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7:14 PM
@Khromonkey he doesn't look like..HE IS A BOSS!
Oh @jayesh is wearing a hat!!! Cute cute cute!
 
Well of course he was a boss, Its just that mathematicians sometimes have difficulties conveying that truth.
 
@Khromonkey hehe maybe...
@khromo you're from mexico right?
 
yes
Have you been in mexico? @Charlie
 
@Khromonkey have you. ever watched "chavo del ocho"?
 
of course
 
7:19 PM
@Khromonkey no no
 
everyone in mexico has watched el chavo del ocho
 
@Khromonkey i watch chapulin colorado and chavo ever since i was born!!!
 
Really? How?
 
@Khromonkey it is still a succes in my country!!!!since 1987
 
what country are you from?
 
7:22 PM
@Khromonkey guess!
@Khromonkey brazil
 
You didnt give me enough time
I was making a serious investigation
I have been to brazil, its awesome. Im saving up to go to the world cup
 
@Khromonkey oh really? Where did you go?
 
Sao Paulo, Rio de Janeiro, Porto Alegre and Torres
and florianopolis
 
@Khromonkey oh nice!!! What did you do here? If I'm not being too nosy...
 
I went to a wedding
The hotels in sao paulo are really cool
Its the cooles hotel ive ever been to
it is shaped like a boat
 
7:29 PM
@Khromonkey indeed
 
I also went to liberdade
 
@Khromonkey it's a really nice place!!!!
 
Also to a cathedral that had a star ponting to north south east and west
 
@Khromonkey da sé?
 
yes
I went when I was 10 so I dont remember all that well
 
7:32 PM
@Khromonkey my favorite cathedral is São Bento
 
I didnt go there
I went to a town square that was supposed to be very important. It has a big bell which tourists can ring
 
@Khromonkey it is awesome! On weekends there's gregorian chant!
 
Gregorian chant is awesome
My math teacher goes to monasteries when he wants to concentrate
 
@Khromonkey yes, amazing
@Khromonkey you're still in school?
 
yes, Im in 11th grade
 
7:37 PM
@Khromonkey hmm
 
Hey all, in the equation x^2 + 8x + 7 = 0, for example, there are 3 x's. The resulting graph would be a parobola, and therefore 2 of the x's fall on the x-intercept. Which 2 x's in the equation fall on the x intercept, and what does the other x represent? It's not as clear as the linear equations where b represented the y-intercept and the m represented the slope. In this quadratic equation, I would like to know what the 3 xs represent.
 
what do you mean there are 3 x's?
 
You dont mesn roots do you? Because it only has two
 
x^2 = x*x
or do all the x's represent the same value?
That quadratic equation is the combination of two linear equations
the linear equations make sense to be straight lines
Im just wondering what causes that quadratic to be a parabola and how to understand each of its segments
specifically the x^2 what does that cause on the graph?
 
Ok, what do you mean the combination of two linear equations?
 
7:46 PM
for example: x^2 + 5x + 6 = (x + 2)(x + 3)
left is quadratic and right is two linear equations
 
where 1 is the slope for each of them and 2 and 3 are the y-intercepts
and if you were to graph them, you would get a straight line
and so its easy to understand what each part of the linear equation represents
 
yes
 
so now I would like to understand what each part of that quadratic equation represents in reference to a graph
 
ok so the general equation of a linear equation is y=mx+b
where m is the slope and b is the y intercept
the general equation for a quadratic equation is y=ax²+bx+c
do you understand this notation?
 
7:49 PM
yes
 
Lets start with the simplest: c c is the y intercept
a is the second simplest: a tells you if the parabola opens upwards or downwards and how wide it is.
for example if a is negative the parabola will open down
like a bridge
or an arch
Do you know a little bit of calculus?
 
little bit
 
hi people can someone help me to prove that $$\forall x>0\quad (1-\frac { 1 }{ x } )\sqrt [ 3 ]{ { x }^{ 2 }-2x+2 } \quad \le \quad x-1$$
 
@pourjour !!!
 
@Charlie hi charlie!!
 
7:54 PM
@pourjour how are you?
 
@Charlie fine and u?
 
So in the equation what does the x^2 and bx represent?
 
@pourjour good, good!
 
@Charlie the Christmas!!
 
@pourjour yes yes!!!:)))
 
7:56 PM
:D
$\forall x>0\quad (1-\frac { 1 }{ x } )\sqrt [ 3 ]{ { x }^{ 2 }-2x+2 } \quad \le \quad x-1$
 
@pourjour im on my mobile...
 
