice dinner, @robjohn.
 
@DemCodeLines How's your calculus going?
 
2:17 AM
I hope he's seeing a dentist for it
 
@PedroTamaroff It's going...
 
@MikeMiller idgi
 
calculus = plaque
 
never knew dat
 
i think I need a break from math, and to then be somehow reinspired
 
2:22 AM
somehow
 
lim x -> pi/2 ((2sec x + 1)/(tan x))
how would i do it?
 
Try writing as 2 fractions
see what happens
 
don't. the world falls apart if you do
 
lim x -> pi/2 ((2sec x)/(tan x)) + lim x -> pi/2 ((1)/(tan x)) ?
 
yes now rewrite the trig functions
 
2:25 AM
i suck at trig
like really bad
and trig identities seem to be a serious weakness
 
just use the definition of sec and tan
 
1/sin and tan
 
nah
 
sec is 1/cos
tan is sin/cos
 
what's csc?
 
2:27 AM
1/sin
 
one of the meanings of $sin^{-1}$
 
csc, sec, cotan. so it's 1 over (sin, cos, tan) the appropriate position.
So csc = 1/sin
sec = 1/cos
cotan = 1/tan
 
yes. what does the limit look like after replacing sec and tan
 
(2(1) / cos x * (sin x / cos x)) + (cos x / sin x) ?
= ( 2 / sin x) + (cos x / sin x) ?
 
yes
now take limit as x to pi/2
 
2:32 AM
= (2 + cos x / sin x)
= 2 + 0 / 1 = 2
?
 
yes
done!
 
So it's not that hard after all. I really just need to know the identities and the unit circle.
 
yes sometimes the trick to finding limits is playing around with the function
 
that's about all there is to trig
 
@seaturtles Hey! I've heard there was a massive tornado in Nebraska. =/
 
2:37 AM
two
perfectly fine weather in omaha
 
Oh, OK. I was worried. =P
 
makes divide by zero joke
 
Here's another one:
 
fire away!
 
"Use analytical methods to evaluate the following limit."
lim x -> infinity (sqrt(x+2) - sqrt(x + 7))
 
2:46 AM
do you know the epsilon delta definition of limit?
 
Do i start with separating them again?
 
not sure what is meant by analytical methods
 
Well forget the "analytical part". How would you "evaluate that limit"?
 
multiply/divide by conjugate
 
@seaturtles You gotta speak to me as if I don't know anything, since...I don't know anything. :D
 
2:48 AM
that seems reasonable
 
@DemCodeLines how would you simplify 1/(1+sqrt(2)) ?
you would multiply and divide by the denominator's conjugate, 1-sqrt(2)
 
You should be able to graph the functions sqrt(x+2) and sqrt(x + 7). This will give you an ideal of what the differences approaches as x to infinity
 
what is the conjugate of sqrt(x+2)-sqrt(x+7) in this case?
 
sqrt(x+2) + sqrt(x+7)?
 
yes
so multiply/divide by that
the denominator is simply that sum
the numerator is sqrt(x+2)-sqrt(x+7) times sqrt(x+2)+sqrt(x+7)
what does that equal?
you should have the formula (a-b)(a+b)=a^2-b^2 ingrained in your skull permanently
 
2:53 AM
I did ((sqrt(x+2)-sqrt(x+7)) / 1) * ((sqrt(x+2) + sqrt(x+7))/(sqrt(x+2) + sqrt(x+7)))
and got 9 / (sqrt(x+2) + sqrt(x+7))
 
(x+2)-(x+7) is -5 not 9
but otherwise yes
what does 9/(blah) go to in the limit?
 
I thought (sqrt(x+2) - sqrt(x+7)) * (sqrt(x+2) + sqrt(x+7)) would take out the square roots and yield x + 2 - x + 7?
 
(x+2)-(x+7)
 
oh right
x + 2 - x - 7
so -5
how would i get the limit of (-5 / sqrt(x+2) + sqrt(x+7)) if x approached infinity?
 
-5 / (thing that goes to infinity), hmmm
 
3:00 AM
It's apparently 0.
But I don't get it
 
you don't get how dividing -5 by arbitrarily big numbers gets you arbitrarily close to 0?
or by "I don't get it" do you actually mean "how do I translate that into formal proofstuff"?
 
Yes, my brain, right now, is going step by step and proof by proof
 
you have to notice that the square root functions go to infinity as x does
 
But I guess it does make sense that as the denominator increases, the number approaches 0.
 
a blind person taking a hike step-by-step will not get to a destination very quickly, or even at all; you need to be able to see where you're going
 
3:04 AM
Here's another one. Ready?
A little more tricky.
lim x -> -8+ ((1/(x+8)) - (1/sqrt(x+8)))
 
common denominator maybe?
 
is that 1/x+8 or 1/(x+8)?
please use parentheses
 
you gotta play around with the functions a little
 
Sorry, corrected.
 
if f(x) diverges and g(x) converges to a nonzero constant, then f(x)g(x) diverges
ah, nevermind
if f(x) and g(x) both go to one of the two infinities then so does f(x)g(x)
factor out sqrt(x+8)
(that's just my thinking)
 
3:14 AM
you got it?
 
yes
 
@DemCodeLines
 
oh, mixed you up with him/her
slinks into corner
 
hehe its ok
 
No, didn't get it. The answer is infinity, but I don't know how it's solved.
 
