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19:03
Seriously, I just got a downvote on math.stackexchange.com/a/191573/31475?
Or an up and a down at the same time
user19161
@EdGorcenski There are nutcases who downvote for strange reasons, like to change the order of answers or if it is not the shortest solution.
I think maybe it was more someone upvoting and then wanting to un-upvote
user19161
I have been the victim of the above downvotes many times.
user19161
I only downvote an answer if it is wrong or a question is it is unclear.
I am always downvoted
19:10
I was downvoted once, but regained my reputation by deleting the post.
I'm not deleting a post with 32 upvotes :D
user19161
I deleted a post once on ELU with 4 downvotes.
Don't you get a badge for that?
I've often thought about intentionally writing a wrong answer, so I can delete the post and get a badge.
user19161
It was a very weird interpretation of things, but not wrong to me. The downvoters just did not have the genius to understand my interpretation.
Does deleting a post give a badge?
19:12
I would, of course, never do such a thing. Often my stupidity is purely authentic.
@Matt Let $(X,\mathcal{A})$ be a measurable space and $\mu$ a measure thereupon. Then let $F(A)=\int_{A}f\mathrm{d}\mu$ -- where $A$ is a measurable set in $X$ and $f:X\to[0,\infty)$ is a measurable function -- is $\mu$-absolutely continuous. The inverse is provided by the Radon-Nikodym theorem. I think this is all how far one can get from there without any assumptions on $f$.
So close. I had -2 votes and I deleted it.
user19161
There was once I got two downvotes for a correct answer while the wrong answer got 10 upvotes.
user19161
After I edited it to bump it almost ten times, I finally got several upvotes.
user19161
I also downvoted the wrong answer myself.
user19161
19:15
Hello @aarthi. What brings you here today?
Hi Math!
I wanted to let you know that we're having a small chat-party!

The Assembly

You know those boring town council meetings you never attend? ...
Come visit if you like :D
user19161
What???
It's a fun time. There might be Gangnam Style.
:D
@Aarthi Hmm, that
is not a small party.
okay so it's a big party
but it's a nerd party!
2
the best kind of party
later we might even play settlers of catan or something
19:21
@Aarthi Oh good!
user19161
Hey @meand!
@JayeshBadwaik i aim to please. :)
@WillHunting Hello William!!!How have you been?
lol, William.
@GustavoBandeira quase levei um susto!
19:24
@MeAndMath ??
@ParthKohli why?
@GustavoBandeira boogie math
@MeAndMath =)
Mas foi um susto logarítmico ou um susto exponencial?
user19161
@MeAndMath Bad bad bad, 3 bros here know my secrets though, but I won't say more in this room. Anyway, I think I will change my username back next week.
@GustavoBandeira $e^x$
@WillHunting Change to a weirder name.
19:27
@WillHunting Am I one of them?
Like Potato lo Paco.
user19161
@JohnJunior Nope. If I did not email you some secret info, you are not.
@WillHunting stop it...
user19161
@MeAndMath Stop what?
@WillHunting with mistery (W)
19:28
@Will Stop breathing.
user19161
@MeAndMath mystery
@WillHunting :D
user19161
@MeAndMath Well, if you know what the mystery is, you will know why it is a secret...
@WillHunting c'mon...
19:29
@WillHunting Easy, just search the log!
user19161
@GustavoBandeira There is nothing there.
Of course there is. I'm the moderator, I can see secrets in chat.
Search the log, William.
user19161
It is a mystery, but it is not a comedy. Rather, it is a tragedy.
Search the logs, Bill.
19:30
C'mon, now search the logs!
user19161
Anyway, I will reveal my secrets to more bros over time if I feel like it.
user19161
I am thinking who is next on my list...
A comic tragedy?
user19161
No, a real tragedy. Trust me.
It can't be that bad.
19:32
@MeAndMath Eu tenho impressão de que ele que pescar na curiosidade. xD
user19161
@JohnJunior I think it is much worse than any of you can possibly imagine.
@GustavoBandeira é,isso aí..num é nada.
@WillHunting Don't try and tell me what I can and can not imagine.