@Charlie wow so u're not at home?
 
if you differentiate ax²+bx+c you will get 2ax+b. To obtain the vertex you use that the derivative must be 0 in a maximum or minimum. Therefore you set 2ax+b=0 to get x=-b/2a. so the vertex is located in x=-b/2a
 
@pourjour no, not at my place
 
@Charlie so, what are u doing right now?:)
 
user19161
8:00 PM
@Khromonkey That looks like Jayesh!
 
@JasperLoy what does?
 
@pourjour talking to you
 
user19161
@Khromonkey You must use the left arrow.
 
user19161
@Charlie Hey M.
 
@Charlie hhhh :D
 
8:01 PM
@skull heeeeeeeyyy!
 
@JasperLoy What do you mean i must use the left arrow?
 
@Charlie Wazzup?
 
@Charlie when are u going to celebrate Christmas?
 
@JasperLoy hey jas jasper jasper!!!!!!!!!!!
 
user19161
@Khromonkey Well, you use the right arrow to reply and the left arrow to link backwards. Hover your mouse over the line and you will see...
 
8:02 PM
@skullpatrol everything fine!! You?
 
user19161
Oh man, they should have these arrows in the chat FAQ.
 
@pourjour tomorrow at night
 
@Charlie Fine thanks :)
 
user19161
Or they should pay me to conduct a how to use chat arrows once a week...
 
@skullpatrol awesome! Long time no see!
 
8:03 PM
Ohh you're saying ramanujan looks like jayesh!
 
user19161
@Khromonkey Did you just wake up?
 
@Charlie yep ;)
 
@Charlie nice!!!
@JasperLoy hhhh
 
@Khromonkey but actually doesnt look that much, no...
 
No, The problem is I fell asleep too late
 
8:05 PM
@Khromonkey are u talking about the inequality?
 
what inequalilty?
 
user19161
Do people search questions before posting?
 
user19161
The reference requests are getting silly.
 
user19161
Every now and then someone comes and asks what is a good book on XXX?
 
user19161
Then YYY will answer ZZZ.
 
8:06 PM
$\forall x>0\quad (1-\frac { 1 }{ x } )\sqrt [ 3 ]{ { x }^{ 2 }-2x+2 } \quad \le \quad x-1$
 
user19161
A few days later the same question again...
 
That would be me, sorry
 
@robjohn any idea about this (sorry for disturbing u)
 
But in all honesty sometimes the questions dont exist on the main page
Allthough if you cant find the question you should ask it yourself
on the main page
I mean as you pointed out it is a very common question @JasperLoy
 
@skullpatrol thats
 
8:10 PM
 
@skullpatrol that's why i wanted yoy to make that mail...unless of course you don't wanna talk away from the chat...
 
Can you help me with an exercise in number theory?
 
user19161
@Khromonkey Then he is nuts.
 
why is p always the largest prime that devides (p-1)!+1?
 
@skullpatrol :) hehehe
 
8:12 PM
any help people?
 
the fact p divides (p-1)!+1 is wilsons theorem
 
@Khromonkey don't think that is true
 
user19161
My knowledge of number theory is limited to gcd and lcm, lol.
 
sorry: smallest
 
Ok people enjoy Christmas !
 
8:14 PM
better!
well - Wilson says that $p$ really is a factor, and any smaller prime gives a remainder of 1
 
@Khromonkey Do you follow my 1-line proof?
 
yes
 
0
Q: Currious property of monotonic functions

EthanIf f(x) is continuous and monontonic on the interval $[1,\infty]$, and $f'(x)\leq\frac{1}{x}$ on the interval $[1,\infty]$, is $$\lim_{n \rightarrow \infty} \frac{1}{nf(n)}\sum_{k=1}^n f(k)=1$$ This is by no means a theorem also, its just a guess I made after expeirmenting with sums of the n...

 
user19161
@OldJohn HAHAHAHAHA
 
8:16 PM
If you know that fact it is obvious
 
what fact? Wilson?
 
yes
 
user19161
@Ethan Speaking of which, you haven't accepted my answer on that question. =)
 
Oh - don't you know that yet?
 
where did you post the answer
Re-post it their
 
8:17 PM
*there
 
there
what ever
 
I mean as long as you understand what It is I am saying, no information was lost, in the communication
 
I know the following about wilson: p| (p-1)!+1
He proved this using the stellated ngons
@OldJohn
 
@Khromonkey that is all you need for my 1-line proof
 
user19161
8:19 PM
Is there an Old John's theorem on primes?
 
