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7:03 PM
@anon the solution is simple, print logo on both sides.
or have a running logo.
 
7:14 PM
@RustynYazdanpour, about Vieta root jumping, see a follow-up to your question, math.stackexchange.com/questions/288715/…
 
@bobdylan by $D_6$ do you mean the group with order 6, or order 12?
 
I see, he looked in three or four hours ago and went away
 
I have now... an expanded office. And it says 'professor' on the door.
 
Congrats Prof :-D
 
I only took it because the real inhabitant left for a while. As of that, I am a leech.
 
7:25 PM
OK leech :(
 
7:39 PM
Hi guys any good free books on combinatorics?
 
Gfology.
Plenty.
 
Can you recommend one?
 
combinatorics is huge
you should say which bit you want to learn
 
and at what level
 
@Khromonkey I just fuqing did.
 
7:52 PM
Gfology?
 
user19161
@Khromonkey What do you mean by free?
 
free as in beer or speech?
 
user19161
First, you know what I believe. Real men read real books.
 
As in beerware.
 
user19161
7:58 PM
Only paper books are real. PDF books are not real.
 
book=book
 
user19161
Second, you know what I always say about notes. They are not as good as real books.
 
user19161
So if you want to study something seriously, read a paper book. QED.
 
user19161
@Khromonkey I recommend Peter Cameron's Combinatorics, which is a real book.
 
@JasonBourne Hey
 
user19161
8:00 PM
@math101 Hey R.
 
Paper books are for amateurs. Real professionals use carved stone. More effort is required, so more care is made to ensure that what is inscribed is correct. Only then are you encountering a true learning environment.
4
None of this "technology" and "laser printing" and "heat binding" nonsense!
 
user19161
Of course, if you are doing research you need to read papers and journals, but that is another matter.
 
8:48 PM
@argon why did you choose "argon"?
 
@skullpatrol $\text{Aaron} \implies \text{Argon}$
It's also an awesome element
Why did you choose @skullpatrol?
 
user19161
@Argon !
 
@skullpatrol Oh :)
@JasonBourne Exams - DONE!
 
user19161
@Argon Fun, fun, fun, fun, HAHAHAHAHA
 
8:53 PM
@JasonBourne Bleh, they were not fun - but they are finished! :D
 
user19161
@Argon Looking forward to the weekend
 
@JasonBourne Yup! Except school starts again on Friday...
 
user19161
@Argon Hey we haven't done the song for a while, let's do it this Friday...
 
@JasonBourne :):)
 
@Argon This would make a good gravatar, no?
 
8:56 PM
@Khromonkey You might have found out in the meanwhile, but the book is called generatingfunctionology
 
@skullpatrol It's like mine, on an angle!
 
@Argon ...and the colors might stand out more :)
 
hmm
Maybe
 
especially the "Do not breathe" part...
 
hehehe
 
8:59 PM
hohoho
 
hihihi
 
hahaha
 
huhuhuhu
 
and sometimes hyhyhy
 
Very nice
 
9:01 PM
:)
 
9:20 PM
@Charlie Do you like this?
 
10:03 PM
whow, this chat is giving people thinking that math nerds have a strange kind of humor quite some support...
good evening gentlemen
 
hi
 
@user58512 hi
 
@draks..., I'm think what you wrote for $\varphi$ is the same as if we do $\mu * id$ (as it shold be)
 
@user58512 that sounds good, doesn't it?
@user58512 but I didn't check multiplicativity yet
 
it holds
 
10:10 PM
I was busy with this one math.stackexchange.com/q/290108/19341
@user58512 cool thanks
 
I want to see this complex stuff used to prove a theorem that ordinary one doesn't
it might not really have any use
 
@user58512 depends...wait...
ohh I already put the link in the comment math.stackexchange.com/questions/269997/…
but: which of the variants I propose would it be?
is $\mu^{\Bbb C}=0$ or $=1$?
...*fetching another beer and having a cigarette*...
 
Suppose I want to show that f(t, y) = e^(t - y) satisfies a Lipschitz condition on D = {(t, y): 0 <= t <= 1, -inf < y < inf}.

I want to show |f(t, y1) - f(t, y2)| <= L |y1 - y2|.

Do I just pick arbitrary values for t, y1, y2, and L? E.g. t = 1, y1 = 1, y2 = 0, so

|1 - e| <= L

and I can just say that this satisfies a Lipschitz condition for L = 2?
 
you need to show it holds for all values
 
For every t and y combination?
 
