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12:05 AM
Is there a name for the fact that nonstrict inequalities are preserved through taking limits?
As in $a_n \le b_n\implies \lim\,a_n\le\lim\,b_n$.
 
I didn't say nothing. Weak order preservation? I'm sure there's a name for that, but no one really cares. :-)
 
My answer is two lines long and has three links in the first line. I need another link in the last sentence to balance the color symmetry for aesthetic purposes. I mean - ahem - the OP's understanding.
Actually I guess it looks better this way, never mind.
 
facepalm
@anon Do you want to receive something meaninglessly cool?
I'll take your silence as "Yes" :-P
 
Receive? As in something free for me?
 
Congratulations, you're now the proud owner of a Guru silver badge.
 
12:16 AM
Oh. Did you just upvote my pencil thing or something?
Cool, thanks.
 
Yeah.
Oh noes! There's a second silver badge approaching your profile! :-P
 
Which one is that?
 
And another!
But that's it for now :-P
Either way. I'm going to sleep now.
 
Well thanks man. Don't know what that was for but good night, I guess.
 
@anon: I'd call it monotonicity. :p
 
12:27 AM
@anon- Do you know how could the dot product of 3x3 matrix and 3x1 matrix could became a 4x1 matrix in this video youtube.com/watch?v=FoI57cdSWM0&feature=relmfu ?
 
@Victor: Give me a time. Too lazy to scour 8 minutes :P @Zhen: Yeah, that works.
 
user20683
What does xi typically mean in Ordinary Differential Equations of the First Order?
 
@anon- For me i never heard of this situation
 
@Victor: Uh, that's not a dot product. It's a 4x3 matrix multiplied by a vector (the vector taken as a 3x1 matrix), which results in a 4x1 matrix. Do you know matrix multiplication?
@World: You're going to have to give more context, it could mean literally anything with no context to go by.
 
user20683
12:31 AM
@anon The equation in question
 
user20683
I was wondering in Calculus whether or not you could integrate Arcsin(x)e^xdx
 
user20683
so I plugged it into Wolfram and got a no
 
user20683
so then I tried setting it to y' instead and that's what popped out
 
@World: There's no "xi" in that equation or the W|A ...
Oh, never mind, "xi" is just a greek letter. You can replace the \xi with a "t" or a "u" if you're uncomfortable with it.
 
@anon - Thanks i will check that out
 
user20683
12:33 AM
@anon the little squiggle thing I think
 
user20683
ah
 
user20683
so it's just some arbitrary variable?
 
A "dummy" variable that's used to express a definite integration (with upper bound dictated by the independent variable $x$)
 
user20683
@anon that makes sense
 
user20683
thanks
 
1:18 AM
Hmm. Someone could get Unsung Hero by starting a new account and only answering questions by OP's with no rep, and asking everyone to not vote on the answers. Once you get a badge you can't lose it, so you could then ask a moderator to merge that account with your primary one and you have the badge even if you're not supposed to :)
 
We'll have to hope that the moderators will be wary of merging accounts where both have non-trivial badge portfolios.
 
1:36 AM
Hi
 
I am reading a paper called 'warning signs for the possible collapse of contemporary mathematics' for a philosophy class. But I am confused, the author uses contemporary mathematics in 'ZFC is the foundation of contemporary mathematics'. So what is contemporary mathematics?
 
It means modern mathematics, the math of today's mathematics community.
 
great, thanks :-)
I find it weird, why do they use contemporary to indicate this?
 
Because that's one of the definitions of the word "contemporary," indeed the default definition in these sorts of intellectual contexts.
 
Perhaps an implication of the fact that English is not my mother tongue.
 
1:53 AM
Let me guess: one of the warning signs is how the mathematical establishment feels a need to actively suppress the author's revolutionary new (insert something here), because its general acceptance would cost them their jobs?
 
that would just be silly. I bet the author will somehow try to make ZFC look uncertain and possibly inconsistent.
 
Which is not too different from how good introductions to axiomatic set theory make it look.,
 
2:45 AM
@anon - Actualy i check out the video and i found the multiplication part doesn't make sense...
 
@Victor: Google "matrix multiplication" and read around.
 