No Na'vi language, please. @MeAnMath @GustavoBandeira
19:34
If people do not speak English here, I will flag them. I am serious!!
user19161
@GustavoBandeira Is that a song?
@ParthKohli Oel ngati kameie
Let's freak out!!!!!!Aqui tem um bando de louco!
@WillHunting Yep.
user19161
What language is that now?
Kanabuie shabora partogli.
19:36
lol, that is the real Na'vi language.
Kaburarti cachaçari si traveco pinto sosco!
user19161
I only know Eng well.
Same here
@GustavoBandeira XD
I know portuguese, english and spanish and I'm learning Deutsch.
@MeAndMath What about Klingon?
19:37
मुझे हिंदी भी आती है. :)
user19161
I should play a game with meandmath, like this. (M)
@GustavoBandeira I tried to learn elvish...
user19161
@MeAndMath Are you an elf?
Me and math: I know english, Javanese, Spanish, Japanese, Chinese and Akkadian!
@WillHunting yes.
19:38
@ParthKohli However did you type that?
user19161
@GustavoBandeira You sure?
@WillHunting Not much.
@GustavoBandeira Javanese? I thought the name of the language is Java. :P :P
user19161
@JayeshBadwaik That is the island.
19:39
@JayeshBadwaik Javanese - Is Java in Japanese... Learn things straight, dude...
@WillHunting Java is also a language.
user19161
@ParthKohli Or transposition.
user19161
@JayeshBadwaik I know, as well as coffee.
Transposition to the key of G# major.
user19161
Hey @johnjunior mind changing your name so that it does not get too confusing?
19:41
Yup, so, why should that language be not considered as the one you know?
"Is epsilon a hero, just because it is to the right of zero? We must fight for an enlightened calculus, where every epsilon has a delta to call their own!!.) ***Same for languages***
@WillHunting John Senior is on vacation so what's the confusion?
user19161
@JohnJunior He's gonna return!
I went to lunch today with a 2 friends, and I mentioned that I'm usually here at SE. One of the guys asked: "What's SE?" the other replied: "It's a meeting place for nerds" - I looked at him with fire in my eyes: "WTF?! SE IS A PLACE FOR HIPSTERS!"
@GustavoBandeira LOL
@WillHunting Maybe I'll leave then.
user19161
19:43
@JohnJunior No...
@JohnJunior Noooooooooooooooooo.
@GustavoBandeira today a number from Pernambuco called me...
@MeAndMath 9720 1797?
user19161
@GustavoBandeira Nerds can be hipsters.
user19161
@MeAndMath For?
19:44
@GustavoBandeira no
@WillHunting what?
@WillHunting Venn diagrams for nerds/hipsters?
user19161
@GustavoBandeira Is that your number?
@WillHunting Yep.
I guess you need area code.
@GustavoBandeira May be I will call you then.
+55 81 9720 1797
user19161
19:45
I will definitely not spend money on overseas calls. Emails will do
@GustavoBandeira give your adress,Id number,CPF...
@WillHunting @JayeshBadwaik I'm beginning to think that Matt is right:

$\Huge\text{This is the black hole of productivity}$
@MeAndMath What did the guy from Pernambuco told you?
user19161
@JohnJunior I am here only because I am not doing any serious stuff anyway.
@GustavoBandeira the call was rejected.
@WillHunting So help out here!
user19161
19:47
@MeAndMath If I can. I help out with the elementary problems!
@WillHunting listen
@JohnJunior It is. I have been trying to complete an exercise for past half an hour, have got nowhere. Must leave this place soon!!
@MeAndMath I guess you thought it was me. xD
user19161
@JayeshBadwaik You cannot leave a BLACK HOLE
@JayeshBadwaik The thing is you will not be able to do any serious stuff as long as you're here. @WillHunting
user19161
19:49
@JohnJunior No, for me it is the other way round like I said. If I have serious stuff to do, I won't be here!
@JohnJunior Yup, so I am now going, see you guys later.
$f$ is a function defined in an interval $I$.Suppose that exists $M>0$ and $\alpha>1$ such that:
$$|f(y)-f(x)|\leq M|x-y|^\alpha$$
$\forall x,y\in I$.Show $f$ is constant.
