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00:00 - 19:0019:00 - 00:00

7:00 PM
did you rest @skull ?
 
7:20 PM
silence...
 
Good evening!
 
@Nimza Hi!!
 
@Charlie hi :)
 
@Nimza wassup?
 
@JonasTeuwen I have the same problem with limit! And our limit is 30 books too :( But there is a solution: there are 3 independent libraries))
 
7:23 PM
@Nimza i can only have ten...
@jasper are you alive?
 
@Charlie so strange... it's too few! Heh) It's so boring here, how are you?
 
@Nimza could be better... yeah ten is too few..and i can only keep for 10 days...
 
@Charlie hm... what a strange library?! But... we have special books that could be given only for one time during all study in university. What happened?
 
@Nimza oh... i'm just not 100% good...
 
eh :(
 
7:29 PM
@Nimza what about you?
 
Maybe somebody here knows about Cartan theorem (1951) in complex analysis?
 
hmm i don't, sorry
 
@Charlie nothing interesting. I didn't have a time for a walk for a month yet :( Work-study-work-study e.t.c.
 
@Nimza know how that feels...
...
sometimes i stay mesmerized when i realize that i'm studying math
it's so incredible!
 
8:08 PM
@Charlie Same here.
 
@GustavoBandeira :)
 
Geometria Analítica do Paulo Boulos, conhece?
 
@GustavoBandeira não...
 
Fui na faculdade hoje, me recomendaram.
 
@GustavoBandeira bacana!
@gustavo have you been studying calculus?
 
8:15 PM
@Charlie Yep. =)
 
@GustavoBandeira what are you studying?
 
Calculus, Geometry and I'll start on Physics.
 
I just did such acool theorem sum of 1/primes = infinity
 
Following the university curricula.
 
hmm
what part of calculus are you?
@jdoe I read:"I just did alcohol theorem..." :P
 
8:17 PM
I'm almost finishing the chapter on limits and entering derivatives.
 
@GustavoBandeira preety cool!are you understanding everything?
 
@GustavoBandeira good , good.hey , are you bold now?
 
Yes
Almost bold. :P
 
hehe
 
8:21 PM
I'm gonna use it as the MSE pic
 
@GustavoBandeira nice!
 
so greaking cool
 
Do you have a favourite function in mathematics?)
 
hmmm
 
favorite function.. Riemann Zeta Function
 
8:26 PM
@Nimza i like trigonometric functions.
@jdoe :)
 
@jdoe nice choice)))
 
@TessaDangerBamkin wassupa?
 
so i have a question for you genii
 
say
 
writing about AI and found this on an essay "I think there is a mathematical theorem stating that meaningful strings in a structured language have unique interpretations if their lengths exceed some rather small bound. I don't know how to formulate such a theorem. " anyone know what thisis?
 
8:27 PM
@Charlie why?
 
for all you cryptographers out there
 
@Nimza why what?
 
@TessaDangerBamkin, sounsds like Kolmogorov complexity
well it doesn't really
 
@Charlie why trigonometric functions?)
 
@Nimza they are cool! I like them.Like the curves, sometimes, the awckward things
 
8:29 PM
@Charlie and what about their analitic continuations in $\mathbb{C}$? Complex cosinus is really cute :)
 
@Nimza :D
i love curves!
 
hm im not sure thats right @jdoe looked it up and from what i can read it seems like its more abuot the decriptive length being related to the length of a string and not the amount of interpretations of a natural language
 
I love surfaces :)
 
@Nimza Nice!
@Nimza what's your favorite?
 
@Charlie I think $w^4 = z^4 - 1$. I've plotted it two weeks ago. I have a nice gif animation, I can send it to your mail
 
8:38 PM
@Nimza awesome!do it!
@Nimza my mail is in my profile
 
@Charlie I can't see it :(
ok
 
@Nimza got it?
 
aha'
 
hi
 
Hi!
 
8:41 PM
hi-hi
 
@Nimza did you send??
 
@Charlie yup
check your mail
 
@Nimza That's awesome!!!
 
does it roll?
 
@Nimza yes, it does!
 
8:45 PM
nice)
green points are branching points
 
looks like a beating heart
 
aha
 
@Nimza there's a heart shape
 
yup, I know one)
 
it's fascinating!
it's breathing :P
 
8:50 PM
a lot of fascinating sets is provided by reach sets of dynamical systems. Did you see some?
 
can you show me one example what you mean
is julia set one?
 
@Nimza no :(
 
@jdoe are you talking about heart shape? then no)
 
 
aha, that's nice :)
 
8:51 PM
 
@jdoe sweet!
 
it's from iterating z^2 + c in the complex plane
 
:)
 
it's very beautiful, but the mathematics is soo hard
youare' brave :P
I like things simple, but tough stuff can be very cool too
 
@jdoe i'm mathsochist
 
8:53 PM
haha
 
I didn't see :(
 
she is being lewd
maybe
 
talking about dynamical systems. that's a reach tube for one linear system cs5711.userapi.com/u2054176/140900259/y_57ffdf0a.jpg
 
thhat's interesting
 
:) aha. nonlinear systems are unimaginable at all!
Minimal surfaces are very beautiful too
 
8:57 PM
:-)
 
@Nimza 8-(.
 
brilliant website
 
@JonasTeuwen I think they should introduce VIP-readers notion :)
 
Really cool!
 
