Mathematics - 2012-12-09 (page 1 of 7)

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Argon

00:00

@leo Not that good... :)

leo

hola @Charlie

Argon

@PeterTamaroff Eu posso falar espanhol na internet ...

Limitless

@Argon That is a nice question.

Charlie

@leo hola, que tal?

Argon

@Charlie MMARILIAAAAAAAAAAAAAAAAAAA

Charlie

00:01

@Argon AAROONNNNNNNNN

Peter Tamaroff

@Argon Eee?

Argon

GOOOOOOOOOOOOOOOOOOOOOOOOOOOL!

Old John

Must sleep - g'night all

Argon

@OldJohn Good night!

Old John

@Argon bye

Charlie

00:02

@Argon WASSUP? HOW'S YOURDAY?

leo

@Charlie about to take some coffee

Peter Tamaroff

@leo Ok, I'm uploading it.

leo

:-)

Argon

@Charlie GOOD :)

Charlie

@leo :D

@Argon awesome!

Argon

00:02

@PeterTamaroff Yo puedo hablar español en Internet

Charlie

@Argon did you see my mail???

Argon

@Charlie Yup :)

leo

@Charlie do you like futebol?

@Argon google.translate?

Argon

@leo Yep

Good night all!

Charlie

@leo no

@Argon :D

leo

00:04

@Argon gnite!

Argon

traductor Google

@leo Buenas noches

leo

@Argon que descanses!

Peter Tamaroff

@Argon OK, ahi las tengo

Charlie

@Argon i'l annoy you for the next eight days :P

Peter Tamaroff

@leo

Charlie

00:10

@Argon can i ask you something?

leo

@PeterTamaroff vamo a ver

Charlie

@PeterTamaroff Nice calligraphy

leo

@PeterTamaroff me parece bien.

en esas pruebas siempre es bueno fijar el $\epsilon$

al principio

Peter Tamaroff

@leo Je, OK.

leo

digamos al inicio uno dice sea $\epsilon\gt 0$ y sigue la prueba

desde luego que se entiende lo que vos querés decir. Solo lo digo porque una vez en un examen escribí algo como la prueba que hiciste y me bajaron puntos por eso

Peter Tamaroff

00:19

@leo Ma bah! En serio? Ni que el epsilon sea tan concreto...

leo

@PeterTamaroff, pero no se. Depnde de que tan estricto sea el profe. Habrá que preguntarle a @MarianoSuárez-Alvarez =)

Peter Tamaroff

@leo Ah! Hace un rato que no hablo con @Mariano

leo

@PeterTamaroff si claro. Aquí por lo menos al inicio, los profes son muy estrictos con los formalismos

luego hay mas libertad

:-)

Peter Tamaroff

@leo Eso me parece bien.

Pero siento que soy bastante riguroso... creo.

user57925

hello

Dylan Sabulsky

00:32

sup

user57925

bored

Dylan Sabulsky

do some math

user57925

I'm not sure what to do

user57925

I was trying to prove if a set has associative operation and forall x, exists y, xyx = x we have a group

user57925

but I didn't see how

peoplepower

00:36

You need uniqueness.

For all $x$, there exists a unique $y$ such that $xyx=x$.

user57925

oh that helps a lot!!!

peoplepower

For instance the multiplication on $\mathbb{Z}_2\times\mathbb{Z}_2$ would be an easy counterexample.

leo

@PeterTamaroff si. Eso es bueno. Permite evitar "falsas" pruebas

@peoplepower or $\{0,1\}$ with multiplication =)

Limitless

@sunflower We had a question just like that recently.

peoplepower

00:52

@leo Touche.

MJD

Bon soir.

BenjaLim

Hey guys

Who knows if deRham cohomology is the same as singular cohomology?

leo

heyo

BenjaLim

@leo hey

There is this question here: math.stackexchange.com/questions/254123/…

I answered it using singular cohomology

I'm wandering if deRham cohomology is the same as singular cohomology

@MJD hey

do you know if singular and de Rham cohomology are the same?

I have only studied the former

leo

@BenjaLim Im two chapters before of de Rham cohomology so I cant help you

but Im almost there :-)

BenjaLim

00:58

@leo what book are you using?

leo

@BenjaLim An introduction to differentiable manifolds by William M. Boothby

BenjaLim

@leo too advanced for me :D

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