@GustavoBandeira yes...
@WillHunting So go and try and do some serious stuff and see how long you last.
user19161
19:52
@JohnJunior Hehe, maybe that's why you said you were in rehab...
@WillHunting And I didn't last...
@WillHunting Lookout!
@GustavoBandeira NOOOOOSSSSSAAAAAAAA
@GustavoBandeira Full access to Hunting's secrets.
user19161
@MeAndMath Do you know the result that a differentiable function on an interval with zero derivative is constant?
@WillHunting yes
user19161
19:56
@MeAndMath Now just divide both sides by the modulus of x-y and work from there.
@WillHunting are you sure?
user19161
@MeAndMath Well, you try it first.
user19161
Fix the y and let x go to y.
@WillHunting I believe that after you watch "A Brief History of Time" your "tragedy" will seem insignificant.
user19161
@JohnJunior Nope, I think there are different tragedies and one can't really compare.
user19161
19:59
You can't compare a man who lost an arm with one who lost a leg and say which is worse.
@WillHunting I'm not saying that.
John is a tragedy destroyer - He wants to deny tragedies for fun.
user19161
@JohnJunior Just an example. :-)
@WillHunting You have to watch it to understand what I mean :)
user19161
So I always try not to trivialize others' problems.
user19161
20:00
@JohnJunior OK OK.
@GustavoBandeira Can't stop looking to that question
user19161
@meandmath Have you done that question?
@MeAndMath A do simplify?
@GustavoBandeira y
Hoje eu vi uma do cara perguntando o que era base 18.
20:02
@WillHunting I'm trying,Mr.Hunting.
@GustavoBandeira I don't want to destroy tragedies I just want to put them in perspective.
Pra eu que achava que sabia de nada...
user19161
@MeAndMath OK, like I said, fix the y and let x go to y after dividing both sides by mod of x-y.
@JohnJunior Master Yoda taught us to never put tragedies in perspective, in his wise words: Eggplant for no four of you.
@GustavoBandeira I'm not sure if there is a translated version of the movie but it is nothing to joke about.
user19161
20:06
@MeAndMath Also, try to apply squeeze theorem and the fact that something goes to 0 iff its modulus goes to 0.
@WillHunting What would the dimension of the vector space $\mathbb R^{\mathbb N}$ be?
I have dimension defined based on the base of a vector space, but I don't know if the base for that space is finite,
And I only know about finitely generated vector spaces.
user19161
@PeterTamaroff Is that the space of all real sequences?
@WillHunting Yes.
user19161
@PeterTamaroff I think the dimension would be the cardinality of the natural numbers then, countably infinite.
@WillHunting Yes, I think so too.
user19161
20:12
A basis would be (1,0,0,...), (0,1,0,...),...
@WillHunting But then, let $S=\{(u_n):u_{n+2}=u_{n+1}+u_n\}$
This is a subspace of $\bf R^N$
I want to find it's dimension.
user19161
@PeterTamaroff Proper subspaces need not have lower dimension in the case of infinite-dimensional vector spaces I think.
user19161
However in the case of finite-dimensional vector spaces that is true.
@WillHunting I just think it has the same cardinality as $\bf R^N$
user19161
@PeterTamaroff That would be so if and only if it is also infinite-dimensional.
20:14
Each sequence is uniquely determined by the pair $(u_1,u_2)$
user19161
Countably infinite is the smallest infinity.
@MeAndMath Cê achou que eu tinha ligado - não era eu - mas você recusou a ligação. Porque cê me odeia? =/
@GustavoBandeira I don't hate you!My phone rejects unknown numbers.But I realized it wasn't you because you could'nt possibly know my number.But I don't hate you.I don't hate anyone.
You hate me. =/
Everybody does 8-(.
20:19
@GustavoBandeira I don't.Trust me
@JonasTeuwen Hi,Jonas.You suddenly appear...
You're no good
@MeAndMath Yes. Whenever the chat is about hostilites against me...
@GustavoBandeira No,no,no no!
