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8:01 PM
my favorite fairy tale is "red shoes" and rumplestilstiskin
 
What's your favorite nonfiction book?
 
user19161
I like "The road less travelled".
 
@κρανίοπεριπολία math books
 
user19161
The book that I want to see most now is...
 
8:05 PM
drum rooooll
 
user19161
Folland's "Advanced calculus"!
 
@κρανίοπεριπολία y u no ping me?
 
user19161
Because I have never seen a copy in any form in my entire life!
 
@JasperLoy when she writes to me yes
 
user19161
I guess I will need to either try to buy it or try to find it in a library.
 
8:06 PM
@Charlie Just getting lazy, sorry.
 
user19161
On the publisher's page one sees only the table of contents.
 
user19161
One cannot even see the first few pages.
 
user19161
There's no preview anywhere on the internet.
 
@JasperLoy I'm sure you can get it through inter-library loan pal
 
user19161
@κρανίοπεριπολία My country is a small one. =)))
 
user19161
8:08 PM
I might need to go to the university library and request access!
 
You can borrow it from another country.
 
user19161
Anyway, it's because Folland is an awesome author.
 
user19161
But his advanced calculus text has very bad reviews...
 
user19161
@dominic I have tried 9000 sites!!!
 
user19161
So what are you people's favourite non-fiction book?
 
8:10 PM
how expensive it is ?
 
@JasperLoy Have you tried the library?
 
user19161
@DominicMichaelis I dunno, anyway, never mind!
 
@jasper mac lane saunders category theory for working mathematicans
 
user19161
@κρανίοπεριπολία Not the university library, but I can request access.
 
category theory is so awesome
 
user19161
8:11 PM
@DominicMichaelis OMG, you are undergrad and you read category theory!
 
i only started but yes
 
user19161
Don't you prefer say set theory?
 
@JasperLoy WorldCat is really good too.
 
user19161
@κρανίοπεριπολία Hmm, OK.
 
8:14 PM
@jasper till now i only handled small categories, so categories interpreted unter set theory
 
user19161
@DominicMichaelis I have MacLane's Algebra!
 
user19161
Here comes Ramanujan!
 
i didn't have a algebra lecture till now, only linear algebra
 
@JasperLoy (removed)
 
user19161
@κρανίοπεριπολία Haha, that's you as well!
 
8:16 PM
No, I'm $\Huge\text{(Removed).}$
 
user19161
Ah, one is small, one is huge, lol.
 
Yip, size matters.
 
@HenningMakholm Was he swinging his club?
 
user19161
Guys, I found a green square!!!
 
8:18 PM
Hi there.
 
user19161
@MattN. Hey Matt!!!
 
How are you doing?
 
user19161
Matt must be as hot as ... Matt Damon, lol.
 
Oow
 
8:19 PM
@Charlie What's wrong?
 
@JasperLoy I'm sorry to disappoint, I'm just average looking.
 
user19161
@MattN. Average is hot!
 
: D
Since when?
 
user19161
Have you not heard of "the girl next door" or "the boy next door"? =)
 
@κρανίοπεριπολία nothing...
 
user19161
8:20 PM
(removed)
 
@JasperLoy No : )
 
$\Huge\text{(removed)}$
 
You like Matt Damon?
 
user19161
Yes, I think Matt Damon is hot.
 
i'm sexy and ONLY i know it
 
user19161
8:22 PM
(removed)
 
$\Huge\text{(removed)}$
 
@JasperLoy What do you think of Richard Armitage?
 
@κρανίοπεριπολία it's what I always say!
 
user19161
@MattN. Never heard of, I will look up now...
 
8:24 PM
@jasper peter facinelli is hot :P
 
I guess hotness of actors is directly related to roles they play. So I guess one cannot find someone hot just by looking at a picture.
 
user19161
@MattN. Average...
 
@κρανίοπεριπολία ?
 
@JasperLoy Then hot? A few lines before you said average = hot...
Need to google peter facinelli ...
 
user19161
@Charlie Average.
 
8:25 PM
@Charlie just pondering...
 
@κρανίοπεριπολία aah
 
@JasperLoy How do you like the actor in Fight Club? (the other one, not Brad Pitt)
 
@JasperLoy Roberto Bolle
 
user19161
@MattN. Average.
 
@JasperLoy Found it: Edward Norton it is.
Do you think anyone apart from Matt Damon is hot?
 
user19161
8:29 PM
@Charlie Hot.
 
@MattN. Matt Damon is probably hot because he was a good will.
 
user19161
@MattN. Brad Pitt, Channing Tatum, Taylor Lautner, Michael Copon, Justin Bieber.
 
@JasperLoy HE IS!
 
I think Gillian Anderson is hot.
 
user19161
@JayeshBadwaik Yes, that is my favourite character.
 
8:31 PM
@JasperLoy Philip Boy
 
user19161
@MattN. Ah now we have moved on to the actresses!
 
@MattN. I agree!!
 
user19161
Jessica Alba.
 
@MattN. I think Eva Mendes is
 
user19161
Jessica Biel.
 
user19161
8:32 PM
@Charlie Agree.
 
user19161
Scarlet Johanson.
 
@JasperLoy Heh, I only knew Pitt and Bieber, had to look up all the other ones.
 