@anon - But in the video it was 3x3 and 3x1 matrix multiplication...
to produce 4x1 matrix...
@anon - Hello, are you here?
@anon - Am i bothering you?
 
Only a little. I zone in and out of the chatroom. Anyway she writes on the board that the columns of A are given by c1, c2, c3, and each of these c's are in R^4 hence the matrix is in fact 4x3.
What makes you think A is 3x3 anyway?
 
@anon - May you show me a example why it is 4x3 ?
 
An example? Just take any three column vectors with four components and put them side-by-side into a matrix...
 
3:00 AM
@anon - Since i never learn matrix before, may you show me this operation of matrix?
is c the column vector?
 
What operation? Do you mean matrix multiplication? Yes, c is the column vector.
 
@anon - so c is 2x1 column vector?
 
4x1
 
@anon- Thanks for your help
 
3:57 AM
hi folks
 
how you doin @kannappan
 
Got a quiz in Analysi 2 at 2.15pm today!
Studying for it!
And getting distracted by SE!
 
ok....cool...best of luck....I distract you one last time for the day ...What is the test book you are following for analysis in your school ?
hi @anon
 
@RajeshD I use Rudin @RajeshD
If you tell me the kind of reference you need, I may be a bit more specific!
 
4:02 AM
What is the title of the book by Rudin ?
 
Principle of Math Analysis!
(Not Real and C'x Analysis.)
 
ok...i purchased it few days ago...just to cm the title i am asking..for it
 
@RajeshD What kind of Analysis do you want to learn?
 
hey
 
Metric Spaces? Real Analysis (Analysis on $\mathbb R$)?
 
4:06 AM
well i need to brush up some basic level and also...go on to study advanced concepts........but at my own pace.............the book shouldn't assume the reader to know too much of notations pre-hand
yeah only real analysis.................not complex analysis
@anon : did you change your gv ?
 
Yep. I've got a number of new GV's lined up for when the fancy strikes me.
 
hm cool
I have a doubt coming up on math.SE
Can we answer our own question and accept the answer ?
 
@RajeshD Yes You can
 
can I award my bounty to myself in that case ?
 
@RajeshD I am not sure abt that!
 
4:10 AM
In theory.
 
yes ??
 
Yes. In theory.
 
@Rajesh I'd like to tell you, for elementary real Analysis, do NOT read Rudin!
Rather read Elementary Analysis: Theory of Calculus by Ross
 
@kannappan : I've read books on basic real analysis like limits sequences, derivatives and the likes.....but never read anything advanced before
 
Then, may be you should try Rudin. But, my last semester Analysis course, I read from this text! This is elementary! Teaches you those $\epsilon-\delta$ rather clearly!
 
4:14 AM
Chatematics, hello!
 
okay okay.....i had a good grip on it before.....but when in doubt i certainly need to re-llok at it and it is not covered in Rudin i guess....but google and wiki are good enough i guess
hi
 
@Sri That edit taught me some TeX for the site! But, it will take like a few more edits for it to go into my system. =)
 
;)
 
I read somewhere in the chat transcript above a comment to which the following little piece of information is related: when a user's suspension ends, s/he gets all the rep points back.
 
4:18 AM
That's correct, innit? I remember Chandru getting his (her?) rep back.
 
@MarianoSuárezAlvarez Related question: what about the upvotes they get during the suspension period?
 
no idea
lemme ask
 
@anon How would Chandru ever get banned?
 
@DylanMoreland Why not? He was suspended sometime back. (Not banned.)
 
He didn't seem the type. It doesn't seem like an easy thing to do.
 
4:21 AM
Oh, let me look into meta.
 
Is it Chandrashekhar we are talking about?
 
The only suspensions I've ever seen are the ones for Harry (obvious) and Bill Dubuque (I don't know how I feel about it but I could always envision it as being possible). Oh well, it doesn't matter.
 
BTW who is this? Harry? Someone else? meta.math.stackexchange.com/questions/832/…
 
That's Harry.
 
4:24 AM
there have been a non negligible number of suspensions, in fact
 
Oh, they're the same person.
There's another thing I didn't know. I don't read meta enough.
 
