Obviously they would not let you into a math course if you got A* in French, Art, Critical thinking and Politics

@Alizter You say that is obvious, but the 'obviously wrong' thing is EXACTLY how it works in the US

You can get by with taking as few/easy math courses as possible and take the most advanced courses in other subjects

:)

And then apply to Harvard, Yale, etc. and if you get in choose to Major in Math

@Jasper well, I went ot Duke so I don't either :-P

@anon You don't happen to have a copy of Gradshteyn and Ryzhik table of integrals handy do you? I think I spotted an error in mine.

nope

@anon okay, thanks anyway

@Jasper No one goes ot undergrad for the curriculum. It is about the name. Harvard and Yale are a big deal because of the prestige

@Jasper Well, in terms of getting a job it isn't superficial. But I see your point. I usually don't either.

Haha @Jasper I am currently at a top 10 engineering school in the US and the caliber of undergraduate students seems rather low for that ranking. I suppose it must be based on other things.

Hello everybody!

Hi blue square!

Hi!

If anybody knows, please help me (maybe with idea): how to show that series $\sum\limits_{n=1}^{\infty} \frac{\sin(n)}{3n^p-\sin(n)}$ is divergent for $0<p\leq\frac{1}{2}$

@skullpatrol good day!

@Nimza And a good day to you too :-)

:)

@Nimza Point a gun at it and ask (politely) if it is divergent.

Greetings

I've just offered a bounty of 500 points to math.stackexchange.com/questions/366266/finding-the-limits (in case you take some interest in it - - read carefully the bounty's requirements )

$$\Huge \text{A Bounty of 500 points!!!}$$

@skullpatrol :-)))

@Chris'ssis :D

@Chris'ssis What do you consider as "middle school knowledge"?

in your requirements...

@skullpatrol I'm very curious about the best solution MSE can provide when giving a bounty of 500 points. Well, that is just a note, it's not mandatory (it's about computing limits by using basic elements of geometry).

icic

@skullpatrol by the way, last week I created a nice question that can be computed by using basic elements of geometry. Maybe I'll post it later.

:D

@skullpatrol don't think too much of my requirements since I usually like crazy things ... (I suppose some people don't ... :-))

I like crazy things too...

@skullpatrol congratulations then ...! :-)

Chelsea lost :-(

How do you solve the following equation for complex z: |z+a|+|z-a|=2|c| where a and c are also complex, ?

@Psycho_pr I think it's an ellipse with foci $a$ and $-a$.

That makes sense as |z-a|=r is a circle

but is there a way I could see this algebraically?

You can express it as a quadratic form in $x$ and $y$ where $z=x+iy$.

I see... (I thought that would be the wrong way but I guess that's the way)

Thanks!

There may be a better way, but I don't see it. :)

I guess one thing would be good to do from the beginning: say that we could always rotate the plane so that a is real, so that at least you can work with one variable less, right?

That may help. I am not entirely sure how much it will ease computation though.