@JasperLoy Charlize theron
 
Victoria Azarenka...
 
user19161
Jenna Dewan.
 
user19161
8:33 PM
Michell Monaghan, sorry for all the wrong spellings...
 
user19161
Tara Reid
 
@JasperLoy Alessandra Ambrosio, she is wonderful
 
user19161
Ashton Kutcher
 
SOFIA VERGARA
 
user19161
8:35 PM
Laura Ramsey
 
@JasperLoy The person who proved Ramsey's theorem? : )
 
user19161
Geezis, this chat has degenerated into this... =)
 
: )
 
Rarely if ever expressible as a ratio of integers.
 
@GitGud I'll have one Choice meal please with an extra set of Fraenkel Fries, a non-empty packet of tomato sauce, one regular coke and a separate double-chicken burger.
 
8:42 PM
xD
I'm failing to understand the double chicken burger thing.
 
@MattN. do you want coke in klein's bottle or a normal bottle?
 
Yes, because there is nothing to understand : )
@JayeshBadwaik Just a regular bottle. : )
@GitGud Better now? : )
 
@MattN. ^ ^
 
@MattN. :-)
 
Well well, I'll see you all later! : )
 
8:46 PM
Bye.
 
9:10 PM
@κρανίοπεριπολία ;)
 
@κρανίοπεριπολία O};)
 
@κρανίοπεριπολία yipyipyip
 
9:17 PM
@κρανίοπεριπολία Skull & Charlie
 
2 mins ago, by Charlie
@κρανίοπεριπολία yipyipyip
@Charlie same answer
 
Born to be wild
 
Born to be alive
@Charlie
 
@κρανίοπεριπολία yes, Skullpatrol
Hi @dominic
 
9:21 PM
@Charlie :-D
 
@κρανίοπεριπολία ;D
 
@Charlie I like it when you call me by the complete name of "skullpatrol."
 
@κρανίοπεριπολία ;) I like it whrn you call me Chucky
 
$$\Huge\text{Chucky}$$
 
i am proofreading a script i think i find to many errors
 
9:26 PM
@Charlie :D
 
$\huge \text {SKULLPATROL}$
2
 
@κρανίοπεριπολία :D
 
Can someone help me with this? math.stackexchange.com/questions/346808/…
 
9:50 PM
$$\Huge\text{Jonas Teuwen}$$
 
@JonasTeuwen hi, how are you??
@κρανίοπεριπολία Mr. Patrol
 
@Charlie Ms. or Miss Chucky?
 
@κρανίοπεριπολία miss, of course
 
@Charlie Ms. used to be very popular.
 
Hmm
Here is srta. Chucky
 
10:00 PM
@Charlie Srta. Chucky
2
 
Anyone here ever heard.of sequence almost constant?
@κρανίοπεριπολία Sr. Skullpatrol
 
@Charlie The Raiders original name was the Oakland Señors.
 
@peter hi, can you give me a tiny hand?
 
@Charlie I can go with medium-large.
But yes.
 
@κρανίοπεριπολία oh!!
 
10:07 PM
@anon Do you know what is the expression for T here? math.stackexchange.com/questions/346808/…
 
no, carpe failed to specify
 
It's impossible to find it without T right ?
@anon
 
duh
I mean, correct.
 
@anon lol
 
@PeterTamaroff I have to show that in a metric space with discrete metric every convergentsequence is "almost constant", I.e, there is x in X and n in N such that a_k=x forall k>n
 
10:10 PM
pick an epsilon smaller than 1; then there is an N such that |a_n-a_m|<epsilon<1 for each n,m>N. Is it possible for any of the terms past N to be distinct?
 
:-/
 
err, I am thinking of cauchy sequence. just pick epsilon<1 and then there will be an N for which |a_n-x|<epsilon<1 for each n>N, and hence a_n is constant past N.
 
@Charlie OK, your metric is $d(x,y)=1$ if $x\neq y$, $d(x,x)=0$.
Yes?
 
So I've been listening to [this](http://www.nyan.cat/) for 25+ minutes straight.
Am I insane?
 
If $x\to x_n$ this means that $d(x,x_n)\to 0$ in the reals.
@GitGud You will be in a few minutes.
 
10:20 PM
I'm just happier and happier.
 
that looks like an easter bunny
 
But $d(x,x_n)=1$ or $0$ for any $n$. Thus if $d(x,x_n)\to 0$, there exists an $N$ such that $d(x,x_n)=0$ for $n\geq N$, that is $x=x_n$ for $n\geq N$.
@Charlie
Remember that singletons are open in discrete spaces.
(actually, its an $\iff$)
@Charlie We good?
 
Must have lost the connection again.
 
10:35 PM
@skull I can read you.
 
@anon Man,.
 
3 hours ago, by Charlie
@κρανίοπεριπολία hi skull @jayesh I lost connection
 
@amWhy I think you're right.
 
@GitGud No problem...I've jumped in LOTS of times, without having fully understood (or missing) part of the question!!
 
@GitGud google translate?
 
10:39 PM
@skull ? What do you mean?
 
@GitGud You said you can read me.
 
You said you might have lost your connection. That can be interpreted as asking for someone to interact with you so you know you're still on-line.
 
@GitGud Ah, I was talking about Charlie leaving in the middle of Peter's explanation.
 
Oh.
 
Gotta go, see you all later...
 
10:46 PM
See you.
 
@κρανίοπεριπολία bye skull :)
@peter forgive me
 
@Charlie For what?
 
@PeterTamaroff not answering
 
@Charlie OK. You did get it, right?
 
10:53 PM
@PeterTamaroff yes, yes, thank you
 

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