@Srivatsan, you question is escalating to the highest ranks of the Powers That Be
it seems not many people know :)
 
lol.
 
Oh =) That is surprising; I assumed it was an obvious question.
Thanks for your effort, btw, Mariano.
 
@Srivatsan May be I'll take a guess:
They all go to A-t-r-?
 
4:31 AM
@KannappanSampath Didn't follow.
 
@Srivatsan I am guessing that they all go to Arturo!
(those rp points of suspended users during the suspension period)
 
@KannappanSampath In that case, you made a typo. :-) But why Arturo? He is a respected member, no doubt, but he doesn't have too much more powers than others. And he hasn't been an mod.
 
Otherwise I am unable to envision a human being with 100k points!
 
Arturo has many Langs as minions writing answers for him
 
There are no human beings with 100k on MSE...
Just Saiyan.
Hmm, that joke might go down the river if nobody knows about DBZ. Oh well.
 
4:37 AM
Well, I don't know what DBZ is... =)
 
Dragon BallZ?
 
Ah, of course. I have seen a few episodes.
 
@Srivatsan What does it mean for a point to be in Closure of a set?
 
It's only good when you're a kid and all you wanna see is invisibly fast fist fights, repetitive half hour trash talking, and planet-sized Kamehamehas.
 
@KannappanSampath Out of nowhere? :) Well, a point p is in the closure of a set A iff every open neighborhood of p intersects A nontrivially. I know I am kind-of stating just the definition, but are you looking for something deeper?
 
4:42 AM
@Srivatsan Yes. Like, a sequential version of it is not true in case of finite sets, right?
 
@KannappanSampath Huh?
 
Can someone give me the reason for the suspension of user chandru1 ??
 
Voting misbehavior? Maybe? I can't remember.
 
@KannappanSampath Let's take an example perhaps?
 
A point $x \in cl(A) \iff \exists (x_n) \to x, x_n \in A$ .
 
4:44 AM
That's right. Do you want to know how this checks out for finite $A$?
 
and $x_n \neq x$ for more than finitely many $n$.
 
@KannappanSampath I don't understand what this means and what this is doing here.
My guess is that you are conflating the notion of a limit point of A with closure of A.
 
Exactly! I need clarification here,please.
 
@RajeshD, he was suspended twice
I can't tell you the reasons tho, for they re supposed to be private
 
@KannappanSampath A'right. Want to make a separate room? Or is this room ok?
 
4:47 AM
first time for 7 days, the second time for 30 days
as per the system recommended schedule
 
This room is fine, @Sri. If we won't be crowding this room with limit points closure and blahs!
 
@KannappanSampath Fine then. I like closure better than limit point. So let's start with that. Honestly, I just find limit points to be too hacky. And I can't recall any applications of it either.
In a topological space, what I said is the definition of the closure. A point $p$ is in the closure of $A$ if every open neighborhood of $p$ intersects $A$ nontrivially.
 
@Srivatsan OK. My understanding is Closure of a set $A$ is $A \cup A'$.
 
Let's come to that. But: specialised to a metric space, the closure can be defined in other ways: A point $p$ is in the closure of $A$ if there exists a sequence $(p_n)$ residing in $A$ that converges to $p$.
 
(telling myself closure means open nbhd, not deleted nbhd)
 
4:50 AM
@Srivatsan From a purely intuitive point of view, limit point is actually more natural: a point $x$ can be in the closure of a set $A$ simply because it happens to be in $A$, but in order to be a limit point of $A$, it must be arbitrarily close to other points of $A$.
 
the derived set A' in fact has many applications. Historically, its study is one of the main sources of Set Theory as We Know It, for example
 
OK. So, that need not be distinct from $p$ for obvious reasons.
(that sequence I mean)
 
Cantor started out precisely by studying the possibe sets of non-convergence of fourier series, which lead to a statement involving iterated derived sets, which to be made precise ended up with him develoing cardinals and ordinals
 
@KannappanSampath It is true that $p_n$ needn't be distinct from $p$. But what is the obvious reason?
 
If I have a finite set and restrict that it must be distinct from $p$, then, closure will be empty, right?
 