9:00 PM
I got that, otherwise only 10 books!
 
oho
@JonasTeuwen in that sense in live in soviet russia still: anybody can take no more than 30 books, the equal rights)))
 
I tried to apply it to d/dx sin(sin(x)) and got cos(x) cos(sin(x))
but that looks wrwong
wait a second, it' s actually correct
 
@jdoe that's right
 
well I'm confused because of this then math.stackexchange.com/questions/222297/…
according to that, shouldn't we have d/dx sin(sin(x)) = 2 cos(x) sin(x)?
certainly cos(x) cos(sin(x)) is not equal to 2 cos(x) sin(x)
 
there are no composition in the linked topic
 
9:13 PM
OH!
 
@jdoe read the question again
 
sin(x)^2 should mean the same as (sin(x))^2
that way sin^2(x) can be reserved for iterated sin
 
but what about traditions?)
@jdoe I don't know a good notation for compositional powers, but maybe $f^{\circ n}$ is ok?
 
that's fine but it's not necessary to write the circ
unless there's multiple operations exponentiation might be over
 
yup :)
 
9:21 PM
I accomplished precisely nothing today, I learned absolutely nothing, I actually think I've forgotten a few things over the course of the day
I had a negative productivity day
 
@jdoe do you know a functional transform $f \mapsto \sum\limits_{k=0}^{\infty} \frac{f^{\circ k}}{k!}$
 
no
 
heh) looks nice
 
looks like some weird fake version of maclaurin series
 
hm) yup, it is exponent $e(f(\cdot))$ if we consider composition as multiplication and usual addition. I don't know if it makes some productive sense
 
9:25 PM
composition as multiplication?
shouldn't you write f^{\times k} then?
 
aha
 
e.g. f^(*2)(x) = f(x)f(x) whereas f^(o2)(x) = f(f(x))
 
yup)
in economics the similar thing is made in study of informational goods
 
what's an informational good? that sounds interesting
 
for example some information considered as goods. In IT it makes sense
 
9:27 PM
cool, I didn't know that sort of stuff was taken into account
 
do you know Leontieff model of production?
 
no
 
:(
there exists a modification of such model for informational goods.
 
so for informational goods, how do you handle the fact that one can copy information infinitely many times at almost zero cost?
 
it is the most interesting thing!)))
 
9:29 PM
:D
 
we make a switch from usual addition and multiplication operations to a structure (idempotent semiring) with usual multiplication but with idempotent addition $a \oplus b = \max(a,b)$
 
I see!
 
we can define matrices powers in this semiring) find eigenvectors e.t.c.
 
cool
 
and the most interesting thing!
What do you think there arises instead of Fourier transform?
 
9:34 PM
Well I don't actually what the fourier transform is used for
 
ah :(
 
in economics
 
in advanced economics I think anything is used) I work mainly with Radon transform over hypersurfaces (within economics!)
 
so what is the fourier transform used for in the normal economics?
 
@jdoe I don't know if it has a clear economical interpretation, but it helps to receive some results (like a tool)
 
9:39 PM
ah right, that's how it is elsewhere
 
:)
 
but then when you're using these idempotent semirings what tool is used?
 
instead of Fourier? Fenhel transform: $f^{*}(y) = \sup_{x} ( x \cdot y - f(x) )$
render)
 
y isn't in the RHS?
 
in the RHS $y$ is multiplied by $x$ (scalar multiplication)
 
9:43 PM
ah!
this looks a lot simpler than the fourier transform!
 
:)
idempotent analysis is a lot simpler I think
 
nice
 
for example if matrix power series is convergent it's sum is defined only by first $n$ members
 
that sounds like a pretty fun theory
 
aha and it has very interesting applications
finding arbitration chains in cross-courses of currency matrix
 
9:46 PM
what is an arbitration chain?
 
do you know what is a cross-course matrix?
 
no
 
a matrix A such that $A[i,j]$ is a number of units of $i$-th currency to be exchanged on unit of $j$-th currency
 
hmm
 
ok?
 
9:49 PM
I'm not sure what that matrix means
it's a bit different than just exchange rates between different currencies?
 
that is :D it's my bad english
 
ahh
okay,
but is it symmetric?
 
no
 
you can change your money back and forth to get more and more each time?
 
hm, not so easy
~30 roubles = 1 $ then 1 rouble = 1/30 $ - there are no symmetry
 
9:51 PM
ohhh
ok!
 
but there may be chains $i_1, i_2, \ldots, i_k$, $i_1 = i_k$ that provide you possibility to gain money)
 
can there be chains where it does end up with more than you started?
ok
wait a second
when you say "currency"
does it mean just dollars, roubles, pounds?
or could it also be also goods?
(like some kind of information)
 
here it means dollars, roubles e.t.c.
 
okay
 
so idempotent analysis provides you possibility to find such chains or to say if they exist
that problem was actual when Europe was introducing the common currency
 
9:56 PM
that's neat!
 