@GustavoBandeira não sou hostil contigo.
Não, ele. xD
@GustavoBandeira Is that you... is that you in the picture?
You look like a drug lord.
user19161
@JonasTeuwen Yes.
20:22
A killing machine.
Creep.
@JonasTeuwen Yep. That's me. =)
I find Jonas very curious..
Cool!
@MeAndMath Why?
Drug lord FTW!
user19161
@meandmath Specifically, divide both sides by mod of x-y, bound the left side by 0, apply squeeze theorem to conclude that the middle term goes to 0 as x goes to a fixed y, then the derivative is 0 everywhere, then the function is constant. QED.
20:24
@WillHunting I would say "Trivial. QED.".
Kinda.
user19161
@JonasTeuwen I am surprised I can do it after not doing math for 9000 years!
I have not done it in two months or so.
@JonasTeuwen Well,You claim to be stupid,when it's obvious,you are not.It's rare among mathematicians that kind of behaviour.And I think you are often Ironic...sometimes,too much.It's an intersting type of humour...But I don't see your expression or hear your voice...can't say.
My expression is very neutral. Some people call me a creep because of that.
user19161
@MeAndMath Jonas is too sexy to be heard and seen!
2
20:25
But I am stupid.
@JonasTeuwen Hey, dawg.
Sup nigga.
Wigga.
@JonasTeuwen Need some help with $\bf R^N$
user19161
Oh no!
Is it's dimesion $\aleph_0$?
20:26
Jonas is sexy:everyone agrees on that.But about stupidity,I don't..
user19161
@PeterTamaroff its
@MeAndMath So there are things to rectify!
user19161
These days I just talk about Jonas and I get stars, how wonderful!
@Gustavo Eu não te odeio,tá?
@JonasTeuwen Now, what is the dimesion of $S=\{(u_n)\in {\bf R^N}:u_{n+2}=u_{n+1}+u_n\; ;\;\forall n\}$?
user19161
20:29
@peter That subspace is the set of all Fibonacci sequences eh?
@MeAndMath Odeia sim. =;
@WillHunting Kinda.
@PeterTamaroff It does not make sense.
@GustavoBandeira Não,não odeio.Que o faz pensar que sim?Se o odiasse não o levaria em cionta,não conversaria contigo...
Is it even a subspace?
20:29
@JonasTeuwen What doesn't make sense?
@JonasTeuwen It is.
I've checked it.
user19161
@JonasTeuwen Just abuse of notation. Fibonacci.
Oh.
So you want to know $0$ or $1$?
${\bf 0}\in S$
$v,w\in S\implies v+w=S$
$v\in S\implies \lambda v\in S$
Other things are not possible unless you are considering covering dimension or small or large inductive dimension or crazy topological stuff.
@JonasTeuwen Huh? I want to nkow what is it's dimesion.
20:31
Oh, wait, it is a space of sequences.
user19161
We are now just asking about the dimension of Fibonacci space.
So first question finite or infinite.
Caaardinalityyyy.
user19161
So let's find a basis!
Let's just grab a beer.
Wadafuq.
@WillHunting I think it has dimesion 2!
user19161
20:32
@PeterTamaroff Why?
@GustavoBandeira Oras!
$\langle \phi^n ,\phi^{-n}\rangle =S$
user19161
@PeterTamaroff What is phi?
@WillHunting $1.618....$
@MeAndMath =)
20:33
The golden rrratio.
@PeterTamaroff isn't 1,618
user19161
@PeterTamaroff I don't know what that is. I know nothing about Fibonacci!
user19161
Come on, we are talking about sequences here!
@WillHunting That is bad and you should feel bad.
@JonasTeuwen é isso aí!
Vamos falar port pra enxer o saco...
20:37
Bleh, I have to go off to give a tennis class.
And the weather is horrible
Bye, silly people.
@PeterTamaroff Bye,Pedro!
XD
Naquele dia cê falou: "Brasileiro gosta de zuar" - eu subentendi que cê não gostava. xD
Vamos zuar!
não como os outros...
depende o que é zuar...
Jonas is so parsimonious with words...