4:54 AM
@MarianoSuárezAlvarez Ah, I see. Derived sets of which set?
 
of the set of non-convergence
 
@KannappanSampath If the space is $T_1$.
 
he insotruced ordinal numbers ot be able to take derived sets transfinitely
 
Hm, can you give a motivation for why derived sets would be useful in this context? // This is an interesting historical take; thanks. (I should say I don't know anything about fourier series convergence theory.)
 
@BrianMScott I am afraid I don't know anything about topological spaces, other than the way they are defined!
(I am a first year undergrad)
 
4:58 AM
I don't recall the details, google should find the story
lemme try
 
@KannappanSampath If you don’t impose some extra condition on the space, $X$ could consist of just two points, $0$ and $1$, with open sets $\varnothing, X$, and $\{0\}$. Then the only open nbhd of $1$ is the entire space, so every nbhd of $1$ contains a point of the sequence $\langle 0,0,0,\dots\rangle$ distinct from $1$.
 
@BrianMScott Well, thanks for pointing it out. [I was restricting attention to metric spaces mostly. :)]
@MarianoSuárezAlvarez Thanks for this.
 
@BrianMScott That makes sense. So, the condition is not obvious.
@Srivatsan I am now terrified that I have not comprehended the material properly for the quiz!
 
IIRC Cohen the independence guy also started out working on fourier series
I recall the analysts bragging about it :P
 
Seems they couldn't hold on to him though :P
 
5:03 AM
@KannappanSampath One often assumes that all spaces under consideration are $T_1$, because this property is equivalent to saying that for every $x\in X$, the singleton $\{x\}$ is a closed set.
 
@Kannappan: When is your quiz?
 
@Srivatsan It is scheduled for Today at 2.15 pm!! :(
 
I see. Then you should maybe focus on the metric thing for now and look at the topological notions later. (No offense, @Brian. :D)
 
If this is for an analysis class, I quite agree.
 
May be I'll get back to you guys for help. I think I'll think in Isolation for now! Thanks @Srivatsan and @Brian.
I am off!
 
5:06 AM
Sure.
Kids these days are so last minute. :-)
Then in 1872 he was able to show the same if the trigonometric series converged on $[a, b] \smallsetminus A$, provided $A^{(n)} = \emptyset$, where $A^{(n)}$ is the $n$-th derived set of $A$. The sequence of derived sets is monotone decreasing, and by taking intersections at appropriate points
$$
A' \supseteq A'' \supseteq \cdots \supseteq A^{(n)} \supseteq \cdots \supseteq \bigcap_{n=1}^{\infty} A^{(n)} \supseteq \cdots
$$
Question: why is this sequence of derived sets monotone decreasing? Is this some special feature of the set $A$?
 
Prove that the derived set of a set is closed
 
@Srivatsan Because $A'$ is what’s left after you remove from $A$ all of its isolated points. You might want to look up Cantor-Bendixson rank for further information.
 
Wow, this stuff is interesting.
@MarianoSuárezAlvarez Thanks, got it.
 
Indeed, it is a very pretty subject
 
@BrianMScott Isn't that not true? E.g., what happens if $A = \mathbb Q$?
I understand that after one step, we get a closed set, so maybe we can assume $A$ is closed without loss of generality.
 
5:19 AM
Most people get introduced to the derived set as just a gadget useful to come up with exercises in general topology and metric spaces.
 
@Srivatsan Then there are no isolated points, so $A=A'=A''=\dots$.
 
you cannot do that
indeed
 
@BrianMScott No, I don't understand this: let's say $A$ is a finite set, hence closed. Then $A'$ is empty, no (and not equal to $A$)?
 
@Srivatsan If $A$ is finite and $T_1$, then $A'=\varnothing$, yes.
 
Yes, let's assume $A \subseteq \mathbb R$.
@BrianMScott So, your claim that $A = A' = A'' = \cdots$ is not right, isn't it? What am I missing?
 
5:22 AM
Try proving the characterization that I mentioned a little while ago: $A'=A\setminus I$, where $I$ is the set of isolated points of $A$. This is often the best way to look at the derived set.
@Srivatsan It’s right when $A=\mathbb{Q}$, which was the case in question. (‘[W]hat happens if $A=\mathbb{Q}$?’)
 