I'm going to bed, good night! :)
 
later
 
good night, thanks for telling me about this!!
 
10:15 PM
hi @PeterTamaroff
 
@skullpatrol Hey
 
hi @IanMateus
 
@skullpatrol What are you up to today?
 
@PeterTamaroff Chillin'... how about you?
 
@skullpatrol Think I'll start with some algebra in a while
 
10:30 PM
@PeterTamaroff I was pondering the converse of the reflexive property of equality...
 
@skullpatrol Converse?
 
@PeterTamaroff Yes.
 
@skullpatrol Explain.
 
The reflexive property of equality states: If a is a real number, then a=a.
 
@skullpatrol Ok, so?
 
10:33 PM
@PeterTamaroff The converse would be If a=a, then a is a real number.
 
@skullpatrol Well, no.
You define equality over something. Before you state $a=a$ you must say what $a$ is.
 
So we can not say a=a iff a is a real number?
 
@skullpatrol Man, equality is something very broad.
 
or a is a real number iff a=a?
 
@skullpatrol No. $A=A$ is a definition.
For functions, for real numbers, for matrices, for topologies, whatever. We define what we mean when we say two things are equal. Or maybe better, equivalent.
@BenjaLim Duuuuuuude
 
10:42 PM
@PeterTamaroff yes
 
@BenjaLim No.
 
anything?
 
@PeterTamaroff Yes, stated as: If we know what we are talking about, then what we are talking about is what we are talking about.
 
@BenjaLim "Hello"
@skullpatrol I don't know where you want to get at.
 
14 mins ago, by skullpatrol
@PeterTamaroff I was pondering the converse of the reflexive property of equality...
@PeterTamaroff So it is not true.
 
10:46 PM
@skullpatrol It is not true.
 
Thank you.
 
11:18 PM
@BillDubuque
 
11:41 PM
One short question: Is it legitimate to write [0;1,1,1,...,n] for a infinte continued fraction? Because I am not sure wheter [0;1,1,1,...,n] is finite if and only if n=1, but for different n is infinite
 
@user45170 I think that that fact that you have $,\cdots, n$ would imply that it is finite.
 
@user45170 You mean $[0;1,1,1\dots,1,\dots]$?
That'd be better.
Or just $[0;\bar 1]$
@user45170 If and only if?
What do you mean by $ [0;1,1,1,...,n] $?
 
$[1;1,1,\cdots] = \varphi$ Yay!
 
@Argon \cdots makes it look odd.
 
@PeterTamaroff Which dots to use?
$[1;1,1,\ddots]$ :)
 
11:44 PM
@Argon Just $\dots$
 
\dots?
 
@Argon Yeah
 
Cool
 
\cdots fit better with say $1\cdot 2 \cdot \;\cdots\;\cdot n$
 
I dont want to check $[0;\bar 1]$, because it is clear that this is finite. I am interested in [0;1,1,1,...,n]. The infinite item should be n>1, every other item =1
 
11:46 PM
@PeterTamaroff Or better yet $1+2+\cdots+n$
 
@Argon Yes.
@user45170 What does $[0;1,1,1,...,n].$ mean? What do you want to symbolize with the three dots?
 
They should be symbolized as infnite dots. I have this sequence, here: $x_{n+1}=1/(1+x_n)$ for a random starting point x_0 > 0 and thought it might be possible to write it as an infinite continued fraction
 
@user45170 Sure :)
Do you know what it converges to?
 
Well that's the problem. If the starting point x_0=1 it converges to 0.618..., but I am not sure if it converges for a different starting point
 
I am terrible with proofs of stuff like this (Pedro is great, though)
But intuitively, I think that it should not matter what value you choose as $x_0$
 
11:52 PM
@user45170 Of course.
@user45170 You have some steps to carry out, but it isn't that hard.
Do you know monotone convergence?
 
Because as $n \to \infty$ the choice of $x_0$ becomes insignificant.
 
Yes I know monotone convergence. If x_n is bounded then it has a finit limit
 
@user45170 You're missing something.
 
The sequence only contains real numbers and x_n<= x_(n+1) or x_n>= x_(n+1)
 
@user45170 That's better. Monotone convergence states that a monotone and bounded sequence in $\mathbb R$ converges.
@user45170 In this case, we have a little "problem."
Let $a_1=a$ with $a\neq -1$.
For easeness, let's assume $a>-1$.
This means $a_2>0$ and in general $a_n>0$, yes?
 
11:59 PM
Yes, but we can take a>0
 
Well, yes. That makes it even nicer.
 
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