10:24 PM
yes
the order of quantifiers is this: exists L, forall t, y1, y2, ________
 
How can I do that?
 
I don't think you can, unless I'm mistaken that function isn't Lipschitz for any L
 
How can I show that it doesn't satisfy LC ever? I'm thinking 1 counterexample will not work?
 
Suppose it was Lipschitz for some L, then for all y, |e^y(1 - e)| <= L
 
Hi @Jason
 
10:31 PM
but that's a contradiction if you take y large enough
 
user19161
@draks... Hi! Where does the name draks come from?
 
@JasonBourne an abbreviation. Why?
or do you want an entymological answer?
 
user19161
@draks... Just wondering.
 
about what?
 
user19161
What draks means.
 
10:35 PM
@JasonBourne if you wonder about all the names around here, you should call yourself Alice Bourne...
 
user19161
@draks... HAHAHAHA, now I have to wonder what Alice means...
 
one pill makes you larger
 
user19161
It seems the account Math Gems is becoming active again.
 
I thought he's gone...
Hey do you think that this
$
\int_0^x \delta\left(\sin\pi\left(\frac{n\pm 1}4\right)\right)\pi'(n)dn
$
would work as a prime counting function for primes of the form $4n\pm 1$?
 
user19161
@draks... HAHA, I don't know any number theory other than gcd and lcm, etc.
 
user19161
10:42 PM
You know what is funny?
 
@draks... erm? - aren't all primes other than 2 of the form $4n\pm1$??
 
@JasonBourne tell me...
 
My ass on fire.
 
user19161
I loved number theory in high school but not anymore after that.
 
what are you interested in?
 
user19161
10:43 PM
@draks... Well, right now I don't really know. I am mostly interested in girls, HAHAHA.
 
@JonasTeuwen I can't stand to say: Tell this to your boy friend...
 
user19161
@draks... Jonas is straight.
 
I don't have one. Do you want to be my boyfriend?
 
sorry I'm already married
 
I won't tell her.
 
10:44 PM
hmmm
no
 
As the great Will said 'it is not cheating if you can't remember!'.
 
I'm not convinced
 
user19161
@JonasTeuwen The great Will Jagy? HAHAHA, I thought only I used the great anon!
 
@draks... Wait until you had me.
Err, never mind that.
I mean: my ass is on fire due to compression of the sciatic nerve.
 
Next life maybe
 
user19161
10:45 PM
Alright guys, slow down before we get flagged.
 
hey this is not russia
 
user19161
Russia is rather liberal actually.
 
really, they are trying to ban the rainbow flag
@JasonBourne where are you from?
 
That's because it is the US flag.
 
user19161
@draks... I prefer to keep that a secret.
 
10:47 PM
ok Mr bourne
 
user19161
I have many secrets. Some bros here know some of them.
 
Do you share a secret with Jonas, Jason?
hey thats a anagramm...
 
user19161
Yes, Jonas and I share many secrets.
 
no, I won't put that additional "l" there
hey can anyone help me with this math.stackexchange.com/q/290108/19341 ?
 
Yes.
@draks... I think so, yes.
 
10:50 PM
ok who is it? you?
 
Perhaps it is, but not now.
 
user19161
@draks... When Jonas says yes, he means no.
 
user19161
I think you can just wait a while for someone to answer you on main.
 
so what does it mean when he tries to hit on me?
 
user19161
Well, that's just for fun.
 
10:53 PM
@JasonBourne yes
 
I hit people for fun.
 
who doesn't?
 
user19161
9 more days to change my username. I am thinking what I should use next, hmm.
 
Do not make it Heinrich Himmler.
 
@JonasTeuwen why should he?
@JasonBourne try some special characters, see here meta.math.stackexchange.com/q/8338/19341
what about $\Bbb J^B$?
A hebrew name would quite be opposite to Heinrich...
 
11:12 PM
I need a beard.
 
oh I need a beer...
 
I am having one as we speak.
 
one for you..
 
Awesome.
 
@JonasTeuwen cheers
 
11:25 PM
Cheers.
 
@JasonBourne I just wondered why you think that russia is quite liberal these days...
 
11:45 PM
well good nite and good luck with your sciatic nerve, @jonas
and like this waiter once said: beer always helps $\color{green}{.}\!\color{goldenrod}{.}\!\color{red}{.}$
 
If you had enough of it it does!
 
you're still young
bye
 
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