Oh, I didn't read you properly then.
Give me a minute.
@BrianMScott I'm sorry but I still don't understand what this characterisation. It is not true that $A' \subseteq A$, is it? (What is true is that $A'' \subseteq A'$.)
 
Compute A' for A = {1/n, n\geq 1}$
 
Oh, I see the problem: you’re looking at the Cantor-Bendixson derivatives starting from an arbitrary subset of a space, and I’m looking at the C-B derivatives of a whole space. For your setting just assume that I was talking about your $A'$.
 
@MarianoSuárezAlvarez Yes, exactly. :) Or, $A = \mathbb Q$.
@BrianMScott Ok, that makes sense. Fine.
@BrianMScott I see. It's quite interesting that the derived set of the whole space could be a strict subset of itself.
 
And the only difference for subsets is that at the first stage you get $\operatorname{cl}A$ minus the isolated points of $A$ instead of $A$ minus the isolated points of $A$.
 
5:36 AM
Exactly. I got that. Thanks.
 
Thought so, but I wanted to be sure.
 
It is interesting, and merits a definition: a space is perfect if it equals its derived subset.
 
@MarianoSuárezAlvarez In other words, a perfect space is a fixed-point of the derived set operator.
Maybe I should call it derivative operator?
Corrected it.
 
the name is a 100 years old or so
 
5:54 AM
For all those holding their breath: when one gets unsuspended, The System™ recomputes reputation when a suspension expires, and all rep points awarded during the suspension (upvotes and downvotes) are included.
4
 
Thanks, Mariano.
 
Thanks, Mariano. I starred it.
 
6:07 AM
Hi guys
 
@Srivatsan, a sensible name for a space which stays put when you compute its derived space would be exponential space... :)
 
Alas, that would've been a perfect name =)
 
There is a question here that was posted as homework. However this answer here math.stackexchange.com/a/103624/5783 answers the full question. How do we deal with people who like to give out full answers for homework?
 
You add a comment, like you did
 
That’s about all you can do.
 
6:10 AM
Right. But the poster looks experienced enough to know not to do this.
 
The "MSE is a knowledge repository" vs. "It is a teaching place" debate is still not resolved conclusively, right?
 
Right. But I think the one on homework is pretty much resolved.
 
There are times when there really isn’t much that one can say without giving a full answer, though I agree that this wasn’t one of them.
@BenjaminLim snort Yes.
 
thermodynamic death will be brought by, in this part of the universe, by the whole of humanity reloading 9gag.com
 
Probably that user might not subscribe to your philosophy. Community consensus notwithstanding, we don't have the right to trample on anyone else's views. So I would say that you did the right thing with the comment; let's wait for the user's reaction (if any).
 
6:14 AM
@MarianoSuárezAlvarez Haha I love 9gag have you seen one on PIPA/SOPA/Megaupload??
@Srivatsan Thanks.
Let's see if that question breaks the record for the most downvoted question.
 
Hopefully not. I don't want the cherished kalle question to be displaced yet.
(Further, it is not as bad as the kalle post.)
 
What was the kalle post?
 
@BrianMScott Hint hint: Check the most downvoted post. :)
 
I was hoping to avoid having to figure out how to do so.
 
I am not sure if it is ok for me to post a link. For some reason tb avoided doing so.
 
6:19 AM
Got it. Thanks.
 
hm, what happened with the question with the copyrighted theorem?
 
I wonder how old the poster of the "new theorem" question is. There is a small chance he is 14-15 and he got downvoted like crazy because he didn't know how to approach such things.
@MarianoSuárezAlvarez Oh, you got to pay royalties everytime you use those results. :)
 
/me wishes people who can would vote to close that...
 
I don't want the dirt on my hands, sorry. =)
 
@Mariano: It's already voted closed. I'm not going to vote to delete it because I don't want it deleted.
 
6:30 AM
@anon I think Mariano was talking about the copyrighted theorem question.
 
Oh...
 
anon: Is the contraction "who're" wrong? See this edit: math.stackexchange.com/posts/103865/revisions.
 
@Srivatsan And I honestly don’t see any legitimate grounds for closing it.
 