Im an idiot
i got it
what is wrong with me?
 
@JasperLoy No - only an old john theorem on asymptotic values of fine continuous functions :)
 
@Khromonkey nothing is wrong...it happens
 
thanks anyways
 
user19161
@OldJohn Ah, that potential theory thing!
 
8:21 PM
@JasperLoy yep :)
 
My brain is more valuable by its calories than by its intellectual worth
 
user19161
I feel like answering all the reference request questions here, since I know the titles of over 9000 books!
 
@Khromonkey I think that you could equally deduce Wilson's theorem from your result about the smallest prime factor - so proving your result without using Wilson is probably as hard as proving Wilson's theorem
 
user19161
But the reason why I don't answer them is because I don't know which book to recommend the asker, since there are over 9000!
 
I have 45 math books
 
8:23 PM
@JasperLoy The other day, for the first time ever, I quoted something in an answer from page 1 of a book ... that must be a rarity, as books almost always spend the first few pages reminding readers of stuff they ought to know
 
I am like the math library for my frined
friends
have you read diestels book in graph theory?
 
user19161
@OldJohn Page 1 usually has many words and few symbols.
 
unless its diestels graph theory
 
user19161
@Khromonkey That's a standard text.
 
I read a little of it in the library
the first page is like super condensed
 
8:25 PM
@JasperLoy yep - or just a list of symbols they are going to use - my quote is here
 
user19161
@Khromonkey Do you know what is the most condensed book I have come across???
 
user19161
It is...
 
not yet
 
user19161
Federer's Geometric Measure Theory!
 
user19161
HAHAHAHAHAHAHA
 
user19161
8:27 PM
When you see that book you will die!
 
how am i supposed to read that laugh?
 
user19161
It is so condensed you will burst out laughing when you see it.
 
@JasperLoy "Basic Number Theory" is even worse than Federer
 
At first glance I read it like it was super evil and accompanied by bachs toccata in D
 
user19161
I intend to write like Federer in future.
 
user19161
8:29 PM
@OldJohn Yes, a very misleading title!
 
@JasperLoy Serre's "A Course in Arithmetic" is also a bit misleading - but is more in the way of a joke, I think
 
user19161
@Khromonkey Check out Federer too.
 
user19161
@Khromonkey Hahahaha, you know nothing about me yet!
 
8:33 PM
@Khromonkey i was thinking about that too ...
 
user19161
My favourite tennis star is...
 
user19161
Nadal!
 
@JasperLoy hey jas have you seen Aaron???
 
user19161
@Charlie He went to Florida.
 
@ Nadal is great but he is very injured
 
user19161
8:36 PM
@Khromonkey Like me, my soul is injured...
 
Why?
 
user19161
That is my secret...
 
guys i cant stay too long but i have to share this wonderful song with you
 
@JasperLoy I KNOW!!!!he told me that somedays ago...but he appeared here once and he doesn't answers my mails... maybe he doesn't have internet now...
 
user19161
@Charlie Yeah, no hurry. He's probably chatting up some girl on the beaches of Florida. =)
 
user19161
8:39 PM
@MSEoris I think I have seen this before.
 
@MSEoris Sublime, marvelous, simply breathtaking!
 
indeed, its perfect nerd humor :) i love it
 
user19161
I'm sorry, I think nerd humour is not funny!!!
 
user19161
That's why it's funny!!!
 
@JasperLoy yeah maybe. he's a nice boy :)
 
8:41 PM
there are certainly many layers of interpretations, but even without the humor the puns alone make it wonderful
 
user19161
The thing I find weird about some questions here is: their proofs can be found in many textbooks, why ask here???
 
I live in a developing country @JasperLoy
 
@JasperLoy laziness?
 
Instead of libraries we have telenovelas
 
user19161
@Khromonkey I thought you said you were from the US?
 
8:44 PM
Im from mexico
 
user19161
@Khromonkey Ah OK.
 
user19161
Anyway, some countries can have very tall buildings but be very primitive otherwise...
 
I said I wanted to go to college in usa
We have tall buildings
 
user19161
So, don't judge a country by its buildings...
 
we just dont have libraries
 
8:45 PM
@JasperLoy textbooks are expensive (too) many times.
 
user19161
Some universities may look very beautiful, but have shit lecturers and shit syllabuses.
 
@Khromonkey true that. infact apart from my university library, I have never gone to any other library ever.
@Charlie Hi!
 
