@robjohn All simple proofs are non-intuitive. :-|. I think I grasp the outline of the proof, but I don't have enough machinery to get to the bottom of it.
@cassandra0 Hmm. There was a time when I was bad at inequalities too. Then I got introduced to Mr. Holder and the grand daddy aand all was good in the world.
@robjohn Ahh found. I searched for "robjohn determinant \lambda" :P
In the following paper http://www.math.ucsd.edu/~ronspubs/74_01_van_der_waerden.pdf,
just in the first paragraph the author defines what $l$-equivalence for two m-tuples $\in [0,l]^m$ means. Can somebody please give me a more precise definition of what he means? I am not even sure what $[0,l]^m$ ...
@RajeshD Ahh, there is already an acronym for that.. Nice. :-) Not yet. I am dying to see it though. Hopefully, when the rush in theatres reduces a little bit?
hi all, anything special about a polynomial where for every complex root there is a conjugate other than that it factors into (x^2+ax+b)(x^2+cx+d)... for real a,b,c,d...?
Van der Waerden's theorem is a theorem in the branch of mathematics called Ramsey theory. Van der Waerden's theorem states that for any given positive integers r and k, there is some number N such that if the integers {1, 2, ..., N} are colored, each with one of r different colors, then there are at least k integers in arithmetic progression all of the same color. The least such N is the Van der Waerden number W(r, k). It is named after the Dutch mathematician B. L. van der Waerden.
For example, when r = 2, you have two colors, say red and blue. W(2, 3) is bigger than 8, because you...
@cassandra0 correct, by the fundamental theorem of finitely generated abelian groups, it suffices to compute $\hom(\Bbb Z^n,\Bbb Z)$, which is quite easy to do.
note that for G an abelian group, hom(G,G)=End(G) is not just an abelian group under pointwise addition, it is also a ring under functional composition