@Sri: Technically it's correct, but while the contraction is perfect in spoken language it's kind of odd-looking (...) in text form, so you don't see it often.
 
@BrianMScott True that. Hence my comment. =)
 
6:33 AM
@Srivatsan No. That edit was wholly unnecessary, and I’d have rejected it if I’d caught it.
 
@BrianMScott Yes. In fact, it seems to me that we are browbeating the poor OP. More nitpicks than in an "usual" post.
 
That reminds me, I wrote a 10 page paper on special relativity when I was 11 or 12 and gave it to my science teacher. If I could, I would hunt it down and burn it.
 
@anon Hm, I used to write out "different proofs" and "more careful proofs" of things we saw in class (the material was original but surely not new to the world) and give it to my instructor to read. I am pretty sure he didn't care so much about them (since the emphasis was on problem-solving than on proofs). But I was quite proud of them at that time.
 
Crap, I've capped. When does the next day start on MSE's clock?
 
@anon That's quick. :) You can now officially take rest.
 
6:47 AM
I’ve now skimmed the full document. I will refrain from adding a comment pointing out that while I no longer remember the details, I discovered and proved something similar but rather more complicated when I was 11. (Mind you, I was sure even then that it was known, and I knew that my proof was extremely ugly!)
 
I have no idea what the theorem on that scribd document is. What is it in a nutshell?
Also, when does the next day start on MSE? :-)
 
Straightforward generalizations to higher order sequences of what’s described in the question.
 
@anon 7PM here, which means 4PM in Cal.
@BrianMScott Hm, impressive for the age. =)
 
What? It's 1AM where I am.
 
@Srivatsan Yep, we’re -0500, and California is -0800.
 
6:51 AM
@anon Oh, then 6PM local time. That's when the MSE day changes.
 
@anon Srivatsan was talking about the start of the MSE day, not the current time.
@anon So you’re on CST.
 
@BrianMScott I get awfully confused with these numbers. So much so that I stopped caring. As and when I need it, I google for the local time. =)
 
I'm in Nebraska now. I guess I have to go to sleep and then wait till dinner tomorrow.
 
@anon I did quite a bit of pro bono answering yesterday.
@Srivatsan I occasionally find it useful to know that we’re -0500 in winter and -0400 in summer.
 
@BrianMScott Hm, how so?
 
6:54 AM
Heh. Since I got 10k I only go for low hanging fruit, and it's not like you can just wait half a day to answer those, so I might end up pro bonoing anyway.
 
@Srivatsan For starters, when trying to estimate quickly and roughly what time it is somewhere else. And I occasionally run into times given only in UT.
 
Close this no-Lagrange-theorem question as duplicate? math.stackexchange.com/questions/103519/…
@BrianMScott Hm, that would be quite handy to me. For instance, for calling India on the telephone. But as I said, I find it rather convenient to just flip AM to PM and add some fudge factors, than to actually calculate the time. :)
 
@Srivatsan I already decided not to vote to close.
 
Oh ok fine. Thanks.
 
@Srivatsan If I were in your situation, I’d know the appropriate conversion.
 
6:57 AM
But may I know why?
 
@Srivatsan Mostly because of the OP’s long comment.
 
@BrianMScott I discovered that it didn't matter so much after all. I could get by in many ways.
How about this post? math.stackexchange.com/questions/99282/…. I thought we could put it to rest.
 
@Srivatsan I’d rather have Henning turn his comment into an answer.
 
@BrianMScott Well, actually, the most tricky thing for me is to get the daylight savings thing right. I don't have it down.
 
@Srivatsan Which? When it goes into and out of effect, or how it works?
 
7:04 AM
@BrianMScott The operative view: when should I do +1030, when +930? (This is for India time. I might have even forgotten these numbers now; but hopefully not. :))
 
cold weather is coming (
the whole winter it was around +7C, but February, ah February
 
I seem to understand things better now!
 
Cool. When is the exam?
 
@Kan: good to hear ) howdy
 
In 2 hours from now!
 
7:07 AM
@Ilya hi again, Ilya.
 
@Ilya I am doing good Ilya!
How are you?
 