3:17 AM
try this: (1/(x+8)) - (1/sqrt(x+8)) = (1/(x+8)) - (sqrt(x+8)/(x+8))
 
@DemCodeLines What are you trying to do?
 
shun the nonscroller
 
scrolls
 
do you see what to do now @DemCodeLines
 
Dam son that's a long scroll.
@DemCodeLines Do you have ChatJAX?
 
3:19 AM
what is scroll
 
not sure if nonnative of English or of internet
 
Not schur.
 
heh heh
 
@seaturtles I don't learn from my mistakes.
I should be studying combinatorics, not algebra. Heh.
But Lang is too cool.
 
@Com Truise scroll is to look further up the chat transcript.
 
3:22 AM
I just finished Algebra
Galois is a sick dude
 
I am doing a test review by the way.
So I have the option to do "Help me solve this"
 
did you get the last problem?
 
Well I hit on it and it made me arrive at the equation: (1 - sqrt(x+8))/(x+8)
The one that @ComTruise gave above.
 
yes use that
 
expression (equations equate things with equal signs)
 
3:24 AM
Then it me that 1 + sqrt(x+8) approaches 1 (1 + sqrt(-8 + 8) = 1) and (x+8) approaches infinity (or undefined since -8 + 8 = 0).
 
so the top goes to 1 and the bottom goes to 0 (from above). So the limit is ininity
 
So since the denominator approaches infinity, the limit as a whole is infinity.
 
@DemCodeLines In general, use that sqrt(a)-sqrt(b)= a-b/(sqrt(a)+sqrt(b))
 
no the demoninator goes to 0
you are letting x to 8+
 
Oh right, it goes to 0 and since it's undefined, the limit becomes infinite.
 
3:25 AM
no
the top is approaching positive constant 1
 
Where'd I go wrong?
 
and the denom is going to 0 from above
so the limit is infinity
 
1/0 -> infinity?
 
NOT THIS AGAIN.
 
do not think of it that way
this is a common problem for calculus students
 
3:27 AM
YES THIS AGAIN :-)
 
$2^2$
 
there is a little finesse required with limits
 
Works!
lim x->0 (sin x)/x
THat would be 0, I think.
 
which side is x going to 0 from?
 
3:32 AM
What is the derivative of $\sin x$ at $x=0$; @DemCodeLines?
 
ignore my comment
 
@DemCodeLines Yes.
There you go.
 
SO, undefined then is the answer.
 
undefined is never the answer on a limit problem
real number, +/- infinity, or does not exist
 
3:37 AM
What if the multiple choice is 1, 0 or undefined?
 
well on this problem it is 1
 
@DemCodeLines sin x / x = (sin x - sin 0)/(x - 0)
 
"Draw a graph to match the description given."
"F(x) has a negative derivative over (- infinity, 1) and (6,9) and a positive derivative over 1,6) and (9, infinity)."
How would I go about graphing this?
 
negative derivative corresp. to negative slope
 
replace "negative derivative" with "is going down" and "positive derivative" with "is going up"
 
3:45 AM
your calculus teacher should have made this clear
 
Sadly, my calculus teacher is awful. That's why I am here reviewing for my test with you guys.
Not that I wouldn't be here otherwise. I'd still be here, but I wouldn't be asking to teach me every single thing.
 
any super tough questions for me?
 
Find the intervals on which f is increasing and decreasing. Superimpose the graphs of f and f' to verify your work. f(x) = 10 - x^2
 
@ComTruise Suppose $A$ is a ring such that for every $n$ there exists a surjection $A\to \Bbb C[x_1,\ldots,x_n]$. Can $A$ be Noetherian?
@seaturtles $\uparrow$
@DemCodeLines Well, did you do it?
 
@PedroTamaroff I thought he was talking to me. So I gave him the question I was currently on.
 
3:54 AM
A Noetherian iff every submodule of A is finitely generated
 
Did you find the intervals?
 
don't know how to
 
oh you are calling the ring A
A Noetherian iff every ideal of A is finitely generated
 
A differentiable function is increasing on an interval if it's derivative is positive there, @DemCodeLines
@DemCodeLines Review your theorems =)
 
lol
 
3:55 AM
@ComTruise Ideals are the submodules of $A$, yes.
 
hmm
 
It's an open problem. Don't waste your time. =P
 
seriously?
 
LOL
I would have tried
to prove "no"
 

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