@Khromonkey mexican telenovelas are famous here too
 
user19161
@JayeshBadwaik Therefore, library.
 
@JayeshBadwaik hi!!!
 
8:47 PM
There is a pretty big library in my school, it has books on measure theory, algebraic number theory and it even has some journals on super advanced stuff
 
user19161
Gee, this Marvis guy types so fast...
 
However the people who run it are nuts
 
user19161
@Khromonkey Are you in a university now?
 
There is not a single book on topology
 
@JayeshBadwaik :*
 
user19161
@Khromonkey If you are in high school, the library there should not have these books.
 
It also has high school
 
user19161
Probably the librarian doesn't know the level of the books and thought they were elementary!
 
I go to a building with high school and university
 
user19161
OIC.
 
user19161
8:49 PM
Sometimes people mistake "Algebra" for x+x=2x.
4
 
They have books on manifold theory but not a single rigurous book in calculus
 
@JasperLoy yes, but dude, my university is one of the 25 good libraries in the whole of india? with the access restricted to around 100,000 students and some university staff every year? number of libraries are too less.
 
unless you consider stewart or calculus for dummies rigorous
 
@jayesh
 
@Charlie wassup?
 
user19161
8:50 PM
@JayeshBadwaik too few, not too less.
 
user19161
@Khromonkey No way!
 
If I want to go to a public library with math books I have to drive one hour.
 
user19161
@khro Just ask me for book recommendations of any topic!
 
@JayeshBadwaik I'm good! You? You've been talking to someone...
:P
 
Besides, my math teachers are all like businesspeople
 
8:52 PM
@Charlie yes, I was nervous. :P
 
user19161
Most of the math teachers I have come across don't really understand the math they teach.
 
@JasperLoy I am getting into an edit war on this - someone keeps trying to delete the first "converges!
 
Half of the time is spent on: we are great investors we take inniciative
 
@JayeshBadwaik oh! Why?
Haha
 
my friend had to explain to the teacher that a graph of a vertical line was not a function from x to y
 
user19161
8:54 PM
@OldJohn I am thinking of other possibilities. If two people edit at the same time the greater edit will override the lesser one, but this does not seem the case here.
 
He had to teach him the vertical line test
 
@JasperLoy Yeah - I think I am right in saying that the sentence needs the word converges twice :)
 
user19161
@OldJohn Yes, this is grade 1 English!
 
user19161
@Khromonkey Most of education is a waste of time.
 
I have your back @OldJohn
 
user19161
8:57 PM
They put 16 year olds in schools and teach then how to solve quadratic equations when they should be having fun instead, lol.
 
@Khromonkey Thank you!
 
no problem
 
Is what I'm asking in this question sufficiently clear? In particular, is it clear why Robert Israel's answer isn't really what I'm looking for?
 
I have to go guys
 
user19161
They try to justify why quadratic equations are impt, not knowing that most of these kids will never use one in their life.
 
8:58 PM
yes
Well see you later guys
@OldJohn thanks for your help in the wilson problem
 
@Khromonkey No problem!
Just noticed that condensation problem is a duplicate - I will vote to close ...
Hi @WillJagy
 
@JasperLoy what if a 16 year old thinks solving quadratic is fun?
 
user19161
@JayeshBadwaik Ah I know someone would start a whole debate on this. I am tired, I need to sleep. Over and out!
 
@JasperLoy g'night!
 
Random question, for anyone who feels like answering it: How did you first find out about math stack exchange?
 
9:06 PM
@MikeSpivey I first found MSE by visiting MO and seeing people being sent in the direction of MSE
 
@OldJohn That was the same for me. Did/do you spend much time on MO?
 
@MikeSpivey Not plucked up courage to ask any questions there yet :)
But I keep an eye on it
 
@OldJohn I understand the feeling. :)
 
@MikeSpivey :)
 
@MikeSpivey I found stackoverflow first, and about six months later, did I get to MSE.
 
9:10 PM
@JayeshBadwaik Are you a programmer?
 
@MikeSpivey No, electronics engineer. But I was programming then (simulation code), and a lot of really good answers on google search seemed to be present on stackoverflow.
 
@JayeshBadwaik I spent the spring working for an investment firm, where I did a lot of coding in Matlab. I found a lot of good answers to my Matlab questions on stack overflow as well.
 
interesting. for me it was c++.
 
9:44 PM
@OldJohn Alright. Why did Mourinho really bench Casillas yesterday? Real Madrid are now completely and utterly fucked.
 
