Say $f'(x)$ is continuous in an open set containing unit disk. Then is the derivative of the function $F(r) = \frac{1}{2 \pi i}\int_{|z|= r} \frac{f(z)}{z} dz $ zero for $0 < r \le 1$
This seems trivial for me since, $F(r) = a_0$ which comes from power series expansion of $f(z)$ and is independent of $r$ so, for $0< r< 1$ $F'(r) = 0$