As armas e os barões assinalados,
Que da ocidental praia Lusitana,
Por mares nunca de antes navegados,
Passaram ainda além da Taprobana,
Em perigos e guerras esforçados,
Mais do que prometia a força humana,
E entre gente remota edificaram
Novo Reino, que tanto sublimaram;
20:43
De onde?
OS LUSÍADAS
"Depende do que é zuar" - Apelou pra redefinição. xD
user19161
@PeterTamaroff I think it is dim 2. Take (1,1,2,3,...) and (1,2,3,5,...). They are linearly independent. For any Fibonacci sequence (a,b,a+b,a+2b,...) set A+B=a and A+2B=b so that B=b-a and A=2a-b. Then A(1,1,2,3,...)+B(1,2,3,5,...)=(a,b,a+b,a+2b,...)
@GustavoBandeira DAQUI A POUCO VÃO NOS BANIR XD
user19161
@jonas I solved Peter's problem, see above.
user19161
20:46
I also solved meandmath's problem, yay!
@WillHunting How does that prove it is not larger than 2?
@MeAndMath Eu num vô receber um e-mail pedindo pra voltar.
@MeAndMath What?
user19161
@JonasTeuwen Hmm, read the proof carefully...
@JonasTeuwen what what?
20:47
@WillHunting Hmm.
@MeAndMath Yeah.
@GustavoBandeira eu peço pra você voltar e você pede para mim! :D
@JonasTeuwen that you are parsimonious?
user19161
@JonasTeuwen The trick is, the first two numbers determine a Fib sequence!
@MeAndMath Eu chamo todo mundo pra minha sala lá. Aí eu dou ban e kicko todo mund, só de zuá.
@GustavoBandeira hehehehe
user19161
@meand Do you understand the solution I gave you?
20:48
@MeAndMath Ye.
@WillHunting Think I did...
@JonasTeuwen you are economic with words
@WillHunting Ah, nice. Sleepy.
@MeAndMath I don't like economics.
Give me all the money and then go fy.
Or so 8-)))).
you're niggard with words
you talk too little
I was asked is there a standard definition of triangle or are there several? I have only one geometry paper where triangle is defined one way.
user19161
I think you guys should post the question on the main site next time after we solve it here so that I can earn some rep!
20:51
@WillHunting MWAHAHAHA
@MeAndMath I talk too little? Sometimes I talk to much. I am never good 8-(((.
user19161
@JaakkoSeppälä How is it defined?
@JonasTeuwen you talk too much but in other meaning
Do explain you mysterious woman!
@JonasTeuwen I am not mysterious
20:53
@MeAndMath Mai tu qué porque qué, né? XD
Yes you are. You are. Tell me! When do I talk too much. Too much!!!
user19161
M for Marilyn, M for mysterious!
@WillHunting If I remember correctly, simply take three point that are not in the same line
user19161
J for Jonas, J for Jasper, J for joker, J for jester.
@JonasTeuwen you are like an arrow..
20:54
@MeAndMath Explain.
I am not that thin :s.
Stop mocking my physique.
user19161
@JaakkoSeppälä And then join them pairwise?
For I am the Hulk (in blue).
@JonasTeuwen a little accurate.you say too little but hit the target
I have to check
@WillHunting you will never see my face.Mwahahaha
user19161
20:55
@JaakkoSeppälä I am no expert in geometry, but I think that's the only definition I would think of.
user19161
@MeAndMath Er, I did not say I want to see it, mwahaha.
@MeAndMath Cool!!
@GustavoBandeira que que eu quero?
@MeAndMath Que será?!
@GustavoBandeira o quê???
20:58
@MeAndMath Djivinha.
@GustavoBandeira eu não tenho bola de cristal...
Porra, isso é óbvio....
@GustavoBandeira o que,cacete
@WillHunting I think that is the only definition but on the other hand, there are different geometries like hyperbolic, Euclid so I was just wondering.
@MeAndMath Tarefa de casa: Faça uma redação de 30 linhas sobre o que você acha que deve ser.
user19161
20:59
@JaakkoSeppälä Ah, maybe you can post on the main site then. I know nothing :-)

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