@WillJagy I don't know, I'm afraid - not enough time in my day to follow all the football I would like, unfortunately
@WillJagy Did the attachment finally arrive?
 
@JayeshBadwaik what are u most great project in c++?
 
@OldJohn, yes, the other page from Pommeranian. Really good book. I looked up the octonions, that strange integer matrix problem works for any vector length in dimension 2,4,8, and Jones and Pall manged to drop from dimension 4 to 3 when the length is an integer. So, maybe, 8 can drop to 7,6,5, but may be a shitload of work.
 
@WillJagy but by "Jagy's theorem" we know it fails for $n^2$ for $n=3, 5, \dots$ :)
 
10:01 PM
@OldJohn, exactly so. There are some famous problems in integer quadratic forms which are true up to some dimension and then false. The best known is that, up to dimension 7, if a positive symmetric and integral matrix has determinant 1, it is integrally equivalent to the identity, that is can be written as P P' where P is integral and P' its transpose. But in dimension 8 we suddenly get E_8, see Gram matrix at math.rwth-aachen.de/~Gabriele.Nebe/LATTICES/E8.html
 
Oi @ian !!
 
@Charlie Oi!
 
@IanMateus e aí?
 
@Charlie tô bem, como vai ser o teu natal?
 
@IanMateus como sempre :P
 
10:07 PM
@Charlie como é? heh
 
Good grief! there is a "Catalogue of Lattices"!!
Always been fascinated by how things change as we increase the dimension ... [like this one](http://math.stackexchange.com/a/258558/32441) - interesting (but purely coincidental, I guess) that things with spheres change at 9 dimensions too ...
 
Yes, Gabriele Nebe is a big name in quadratic forms. The main tradition is in Germany, I think it is fair to say that.
 
@WillJagy Carrying the torch lit by gauss and some others around that time :)
160,000 lattices in their database - that is insane ...
 
@IanMateus a gente se reúne, come :P troca presentes, essas coisas
 
You were spot on with your suggestion of lacunary series in that old answer :)
 
10:19 PM
Lacunary series? I would never say that in public, I was brought up properly.
 
@WillJagy I apologise profusely ... and promise never to use such a foul name for a variable in a C++ program ... :)
 
@OldJohn, I'm glad you have seen reason. I think words such as smegma, spooge, and so on, have no place in polite discourse. What old answer did you mean? Or, hmmm, there may be a joke i have entirely failed to understand. Or maybe a reference to Charlie and Ian Mateus, who are conversing in some invented language
 
@WillJagy it's PORTUGUESE
 
@Charlie, well, you may be telling the truth. In that case, you tell me why Jose Mourinho benched Iker Cassilas yesterday against Malaga.
 
10:35 PM
@WillJagy I don't like soccer
 
@WillJagy It was in a comment to this question where you used the dreaded word ... I win!
 
Hello
 
hello
@Justin wassup?
 
@OldJohn A touch, I do confess it! I fear I breathe my last.
 
@WillJagy I promise not to reveal your lapse to anyone ... other than the chatters present here ...
... and the readers of MSE who actually read comments ...
@WillJagy so ... you are a number theorist who delves into analysis sometimes, and I am an analyst (of sorts) who likes to delve into number theory - are we anti-matter versions of each other???
 
10:45 PM
@OldJohn, I'm not supposed to speak any more, being officially dead. I see why you expected I would recall that comment, it is part of the Pommeranian question we had been discussing. Let's see, the complex analysis bit was a sequence of questions on MO about solving f(f(x)) = g(x) for a fixed function g(x), near a fixed point g(a) = a. The short version is that f(x) is almost never holomorphic, or defineable, around a.
 
@WillJagy That sounds interesting and actually no longer surprises me - a bit like the fact that almost all continuous curves in $\mathbb{C}$ are actually non-smooth - like brownian motion
well - ok - it does surprise me a bit ...
 
@OldJohn, for the quick version see mathoverflow.net/questions/45608/… with a fair percentage of published (and responsible) background at zakuski.utsa.edu/~jagy/other.html It is an interesting topic that has attracted any number of irresponsible blog posts
 
@WillJagy It looks extremely interesting - but I think I need to stop myself form thinking I should get too involved in it, having struggled to read Carleson and Gamelin's book on complex dynamics. There are too many fascinating areas of maths to look into - can I ask for another whole lifetime to learn?
 
11:00 PM
@OldJohn you said everything john...
 
