@Srivatsan Except on the Wiki page, they use monotonic for the other sequence, but any sequence of bounded variation is the difference of two monotonic sequences
@robjohn No! please don't do that! That's a sin on a similar level as LaTeX'ing books written by typewriters. You destroy works of art and you have to fear to burn in tb's hell for that. :)
@Srivatsan I preserved a few of those notes that I took carefully during the first years of study. I threw most of my notes from high school in to the thrash can when I moved the third or fourth time because I figured: since I've never looked at them I won't look at them within the next, say 20 years. From elementary school I don't know. Maybe my mother has one or two notebooks somewhere.
The generic filter "generates" new sets, it also generates a new function. If your conditions are functions and the extension involves set inclusion (i.e. $p\le q$ means $p\subseteq q$ and ...) then the result is a function.
Simply note that two conditions are compatible if they agree on the intersection of their domains. It means, in particular that $p\cup q$ is also a condition.
@tb yes, but they are darn long unless I put them in \text{...} but that elides all spacing to one space. So I need to do spacing outside the \text{...} and escaped with \ . Ick!!!
Heh, I just looked at the OP of this question, and he hasn't been here since he said that he had answered the problem. I don't think I have to worry about being accepted on that problem ;-)