I'm fine. Going today to Milan till Wednesday
@Srivatsan: hey-hey
 
@Ilya In that case, we might have to say good-byes today. I might not appear in MSE for long time. (For a long long time, in fact.)
 
I came across a startling result (though cannot be extended to general topology): A subset is totally bdd iff every sequence has a cauchy subsequence!
 
@Srivatsan: than it's nice that I've caught you. What happened? Hope, nothing bad
 
7:10 AM
@Srivatsan From when is that?
 
@Ilya Well, I am sort of ok. I am going to India for sometime.
@KannappanSampath From Wed/Thursday.
 
Does this make sense to anyone?
 
@Srivatsan If I may ask - planned or unplanned?
 
@Ilya Planned at short notice. :)
 
@Srivatsan Cool man. So, you'll be in India for like two months?
 
7:12 AM
@anon it does, but the notation I don't appreciate
 
@KannappanSampath Something like that.
 
I assume, N(A) stands for Null space of A
 
@Srivatsan well - I guess if you could say smth more you would already say it, so I stop my questions and can only wish you a good luck. Hope that will see you soon
 
Ls(A,b) GK!
 
@KannappanSampath linear space. the question is clear, the notation is not good
 
7:13 AM
generated by A and b?
 
@Ilya Thanks for understanding. :)
 
@KannappanSampath aha
 
I think it is the set of solutions of $Ax=b$.
 
@Srivatsan not at all
 
@anon If $x$ is a solution to the linear system $Ax=b$, and $y$ is in the null space of $A$, show that $x+ty$ is a solution to $Ax=b$ for all $t\in\mathbb{C}$. I have no idea what $w$ is supposed to be, however.
 
7:14 AM
@Ilya Not at all understanding? =)
 
I need to iron my shirts so I will be away
@Srivatsan :-PPPP that's my 4-tongue answer to you
 
I had a feeling it was a linear system.
 
@BrianMScott Guess: $w= x+ty$
 
Maybe; I optimistically prefer the conjecture that $w$ is a typo for $x$.
 
@BrianMScott If $w$ is actually $x$, then why would $w-y$ be in N(A)?
 
7:17 AM
What in the world. This user has had an account for 7 months but only just now did anything whatsoever on MSE.
 
I hate it if people don't write replies to mails!
 
@anon Your answer was wonderful! My congratulations!
 
He is from Bangalore and a "research Scholar" in TCS.

Conjecture: He is from IISc.
 
@Fortuon: Why thank you. I assume you're talking about the one where I just posted a picture from the first page of a Google Image search?
 
@KannappanSampath Who is this?
 
7:20 AM
@Srivatsan That user about who Anon was talking about! =)
 
@anon Indeed. That is the one .I believe Mathematicians should be lazy. In fact as lazy as we can get away with being!
 
@KannappanSampath I see. How do you know "he" is from Bangalore?
 
@Srivatsan Sorry: I was confused for a moment. I agree with your guess about $w$ and was hoping that $y$ was an error for $x$.
 
@Srivatsan the location is on zir homepage math.stackexchange.com/users/12518/hyperbolic
 
@Srivatsan His profile says so. To clarify: I am talking about Hyperbolic, regd. user for 7 months seen last 3 minutes ago, with a question Pythagoras Theorem!
 
7:23 AM
@BrianMScott Agreed.
@FortuonPaendrag @Kannappan Thank you. I must be blind.
 
with an answer, not question
 
But, the gender, as you pointed, is not clear.
 
No problems! Don't inflict pain on yourself this way!
@Srivatsan!
@Srivatsan I wanted to ask you long long ago... that if you knew someone by name, Prahladh Harsha!
 
I know of him. He did his undergrad in IITM, I believe.
 
@Srivatsan You are not wrong!
He did his Ph.D from the MIT, Boston.
 
7:27 AM
Sure, that I am more confident about. Under Madhu Sudan.
 
Yes!
Later @Srivatsan.Got to go for Lunch!
 
Later, Kannappan.
 
I think people should hide easter eggs in their answers before they delete them. That would make MSE a more fun place.
 
The ‘new discovery’ question is now half a kalle.
 
=)
 
7:42 AM
1 kalle sounds like an interesting unit of measurement.
 

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