@Charlie I did???
@Charlie ah - "another whole lifetime to learn"? a quote from a Joan Baez song, I think :)
 
@OldJohn, you may ask. Anyway, it is a pretty trivial and very small part of dynamics. The whole story is a trick due to Jean Ecalle in his dissertation, approximately 1970, which he was rude enough to write in French. The way he does it almost always gives a term involving log(z-a) so is defined on a sector.
 
@WillJagy Do you have a handy reference for deriving a parametrised solution of $a^3=b^2+c^2$ using gaussian integers? - I am sure it must be elementary, but had too much whisky tonight to do it :)
 
hi
i've been doing some tedious exercises
what's this kind of thing called?
 
11:16 PM
Abstract nonsense? (aka category theory)
 
@OldJohn, I am not so sure a parametri(sz)ed solution is easy. I can tell you that there are solutions for a given a if and only if, for any (positive) prime q == 3 mod 4, then v_q(a) is even, meaning the exponent of q in the prime factori(sz)ation of a is even. If so, all solutions can be produced using the factori(sz)ation. Parameters, maybe, maybe not.
 
@OldJohn: is there some way to make it less tedious?
it seems like i'm just shuffling symbols around
and searching for domains/codomains that "match up"
 
@wj32 There is a cure ... take up analysis :)
 
i have even less motivation when i'm studying analysis :(
 
@wj32 I gave up on algebra after spending most of a day chasing elements round diagrams in a five-lemma situation, and realising I was never going to win
 
11:19 PM
ok what i meant was, is there some way to make sense of what i'm doing
 
It was too much like wack-a-mole
 
right now it seems like black magic
it always seems to magically work out in the end
 
@wj32 Sorry - I am being facetious - I should let someone who knows answer. I guess the best I could say is "sleep on it" it will probably look better tomorrow ...
 
ok thanks, i might try asking on the main site
 
@WillJagy I think this works: $a=m^3-3m n^2$, $b=3m^2n-n^3$, $c=m^2+n^2$, and I am sure it can be obtained by looking at factorisations in Gaussian integers - but getting confused
@wj32 Probably a good idea - if you can phrase it into a good question, it should get some attention from people who are not as drunk as me :)
 
11:26 PM
@OldJohn, give me a minute. Just remember that your "a" must be the sum of two squares.
@OldJohn, you were close. If you change letters to now write a^2 + b^2 = c^3, one set of solutions is a = u^3 - 3 u v^2, b = u^2 v + v^3; c = u^2 + v^2. These are by no means all solutions, although it does identify all possible "c".
 
@WillJagy should your expression for $b$ have a minus sign instead of a plus?
 
@OldJohn, sorry. One method gives a = u^3 + u v^2, b = u^2 v + v^3, c = u^2 + v^2. The other one is yours, a = u^3 - 3 u v^2, b = 3 u^2 v - v^3, c = u^2 + v^2.
 
11:41 PM
@WillJagy Thanks, Will - I will look at it again tomorrow, when I hope to have a clearer paleolithic mind :)
@WillJagy Oh - have you seen how to get LaTeX working in this chatroom?
 
@OldJohn, yes, those give two families. However, the number of different representations for a given c = u^2 + v^2, and for that matter such c^3, increases depending on the number of distinct prime factors p == 1 mod 4. An explicit value is known. the exponents on the other prime factors do not increase the number of expressions.
 
@WillJagy Tricky little suckers, these diophantine equations!
 
@OldJohn, no, but I see on the right column there is a post by anon about Latex support for chat, on 18 December
@OldJohn, do you want all solutions to a^2 + b^2 = c^3? I have my doubts about a single formula.
 
@WillJagy There is some strange process (I did it once) - you drag something to the "bookmark bar" in Chrome or Firefox and when you click on it, then all the LaTeX in the chat becomes readable - you only have to click the "thing" once per session - there are some instructions in anon's link, I think
 
@OldJohn, if I've got to I will make a Latex pdf and email you that. As far as chat, I want to keep my Latex virginity.
 
11:50 PM
@WillJagy No - I am not desperate for a formula for all solutions - what is really bothering me is that I can't work out how to derive my particular parametrisation using Gaussian integers - it must be something easy, since all the bits look like parts of the expansion of something like $(x+iy)^3$
I think I should resign myself to the fact that I am going to achieve nothing useful this side of Christmas :)
 
@OldJohn, if N(z) = z bar(z) is the squared magnitude, then N(z^3) = (N(z))^3. Take z = x + y i
 
@WillJagy Yep - I got that far OK ...
 

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